Odisha State Board BSE Odisha 7th Class Maths Solutions Chapter 5 ପରିମେୟ ସଂଖ୍ୟା Ex 5.5 Textbook Exercise Questions and Answers.
BSE Odisha Class 7 Maths Solutions Chapter 5 ପରିମେୟ ସଂଖ୍ୟା Ex 5.5
Question 1.
ନିମ୍ନଲିଖତ ସଂଖ୍ୟାମାନଙ୍କର ଗୁଣନାତ୍ମକ ବିଲୋମୀ ନିର୍ଣୟ କର ।
(କ) \frac{5}{9}
ସମାଧାନ:
\frac{9}{5}
(ଖ) \frac{-4}{3}
ସମାଧାନ:
\frac{-3}{4}
(ଗ) -2
ସମାଧାନ:
-\frac{1}{2}
(ଘ) 8
ସମାଧାନ:
\frac{1}{8}
(ଙ) 1 \frac{1}{2}
ସମାଧାନ:
1 \frac{1}{2} = \frac{3}{2} ∴ ଗୁଣନାତ୍ମକ ବିଲୋମୀ = \frac{3}{2}
(ଚ) \frac{11}{-12}
ସମାଧାନ:
\frac{-12}{11}
(ଛ) \frac{-2}{-19}
ସମାଧାନ:
\frac{-19}{-2} ଚା \frac{19}{2}
(ଜ) -2 \frac{1}{7}
ସମାଧାନ:
-2 \frac{1}{7} = \frac{-15}{7} ∴ ଗୁଣନାତ୍ମକ ବିଲୋମୀ = \frac{7}{15}
Question 2.
ଭାଗଫଳ ଲେଖ ।
(କ) 3 ÷ \frac{4}{5}
ସମାଧାନ:
3 × (\frac{4}{5} ର ବ୍ୟୁତ୍କ୍ରମ) = 3 × \frac{5}{4} = \frac{15}{4}
(ଖ) \frac{-3}{5} ÷ 2
ସମାଧାନ:
= \frac{-3}{5} × (2 ର ବ୍ୟୁତ୍କ୍ରମ) = \frac{-3}{5} × \frac{1}{2} = –\frac{3}{10}
(ଗ) \frac{-4}{7} ÷ 3
ସମାଧାନ:
\frac{-4}{7} × (3 ର ବ୍ୟୁତ୍କ୍ରମ) = \frac{-4}{7} × \frac{1}{3} = –\frac{4}{21}
(ଘ) \frac{1}{5} \div \frac{6}{7}
ସମାଧାନ:
= \frac{1}{5} × (\frac{6}{7} ର ବ୍ୟୁତ୍କ୍ରମ) = \frac{1}{5} × \frac{7}{6} = \frac{7}{30}
(ଙ) \frac{-1}{8} \div \frac{3}{4}
ସମାଧାନ:
= \frac{-1}{8} × (\frac{3}{4} ର ବ୍ୟୁତ୍କ୍ରମ) = -\frac{1}{8} \times \frac{4}{3}=-\frac{4}{24}=-\frac{1}{6}
(ଚ) \frac{-7}{6} \div\left(\frac{-2}{3}\right)
ସମାଧାନ:
\frac{-7}{6} × (\frac{-2}{3} ର ବ୍ୟୁତ୍କ୍ରମ) = =-\frac{7}{6} \times\frac{-3}{2}=\frac{(-7) \times(-3)}{6 \times 2}=\frac{7}{4}
(ଛ) \frac{-5}{6} \div\left(\frac{-1}{4}\right)
ସମାଧାନ:
\frac{-5}{6} × (-\frac{1}{4} ର ବ୍ୟୁତ୍କ୍ରମ) = -\frac{5}{6} \times \frac{-4}{1}=\frac{(-5) \times(-4)}{6}=\frac{10}{3}
(ଜ) \frac{-3}{13} \div\left(\frac{-4}{65}\right)
ସମାଧାନ:
\frac{-3}{13} × (-\frac{4}{65} ର ବ୍ୟୁତ୍କ୍ରମ) = \left(-\frac{3}{13}\right) \times\left(-\frac{65}{4}\right)=\frac{(-3) \times(-65)}{13 \times 4}=\frac{3 \times 65}{13 \times 4}=\frac{3 \times 13 \times 5}{13 \times 4}=\frac{15}{4}=\frac{3}{4}