Odisha State Board BSE Odisha 7th Class Maths Solutions Chapter 5 ପରିମେୟ ସଂଖ୍ୟା Ex 5.5 Textbook Exercise Questions and Answers.
BSE Odisha Class 7 Maths Solutions Chapter 5 ପରିମେୟ ସଂଖ୍ୟା Ex 5.5
Question 1.
ନିମ୍ନଲିଖତ ସଂଖ୍ୟାମାନଙ୍କର ଗୁଣନାତ୍ମକ ବିଲୋମୀ ନିର୍ଣୟ କର ।
(କ) \(\frac{5}{9}\)
ସମାଧାନ:
\(\frac{9}{5}\)
(ଖ) \(\frac{-4}{3}\)
ସମାଧାନ:
\(\frac{-3}{4}\)
(ଗ) -2
ସମାଧାନ:
\(-\frac{1}{2}\)
(ଘ) 8
ସମାଧାନ:
\(\frac{1}{8}\)
(ଙ) 1 \(\frac{1}{2}\)
ସମାଧାନ:
1 \(\frac{1}{2}\) = \(\frac{3}{2}\) ∴ ଗୁଣନାତ୍ମକ ବିଲୋମୀ = \(\frac{3}{2}\)
(ଚ) \(\frac{11}{-12}\)
ସମାଧାନ:
\(\frac{-12}{11}\)
(ଛ) \(\frac{-2}{-19}\)
ସମାଧାନ:
\(\frac{-19}{-2}\) ଚା \(\frac{19}{2}\)
(ଜ) -2 \(\frac{1}{7}\)
ସମାଧାନ:
-2 \(\frac{1}{7}\) = \(\frac{-15}{7}\) ∴ ଗୁଣନାତ୍ମକ ବିଲୋମୀ = \(\frac{7}{15}\)
Question 2.
ଭାଗଫଳ ଲେଖ ।
(କ) 3 ÷ \(\frac{4}{5}\)
ସମାଧାନ:
3 × (\(\frac{4}{5}\) ର ବ୍ୟୁତ୍କ୍ରମ) = 3 × \(\frac{5}{4}\) = \(\frac{15}{4}\)
(ଖ) \(\frac{-3}{5}\) ÷ 2
ସମାଧାନ:
= \(\frac{-3}{5}\) × (2 ର ବ୍ୟୁତ୍କ୍ରମ) = \(\frac{-3}{5}\) × \(\frac{1}{2}\) = –\(\frac{3}{10}\)
(ଗ) \(\frac{-4}{7}\) ÷ 3
ସମାଧାନ:
\(\frac{-4}{7}\) × (3 ର ବ୍ୟୁତ୍କ୍ରମ) = \(\frac{-4}{7}\) × \(\frac{1}{3}\) = –\(\frac{4}{21}\)
(ଘ) \(\frac{1}{5} \div \frac{6}{7}\)
ସମାଧାନ:
= \(\frac{1}{5}\) × (\(\frac{6}{7}\) ର ବ୍ୟୁତ୍କ୍ରମ) = \(\frac{1}{5}\) × \(\frac{7}{6}\) = \(\frac{7}{30}\)
(ଙ) \(\frac{-1}{8} \div \frac{3}{4}\)
ସମାଧାନ:
= \(\frac{-1}{8}\) × (\(\frac{3}{4}\) ର ବ୍ୟୁତ୍କ୍ରମ) = \(-\frac{1}{8} \times \frac{4}{3}=-\frac{4}{24}=-\frac{1}{6}\)
(ଚ) \(\frac{-7}{6} \div\left(\frac{-2}{3}\right)\)
ସମାଧାନ:
\(\frac{-7}{6}\) × (\(\frac{-2}{3}\) ର ବ୍ୟୁତ୍କ୍ରମ) = \(=-\frac{7}{6} \times\frac{-3}{2}=\frac{(-7) \times(-3)}{6 \times 2}=\frac{7}{4}\)
(ଛ) \(\frac{-5}{6} \div\left(\frac{-1}{4}\right)\)
ସମାଧାନ:
\(\frac{-5}{6}\) × (-\(\frac{1}{4}\) ର ବ୍ୟୁତ୍କ୍ରମ) = \(-\frac{5}{6} \times \frac{-4}{1}=\frac{(-5) \times(-4)}{6}=\frac{10}{3}\)
(ଜ) \(\frac{-3}{13} \div\left(\frac{-4}{65}\right)\)
ସମାଧାନ:
\(\frac{-3}{13}\) × (-\(\frac{4}{65}\) ର ବ୍ୟୁତ୍କ୍ରମ) = \(\left(-\frac{3}{13}\right) \times\left(-\frac{65}{4}\right)=\frac{(-3) \times(-65)}{13 \times 4}=\frac{3 \times 65}{13 \times 4}=\frac{3 \times 13 \times 5}{13 \times 4}=\frac{15}{4}=\frac{3}{4}\)