# BSE Odisha 6th Class Maths Solutions Chapter 5 ଭଗ୍ନ ସଂଖ୍ୟା Ex 5.6

Odisha State Board BSE Odisha 6th Class Maths Solutions Chapter 5 ଭଗ୍ନ ସଂଖ୍ୟା Ex 5.6 Textbook Exercise Questions and Answers.

## BSE Odisha Class 6 Maths Solutions Chapter 5 ଭଗ୍ନ ସଂଖ୍ୟା Ex 5.6

Question 1.
ନିମ୍ନ ଭଗ୍ନସଂଖ୍ୟା ମଧ୍ୟରେ ତୁଳନା କର।

(କ) $$\frac{7}{10}, \frac{8}{10}$$
ସମାଧାନ:
$$\frac{7}{10}<\frac{8}{10}$$ (∵ 7 < 8)

(ଖ) $$\frac{11}{26}, \frac{15}{26}$$
ସମାଧାନ:
$$\frac{11}{26}<\frac{15}{26}$$ (∵ 11 < 15)

(ଗ) $$\frac{12}{105}, \frac{8}{105}$$
ସମାଧାନ:
$$\frac{12}{105}>\frac{8}{105}$$ (∵ 12 > 8)

Question 2.
ଊର୍ଦ୍ଧ୍ୱ କ୍ରମରେ ସଜାଇ ଲେଖ।

(କ) $$\frac{1}{8}, \frac{5}{8}, \frac{3}{8}$$
ସମାଧାନ:
$$\frac{1}{8}<\frac{5}{8}<\frac{3}{8}$$ (∵ 1 < 3 < 5)

(ଖ) $$\frac{12}{17}, \frac{5}{17}, \frac{10}{17}$$
ସମାଧାନ:
$$\frac{12}{17}<\frac{5}{17}<\frac{10}{17}$$ (∵ 5 < 10 < 12)

Question 3.
ଅଧଃକ୍ରମରେ ସଜାଇ ଲେଖ।

(କ) $$\frac{1}{5}, \frac{11}{5}, \frac{3}{5}$$
ସମାଧାନ:
$$\frac{1}{5}>\frac{11}{5}>\frac{3}{5}$$ (∵ 11 > 3 > 1)

(ଖ) $$\frac{4}{13}, \frac{1}{13}, \frac{15}{13}$$
ସମାଧାନ:
$$\frac{4}{13}>\frac{1}{13}>\frac{15}{13}$$ (∵ 15 > 4 > 1)