CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Additional Exercise

Odisha State Board CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Additional Exercise Textbook Exercise Questions and Answers.

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Additional Exercise

Question 1.
Prove that the sum of the vectors directed from the vertices to the midpoints of opposite sides of a triangle is zero.
Solution:
Let D, E, F are midpoints of side BC, CA and AB of ΔABC
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Additional Exercise Q.1

Question 2.
Prove by vector method that the diagonals of a quadrilateral bisect each other iff it is a parallelogram.
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Additional Exercise Q.2

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Additional Exercise

Question 3.
If G is the centroid of a triangle ABC, prove that \(\overrightarrow{GA}+\overrightarrow{GB}+\overrightarrow{GC}=\overrightarrow{0}\).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Additional Exercise Q.3

Question 4.
If M is the midpoint of the side B͞C of a triangle ABC, prove that \(\overrightarrow{AB}+\overrightarrow{AC}=2 \overrightarrow{AM}\).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Additional Exercise Q.4

Question 5.
If \(\vec{a} \text { and } \vec{b}\) are the vectors represented by the adjacent sides of a regular hexagon, taken in order, what are the vectors represented by the other sides taken in order?
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Additional Exercise Q.5

Question 6.
If the points with position vectors 10î +3ĵ, 12î – 5ĵ and aî +11ĵ are collinear, find the value of a.
Solution:
Let the points are A, B and C.
As A, B and C are co-llinear.
We have \(\overrightarrow{AB}=\overrightarrow{AC}\)
\(\overrightarrow{AB}=\lambda \overrightarrow{AC}\)
⇒ (12i – 5j) – (10i + 3j)
⇒ λ [(ai + 11j) – (10i + 3j)
⇒ 2i – 8j = (a – 10)λ i + 8λ j
Comparing the components we have
8λ = -8
⇒ λ = -1
(a – 10) (-1) = 2
⇒ -a + 10 = 2
⇒ a = 8

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Additional Exercise

Question 7.
Prove that the four points with position vectors \(2 \vec{a}+3 \vec{b}-\vec{c}, \vec{a}-2 \vec{b}+3 \vec{c}, 3 \vec{a}+4 \vec{b}-2 \vec{c}\) and \(\vec{a}-6 \vec{b}+6 \vec{c}\) are coplanar.
Solution:
Let the points are A, B, C
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Additional Exercise Q.7

Question 8.
For any vector \(\vec{r}=x \hat{i}+y \hat{j}+z \hat{k}\) prove that \(\vec{r}=(\vec{r} \cdot \hat{i}) \hat{i}+(\vec{r} \cdot \hat{j}) \hat{j}+(\vec{r} \cdot \hat{k}) \hat{k}\).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Additional Exercise Q.8

Question 9.
If two vectors \(\vec{a} \text { and } \vec{b}\) are such \(|\vec{a}|={3},|\vec{b}|=2 \text { and } \vec{a} \cdot \vec{b}={6}\text { find }|\vec{a}+\vec{b}| \text { and }|\vec{a}-\vec{b}|\).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Additional Exercise Q.9

Question 10.
If \(\vec{a}\) makes equal angles with î, ĵ and k̂ and has magnitude 3, prove that the angle between \(\vec{a}\) and each of î ,ĵ and k̂ is \(\cos ^{-1}\left(\frac{1}{\sqrt{3}}\right)\).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Additional Exercise Q.10

Question 11.
If \(\vec{a}, \vec{b}, \vec{c}\) are such that \(\vec{a} \cdot \vec{b}=\vec{a} \cdot \vec{c}\) then show that \(\vec{a}=\overrightarrow{0} \text { or } \vec{b}=\vec{c} \text { or } \vec{a}\) is perpendicular to \(\vec{b}-\vec{c}\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Additional Exercise Q.11

Question 12.
If \(\vec{a}+\vec{b}+\vec{c}=\overrightarrow{0},|\vec{a}|={3},|\vec{b}|={5}\text { and }|\vec{c}|=7\), find the angle between \(\vec{a} \text { and } \vec{b}\).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Additional Exercise Q.12

Question 13.
If \(\vec{a}, \vec{b}, \vec{c}\) are unit vectors such that \(\vec{a}+\vec{b}+\vec{c}=\overrightarrow{0}\), find the value of \(\vec{a} \cdot \vec{b}+\vec{b} \cdot \vec{c}+\vec{c} \cdot \vec{a}\).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Additional Exercise Q.13

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Additional Exercise

Question 14.
Find the angles which the vector \(\vec{a}=\hat{i}-\hat{j}+\sqrt{2} \hat{k}\) makes with the coordinate axes.
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Additional Exercise Q.14

Question 15.
Find the angle between \(\vec{a} \text { and } \vec{b}\) if \(|\vec{a} \times \vec{b}|=\vec{a} \cdot \vec{b}\).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Additional Exercise Q.15

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