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Odisha State Board BSE Odisha 6th Class English Solutions Follow-Up Lesson 4 The Three Questions Textbook Exercise Questions and Answers.

BSE Odisha Class 6 English Solutions Follow-Up Lesson 4 The Three Questions

BSE Odisha 6th Class English Follow-Up Lesson 4 The Three Questions Text Book Questions and Answers

Session – 1 ( ସୋପାନ – ୧)

I. Pre-Reading (ପଢ଼ିବା ପୂର୍ବରୁ):
Here is a similar story for you. Read the story and do the activities. Some activities are given. The rest of the activities will be designed by your teacher. S/he will write them on the blackboard and help you do the tasks.
(ଏଠାରେ ତୁମ ପାଇଁ ଗୋଟିଏ ଏକାପରି ଗପ ଅଛି । ଗପଟିକୁ ପଢ଼ ଏବଂ କାର୍ଯ୍ୟାବଳୀଟିକୁ କର । କେତେକ କାର୍ଯ୍ୟାବଳୀ ଦିଆଯାଇଛି । ଅବଶିଷ୍ଟ କାର୍ଯ୍ୟାବଳୀ ତୁମ ଶିକ୍ଷକଙ୍କଦ୍ୱାରା ପ୍ରସ୍ତୁତ କରାଯିବ । ସେ (ପୁ/ସ୍ତ୍ରୀ) ସେଗୁଡ଼ିକୁ କଳାପଟାରେ ଲେଖିଦେବେ ଏବଂ ଏହି ପ୍ରଶ୍ନଗୁଡ଼ିକର ଉତ୍ତର କରିବାରେ ତୁମକୁ ସାହାଯ୍ୟ କରିବେ ।)

II. While-Reading (ପଢ଼ିବା ସମୟରେ)
Text – (ପାଠ୍ୟବସ୍ତୁ)

Read paragraphs 1-3 silently and answer the questions that follow.
(ଅନୁଚ୍ଛେଦ ୧ – ୩ କୁ ନୀରବରେ ପଢ଼ା ଏବଂ ପରବର୍ତ୍ତୀ ପ୍ରଶ୍ନଗୁଡ଼ିକର ଉତ୍ତର ଦିଅ ।)
1. Once there was a great king in Germany. He liked soldiers very much because he was a good soldier himself. He had a special liking for one section of tall soldiers in his army. He kept that section under his own care and loved to watch it. He wanted to make it the best section of the army and tried hard to get the best men for it.

2. At the first meeting, the king used to ask every new soldier the following three questions.
“How old are you?
How long have you served me already?
Do you like the food or the quarters here ?”

3. Once a man from another country came to join the German army. He did not know the German language, “How can I answer the king’s questions ?” he said, “I can’t understand them.”

ଓଡ଼ିଆ ଅନୁବାଦ :
(୧) ଏକଦା (ଥରେ) ଜର୍ମାନୀ ଦେଶରେ ଜଣେ ବିଶିଷ୍ଟ (ମହାନ୍) ରାଜା ଥିଲେ । ସେ ସୈନିକମାନଙ୍କୁ ବହୁତ ଭଲ ପାଉଥିଲେ କାରଣ ସେ ନିଜେ ଜଣେ ଭଲ ସୈନିକ ଥିଲେ । ତାଙ୍କର ତାଙ୍କ ସୈନ୍ୟବାହିନୀର ଏକ ଡେଙ୍ଗା ସୈନ୍ୟ ବିଭାଗ ପାଇଁ ସ୍ବତନ୍ତ୍ର ପସନ୍ଦ|ରୁଚି ଥିଲା । ସେ ସେହି ସୈନ୍ୟ ବିଭାଗ (ଦଳକୁ) ତାଙ୍କ ନିଜ ଦାୟିତ୍ଵରେ ରଖିଥିଲେ ଏବଂ ଏହାକୁ ଦେଖିବାକୁ ଭଲ ପାଉଥିଲେ । ସେ ଏହାକୁ ସୈନ୍ୟବାହିନୀର ସବୁଠାରୁ ଭଲ ବିଭାଗ (ଦଳ) ରୂପେ ଗଢ଼ିବାକୁ ଚାହୁଁଥିଲେ ଏବଂ ଏଥ‌ିପାଇଁ ସର୍ବୋତ୍ତମ ଲୋକମାନଙ୍କୁ ପାଇବାକୁ ବହୁତ ଚେଷ୍ଟା କରୁଥିଲେ ।

(୨) ପ୍ରଥମ ସାକ୍ଷାତ୍‌ରେ ରାଜା ପ୍ରତ୍ୟେକ ନୂଆ ସୈନିକଙ୍କୁ ପ୍ରାୟତଃ ନିମ୍ନଲିଖ୍ ତିନିଗୋଟି ପ୍ରଶ୍ନ ପଚାରୁଥିଲେ ।
ତୁମେ କେତେ ସମୟଧରି ମୋତେ ସେବା ପ୍ରଦାନ କରିଛ ? ତୁମେ ଏଠାରେ ଖାଦ୍ୟ କିମ୍ବା ବାସଗୃହ ପସନ୍ଦ କରୁଛ ?

(୩) ଥରେ ଅନ୍ୟ ଦେଶରୁ ଜଣେ ଲୋକ ଜର୍ମାନ୍ ସୈନ୍ୟବାହିନୀରେ ଯୋଗଦେବାକୁ ଆସିଲେ । ସେ ଜର୍ମାନ୍ ଭାଷା ଜାଣି ନଥୁଲେ, ସେ କହିଲେ, ‘‘କିପରି ମୁଁ ରାଜାଙ୍କର ପ୍ରଶ୍ନଗୁଡ଼ିକର ଉତ୍ତର ଦେଇପାରିବି ? ମୁଁ ତ ସେଗୁଡ଼ିକୁ ବୁଝିପାରିବି ନାହିଁ ।?

Comprehension Questions – (ବୋଧମୂଳକ ପ୍ରଶ୍ନବଳୀ) :

Question 1.
Why did the king like soldiers ?
(କାହିଁକି ରାଜା ସୈନ୍ୟବାହିନୀକୁ ଭଲ ପାଉଥିଲେ ?)
Answer:
The king liked soldiers very much because he was a good soldier himself.

Question 2.
How many questions did the king ask a new soldier?
(ଜଣେ ନୂଆ ସୈନିକକୁ ରାଜା କେତେଗୋଟି ପ୍ରଶ୍ନ ପଚାରୁଥିଲେ ?)
Answer:
The king used to ask three questions to a new soldier.

Question 3.
What was the problem with the new soldier?
(ନୂଆ ସୈନିକର କ’ଣ ସମସ୍ୟା ଥିଲା ?)
Answer:
The problem with the new soldier was that he did not know the German language.

Session – 2 (ସୋପାନ – ୨)
III. Post-Reading (ପଢ଼ିସାରିବା ପରେ)

Read paragraphs 4-6 silently and answer the questions that follow.
(ଅନୁଚ୍ଛେଦ ୪ – ୬ କୁ ନୀରବରେ ପଢ଼ ଏବଂ ପରବର୍ତ୍ତୀ ପ୍ରଶ୍ନଗୁଡ଼ିକର ଉତ୍ତର ଦିଅ ।)
4. His officer told him all three questions and the way of answering them. He said the king always asked the same questions in the same order. So the soldier decided to answer them in that order

5. One day the king came to visit the army. He saw the new soldier and began to ask him questions. But this time the questions were in a different order. The soldier did not know this because he did not. understand the king’s words at all.

6. King: How long have you been in my service?
Soldier: Thirty years, sir.
King: How is it? You look so young! What’s your age?
Soldier: Three weeks, sir.
King: What do you mean? Are you mad, or am I?
Soldier: Both sir.

ଓଡ଼ିଆ ଅନୁବାଦ :
(୪). ତାଙ୍କର ଉଚ୍ଚ/ପଦସ୍ଥ କର୍ମଚାରୀ ତାଙ୍କୁ ସମସ୍ତ ତିନୋଟି ପ୍ରଶ୍ନ ଏବଂ ସେଗୁଡ଼ିକୁ ଉତ୍ତରଦେବା ଶୈଳୀ କହିଦେଲେ । ସେ କହିଲେ ଯେ ରାଜା ସର୍ବଦା ସେହି ଏକା ପ୍ରଶ୍ନ ଏକାକ୍ରମରେ ପଚାରନ୍ତି । ତେଣୁ ସୈନିକଟି ସ୍ଥିରକଲା ସେଗୁଡ଼ିକୁ ସେହି କ୍ରମରେ ଉତ୍ତର ଦେବାକୁ ।
(୫) ଦିନେ ରାଜା ସୈନ୍ୟବାହିନୀକୁ ପରିଦର୍ଶନ କରିବାକୁ ଆସିଲେ । ସେ ନୂଆ ସୈନିକକୁ ଦେଖିଲେ ଏବଂ ତାଙ୍କୁ ପ୍ରଶ୍ନଗୁଡ଼ିକ ପଚାରିବାକୁ ଆରମ୍ଭ କଲେ । କିନ୍ତୁ ଏଥର ପ୍ରଶ୍ନଗୁଡ଼ିକ ଭିନ୍ନ କ୍ରମରେ ଥିଲା । ସୈନିକଟି ଏହା ଜାଣିନଥୁଲା କାରଣ ସେ ରାଜାଙ୍କର ଶବ୍ଦଗୁଡ଼ିକୁ ଆଦୌ ବୁଝିପାରୁ ନଥିଲା ।

(୬) ରାଜା: କେତେକାଳ ହେଲା ତୁମେ ମୋ’ର ସେବାରେ ନିୟୋଜିତ ଅଛ ?
ସନିକ: ତିରିଶ ବର୍ଷ, ମହାଶୟ ।
ରାଜା: ଏହା କିପରି ସମ୍ଭବ ? ତୁମେ ଏତେ ଯୁବକ/କମ୍ ବୟସର ଦେଖାଯାଉଛ ? ତୁମର ବୟସ କେତେ ?
ସନିକ: ତିନି ସପ୍ତାହ, ମହାଶୟ ।
ରାଜା: ତୁମେ କ’ଣ ଭାବୁଛ ? ତୁମେ ପାଗଳ ନା ମୁଁ ?
ସନିକ: ଉଭୟ, ମହାଶୟ ।

Comprehension Questions – (ବୋଧମୂଳକ ପ୍ରଶ୍ନବଳୀ) :

Question 1.
Who helped the new soldier in preparing to answer the king’s questions?
(କିଏ ନୂଆ ସୈନିକକୁ ରାଜାଙ୍କ ପ୍ରଶ୍ନଗୁଡ଼ିକର ଉତ୍ତର ଦେବାପାଇଁ ପ୍ରସ୍ତୁତ କରିବାରେ ସାହାଯ୍ୟ କଲା ?)
Answer:
His officer helped the new soldier, in preparing to answer the king’s questions.

Question 2.
What did the king ask first?
(ରାଜା ପ୍ରଥମେ କ’ଣ ପଚାରିଲେ ?)
Answer:
The king first asked, “How long have you been in my service?

Question 3.
What did the soldier answer?
(ସୈନିକଟି କ’ଣ ଉତ୍ତର ଦେଲା ?)
Answer:
The soldier answered, “Thirty years, sir.”

Session – 3 ( ସୋପାନ – ୩)
III. Post-Reading (ପଢ଼ିସାରିବା ପରେ)

1. Writing- (ଲେଖୁବା) :
(a) Answer the following questions
(କବିତାଟି କେଉଁ ବିଷୟରେ ଆଧାରିତ ?)

(i) Why did the king like soldiers?
(କାହିଁକି ରାଜା ସୈନିକମାନଙ୍କୁ ଭଲ ପାଉଥିଲେ ?)
Answer:
The king liked the soldiers very much because he was a good soldier himself.

(ii) How many questions did the king ask?
(ରାଜା କେତୋଟି ପ୍ରଶ୍ନ ପଚାରିଲେ ?)
Answer:
The king asked three questions.

(iii) What was the problem with the new soldier ?
(ନୂଆ ସୈନିକର କ’ଣ ସମସ୍ୟା ଥିଲା ?)
The solder did not know.
Answer:
The soldier did not know the German language. So the problem with the new soldier was how he could answer the king’s questions.

(iv) Who helped him?
(କିଏ ତାକୁ ସାହାଯ୍ୟ କଲା ?)
Answer:
His officer helped him to answer the king’s questions.

(v) Did the help work ?
(ସାହାଯ୍ୟଟି କାମରେ ଲାଗିଲା କି ?)
Answer:
No, the help did not work at all.

(vi) Why? (କାହିଁକି ?)
Because the king did
Answer:
Because the king did not ask the same questions in the same order. As the questions were in a different order, the soldier did not answer the king’s questions correctly.

b. Match the questions under ‘A’ with the answers under ‘B’.
(‘A” ତଳେ ଥ‌ିବା ପ୍ରଶ୍ନଗୁଡ଼ିକୁ ‘B’ ତଳେ ଥିବା ଉତ୍ତରଗୁଡ଼ିକ ସହ ମିଳାଅ ।)

Answer:

Answer:

Now write on what really happened based on your matching.
(ବର୍ତ୍ତମାନ ତୁମର ଯୋଡ଼ିବାକୁ ଭିତ୍ତିକରି ଯାହା ପ୍ରକୃତରେ ଘଟିଗଲା ଲେଖ ।)
When the king asked, “________ old _______?” The soldier replied, “__________” . Next , when he “How long _________ ?” The soldier replied, “___________”Finally, When____________________________ The soldier replied,___________________.
Answer:
When the king asked, “How old are you ?” The soldier replied, “Three weeks, sir.” Next, when he asked, “How long have you served me already? The soldier replied, “Thirty years, sir.” Finally, when the king asked. “Do you like the food or the quarters here ?’’ The soldier replied, “Both sir.’’

Word Note – (ଶବ୍ଦାର୍ଥ)
(The words / phrases have been defined mostly on contextual meanings.)
(ଶବ୍ଦ । ଖଣ୍ଡବାକ୍ୟଗୁଡ଼ିକ ଅଧିକାଂଶତଃ ପ୍ରସଙ୍ଗଗତ ଅର୍ଥ ଉପରେ ନିର୍ଭର କରି ବ୍ୟାଖ୍ୟା କରାଯାଇଛି ।)

great – ବହୁତ ଭଲ
soldier – ସନିକ
liking – ପସନ୍ଦ
section – ବିଭାଗ
tall – ଲମ୍ବା
army – ସେନା
own – ନିଜର
care – ଯତ୍ନ
hard – କଠିନ
used to – ଅଭ୍ୟସ୍ତ
served – ପରିବେଷିତ
quarters – କ୍ୱାର୍ଟର୍ସ
German language – ଜର୍ମାନ ଭାଷା
order – କ୍ରମ
understand – ମୋତେ ବୁ
mad – ପାଗଳ
developed – ବିକଶିତ
satisfaction – ସନ୍ତୁଷ୍ଟ
anger – କ୍ରୋଧ
deaf – ବଧିର
seriously ill – ଗୁରୁତର ଅସୁସ୍ଥ
special liking- ବିଶେଷ ପସନ୍ଦ
same order – ସମାନ କ୍ରମ
decided – ସ୍ଥିର କଲା
visit – ପରିଦର୍ଶନ କରନ୍ତୁ
how long – କେତେ ଦିନ
began – ଆରମ୍ଭ ହେଲା
at all – ସବୁ ସମୟରେ
service – ସେବା
so young – ଏତେ ଯୁବକ
age – ବୟସ
weeks – ସପ୍ତାହଗୁଡିକ
mean – ଅର୍ଥ
both – ଉଭୟ
classmate – ସହପାଠୀ
problems – ସମସ୍ୟାଗୁଡିକ
finally – ଶେଷରେ

Odisha State Board Elements of Mathematics Class 12 CHSE Odisha Solutions Chapter 7 Continuity and Differentiability Ex 7(d) Textbook Exercise Questions and Answers.

CHSE Odisha Class 12 Math Solutions Chapter 7 Continuity and Differentiability Exercise 7(d)

Question 1.
Prove the formulae (4) to (7).
Solution:
(4) \(\frac{d}{d x}\)(cos-1 x) = \(\frac{-1}{\sqrt{1-x^2}}\)
Let y = cos^-1 x
⇒ x = cos y
⇒ \(\frac{d}{d x}\) = \(\frac{1}{\left(\frac{d x}{d y}\right)}\) = \(\frac{1}{-\sin y}\)
But sin y ≥ 0 when
y ∈ [0, π] ( ∵ [0, π] is the principal value branch for cos^-1 x)
∴ \(\frac{d y}{d x}\) = \(\frac{-1}{\sqrt{1-\cos ^2 y}}\) = \(\frac{-1}{\sqrt{1-x^2}}\)

(5) Let y = tan^-1 x
⇒ x = tan y

(6) Let y = cot^-1 x
⇒ x = cot y

(7) Let y = cosec^-1 x
⇒ x = cosec y

Question 2.
Find derivatives of the following functions.
sin^-1 2x
Solution:
y = sin^-1 2x

Question 3.
cot^-1 √x
Solution:
cot^-1 √x

Question 4.
sec^-1 (2x + 1)
Solution:
y = sec^-1 (2x + 1)

Question 5.
cos^-1 \(\sqrt{\frac{1+x}{2}}\)
Solution:

Question 6.
cos^-1 \(\left(\frac{x-\frac{1}{x}}{x+\frac{1}{x}}\right)\)
Solution:

Question 7.
tan^-1 (cos √x)
Solution:
y = tan^-1 (cos √x)

Question 8.
x² cosec^-1 \(\left(\frac{1}{\ln x}\right)\)
Solution:

Question 9.
cot^-1 \( \frac{\sqrt{1-x^2}}{x} \)
Solution:

Question 10.
(x sin^-1 x)¹⁵
Solution:
y = (x sin^-1 x)¹⁵

Question 11.
sin^-1 \( \sqrt{\frac{1-x}{1+x}} \)
Solution:

Odisha State Board Elements of Mathematics Class 12 CHSE Odisha Solutions Chapter 1 Relation and Function Ex 1(c) Textbook Exercise Questions and Answers.

CHSE Odisha Class 12 Math Solutions Chapter 1 Relation and Function Exercise 1(c)

Question 1.
Show that the operation ∗ given by x ∗ y = x + y – xy is a binary operation on Z, Q and R but not on N.
Solution:
The operation ∗ given by
x ∗ y = x + y – xy
Clearly for all x, y ∈ Z
x + y – xy ∈ Z
⇒ x ∗ y ∈ Z
∴ ∗ is a binary operation on Z.
For all x, y ∈ Q
x + y – xy ∈ Q
⇒ x ∗ y ∈ Q
⇒ ∗ is a binary operation on Q for all x, y, ∈ R.
x + y – xy ∈ R
⇒ x ∗ y ∈ R
⇒ ∗ is a binary operation on R
Again 3, 4 ∈ N.
3 + 4 – 3 x 4 = 7 – 12 = – 5 ∉ N
i.e., x, y ∈ N
≠ x ∗ y ∈ N
∴ ∗ is not a binary operation on N.

Question 2.
Determine whether the following operations as defined by ∗ are binary operations on the sets specified in each case. Give reasons if it is not a binary operation.
(i) a ∗ b = 2a + 3b on Z.
(ii) a ∗ b = ma – nb on Q⁺ where m and n ∈ N.
(iii) a ∗ b = a + b (mod 7) on {0, 1, 2, 3, 4, 5, 6}
(iv) a ∗ b = min {a, b} on N.
(v) a ∗ b = GCD {a, b} on N.
(vi) a ∗ b = LCM {a, b} on N.
(vii) a ∗ b = LCM {a, b} on {0, 1, 2, 3, 4……, 10}
(viii) a ∗ b = \(\sqrt{a^2+b^2}\) on Q⁺
(ix) a ∗ b =a × b (mod 5) on {0, 1, 2, 3, 4}.
(x) a ∗ b = a² + b² on N.
(xi) a ∗ b = a + b – ab on R – {1}.
Solution:
(i) For all a, b ∈ Z
2a + 3b ∈ Z
⇒ a ∗ b ∈ Z
∗ is a binary operation on Z.

(ii) Let a = 1, b = 2
m = 1, n = 3
ma – nb = 1 – 6 = – 5 ∉ Q⁺
∴ a, b ∈ Q⁺ ≠ a ∗ b ∈ Q⁺
⇒ ∗ is not a binary operation on Q⁺

(iii) a ∗ b = a + b (mod 7) ∈ {0, 1, 2, 3, 4, 5, 6}
for a, b ∈ 7
∗ is a binary operation on the given set.

(iv) a, b ∈ N ⇒ min {a, b} ∈ N
∴ a ∗ b ∈ N
⇒ ∗ is a binary operation on N.

(v) for all a, b ∈ N, GCD [a, b] ∈ N
⇒ a ∗ b ∈ N
⇒ ∗ is a binary operation on N.

(vi) for all a, b ∈ N, LCM {a, b} ∈ N
⇒ a ∗ b ∈ N
⇒ ∗ is a binary operation on N.

(vii) Let A = {0, 1, 2, ….. 10}
4, 5 ∈ A but 4 ∗ 5 = LCM {4, 5}
= 20 ∉ A
⇒ ∗ is not a binary operation on A.

(viii) for all a, b ∈ Q⁺
a ∗ b = \(\sqrt{a^2+b^2}\) ∉ Q⁺
⇒ ∗ is not a binary operation on Q⁺.

(ix) For all a, b ∈ {0, 1, 2, 3, 4}
a ∗ b = a × b (mod 5) ∈ {0, 1, 2, 3, 4}
∴ ∗ is a binary operation on the given set.

(x) for all a, b ∈ N, a * b = a² + b² ∈ N
∴ ∗ is a binary operation on N.

(xi) For all a, b ∈ R – {1}
a ∗ b = a + b – ab ∈ R – {1}
∴ ∗ is a binary operation on R – {1}

Question 3.
In case ∗ is a binary operation in Q2 above, test whether it is (i) associative
(ii) commutative, Test further if the identity element exists and the inverse element for any element of the respective set exists.
Solution:
(i) On Z the binary operation is
a ∗ b = 2a + 3b
Commutative:
b ∗ a = 2b + 3a ≠ a ∗ b
∴ ∗ is not commutative.

Associative:
(a ∗ b) ∗ c = (2a + 3b) ∗ c
= 2 (2a + 3b) + 3c
= 4a + 6b + 3c
a ∗ (b ∗ c) = a ∗ (2b + 3c)
= 2a + 3 (2b + 3c)
= 2a + 6b + 9c
As (a ∗ b) ∗ c ≠ a ∗ (b ∗ c)
∗ is not associative.

Existance of identity:
Let e is the identity
∴ e ∗ a = a
⇒ 2e + 3a = a
⇒ e = -2a / 2 = -a
which depends on a.
∴ Identity element does not exist.

(iii) A = (0, 1, 2, 3, 4, 5, 6}
Commutative:
a ∗ b = a + b (mod 7)
= The remainder obtained when a + b is divided by 7.
b ∗ a = b + a (mod 7) = a + b (mod 7)
∴ ∗ is commutative.

Associative:
(a ∗ b) ∗ c = {a + b (mod 7)} ∗ c
= a + b + c (mod 7)
= The remainder obtained if a + b + c is divided by 7.
a ∗ (b ∗ c) = a ∗ {b + c (mod 7)}
= a + b + c (mod 7)
= The remainder obtained if a + b + c is divided by 7.
∴ (a ∗ b) ∗ c = a + (b ∗ c)
∴ ∗ is associative.

Existance of identity:
Let e is the identity
⇒ e ∗ a = a ∗ e = a
⇒ e + a mod 7 = a
⇒ e = 0
∴ 0 is the identity.

Existance of inverse:
Let a^-1 = the inverse of a
⇒ a ∗ a^-1 = a^-1 ∗ a = e = 0
⇒ a + a^-1 (mod 7) = 0
⇒ a + a^-1 is divisible by 7.
1^-1 = 6, 6^-1 = 1
2^-1 = 5, 5^-1 = 2
3^-1 = 4, 4^-1 = 3

(iv) a ∗ b = min {a, b} on N.
Commutative:
a ∗ b = min {a, b}
b ∗ a – min {b, a} = a ∗ b
∴ ∗ is commutative.
Associative:
(a ∗ b) ∗ c = min {a, b} ∗ c
= min {a, b, c}
a ∗ (b ∗ c)= a ∗ min {b, c}
= min {a, b, c}
⇒ a ∗ (b ∗ c) = (a ∗ b) ∗ c
∴ ∗ is associative.

Existance of Identity:
Let e is the identity
∴ For all a ∈ N
e ∗ a = a ∗ e = a
⇒ min {e, a} = a
No such element exists in N.
∴ ∗ has no identity element on N.

(v) a ∗ b = GCD {a, b} on N.
b ∗ a = GCD {b, a} = GCD {a, b} = a ∗ b
∴ ∗ is commutative.
Associative:
(a ∗ b) ∗ c = GCD {a, b} ∗ c
= GCD {a, b, c}
a ∗ (b ∗ c) = a ∗ GCD {b, c}
= GCD {a, b, c}
⇒ (a ∗ b) ∗ c = a ∗ (b ∗ c)
⇒ ∗ is associative.

Existance of Identity:
Let e is the identity
∴ a ∗ e = e ∗ a = a
⇒ GCD {e, a} = a
No such element exists in N
⇒ ∗ has no indentity element.

(vi) a ∗ b = LCM {a, b} on N
Commutative:
a ∗ b = LCM {a, b}
= LCM {b, a}
= b ∗ a
∴ ∗ is commutative.

Associative
(a ∗ b) ∗ c = LCM {a, b} ∗ c
= LCM {a, b, c}
a ∗ (b ∗ c) =» a ∗ LCM {b, c}
= LCM {a, b, c}
⇒ (a ∗ b) ∗ c = a ∗ (b ∗ c)
∴ ∗ is associative.

Existance of Identity:
Let e is the identity
∴ e ∗ a = a ∗ e = a
⇒ LCM {e, a} = a
⇒ e – 1
∴ 1 is the identity element.

Existance of inverse:
Let a^-1 is the inverse of a
⇒ a * a^-1 = e = 1
⇒ LCM [a, a^-1} = 1
a = a^-1 = 1
Only 1 is invertible with 1^-1 = 1.

(ix) a ∗ b = a × (mod 5) on {0, 1, 2, 3, 4}

Commutative:
a ∗ b = a x b (mod 5)
= Remainder on dividing a x b by 5
= Remainder on dividing b x a by 5
= b x a (mod 5)
= b x a
∴ ∗ is commutative.

Associative:
(a ∗ b) ∗ c=a x b (mod 5) ∗ c
= a x b x c (mod 5)
a and a ∗ {b ∗ c} = a ∗ {b x c (mod 5)}
= a x b x c (mod 5)
∴ (a ∗ b) ∗ c -=a ∗ (b ∗ c)
⇒ ∗ is associative.

Existance of identity:
Let e is the identity
∴ For all a ∈ {0, 1, 2, 3, 4}
a ∗ a = e ∗ a = a
a × e (mod 5) = a
⇒ e = 1
∴ 1 is the identity element.

Existance of inverse:
Let a^-1 is the inverse of a
∴ a ∗ a^-1= a^-1 ∗ a = e = 1
⇒ a x a^-1 (mod 5) = 1
⇒ 1^-1 = 1
2^-1 = 3, 3^-1 = 2, 4^-1 = 4
0 has no inverse.

(x) a ∗ b = a² + b² on N.
Commutative:
a ∗ b = a² + b²
b ∗ a = b² + a² = a² + b² = a ∗ b
∴ ∗ is commutative.

Associative:
(a ∗ b) ∗ c = (a² + b²) ∗ c
= (a² + b²)² + c²
a ∗ (b ∗ c) = a ∗ (b² + c²)
= a² + (a² + b²)²
(a ∗ b) ∗ c ≠ a ∗ (b ∗ c)
∴ ∗ is not associative.

Existance of Identity:
Let e is the identity
a ∗ e = e ∗ a = a
⇒ a² + e² = a
⇒ e = \( \sqrt{a-a^2}\) which depends on a
∴ Identity does not exist.

(xi) a ∗ b = a + b – ab on R – {1}
Commutative:
a ∗ b = a + b – ab
b ∗ a = b + a – ba
a ∗ b = b ∗ a
∴ ∗ is commutative.

Associative:
a ∗ (b ∗ c) = a ∗ (b + c – bc)
= a + (b + c – bc) – a (b + c – bc)
= a + b + c – bc – ab – ac + abc
(a ∗ b) ∗ c = (a + b – ab) ∗ c
= a + b – ab + c – (a + b – ab) c
= a + b + c – ab – bc – ca + abc
∴ (a ∗ b) ∗ c = a ∗ (b ∗ c)
⇒ ∗ is associative.

Existance of Identity:
Let e is the identity
∴ e ∗ a = a ∗ e = a
⇒ a + e – ae = a
⇒ e (1 – a) = 0
⇒ e = 0 (∵ a ≠ 1)
∴ 0 is the identity.

Existance of inverse:
Let a^-1 is the inverse of a
⇒ a ∗ a^-1 = a^-1 ∗ a = e
⇒ a + a^-1 – aa^-1 = 0
⇒ a^-1 (1 – a) = – a
⇒ a^-1 = \(\frac{a}{a-1}\) for a ∈ R – {1}

Question 4.
Construct the composition table/multiplication table for the binary operation ∗ defined on {0, 1, 2, 3, 4} by a ∗ b = a × b {mod 5). Find the identity element if any. Also find the inverse elements of 2 and 4.
[This operation is called multiplication moduls 5 and denoted by x⁵. In general, on a finite subset of N, x_m denotes the operation of multiplication modulo m where m is a fixed positive integer].
Solution:
A = {0. 1, 2, 3, 4}
a ∗ b = a × b mod 5

∗	0	1	2	3	4
0	0	0	0	0	0
1	0	1	2	3	4
2	0	2	4	1	3
3	0	3	1	4	2
4	0	4	3	2	1

As 3rd row is identical to the first row we have 1 is the identity clearly 2^-1 = 3 and 4^-1 = 4.

Odisha State Board Elements of Mathematics Class 12 CHSE Odisha Solutions Chapter 7 Continuity and Differentiability Ex 7(e) Textbook Exercise Questions and Answers.

CHSE Odisha Class 12 Math Solutions Chapter 7 Continuity and Differentiability Exercise 7(e)

Differentiate the following functions by proper substitution.
Question 1.
sin^-1 2x\( \sqrt{1-x^2} \)
Solution:
y = sin^-1 2x\( \sqrt{1-x^2} \)   [Put x = sin θ
= sin^-1 (2 sin θ . cos θ)
= sin^-1 sin 2θ = 2θ = 2 sin^-1 x.
\(\frac{d y}{d x}\) = \(\frac{2}{\sqrt{1-x^2}}\)

Question 2.
tan^-1 \(\frac{2 x}{1-x^2}\)
Solution:
y = tan^-1 \(\frac{2 x}{1-x^2}\)
= tan^-1 \(\frac{2 \tan \theta}{1-\tan ^2 \theta}\) = tan^-1 (tan 2θ)
= 2θ = 2 tan^-1 x
∴ \(\frac{d y}{d x}\) = \(\frac{2 x}{1-x^2}\)

Question 3.
tan^-1 \(\sqrt{\frac{1-t}{1+t}}\)
Solution:

Question 4.
\(\left[\left(\frac{1+t^2}{1-t^2}\right)^2-1\right]^{\frac{1}{2}}\)
Solution:

Question 5.
tan^-1 \(\left(\frac{\sqrt{x}+\sqrt{a}}{1-\sqrt{x a}}\right)\)
Solution:

Question 6.
sin^-1 (\(\frac{2 x}{1+x^2}\))
Solution:
y = sin^-1 \(\frac{2 x}{1+x^2}\)  [Put x = tan θ
= sin^-1 \(\frac{2 \tan \theta}{1+\tan ^2 \theta}\) = sin^-1 sin θ
= 2θ = 2 tan^-1 x
∴ \(\frac{d y}{d x}\) = \(\frac{2 x}{1+x^2}\)

Question 7.
sec^-1 \(\left(\frac{\sqrt{a^2+x^2}}{a}\right)\)
Solution:

Question 8.
sin^-1 \(\left(\frac{2 \sqrt{t^2-1}}{t^2}\right)\)
Solution:

Question 9.
cos^-1 \(\left(\frac{1-t^2}{1+t^2}\right)\)
Solution:
y = cos^-1 \(\left(\frac{1-t^2}{1+t^2}\right)\) [Put t = tan θ
= cos^-1 \(\frac{1-\tan ^2 \theta}{1+\tan ^2 \theta}\)
= cos^-1 cos 2θ = 2 tan^-1 t
∴ \(\frac{d y}{d x}\) = \(\frac{2}{1+t^2}\)

Question 10.
cos^-1 (2t² – 1)
Solution:
y = cos^-1 (2t² – 1) [Put t = tan θ
= cos^-1 (2 cos² θ – 1)
= cos^-1 cos 2θ = 2θ = 2 cos^-1 t
∴ \(\frac{d y}{d x}\) = – \(\frac{2}{\sqrt{1-t^2}}\)

Odisha State Board Elements of Mathematics Class 12 CHSE Odisha Solutions Chapter 7 Continuity and Differentiability Ex 7(f) Textbook Exercise Questions and Answers.

CHSE Odisha Class 12 Math Solutions Chapter 7 Continuity and Differentiability Exercise 7(f)

Find derivatives of the following functions.
Question 1.
x^x
Solution:
Let y = x^x
Then In y = x . In x
⇒ \(\frac{d}{d x}\)(In y) = \(\frac{d}{d x}\)(x . In x)
⇒ \(\frac{1}{y}\)\(\frac{d y}{d x}\) = In x + x . \(\frac{1}{x}\) = In x + 1 = 1 + In x
⇒ \(\frac{d y}{d x}\) = y (1 + In x) = x^x (1 + In x) = x^x In (ex)

Question 2.
\(\left(1+\frac{1}{x}\right)^x\)
Solution:

Question 3.
x^{sin x}
Solution:
y = x^{sin x}
⇒ In y = sin x . In x
⇒ \(\frac{1}{y}\)\(\frac{d y}{d x}\) = cos x In x + sin x . \(\frac{1}{x}\)
⇒ \(\frac{d y}{d x}\) = x^{sin x} (cos x . In x + \(\frac{\sin x}{x}\))

Question 4.
(log x)^{tan x}
Solution:
y = (log x)^{tan x}
⇒ log y = tan x . log (log x)
⇒ \(\frac{1}{y}\)\(\frac{d y}{d x}\) = sec² x log (log x) + tan x . \(\frac{1}{\log x}\) . \(\frac{1}{x}\)
⇒ \(\frac{d y}{d x}\) = (log x)^{tan x} {sec² x . log log x + \(\frac{\tan x}{x \log x}\)}

Question 5.
\(2^{\left(2^x\right)}\)
Solution:
y = \(2^{\left(2^x\right)}\)
⇒ In y = 2^x . In 2
⇒ \(\frac{1}{y}\)\(\frac{d y}{d x}\) = 2^x . In 2 . In 2
⇒ \(\frac{d y}{d x}\) = \(2^{\left(2^x\right)}\) . 2^x . (In 2)²

Question 6.
\((1+\sqrt{x})^{x^2}\)
Solution:

Question 7.
\(\left(\sin ^{-1} x\right)^{\sqrt{1-x^2}}\)
Solution:

Question 8.
\((\tan x)^{\log x^3}\)
Solution:

Question 9.
x^1/x + (sin x)^x
Solution:

Question 10.
(cos x)^x + x^{cos x}
Solution:

Question 11.
(x² + 1)^2/3 (3x + 1)^1/4 √x
Solution:

Question 12.
\(\frac{(x+1)(x+2)^2(x+3)^3}{(x-1)(x-2)^2(x-3)^3}\)
Solution:

Question 13.
(sin x)^x \(\sqrt{\sin x}\left(1+x^2\right)^{\frac{1}{2}+x}\)
Solution:

Question 14.
(sec x + tan x)^{cot x}
Solution:
y = (sec x + tan x)^{cot x}
⇒ In y = cot x . In (sec x + tan x)
⇒ \(\frac{1}{y}\)\(\frac{d y}{d x}\) = -cosec² x . In (sec x + tan x) + cot x . \(\frac{1}{\sec x+\tan x}\) × (sec x . tan x + sec² x)
= -cosec² x . In (sec x + tan x) + cot x . sec x
∴ \(\frac{d y}{d x}\) = y {-cosec² x . In (sec x + tan x) + cosec x}
= (sec x + tan x)^{cot x} {cosec x – cosec² x . In (sec x + tan x)}

Question 15.
(2^√x)^1+√x
Solution:

CHSE Odisha 11th Class Sociology Book Solutions (+ 2 1st Year)

CHSE Odisha Class 11 Sociology Book Solutions in English Medium

Unit 1 Sociology & Its Relationship

• Sociology & Its Relationship Objective Questions
• Sociology & Its Relationship Short Answer Questions
• Sociology & Its Relationship Long Answer Questions

Unit 2 Basic Concepts

• Basic Concepts Objective Questions
• Basic Concepts Short Answer Questions
• Basic Concepts Long Answer Questions

Unit 3 Social Institutions

• Social Institutions Objective Questions
• Social Institutions Short Answer Questions
• Social Institutions Long Answer Questions

Unit 4 Process, Stratification and Change

• Process, Stratification and Change Objective Questions
• Process, Stratification and Change Short Answer Questions
• Process, Stratification and Change Long Answer Questions

Unit 5 Sociology, Methods and Techniques

• Sociology, Methods and Techniques Objective Questions
• Sociology, Methods and Techniques Short Answer Questions
• Sociology, Methods and Techniques Long Answer Questions

CHSE Odisha Class 11 Sociology Book Solutions in Odia Medium

Unit 1 ସମାଜ ବିଜ୍ଞାନ ଏବଂ ଏହାର ସମ୍ପର୍କ

• ସମାଜ ବିଜ୍ଞାନ ଏବଂ ଏହାର ସମ୍ପର୍କ Objective Questions
• ସମାଜ ବିଜ୍ଞାନ ଏବଂ ଏହାର ସମ୍ପର୍କ Short Answer Questions
• ସମାଜ ବିଜ୍ଞାନ ଏବଂ ଏହାର ସମ୍ପର୍କ Long Answer Questions

Unit 2 ମୌଳିକ ଧାରଣା

• ମୌଳିକ ସମ୍ପ୍ରତ୍ୟୟ Objective Questions
• ମୌଳିକ ସମ୍ପ୍ରତ୍ୟୟ Short Answer Questions
• ମୌଳିକ ସମ୍ପ୍ରତ୍ୟୟ Long Answer Questions

Unit 3 ସାମାଜିକ ଅନୁଷ୍ଠାନ

• ସାମାଜିକ ଅନୁଷ୍ଠାନ Objective Questions
• ସାମାଜିକ ଅନୁଷ୍ଠାନ Short Answer Questions
• ସାମାଜିକ ଅନୁଷ୍ଠାନ Long Answer Questions

Unit 4 ସାମାଜିକ ପ୍ରକ୍ରିୟା, ସ୍ତରୀକରଣ ଏବଂ ପରିବର୍ତ୍ତନ

• ପ୍ରକ୍ରିୟା, ସ୍ତରୀକରଣ ଏବଂ ପରିବର୍ତ୍ତନ Objective Questions
• ପ୍ରକ୍ରିୟା, ସ୍ତରୀକରଣ ଏବଂ ପରିବର୍ତ୍ତନ Short Answer Questions
• ପ୍ରକ୍ରିୟା, ସ୍ତରୀକରଣ ଏବଂ ପରିବର୍ତ୍ତନ Long Answer Questions

Unit 5 ସମାଜଶାସ୍ତ୍ର, ପଦ୍ଧତି ଏବଂ କୌଶଳ

• ସମାଜଶାସ୍ତ୍ର, ପଦ୍ଧତି ଏବଂ ପ୍ରୟୋଗ କୌଶଳ Objective Questions
• ସମାଜଶାସ୍ତ୍ର, ପଦ୍ଧତି ଏବଂ ପ୍ରୟୋଗ କୌଶଳ Short Answer Questions
• ସମାଜଶାସ୍ତ୍ର, ପଦ୍ଧତି ଏବଂ ପ୍ରୟୋଗ କୌଶଳ Long Answer Questions

CHSE Odisha Class 11 Sociology Syllabus (+2 1st Year)

SOCIOLOGY
Paper-I
Introducing Sociology

Unit I Sociology & Its Relationship
Emergence, Meaning, Nature and Scope, Relationship of Sociology with Social Sciences – History, Economics, Anthropology, Psychology, Political Science.

Unit II Basic Concepts
Society – Meaning and Characteristics Individual and Society
Community – Meaning and Characteristics
Association – Meaning & Characteristics,
Social Group – Meaning and Characteristics, Types – Primary, Secondary, In-Group, Out-Group
Culture – Meaning, Characteristics, Types – Material, Non-Material, Importance

Unit III Social Institutions
Family – Meaning, Characteristics, Types, Functions
Kinship – Meaning, Characteristics, Types
Education – Meaning, Importance
Economic – Property, Division of Labour

Unit IV Process, Stratification and Change
Social Processes: Associative – Co-operation, Accommodation Dissociative- Competition, Conflict
Social Stratification – Meaning, Characteristics Bases – Caste, Class, Gender
Social Change – Meaning, Characteristics, Factors – Technological Cultural

Unit V Sociology, Methods and Techniques
Auguste Comte: Law of Three Stages, Emile Durkheim: Suicide, G.S.Ghurey: Caste, M.N. Srinivas: Sanskritisation, Methods: Observation – Meaning and Types, Tools and Techniques: Questionnaire and Schedule – Meaning, Merits and Demerits.

BOOK PRESCRIBED:
1. Bureau’s Higher Secondary (+2) Sociology, Part-I Published by Odisha State Bureau of Textbook Preparation & Production, Bhubaneswar.
2. Sociology, Part-I, NCERT.

CHSE Odisha 12th Class Education Book Solutions (+ 2 2nd Year)

CHSE Odisha Class 12 Education Book Solutions in English Medium

Unit I Contribution of Educators

• Chapter 1 Mahatma Gandhi
• Chapter 2 Pandit Gopabandhu Das
• Chapter 3 Sri Aurobindo
• Chapter 4 Jean Jacques Rousseau
• Chapter 5 John Dewey

Unit II Learning and Motivation

• Chapter 6 Meaning, Nature, and Factors of Learning
• Chapter 7 Theories of Learning: Trial and Error Theory, and Laws of Learning
• Chapter 8 Classical Conditioning Theory
• Chapter 9 Insightful and Observational Learning
• Chapter 10 Learning as Construction of Knowledge
• Chapter 11 Motivation in Learning – Meaning, Types & Techniques of Motivation

Unit III Current Issues in Education

• Chapter 12 Universalization of Elementary Education (UEE) and RTE
• Chapter 13 Education for National Integration and International Understanding
• Chapter 14 Environmental Education
• Chapter 15 Value Education and Human Rights Education
• Chapter 16 Information and Communication Technology (ICT) in Education
• Chapter 17 Life Skills Education

Unit IV Educational Statistics

• Chapter 18 Statistics: Meaning, Nature, and Uses
• Chapter 19 Frequency Distribution
• Chapter 20 Graphical Representation of Data and Measures of Central Tendency

Unit 1 Contribution of Educators

• Contribution of Educators Objective Questions
• Contribution of Educators Short Answer Questions
• Contribution of Educators Long Answer Questions

Unit 2 Learning and Motivation

• Learning and Motivation Objective Questions
• Learning and Motivation Short Answer Questions
• Learning and Motivation Long Answer Questions

Unit 3 Current Issues in Education

• Current Issues in Education Objective Questions
• Current Issues in Education Short Answer Questions
• Current Issues in Education Long Answer Questions

Unit 4 Educational Statistics

• Educational Statistics Questions and Answers

CHSE Odisha Class 12 Education Book Solutions in Odia Medium

Unit 1 ଶିକ୍ଷାବିତମାନଙ୍କର ଦାନ

• Chapter 1 ମହାତ୍ମା ଗାନ୍ଧି
• Chapter 2 ପଣ୍ଡିତ ଗୋପବନ୍ଧୁ ଦାସ
• Chapter 3 ଶ୍ରୀ ଅରବିନ୍ଦ
• Chapter 4 ଜିନ୍ ଜାକୁଏସ୍ ଋଷୋ
• Chapter 5 ଜନ୍ ନ୍ୟୁଇ

Unit 2 ଶିକ୍ଷଣ ଏବଂ ଅଭିପ୍ରେରଣା

• Chapter 6 ଶିକ୍ଷଣ ପ୍ରକ୍ରିୟା ଓ ଶିକ୍ଷଣ ତତ୍ତ୍ବ
• Chapter 7 ପର୍ଯ୍ୟବେକ୍ଷଣାତ୍ମକ ଶିକ୍ଷଣ
• Chapter 8 ଶିକ୍ଷଣରେ ଅଭିପ୍ରେରଣା

Unit 3 ବିଦ୍ୟାଳୟ ଶିକ୍ଷା ସମସ୍ୟା

• Chapter 9 ପ୍ରାଥମିକ ଶିକ୍ଷାର ସାର୍ବଜନୀନୀକରଣ ଓ ଶିକ୍ଷାଧିକାର
• Chapter 10 ଜାତୀୟ ସଂହତି ଓ ଆନ୍ତର୍ଜାତିକ ବୁଝାମଣା ପାଇଁ ଶିକ୍ଷା
• Chapter 11 ପରିବେଶ ଶିକ୍ଷା
• Chapter 12 ମୂଲ୍ୟବୋଧ ଶିକ୍ଷା ଓ ମାନବାଧିକାର ଶିକ୍ଷା
• Chapter 13 ଶିକ୍ଷାରେ ସୂଚନା ଓ ସଞ୍ଚାର ପ୍ରଯୁକ୍ତି ବିଦ୍ୟା
• Chapter 14 ଜୀବନ ନୈପୁଣ୍ୟ (ଦକ୍ଷତା) ଶିକ୍ଷା

Unit 4 ଶୈକ୍ଷିକ ପରିସଂଖ୍ୟାନ

• Chapter 15 ଶୈକ୍ଷିକ ପରିସଂଖ୍ୟାନ (ପରିସଂଖ୍ୟାନ, ପୌନଃପୁନଃ ବିତରଣ, ତଥ୍ୟର ରେଖଚିତ୍ର ବା ଗ୍ରାଫୀୟ ପ୍ରଦର୍ଶନ, କେନ୍ଦ୍ରୀୟ ପ୍ରବଣତା ମାପ)

CHSE Odisha Class 12 Education Syllabus (+2 2nd Year)

EDUCATION ELECTIVE (Second Year)
Theory – 70 marks & Practical – 30 marks.
Theory Paper – II
FOUNDATIONS OF EDUCATION – II

Unit I Fundamentals of Education (20 periods)
Contribution of Educators: Mahatma Gandhi, Pandit Gopabandhu Das, Sri Aurobindo, Jena Jacques Rousseau, John Dewey.

Unit-II Learning and Motivation (20 Periods)
Meaning, Nature and Factors of Learning, Theories of Learning: Trial and Error Theory and Laws of Learning, Classical Conditioning Theory, Insightful Learning, Learning and Construction of knowledge, Motivation in Learning: Meaning, Types, and Techniques of motivation.

Unit-III Current Issues in Education (20 Periods)
Universalisation of Elementary Education (UEE) and RTE, Education for National Integration and International Understanding, Environmental Education, Value Education, Human Rights Education, Information and Communication Technology (ICT) in education, and Life-skills Education.

Unit-IV Educational Statistics (20 Periods)
Statistics: Meaning, Nature and uses, Frequency Distribution, Graphical Representation of Data: Histogram, Polygon, and Pie-Chart, Measures of Central Tendency: Mean, Median, and mode – meaning, calculation, and uses.

Practical (60 Periods)
(To be examined by both external and Internal Examiners)
A. Practice Teaching Five Lessons in the Classroom in the selected subject (30 Periods)
B. Preparation of Five Improvised Teaching Aids relating to the Five lesser planes along with their improvised teaching aids records (30 Periods)
For the Final Practical Examination, students shall deliver one lesson in their method subject.
Practice teaching records and improvised teaching aids records will be submitted during the final examination.

BOOKS RECOMMENDED:
1. Bureau Uchcha Madhyamik Siksha 2 (in Odia)
2. Bureau’s Higher Secondary Education II. Published by Odisha State Bureau of Textbook Preparation & Production, Bhubaneswar.

CHSE Odisha Class 12 Text Book Solutions

CHSE Odisha 12th Class Logic Book Solutions (+ 2 2nd Year)

CHSE Odisha 12th Class Logic Book Solutions in English Medium

• Chapter 1 The Theory of Inference
• Chapter 2 Syllogism
• Chapter 3 Mixed Syllogism
• Chapter 4 Deductive and Inductive Fallacies
• Chapter 5 Symbolic Logic
• Chapter 6 Experimental Methods of Mill
• Chapter 7 Scientific Explanation
• Chapter 8 Naya Theory of Knowledge
• Chapter 9 Doctrine of Karma
• Chapter 10 Gandhi: Truth and Non-Violence

CHSE Odisha 12th Class Logic Book Solutions in Odia Medium

Unit 1 ଅନୁମାନ – ଅନୁମାନର ପ୍ରକାରଭେଦ – ଅବ୍ୟବହିତ ଓ ବ୍ୟବହିତ

• ଅନୁମାନ – ଅନୁମାନର ପ୍ରକାରଭେଦ – ଅବ୍ୟବହିତ ଓ ବ୍ୟବହିତ Objective Questions
• ଅନୁମାନ – ଅନୁମାନର ପ୍ରକାରଭେଦ – ଅବ୍ୟବହିତ ଓ ବ୍ୟବହିତ Short & Long Answer Questions

Unit 2 ବ୍ୟବହିତ ଅନୁମାନ ଓ ମିଶ୍ର ତ୍ରିପଦୀଯୁକ୍ତି

• ବ୍ୟବହିତ ଅନୁମାନ ଓ ମିଶ୍ର ତ୍ରିପଦୀଯୁକ୍ତି Objective Questions
• ବ୍ୟବହିତ ଅନୁମାନ ଓ ମିଶ୍ର ତ୍ରିପଦୀଯୁକ୍ତି Short Answer Questions
• ବ୍ୟବହିତ ଅନୁମାନ ଓ ମିଶ୍ର ତ୍ରିପଦୀଯୁକ୍ତି Long Answer Questions

Unit 3 ତର୍କଦୋଷ ଓ ପ୍ରତୀକାତ୍ମକ ତର୍କଶାସ୍ତ୍ର

• ତର୍କଦୋଷ ଓ ପ୍ରତୀକାତ୍ମକ ତର୍କଶାସ୍ତ୍ର Objective Questions
• ତର୍କଦୋଷ ଓ ପ୍ରତୀକାତ୍ମକ ତର୍କଶାସ୍ତ୍ର Short Answer Questions
• ତର୍କଦୋଷ ଓ ପ୍ରତୀକାତ୍ମକ ତର୍କଶାସ୍ତ୍ର Long Answer Questions

Unit 4 ମିଲ୍‌ଙ୍କ ପରୀକ୍ଷଣ ପଦ୍ଧତି, ବୈଜ୍ଞାନିକ ବ୍ୟାଖ୍ୟାନ

• ମିଲ୍‌ଙ୍କ ପରୀକ୍ଷଣ ପଦ୍ଧତି, ବୈଜ୍ଞାନିକ ବ୍ୟାଖ୍ୟାନ Objective Questions
• ମିଲ୍‌ଙ୍କ ପରୀକ୍ଷଣ ପଦ୍ଧତି, ବୈଜ୍ଞାନିକ ବ୍ୟାଖ୍ୟାନ Short & Long Answer Questions

Unit 5 ନ୍ୟାୟଙ୍କ ଜ୍ଞାନ ସିଦ୍ଧାନ୍ତ ଓ କର୍ମବାଦ

• ନ୍ୟାୟଙ୍କ ଜ୍ଞାନ ସିଦ୍ଧାନ୍ତ ଓ କର୍ମବାଦ Objective Questions
• ନ୍ୟାୟଙ୍କ ଜ୍ଞାନ ସିଦ୍ଧାନ୍ତ ଓ କର୍ମବାଦ Short & Long Answer Questions

CHSE Odisha Class 12 Logic Syllabus (+2 2nd Year) in English

Unit 1
The Theory of Inference: Classification of Inference, Conversion, Obversion, Categorical Syllogism: Structure, Figure, Moods. Rules of syllogism, Determination of valid Moods.

Unit 2
Special rules of Figures, Aristotle’s Dictum, Direct and Indirect Reduction.
Mixed Syllogism: Different forms – Hypothetical categorical, Alternative Categorical, Disjunctive Categorical, Dilemma: Forms, Refutation, Rebuttal of Dilemma.

Unit 3
Fallacy: Deductive Fallacy, Semi-logical Fallacies, Inductive Fallacies: Fallacy of Illicit Generalisation, False Analogy, Ignoratio Elenchi. Propositional Logic: Symbolic Logic and its Characteristics, Propositional Variables, Logical Constants, Propositional Connectives, Truth Functions, Construction of Truth Tables, Testing Validity by direct Truth Table Method.

Unit 4
Methods of Experimental Enquiry: Mill’s Five Experimental Methods.
Scientific Explanation: Nature of Scientific Explanation.

Unit 5
Nyaya Theory of Knowledge :Perception and Inference: Vyapti and its ascertainments.
Doctrine of karma: Niskama Karma of Bhagavad Gita, Gandian Concept of Non Violence.

CHSE Odisha Class 12 Logic Book Syllabus (+2 2nd Year)

Unit 1 ଅନୁମାନ – ଅନୁମାନର ପ୍ରକାରଭେଦ – ଅବ୍ୟବହିତ ଓ ବ୍ୟବହିତ
ଅନୁମାନ – ଅନୁମାନର ପ୍ରକାରଭେଦ – ଅବ୍ୟବହିତ ଓ ବ୍ୟବହିତ ଅନୁମାନ – ଅବ୍ୟବହିତ ଅନୁମାନ – ସମବର୍ତ୍ତନ, ବ୍ୟାବର୍ତ୍ତନ; ବ୍ୟବହିତ ଅନୁମାନ– ତ୍ରିପଦୀଯୁକ୍ତି, ଏହାର ଅବୟବାବଳୀ, ନ୍ୟାୟ-ସଂସ୍ଥାନ, ନ୍ୟାୟରୂପ, ତ୍ରିପଦୀଯୁକ୍ତିର ସାଧାରଣ ନିୟମାବଳୀ, ନ୍ୟାୟରୂପ-ମାନଙ୍କର ନିର୍ଦ୍ଧାରଣ ପ୍ରକ୍ରିୟା ।

Unit 2 ବ୍ୟବହିତ ଅନୁମାନ ଓ ମିଶ୍ର ତ୍ରିପଦୀଯୁକ୍ତି
ପ୍ରତ୍ୟେକ ସଂସ୍ଥାନର ସ୍ବତନ୍ତ୍ର ନିୟମାବଳୀ, ଆରିଷ୍ଟୋଟଲଙ୍କ ମୌଳିକ ସୂତ୍ର, ସାକ୍ଷାତ୍ ଓ ଅସାକ୍ଷାତ୍ ରୂପାନ୍ତରୀକରଣ ।
ମିଶ୍ର ତ୍ରିପଦୀଯୁକ୍ତି – ବିଭିନ୍ନ ପ୍ରକାର : ପ୍ରାକଳ୍ପିକ ନିରପେକ୍ଷ, ବିଯୋଜକ – ନିରପେକ୍ଷ, ବୈକଳ୍ପିକ — ନିରପେକ୍ଷ, ଦ୍ବିଶୃଙ୍ଗକ ନ୍ୟାୟ, ଦ୍ବିଶୃଙ୍ଗକ ଯୁକ୍ତିର ପ୍ରକାରଭେଦ, ଦ୍ବି ଶୃଙ୍ଗକ ଯୁକ୍ତିର ଆକାରଗତ ବୈଧତା, ବସ୍ତୁଗତ ସତ୍ୟାସତ୍ୟ ବିଚାର, ଦ୍ବିଶୃଙ୍ଗକ ଯୁକ୍ତିର ପ୍ରତିରୋଧ ।

Unit 3 ତର୍କଦୋଷ ଓ ପ୍ରତୀକାତ୍ମକ ତର୍କଶାସ୍ତ୍ର
ତର୍କଦୋଷ – ଅବରୋହୀ ତର୍କଦୋଷ, ଅବରୋହୀ – ଅନୁମାନ ସମ୍ପର୍କୀୟ ତର୍କଦୋଷ, ଆପାତଃ ତର୍କଦୋଷ । ଆରୋହୀ ତର୍କଦୋଷ – ଅବୈଧ ସାମାନ୍ୟକରଣ ତର୍କଦୋଷ, ଦୁଷ୍ଟ ଉପମା କିମ୍ବା ଦୁର୍ବଳ ଉପମା ତର୍କଦୋଷ, ବଳକା ତର୍କଦୋଷ, ଅବାନ୍ତର ପ୍ରସଙ୍ଗ ଦୋଷ ।
ପ୍ରତୀକାମୂକ ତର୍କଶାସ୍ତ୍ର ଏବଂ ଏହାର ବୈଶିଷ୍ଟ୍ୟ- ତର୍କବାକ୍ୟମୂଳକ ଚଳ- ତର୍କଶାସ୍ତ୍ରୀୟ ସ୍ଥିରାଙ୍କ- ସତ୍ୟଫଳନ – ସତ୍ୟସାରଣୀ- ସତ୍ୟ ସାରଣୀ ପଦ୍ଧତି । ସାକ୍ଷାତ୍ ସତ୍ୟସାରଣୀ ପଦ୍ଧତି ସାହାଯ୍ୟରେ ବୈଧତା ପରୀକ୍ଷା ।
ପୁନରୁକ୍ତିକ ତର୍କବାକ୍ୟମୂଳକ ସୂତ୍ର- ବିରୁଦ୍ଧ ତର୍କବାକ୍ୟମୂଳକ ସୂତ୍ର- ଆପାତିତ ତର୍କବାକ୍ୟମୂଳକ ସୂତ୍ର । ବିଭିନ୍ନ ଉଦାହରଣମାନଙ୍କର ସାକ୍ଷାତ୍ ସତ୍ୟ ସାରଣୀ ପଦ୍ଧତି ସାହାଯ୍ୟରେ ବୈଧତା ପରୀକ୍ଷା ।

Unit 4 ମିଲ୍ଲଙ୍କ ପରୀକ୍ଷଣ ପଦ୍ଧତି, ବୈଜ୍ଞାନିକ ବ୍ୟାଖ୍ୟାନ
ମିଲ୍‌ଙ୍କ ପରୀକ୍ଷଣ ପଦ୍ଧତି—ମିଲ୍‌ଙ୍କ ପାଞ୍ଚଟି ପରୀକ୍ଷଣ ପଦ୍ଧତି— (୧) ଅନ୍ବୟ ପଦ୍ଧତି, (୨) ବ୍ୟତିରେକ ପଦ୍ଧତି, (୩) ସଂଯୁକ୍ତ ପଦ୍ଧତି, (୪) ସହଚାରୀ ପରିବର୍ତ୍ତନ ପଦ୍ଧତି, (୫) ପରିଶେଷ ପଦ୍ଧତି ।
ବୈଜ୍ଞାନିକ ବ୍ୟାଖ୍ୟାନ– ବୈଜ୍ଞାନିକ ବ୍ୟାଖ୍ୟାନର ଲକ୍ଷଣ ।

Unit 5 ନ୍ୟାୟଙ୍କ ଜ୍ଞାନ ସିଦ୍ଧାନ୍ତ ଓ କର୍ମବାଦ
ନ୍ୟାୟଙ୍କ ଜ୍ଞାନ ସିଦ୍ଧାନ୍ତ – ପ୍ରତ୍ୟକ୍ଷ ଓ ଅନୁମାନ, ବ୍ୟାପ୍ତି ଓ ଏହାର ନିର୍ଦ୍ଧାରଣ ପ୍ରକ୍ରିୟା
କର୍ମବାଦ – ଭଗବତ୍ ଗୀତାର ନିଷ୍କାମ କର୍ମ, ଗାନ୍ଧିଜୀଙ୍କ ଅହିଂସାବାଦ

CHSE Odisha Class 12 Text Book Solutions

CHSE Odisha 12th Class Economics Book Solutions (+ 2 2nd Year)

CHSE Odisha Class 12 Economics Book Solutions in Odia Medium

Chapter 1 ଅର୍ଥଶାସ୍ତ୍ରର ସଂଜ୍ଞା, ପରିସର ଓ ବିଷୟବସ୍ତୁ

• ଅର୍ଥଶାସ୍ତ୍ରର ସଂଜ୍ଞା, ପରିସର ଓ ବିଷୟବସ୍ତୁ Objective & Short Answer Questions
• ଅର୍ଥଶାସ୍ତ୍ରର ସଂଜ୍ଞା, ପରିସର ଓ ବିଷୟବସ୍ତୁ Long Answer Questions

Chapter 2 ଅର୍ଥବ୍ୟବସ୍ଥାର ପରିଚୟ ଏବଂ ଅର୍ଥଶାସ୍ତ୍ରର କେନ୍ଦ୍ରୀୟ ସମସ୍ୟାବଳୀ

• ଅର୍ଥବ୍ୟବସ୍ଥାର ପରିଚୟ ଏବଂ ଅର୍ଥଶାସ୍ତ୍ରର କେନ୍ଦ୍ରୀୟ ସମସ୍ୟାବଳୀ Objective & Short Answer Questions
• ଅର୍ଥବ୍ୟବସ୍ଥାର ପରିଚୟ ଏବଂ ଅର୍ଥଶାସ୍ତ୍ରର କେନ୍ଦ୍ରୀୟ ସମସ୍ୟାବଳୀ Long Answer Questions

Chapter 3 ମୌଳିକ ଧାରଣା (ମାନବୀୟ ଅଭାବ, ଉପଯୋଗିତା, ଦ୍ରବ୍ୟ, ମୂଲ୍ୟ, ଦର ଓ ସମ୍ପଦ)

• ମୌଳିକ ଧାରଣା Objective Questions
• ମୌଳିକ ଧାରଣା Short Answer Questions
• ମୌଳିକ ଧାରଣା Long Answer Questions

Chapter 4 ଉପଭୋଗର ନିୟମ

• ଉପଭୋଗର ନିୟମ Objective Questions
• ଉପଭୋଗର ନିୟମ Short & Long Answer Questions

Chapter 5 ଚାହିଦା

• ଚାହିଦା Objective Questions
• ଚାହିଦା Short Answer Questions
• ଚାହିଦା Long Answer Questions

Chapter 6 ଉତ୍ପାଦନ

• ଉତ୍ପାଦନ Objective Questions
• ଉତ୍ପାଦନ Short & Long Answer Questions

Chapter 7 ପରିବ୍ୟୟ

• ପରିବ୍ୟୟ Objective Questions
• ପରିବ୍ୟୟ Short Answer Questions
• ପରିବ୍ୟୟ Long Answer Questions

Chapter 8 ଆୟ

Chapter 9 ଯୋଗାଣ

• ଯୋଗାଣ Objective & Short Answer Questions
• ଯୋଗାଣ Long Answer Questions

Chapter 10 ବଜାର

• ବଜାର Objective Questions
• ବଜାର Short Answer Questions
• ବଜାର Long Answer Questions

Chapter 11 ସମଷ୍ଟି ଅର୍ଥନୀତି

• ସମଷ୍ଟି ଅର୍ଥନୀତି Objective & Short Answer Questions
• ସମଷ୍ଟି ଅର୍ଥନୀତି Long Answer Questions

Chapter 12 ଜାତୀୟ ଆୟ

• ଜାତୀୟ ଆୟ Objective Questions
• ଜାତୀୟ ଆୟ Short Answer Questions
• Long Answer Questions

Chapter 13 କେନ୍‌ସଙ୍କ ଆୟ ନିର୍ଦ୍ଧାରଣ ତତ୍ତ୍ବ

• କେନ୍‌ସଙ୍କ ଆୟ ନିର୍ଦ୍ଧାରଣ ତତ୍ତ୍ବ Objective Questions
• କେନ୍‌ସଙ୍କ ଆୟ ନିର୍ଦ୍ଧାରଣ ତତ୍ତ୍ବ Short Answer Questions
• କେନ୍‌ସଙ୍କ ଆୟ ନିର୍ଦ୍ଧାରଣ ତତ୍ତ୍ବ Long Answer Questions

Chapter 14 ମୁଦ୍ରା

• ମୁଦ୍ରା Objective Questions
• ମୁଦ୍ରା Short & Long Answer Questions

Chapter 15 ବ୍ୟାଙ୍କ

• ବ୍ୟାଙ୍କ Objective Questions
• ବ୍ୟାଙ୍କ Short Answer Questions
• ବ୍ୟାଙ୍କ Long Answer Questions

Chapter 16 ରାଷ୍ଟ୍ରବିତ୍ତ

• ରାଷ୍ଟ୍ରବିତ୍ତ Objective Questions
• ରାଷ୍ଟ୍ରବିତ୍ତ Short Answer Questions
• ରାଷ୍ଟ୍ରବିତ୍ତ Long Answer Questions

Chapter 17 ବଜେଟ୍

CHSE Odisha Class 12 Economics Book Solutions in English Medium

Part A: Introductory Microeconomics

Unit 1 Introduction

• Chapter 1 Definition of Economics and Central Problems of An Economy
• Chapter 2 Basic Economic Concepts (Wants, Utility, Goods, Value, Price and Wealth)

Unit II Consumption and Demand

• Chapter 3 Laws of Consumption
• Chapter 4 Demand and Price Elasticity of Demand

Unit III Production

• Chapter 5 Production

Unit IV Cost, Revenue and Supply

• Chapter 6 Cost and Revenue
• Chapter 7 Supply

Unit V Market

• Chapter 8 Market

Part B: Introductory Macroeconomics

Unit VI Introduction

• Chapter 9 Meaning of Macroeconomics

Unit VII National Income

• Chapter 10 Aggregates Related to National Incorne
• Chapter 11 Theory of Income Determination

Unit VIII Money, Banking and Public Finance

• Chapter 12 Money and Banking
• Chapter 13 Public Finance

CHSE Odisha Class 12 Economics Syllabus (+2 2nd Year)

Second Year CHSE (2025-2026)
Economics Paper-II
(Elementary Micro and Macro Economics)

Part A: Introductory Micro Economics

Unit I Introduction (10 Periods, 10 Marks)

• Definition, scope, and subject matter of economics.
• Meaning of economy and central problems of an economy – scarcity and choice, what, how, and for whom to produce?
• Basic concepts – wants, utility, goods, value, price, and wealth.

Unit II Consumption and Demand (14 Periods, 15 Marks)

• Laws of consumption – marginal and total utility, law of diminishing marginal utility, the law of equimarginal utility, and conditions of consumer’s equilibrium.
• Demand – meaning and determinants, individual and market demand, demand schedule and demand curve, movement along and shifts in the demand curve.
• Price elasticity of demand – concept, determinants, measurement of price elasticity of demand; percentage and geometric methods (linear demand curve), the relation of price elasticity of demand with total expenditure.

Unit III Production (10 Periods, 10 Marks)

• Meaning of production and production function – short run and long run.
• Total, Average, and Marginal Product.
• Law of variable proportions and returns to a factor.

Unit IV Cost, Revenue, and Supply (12 Periods, 15 Marks)

• Cost – money and real cost, implicit and explicit cost, fixed and variable cost, Total, average, and marginal costs in the short ru,n and their relationship (simple analysis).
• Revenue – Total, average, and marginal revenue and their relationship.
• Supply – meaning and law of supply

Unit V Market (8 Periods, 10 Marks)

• Meaning and forms of market, pure and perfect competition, price determination under perfect competition, and effects of shifts in demand and supply.
• Meaning and features of monopoly, monopolistic competition, and oligopoly.

Part B: Introductory Macroeconomics

Unit VI Introduction (4 Periods, 5 Marks)

• Meaning of macroeconomics, Distinction between macro- and microeconomics, the subject matter of macroeconomics

Unit VII National Income (10 Periods, 15 Marks)

• Meaning and aggregates related to national income – GNP, NNP, GDP, and NDP at market price and factor cost.
• National disposable income (Gross and Net), Private Income, Personal income, Personal disposable income, Nominal and real national income.
• Income determination – Aggregate Demand and Supply and their components, simple Keynesian Theory of Income Determination.

Unit VIII Money, Banking, and Public Finance (12 Periods, 20 Marks)

• Meaning and Functions of Money.
• Meaning and Functions of Commercial Banks.
• Functions of the Central Bank.
• Meaning of Public Finance and Difference between public and private finance.
• Budget – Meaning and objectives, a balanced and unbalanced budget, surplus and deficit budget.

CHSE Odisha Class 12 Text Book Solutions

BSE Odisha Class 7 Sanskrit Solutions Book Pdf Download

• Chapter 1 ‘ର’ କାରାନ୍ତପୁଲିଙ୍ଗଃ
• Chapter 2 ‘ଇ’ କାରାନ୍ତସ୍ତୀଲିଙ୍ଗଃ
• Chapter 3 ‘ଈ’ କାରାନ୍ତସ୍ଵୀଲିଙ୍ଗଃ
• Chapter 4 ‘ଇ’ କାରାନ୍ତନପୁଂସକଲିଙ୍ଗଃ
• Chapter 5 ସଂଖ୍ୟା
• Chapter 6 ପୂରଣବାଚକଶବ୍ଦାଃ
• Chapter 7 ସମୟଃ
• Chapter 8 ସର୍ବନାମ ପ୍ରୟୋଗଃ
• Chapter 9 କାରକପ୍ରୟୋଗଃ
• Chapter 10 ପ୍ରଥମାବିଭକ୍ତିପ୍ରୟୋଗଃ
• Chapter 11 ଦ୍ଵିତୀୟାବିଭକ୍ତିପ୍ରୟୋଗଃ
• Chapter 12 ତୃତୀୟା ବିଭକ୍ତିପ୍ରୟୋଗଃ
• Chapter 13 ଚତୁର୍ଥୀବିଭକ୍ତିପ୍ରୟୋଗଃ
• Chapter 14 ପଞ୍ଚମୀବିଭକ୍ତିପ୍ରୟୋଗଃ
• Chapter 15 ଷଷ୍ଠୀବିଭକ୍ତିପ୍ରୟୋଗଃ
• Chapter 16 ସପ୍ତମୀବିଭକ୍ତିପ୍ରୟୋଗଃ
• Chapter 17 ଆତ୍ମ-ନ-ବା ପ୍ରୟୋଗଃ
• Chapter 18 ଲଙ୍ଲକାର ପ୍ରୟୋଗଃ
• Chapter 19 ବିଦ୍ୟାଳୟଃ
• Chapter 20 ସମ୍ଭାଷଣମ୍
• Chapter 21 ଶିଶୁଗୀତମ ଭାରତଭକ୍ତାଃ

BSE Odisha 7th Class Text Book Solutions

Odisha State Board BSE Odisha 6th Class English Solutions Test-2(A) Textbook Exercise Questions and Answers.

BSE Odisha Class 6 English Solutions Test-2(A)

BSE Odisha 6th Class English Test-2(A) Text Book Questions and Answers

□ The figures in the right-hand margin indicate the marks for each question.
1. Write the following names of persons in English.
(Teacher will provide names of six persons in Odia.)

ଡାକ୍ତର ରାଜେନ୍ଦ୍ର ପ୍ରସାଦ
ରଣଜିତ ସିଂହ
ଅରବିନ୍ଦ ଘୋଷ
ବାଘା ଜତିନ
ସମ୍ରାଟ ଅଶୋକ |
ରାଜା ଦଶରଥ

Answer:
Doctor Rajendra Prasad
Ranjit Singh
Aurobindo Ghose
Bagha Jatin
Emperor Ashok
King Dasaratha

2. Write the following names of places in English.
(Teacher will provide names of six places in Odia.)

ପୁଡୁଚେରୀ |
ଶ୍ରୀ ଲଙ୍କା
ବିଜୟ ନାଗର
ମଥୁରା |
ମୁମ୍ବାଇ |
କପିଳାସ

Answer:
Puducherry
Srilanka
Vijaya Nagar
Mathura
Mumbai
Kapilas

3. Your teacher will give a dictation of twelve words. Listen to him/her and write.

Answer:
village
classmate
friend
decided
deaf
Good Morning
fever
Germany
soldier
quarters
country
understand

4. Given below are some words. Your teacher will read aloud seven of them. Tick those s/he reads aloud.
language, young, neither, retire, gunny bag, religious, sight, greedy, weather, straightened, beautiful, special, elephant, bicycle
[Listen to your teacher carefully and tick those words as he reads aloud.]

5. Your teacher will read aloud a paragraph. Listen to him/her and fill in the gaps. (Question with Answer)
Once there lived a poor man in a village. He had a rich classmate. He lived in a town. They did not meet for a long time. In the meantime, the rich friend had problems with his ear and became deaf. His friend in the village could not know this.

6. Match the words which sound alike at the end. (Question with Answer)

Answer:

7. Read The poem and answer the questions incomplete sentences.

There was a dog and there was a cat.
One very thin and the other is fat.
Neither of them was a pet.
But the cat always sat on a mat.
and claimed she was a loving pet.

Question (i)
Who were there in the poem?
Answer:
In the poem, there were a dog and a cat.

Question (ii)
How were they?
Answer:
One was very thin and the other was fat.

Question (iii)
Were they pets?
Answer:
No, neither of them was a pet.

Question (iv)
Who sat on a mat?
Answer:
The cat always sat on a mat.

Question (v)
What did the cat claim?
Answer:
The cat claimed that she was a loving pet.

(vi)
Who was very thin?
Answer:
The dog was very thin.

8. Read the following paragraph and answer the questions in complete sentences.
“There is a special school in Karagudi. It is special because it is not for children. Can you guess for whom it is ? It is for baby elephants. Who teaches them? The elephant trainers teach them. Like our schools, they have a timetable. They learn, play and eat according to this timetable.

Question (i)
What is there in Karagudi?
Answer:
There is a special school in Karagudi.

Question (ii)
Why is this school special?
Answer:
This school is special because it is not for children.

Question (iii)
Who are the students?
Answer:
Baby elephants are the students.

Question (iv)
Who are the teachers?
Answer:
The elephant trainers are the teachers.

Question (v)
What do they have like our schools?
Answer:
Like our schools, they have a timetable.

Question (vi)
How do they follow it?
Answer:
According to this timetable, they learn, play, and eat in the special school.

9. Read the following poem and answer the questions in complete sentences.

It was a very cool night And there
was no crab in sight.
The fox looked for one
But there was none.
“Where did they go ?”
Not even one in sight!
They must be in their holes If
I’m right.”

Question (i)
How was the night?
Answer:
It was a very cool night.

Question (ii)
What was not in sight?
Answer:
There was no crab in sight.

Question (iii)
Who looked for the crab?
Answer:
The fox looked for the crab.

Question (iv)
Did he find one?
Answer:
No, he did not find any crab, because there was none.

Question (v)
Where did they go?
Answer:
They must have been in their holes.

Question (vi)
Who were there in the poem?
Answer:
There were the fox and the crab in the poem.

10. Read the following paragraph and answer the questions in complete sentences.
Mahagiri was a big elephant. He was trained at a special school. He was bought by a merchant. The merchant made a lot of money by putting Mahagiri to work. The elephant was often sent to the forest to carry heavy logs of wood. Sometimes, he carried people from one place to another. Once, he even carried a bridegroom to the bride’s house! At times he was sent to a famous temple in a village nearby to lead the festival procession.

Question (i)
What is this paragraph about?
Answer:
This paragraph is about an elephant.

Question (ii)
Who was Mahagiri?
Answer:
Mahagiri was a big elephant.

Question (iii)
Where was Mahagiri trained?
Answer:
Mahagiri was trained at a special school.

Question (iv)
Who bought it?
Answer:
A merchant bought it.

Question (v)
How did the merchant make a lot of money?
Answer:
The merchant made a lot of money by putting Mahagiri to work.

Question (vi)
Why was the elephant often sent to the forest?
Answer:
The elephant was often sent to the forest to carry heavy logs of wood.

Question (vii)
What did he sometimes carry?
Answer:
Sometimes, he carried people from one place to another.

Question (viii)
What did he once even carry?
Answer:
Once, he even carried a bridegroom to the bride’s house.

Question (ix)
Where was he sent to at times?
Answer:
At times he was sent to a famous temple in a village nearby.

Question (x)
Why was he sent to a famous temple?
Answer:
He was sent to a famous temple to lead the festival procession.