BSE Odisha 9th Class English Solutions Chapter 8 The Noble Nature

Odisha State Board BSE Odisha 9th Class English Solutions Chapter 8 The Noble Nature Textbook Exercise Questions and Answers.

BSE Odisha Class 9 English Solutions Chapter 8 The Noble Nature

BSE Odisha 9th Class English The Noble Nature Text Book Questions and Answers

E. Let’s Understand The Poem: (ଆସ କବିତାଟିକୁ ବୁଝିବା)

Read the poem silently and try to find out the answer to the following.
(ନୀରବରେ କବିତାଟିକୁ ପଢ଼ ଏବଂ ନିମ୍ନଲିଖ ପ୍ରଶ୍ନଗୁଡ଼ିକର ଉତ୍ତର ପାଇବାକୁ ଚେଷ୍ଟା କର ।)
Discuss the answers with your partner. (ତୁମର ସହପାଠୀଙ୍କ ସହ ଉତ୍ତରଗୁଡ଼ିକ ଆଲୋଚନା କର ।)

Question 1.
What is noteworthy in an oak?
(ଓକ୍ ଗଛ କ’ଣ ପାଇଁ ପ୍ରସିଦ୍ଧ ?)
Answer:
An oak tree is a large tree with tough, hardwood. It is a European tree that lives for about three hundred years. It is noteworthy for its largeness and longevity.

Question 2.
Who is fairer: an oak or a lily? How?
(ସୁନ୍ଦର କିଏ : ଏକ ଓକ୍ ଗଛ ନା ଏକ କଇଁ ? କିପରି ?)
Answer:
A lily is fairer than an oak. A lily appears only for a day but it gives pleasure and fragrance as it is a flower of light.

Question 3.
What ultimately happens to an oak?
(ଶେଷରେ ଓକ୍ ଗଛର କ’ଣ ହୁଏ ?)
Answer:
An oak tree grows large in size and lives for many years. Ultimately it becomes bald, sere, and finally falls to the ground.

Question 4.
Is a man blessed with a long life and material prosperity?
(ମଣିଷ କ’ଣ ଏକ ଦୀର୍ଘ ଜୀବନ ଏବଂ ଭୌତିକ ସମୃଦ୍ଧି ପାଇଁ ଆଶୀର୍ବାଦ ପାଇଛି ?)
Answer:
No, a man is not at all blessed with a long life and material prosperity. The lifetime of man is very short in comparison with an oak.

BSE Odisha 9th Class English Solutions Chapter 8 The Noble Nature

Question 5.
What are your impressions about the lily? (Clue: Ref. to L7 and 8)
(ଲିଲି ସମ୍ପର୍କରେ ଆପଣଙ୍କର ଧାରଣା କ’ଣ ?)
Answer:
The lily is a tiny flower and it lives for a day. It falls and dies that night. Still, it is a flower of light. It gives pleasure to its nobility.

Question 6.
Can a short life be perfect? Which lines suggest this and how?
(ଏକ ସ୍ବଳ୍ପ ଜୀବନ ଆଦର୍ଶ ଜୀବନ ହୋଇପାରିବ କି ? କେଉଁ ଧାଡ଼ି ଏହି ପରାମର୍ଶ ଦେଉଛି ଏବଂ କିପରି ?)
Answer:
No doubt a short life can be perfect. The lines “In small proportions, we just beauties see; And in short measures life may perfect be ” suggest this. The poet says that big size and long life do not make him worthy. Even the small and short-lived can be perfect by virtue of their noble qualities.

Question 7.
Choose the best possible meaning of ‘Just’ in line with the following :
(ନିମ୍ନଲିଖ୍ ଧାଡ଼ି ମଧ୍ୟରୁ ‘Just’ର ସବୁଠାରୁ ଭଲ ସମ୍ଭାବ୍ୟ ଅର୍ଥ ବାଛ ।)
(a) only a short time ago (b) really (c) morally fair
Answer:
(a) only a short time ago

F. Let’s Appreciate The Poem: (ଆସ କବିତାର ମୂଲ୍ୟାୟନ କରିବା)
(a) Comprehension questions : (ବୋଧଗମ୍ୟ ପ୍ରଶ୍ନ )

Question 1.
Why is a lily far fairer than an oak?
(ଗୋଟିଏ ଲିଲି ଏକ ଓକ୍ ଅପେକ୍ଷା ଅଧିକ ସୁନ୍ଦର କାହିଁକି)
Answer:
The qualities of a lily flower though small and short-lived is better than oak. So a lily is far fairer than an oak.

Question 2.
Which qualities make a man noble?
(କେଉଁ ଗୁଣସବୁ ଜଣେ ବ୍ୟକ୍ତିଙ୍କୁ ମହତ୍ କରିଥାଏ ?)
Answer:
Noble qualities like truthfulness, righteousness, rationality, etc. make a man noble.

Question 3.
Is long life a yardstick to judge the worth of a human being?
(ମଣିଷର ମୂଲ୍ୟକୁ ବିଚାର କରିବାପାଇଁ ତା’ର ଲମ୍ବା ଜୀବନ ଏକ ମାପକାଠି କି ?)
Answer:
Long life is not a yardstick to judge the worth of a human being. It is the good qualities of a man that matter.

BSE Odisha 9th Class English Solutions Chapter 8 The Noble Nature

Question 4.
Do you agree with the idea that in short measures life may perfect be?
(ସ୍ବଳ୍ପ ସମୟବିଶିଷ୍ଟ ଜୀବବିଶେଷରେ ଜୀବନ ପୂର୍ଣାଙ୍ଗ ହୋଇପାରେ – ଏଥରେ ତୁମେ ସମ୍ମତ କି ?)
Answer:
I do agree with the idea that in short measures life may be perfect as it is in the case of a lily.

Question 5.
Of a day, that night, smell, short – what do these suggest?
(ଗୋଟିଏ ଦିନର, ସେହି ରାତି, ସୁଗନ୍ଧ, କ୍ଷୁଦ୍ର – ଏସବୁ କ’ଣ ପରାମର୍ଶ ଦେଉଛି ?)
Answer:
These words suggest that the life of a short-lived is perfect like the life of a lily.

(b) Read the last four lines of the poem and answer the following by choosing the most appropriate option given for each.
(କବିତାର ଶେଷ ଚାରିଧାଡ଼ି ପଢ଼ ଏବଂ ପ୍ରତ୍ୟେକରେ ଦିଆଯାଇଥିବା ସବୁଠାରୁ ଉପଯୁକ୍ତ ବିକଳ୍ପ ବାଛି ନିମ୍ନଲିଖୁଗୁଡ଼ିକର ଉତ୍ତର ଦିଅ ।)

Question 1.
We see beauty in lily because
(ଆମେ କଇଁ ଫୁଲରେ ସୌନ୍ଦର୍ଯ୍ୟ ଦେଖୁ କାରଣ)
(i) it is short-lived
(ii) it is the flower of light
(iii) small is beautiful
(iv) it is not like an oak
Answer:
(ii) it is the flower of light

Question 2.
The poet’s philosophy of life is that
(କବିଙ୍କର ଜୀବନ ଦର୍ଶନ ହେଉଛି)
(i) one must enjoy life to the fullest extent
(ii) one must make others happy
(iii) small things can make life beautiful
(iv) longevity should be the good of our life
Answer:
(iii) small things can make life beautiful

Question 3.
In a phrase of the poem, the poet suggests that a ‘short life’ is
(କବିତାର ଏକ ଶବ୍ଦପୁଞ୍ଜରେ କବି ପରାମର୍ଶ ଦିଅନ୍ତି ଯେ ସ୍ଵଳ୍ପ ଜୀବନ)
(i) die that night
(ii) flower of light
(iii) small proportions
(iv) short measures
Answer:
(iv) short measures

BSE Odisha 9th Class English Solutions Chapter 8 The Noble Nature

Question 4.
If you were asked to describe lily in a few words, how would you do it in the context of the poem?
(ତୁମକୁ ଯଦି କଇଁଫୁଲକୁ କିଛି ଶବ୍ଦରେ ବର୍ଣ୍ଣନା କରିବାକୁ କୁହାଯିବ, ତୁମେ ଏହି କବିତାର ପରିପ୍ରେକ୍ଷୀରେ କିପରି କରିବ ?)
(i) a flower-bearing plant
(ii) beautiful but short-lived
(iii) a water plant
(iv) sweet-smelling flower
Answer:
(ii) beautiful but short-lived

G. Let’s Do The Activities: (ଆସ କାର୍ଯ୍ୟଗୁଡ଼ିକୁ କରିବା)
(a) Now, read the poem aloud with your friends.
(ବର୍ତ୍ତମାନ କବିତାଟିକୁ ତୁମ ସାଙ୍ଗମାନଙ୍କ ସହ ବଡ଼ ପାଟିରେ ପଢ଼ ।)

(b) Do you want to be a noble human being? Discuss it in groups.
(ତୁମେ ଜଣେ ମହତ୍ ବ୍ୟକ୍ତି ହେବାକୁ ଚାହୁଁଛି କି ? ଦଳ ମଧ୍ୟରେ ଏହା ଆଲୋଚନା କର ।)
Answer:
Yes, I want to be a noble human being. First of all, I’ll try my best to make others happy by virtue of my good qualities. Because I know that I am short-lived. During that period I’ll also make my life perfect.

(c) Have you read the Odia poem, Sefali Prati by Kuntala Kumari Sabat? If not, read the poem and find out the similarities. (ତୁମେ କୁନ୍ତଳା କୁମାରୀ ସାବତଙ୍କ ଓଡ଼ିଆ କବିତା ‘ଶେଫାଳୀ ପ୍ରତି’ ପଢ଼ିଛ କି ? ଯଦି ପଢ଼ି ନାହଁ, କବିତାଟିକୁ ପଢ଼ ଏବଂ ସାମଞ୍ଜସ୍ୟ ନିରୂପଣ କର ।)
Answer:
Yes, I have read the Odia poem ‘Sefali Prati’ by Kuntala Kumari Sabat. It is very similar to the present poem ‘The Noble Nature’. Shefali is a small flower that blooms for a night, but it fascinates people with its beauty and sweet fragrance. It gives pleasure to everybody even if it is short-lived. Similarly, in this poem, the poet says that though the lily is a short-lived flower, still it attracts people with its natural beauty and fragrance.

BSE Odisha 9th Class English Solutions Chapter 8 The Noble Nature

BSE Odisha 9th Class English The Noble Nature Important Questions and Answers

Very Short & Objective Questions With Answers.
Answer The Followings In A Sentence.

Question 1.
What does the poet compare a man to?
Answer:
The poet compares a man to a long-lived oak tree.

Question 2.
What is noteworthy in an oak?
Answer:
It is noteworthy for an oak’s largeness and longevity.

Question 3.
How long does an oak live?
Answer:
An oak lived for about three hundred years.

Question 4.
Is a man blessed with long life?
Answer:
No, a man is not blessed with long life.

Question 5.
Who is fairer; an oak or a lily?
Answer:
A lily is fairer than an oak.

BSE Odisha 9th Class English Solutions Chapter 8 The Noble Nature

Question 6.
How long does a lily live?
Answer:
A lily lives for a day and dies that night.

Question 7.
How is a lily flower described in the passage?
Answer:
A lily flower is described as delicate and short-lived.

Question 8.
Where does a person see the beauties?
Answer:
A person sees the beauties in small things.

Question 9.
Where does the perfection of life exist?
Answer:
The perfection of life exists in a short life.

Question 10.
What is the poet’s philosophy of life?
Answer:
The poet’s philosophy of life is that small thing can make life beautiful.

The Noble Nature Summary in English

Lead In:
We have beautiful things around us. The hills, mountains, rivers, and woods attract us. Good and noble people also impress us. All noble things influence us. In the poem, “The Noble Nature”, the poet talks about the qualities that make a man noble. He describes a perfect life. He compares man to a sturdy oak and to a delicate lily in support of his view. According to the poet, big size and long life do not matter. Even the small and the short-lived can be perfect. Listen to your teacher reading the poem aloud. Now find out what a nobleman is compared to.

Notes:
woods – ଜଙ୍ଗଲ,
attract – ଆକର୍ଷିତ କରେ,
impress – ମନରେ ଏକ ଛାପ ପକାଇବା,
describes – ବର୍ଣ୍ଣନା କରନ୍ତି
compares – ତୁଳନା କରନ୍ତି,
perfect – ଆଦର୍ଶ,
influence – ପ୍ରଭାବିତ କରିବା,
quality – ଗୁଣ
sturdy – ହୃଷ୍ଟପୁଷ୍ଟ,
delicate – କୋମଳ

ଉପକ୍ରମ :
ଆମ ଚତୁଃପାର୍ଶ୍ଵରେ ସୁନ୍ଦର ସୁନ୍ଦର ଜିନିଷମାନ ରହିଛି। ପାହାଡ଼, ପର୍ବତ, ନଦୀ ଏବଂ ଜଙ୍ଗଲଗୁଡ଼ିକ ଆମକୁ ଆକୃଷ୍ଟ କରେ । ଉତ୍ତମ ଓ ମହତ୍ଵ ଲୋକମାନେ ମଧ୍ୟ ଆମ ମନରେ ଏକ ଛାପ ପକାଇଥାଆନ୍ତି । ସବୁ ମହତ୍ ବସ୍ତୁ ଆମକୁ ପ୍ରଭାବିତ କରିଥାଏ । “The Noble Nature” କବିତାରେ କବି ସ୍ବାଭାବିକ ଗୁଣ ବିଷୟରେ କହିଛନ୍ତି ଯାହାକି ମଣିଷକୁ ମହାନ୍ କରିଥାଏ । ସେ ଗୋଟିଏ ଆଦର୍ଶ ଜୀବନ କଥା ବର୍ଣ୍ଣନା କରିଛନ୍ତି । ସେ ତାଙ୍କ ମତ ସପକ୍ଷରେ ଗୋଟିଏ ମଣିଷକୁ ଗୋଟିଏ ହୃଷ୍ଟପୁଷ୍ଟ ଓକ୍ ବୃକ୍ଷ ଓ ସୂକ୍ଷ୍ମ/ସୁକୋମଳ କଇଁଫୁଲ ସହିତ ତୁଳନା କରିଛନ୍ତି । କବିଙ୍କ ମତରେ ବଡ଼ ଆକାର ଓ ଦୀର୍ଘ ଜୀବନ ମୁଖ୍ୟ କଥା ନୁହେଁ । ଏପରିକି କ୍ଷୁଦ୍ର ଓ ସ୍ୱଳ୍ପଜୀବୀ ମଧ୍ୟ ଆଦର୍ଶ ହୋଇପାରିବ । କବିତାଟିକୁ ଶିକ୍ଷକ ବଡ଼ ପାଟିରେ ପଢ଼ୁଥିବା ଶୁଣ । ବର୍ତ୍ତମାନ କାହାକୁ ମହତ୍ ଲୋକ ସହିତ ତୁଳନା କରାଯାଇଛି ଖୋଜି ବାହାର କର ।

BSE Odisha 9th Class English Solutions Chapter 8 The Noble Nature

Summary:
Ben Jonson compares man to a long-lived oak tree and a short-lived lily flower in a beautiful manner. An oak tree survives for hundreds of years and it is- famous for the largeness of its size. Ultimately it becomes bare and dry and falls to the ground. Its life comes to an end after a pretty long time. On the contrary, a lily is a tiny flower. It blooms for a very short time. It falls and dies on the very day at night.

It is a flower of light and it attracts the attention of all by dint of its natural beauty. The poet says that we see beauties in small things. Because God has made every tiny creature or thing very beautiful and noble. They spread their fragrance even if they are short-lived. Similarly, man can make his life noble although it is short-lived. His nobility makes him perfect in his short life.

Notes:
survives – ତିଷ୍ଠି ରହେ,
virtue – ଭଲ ଗୁଣ,
nobility – ମହତ୍ଵପଣିଆ,
blooms – ଫୁଟେ,
attracts – ଆକର୍ଷିତ କରେ,
attention – ଧ୍ୟାନ
natural beauty – ପ୍ରାକୃତିକ ସୌନ୍ଦର୍ଯ୍ୟ,
beauties – ସୌନ୍ଦର୍ଯ୍ୟ,
fragrance – ସୁଗନ୍ଧ
noble – ମହାନ୍/ମହତ୍
short-lived – କ୍ଷଣସ୍ଥାୟୀ/ସ୍ୱଳ୍ପଜୀବୀ

ସାରାଂଶ :
କବି ବେନ୍ ଜନସନ୍ ଅତି ଚମତ୍କାର ଭାବରେ ମଣିଷକୁ ଦୀର୍ଘଜୀବୀ ଓକ୍ ବୃକ୍ଷ ଓ ସ୍ୱଳ୍ପଜୀବୀ କଇଁଫୁଲ ସହିତ ତୁଳନା କରିଛନ୍ତି । ଗୋଟିଏ ଓକ୍ ବୃକ୍ଷ ଶହ ଶହ ବର୍ଷ ଧରି ବଞ୍ଚୁଥାଏ ଓ ଏହା ଏହାର ଆକାରର ବିଶାଳତା ପାଇଁ ପ୍ରସିଦ୍ଧ । କିନ୍ତୁ ପରିଣତିସ୍ଵରୂପ ଏହା ପତ୍ରବିହୀନ ହୋଇ ଶୁଖୁଏ ଓ ଭୂମିରେ ପଡ଼ି ମାଟିରେ ମିଶିଯାଏ । ଏହା ବହୁତ ଦିନ ବଞ୍ଚିବା ପରେ ମରିଯାଏ । କଇଁ ଫୁଲଟିଏ ଅତି କ୍ଷୁଦ୍ର ଓ ନଗଣ୍ୟ । ଏହା ଅତି ସ୍ଵଳ୍ପ ସମୟ ପାଇଁ ପ୍ରସ୍ଫୁଟିତ ହୋଇଥାଏ । ଠିକ୍ ସେହିଦିନ ରାତିରେ ଏହା ଝଡ଼ିପଡ଼େ ଓ ଏହାର ମୃତ୍ୟୁ ଘଟିଥାଏ । ଏହା ଏକ ସୁନ୍ଦର ଓ ଉଜ୍ଜ୍ଵଳ ଫୁଲ ଏବଂ ଏହାର ପ୍ରାକୃତିକ ସୌନ୍ଦର୍ଯ୍ୟ ସମସ୍ତଙ୍କୁ ଆକୃଷ୍ଟ କରିଥାଏ । କବି କହୁଛନ୍ତି ଯେ ଆମେ କ୍ଷୁଦ୍ରବସ୍ତୁରେ ସୌନ୍ଦର୍ଯ୍ୟ ଦେଖୁ । କାରଣ ଈଶ୍ବର ପ୍ରତ୍ୟେକ କ୍ଷୁଦ୍ର ପ୍ରାଣୀ ଓ ବସ୍ତୁକୁ ସୁନ୍ଦର ଏବଂ ମହତ୍ କରିଛନ୍ତି । ଯଦିଓ ଫୁଲଗୁଡ଼ିକ ସ୍ୱଳ୍ପଜୀବୀ ତଥାପି ସେମାନେ ସେମାନଙ୍କର ମହକ ପ୍ରସାରିତ କରିଥାଆନ୍ତି । ଠିକ୍ ସେହିପରି ମଣିଷ ତା’ର ଜୀବନକୁ ମହତ୍ କରିପାରେ ଯଦିଓ ସେ ସ୍ଵଳ୍ପକାଳ ବଞ୍ଚୁଥାଏ । ତା’ର ସ୍ବଚ୍ଛ ଜୀବନ ମଧ୍ୟରେ ତା’ର ମହାନତା ତାକୁ ପୂର୍ଣ୍ଣାଙ୍ଗ ବା ତ୍ରୁଟିହୀନ କରାଇଥାଏ ।

BSE Odisha 9th Class English Solutions Chapter 8 The Noble Nature

The Text : (ପାଠ୍ୟବିଷୟ)
Stanza – 1
It is not growing like a tree
In bulk, doth make Man better be;
Or standing long an oak, three hundred year,
To fall a long at last, dry, bald, and sere :
ଅନୁବାଦ :
ଓକ୍ ବୃକ୍ଷ ବଡ଼ ହୋଇ ଖୁବ୍ ବିଶୀଳ ହୁଏ । ତିନିଶହ ବର୍ଷ ଧରି ଛିଡ଼ା ହୋଇଥ‌ିବା ଏହି ଓକ୍ ବୃକ୍ଷ ପରିଶେଷରେ ପତ୍ରବିହୀନ ବା ଥୁଣ୍ଟା ହୋଇ ଶୁଝାଯାଏ ଓ ତଳେ ପଡ଼ିଯାଇ ମାଟିରେ ମିଶିଯାଏ । ମାତ୍ର ମଣିଷ ସ୍ଵଳ୍ପକାଳ ପାଇଁ ବଞ୍ଚୁଥିଲେ ମଧ୍ୟ ତା’ର ମହତ୍ତ୍ଵ ବଳରେ ସେ ନିଜକୁ ସରସ ଓ ସୁନ୍ଦର କରି ଗଢ଼ିତୋଳେ ।

Stanza – 2
A lily of a day
Is fairer far in May,
Although it fall and die that night-
It was the plant and flower of Light
In small proportions we just beauties see;
And in short measures life may perfect be
ଅନୁବାଦ :
ଗୋଟିଏ ସୁନ୍ଦର କଇଁଫୁଲ ଦିନକ ପାଇଁ ପ୍ରସ୍ଫୁଟିତ ହୁଏ । ମଇ ମାସରେ ଏହି ସୁନ୍ଦର ଓ କୋମଳ ଫୁଲଟି ସମସ୍ତଙ୍କୁ ଆନନ୍ଦ ପ୍ରଦାନ କରେ । ଯଦିଓ ଏହା ଗୋଟିଏ ଦିନରେ ଫୁଟି ସେହିଦିନ ରାତିରେ ଝଡ଼ିପଡ଼େ ତଥାପି ଏହା ଖୁବ୍ ସୁନ୍ଦର ଓ ଆନନ୍ଦ ପ୍ରଦାନକାରୀ । ଆମେ ସୂକ୍ଷ୍ମ ଓ କ୍ଷୁଦ୍ରବସ୍ତୁର ସରସତା ଓ ସୌନ୍ଦର୍ଯ୍ୟ ଉପଭୋଗ କରୁ । ଠିକ୍ ସେହିପରି ମଣିଷ ତା’ର ସ୍ବଚ୍ଛ ରହଣି ମଧ୍ୟରେ ମହତ୍ ଗୁଣଦ୍ୱାରା ତା’ର ଜୀବନକୁ ସରସ ଓ ସୁନ୍ଦର କରିପାରେ । ବୃହତ୍ ଆକାର ଓ ଦୀର୍ଘ ଜୀବନ ବଡ଼ କଥା ନୁହେଁ, ବଡ଼ କଥା ହେଉଛି ମହତ୍ ସ୍ବଭାବ ।

About The Poet:
Ben Johnson (1572-1637) was an English Renaissance dramatist, poet, and actor. A contemporary of William Shakespeare, he is best known for his ‘Comedy of Humour’ with a tone of satire. Jonson’s poetry, like his drama, is informed by his classical learning. In the poem, The Noble Nature, he talks about the qualities that make a man noble. He compares man to a sturdy oak and to a delicate lily, in support of his views.

Notes:
Renaissance – ପୁନର୍ଜାଗରଣ,
dramatist – ନାଟ୍ୟକାର,
actor – କଳାକାର,
contemporary – ସମସାମୟିକ,
satire – ବ୍ୟଙ୍ଗ
classical – କଳାତ୍ମକ,
view – ମତ

କବିଙ୍କ ସମ୍ପର୍କରେ :
ବେନ୍ ଜନସନ୍ ଜଣେ ପୁନର୍ଜାଗରଣ ଯୁଗର ଇଂରେଜୀ ନାଟ୍ୟକାର, କବି ଓ ଅଭିନେତା । ଉଇଲିୟମ୍ ସେକ୍ସପିୟରଙ୍କ ସମସାମୟିକ ଭାବେ ସେ ବିହ୍ନପାତ୍ମକ ରଚନା ‘Comedy of Humour’ ପାଇଁ ବେଶ୍ ଜଣାଶୁଣା । ଜନସନ୍‌ଙ୍କ କବିତା ତାଙ୍କ ନାଟକ ଭଳି ତାଙ୍କ ସାର୍ବଜନୀନ ଶିକ୍ଷାର ସୂଚନା ଦିଏ । ‘The Noble Nature’ କବିତାରେ ସେ ମଣିଷକୁ ମହତ୍ କରୁଥିବା ଗୁଣାବଳୀ ବିଷୟରେ କହିଛନ୍ତି । ତାଙ୍କ ମତାମତ ସପକ୍ଷରେ ସେ ମଣିଷକୁ ଏକ ହୃଷ୍ଟପୁଷ୍ଟ ଓକ୍ ଗଛ ଓ ସୁକୋମଳ କଇଁ ସହ ତୁଳନା କରିଛନ୍ତି ।

BSE Odisha 9th Class English Solutions Chapter 8 The Noble Nature

Notes And Glossary : (ଟିପ୍‌ପଣୀ ଓ କଠିନ ଶବ୍ଦାର୍ଥ)

oak — a large tree with tough and hard wood – ଇଉରୋପରେ ଦେଖାଯାଉଥ‌ିବା ଏକ ବିଶାଳ ବୃକ୍ଷ ଯାହାର କାଠ ଚେମଡ଼ା ଓ କଠିନ ଏବଂ ଏହା ଆପାତତଃ ୩୦୦ ବର୍ଷ ବଞ୍ଚି ରହେ ।
Oak is a large tree with tough and hard wood.
bulk — largeness of size
It was difficult to move not because of its weight but because of its bulk.
doth — (old use) — does
bald — bare/without leaves — ଥୁଣ୍ଟା / ପତ୍ର ବିନା |
The trees look bald in winter.
sere — dried and withered
After three hundred years the oak tree becomes sere.
measures — sizes — ଆକାର
fairer — more beautiful, more charming — ଅଧ୍ଵ ସୁନ୍ଦର
A rose is fairer than a china rose.
log – trunk (of a tree) — ଗଛର ଗଣ୍ଠି
The log is floating in the water.
although — though — ଯଦିଓ
proportions — the size and shape of something — କୌଣସି ଜିନିଷର ଆକାର ଓ ଆକୃତି
This drawing is not in proportion; the man is larger than the house.
just — right/proper
I don’t think you were being just punishing him but not her.
beauties (n) — plural of beauty — ସୌନ୍ଦର୍ୟ୍ୟ
short measure — short life — ସ୍ୱଳ୍ପ ଜୀବନ
A man should make life perfect in his short measure.
perfect — ପରଫେକ୍ଟ
The poet describes a perfect life in this poem.
[Your teacher will read the poem aloud again. See if you found out what a noble man compared to Share your answer with the class.]

CHSE Odisha Class 11 Math Solutions Chapter 5 Principles Of Mathematical Induction Ex 5

Odisha State Board Elements of Mathematics Class 11 Solutions CHSE Odisha Chapter 5 Principles Of Mathematical Induction Ex 5 Textbook Exercise Questions and Answers.

CHSE Odisha Class 11 Math Solutions Chapter 5 Principles Of Mathematical Induction Exercise 5

Prove the following by induction.

Question 1.
1 + 2 + 3 + …… + n = \(\frac{n(n+1)}{2}\)
Solution:
Let pn be the given statement
CHSE Odisha Class 11 Math Solutions Chapter 5 Principles Of Mathematical Induction Ex 5

Question 2.
12 + 22 + …… + n2 = \(\frac{n(n+1)(2 n+1)}{6}\)
Solution:
Let pn be the given statement
when n = 1
12 =1 = \(\frac{1(1+1)(2 \times 1+1)}{6}\)
P1 is true
Let Pk be true.
i.e. 12 + 22 + … + k2 = \(\frac{k(k+1)(2 k+1)}{6}\)
we shall prove Pk + 1 is true i.e., 12 + 22 + … + k2 + (k + 1)2
\(=\frac{(k+1)(k+2)(2 k+3)}{6}\)
CHSE Odisha Class 11 Math Solutions Chapter 5 Principles Of Mathematical Induction Ex 5 1
∴ Pk+1 is true
∴ Pn is true of all values of n∈N.

Question 3.
1 + r + r2+ …. + rn = \(\frac{r^{n+1}-1}{r-1}\)
Solution:
Let Pn be the given statement
CHSE Odisha Class 11 Math Solutions Chapter 5 Principles Of Mathematical Induction Ex 5 2
CHSE Odisha Class 11 Math Solutions Chapter 5 Principles Of Mathematical Induction Ex 5 3

Question 4.
5n – 1 is divisible by 4.
Solution:
Let Pn = 5n – 1
When n = 1,
51 – 1 = 4 is divisible by 4.
∴ P1, is true.
Let Pk be true i.e.,
5k – 1 is divisible by 4.
Let 5k+1 – 1 = 4m, me Z
Now 5k + 1 – 1 = 5k. 5 – 5 + 4
= 5 (5k – 1) + 4
= 5 × 4m + 4 = 4 (5m + 1)
which is divisible by 4.
∴ Pk+1 is true.
∴ Pn is true for all values of n ∈ N

CHSE Odisha Class 11 Math Solutions Chapter 5 Principles Of Mathematical Induction Ex 5

Question 5.
72n + 23n-3  3n-1 is divisible by 25 for any natural number n > 1.
Solution:
Let 72n + 23n-3 . 3n-1
when n = 1, 71 + 20 . 30 ⇒ 49 + 1 = 50
which is divisible by 25.
∴ P1 is true. Let Pk be true.
i.e., 72k + 23k-3 3k-1 is divisible by 35
Now \(7^{2 \overline{k+1}}+2^{3 \overline{k+1}-3} 3^{\overline{k+1}-1}\)
=72k+2 + 23k. 3k
= 72k. 72 + 23k-3 23. 3k-1. 31
= 72k. 49 + 23k-3. 3k-1. 24
= 72k (25 + 24) + 24. 23k-3. 3k-1
= 72k. 25 + 24 (72k + 23k-3. 3k-1)
= 72k. 25 + 24 × 25m
Which is divisible by 25 (∵ Pk is true)
∴ Pk+1 is true
∴ Pn is true for all values of n > 1.

Question 6.
7. 52n-1 + 23n+1 is divisible by 17 for every natural number n ≥ 1.
Solution:
Let Pn = 7. 52n – 1 + 23n+1.
When n = 1, 7.5 + 24 = 35 + 16 = 51
Which is divisible by 17.
P1, is true.
Let Pk be true i.e., 7.52k-1 + 23k+1  is divisible by 17.
Let 7.52k-1 + 23k+1 = 17 m, m ∈ Z
Now, \(7.5^{2 \overline{k+1}-1}+2^{3 \overline{k+1}+1}\)
= 7.52k-1 + 23k+4
= 7.52k-1 . 52 + 23k+1 . 23
= 25. 7. 52k-1 + 8. 23k+1
= (17 + 8) 7.52k-1 + 8. 23k+1
= 17. 7. 52k-1 + 8 (7. 52k-1 + 23k+1)
= 17 × 7 × 52k-1 + 8 × 17m
Which is divisible by 17.
Hence Pk+1. is true.
∴ Pn is true for all values of n ≥ 1.

Question 7.
4n+1 + 15n + 14 is divisible by 9 for every natural number n ≥ 0.
Solution:
Let Pn = 4n+1+ 15 n + 14
when n = 1, 42 + 15 + 14 = 45 is divisible by 9.
∴ P1 is true. Let Pk be true.
i.e., 4k+1 + 15k + 14 is divisible by 9.
Now, 4k+1+1 + 15 (k + 1) + 14
= 4k+2 + 15k + 29
= 4k+1. 4 + 60k + 56 – 45k – 27
= 4 (4k+1 + 15k + 14) – 9 (5k + 3)
Which is divisible by 9.
∴ Pk+1, is true.
∴ Pn is true for all values of n ≥ 0.

Question 8.
3(2n-1) + 7 is divisible by 9 for every natural number n ≥ 2.
Solution:
Let Pn = 32(n-1) + 7
When n = 2. 32 + 7 = 16 is divisible by 8.
∴ P2 is true.
Let Pk be true.
i.e., 52(k-1) + 7 is divisible by 8.
Let 32k-2 + 7 = 8m. m ∈ Z.
Now \(3^{2(\overline{k+1}-1)}\) + 7 = 32k + 7
= 32k-2. 32 + 63 – 56
= 9(32k-2 + 7) – 56
= 9 × 8m – 56 = 8 (9m – 7)
Which is divisible by 8.
Pk+1 is true.
Pn is true for all values on n ≥ 2.

Question 9.
5(2n-4)  – 6n + 32 is divisible by 9 for every natural number n ≥ 5.
Solution:
Let P = 52(n-4) – 6n + 32
For n = 5, P5 = 52 – 6. 5 + 32
= 25 – 30 + 32 = 27
Which is divisible by 9.
Hence P5 is true.
Let Pk is true.
Let Pk is divisible by 9.
Let Pk = 52(k-4) – 6k + 32 = 9., m ≥ Z
52k+2 = 576 m + 24k  + 25 … (1)
we shall prove that Pk+1 is true.
Now 52(K+1)+2 – 24(k+1) – 25
= 52 (52k+2) – 24k – 24 – 25
= 52[576m + 24k + 25] – 24k – 24 – 25
= 25 × 576 m + 25 × 24k + 25 × 25 – 24k – 24 – 25
= 25 × 576 m + 576 k + 576
= 576 [25 m + k + 1]
which is divisible by 576
∴ Pk+1 is true.
So by the method of induction Pn is true for all n.
i.e., 52n+2  – 24n – 25 is divisible by 576 for all n ∈ N.
Hence Pk+1 is true.
So by methods of induction Pn is true.
i.e., 52n+2 – 24n – 25 is divisible by 576 for all n.

CHSE Odisha Class 11 Math Solutions Chapter 5 Principles Of Mathematical Induction Ex 5

Question 10.
\(\frac{1}{1.2}+\frac{1}{2.3}+\ldots+\frac{1}{n(n+1)}=\frac{n}{n+1}\)
Solution:
when n = 1,
CHSE Odisha Class 11 Math Solutions Chapter 5 Principles Of Mathematical Induction Ex 5 4
CHSE Odisha Class 11 Math Solutions Chapter 5 Principles Of Mathematical Induction Ex 5 5

Question 11.
1.3 + 2.4 + 3.5 + …….. + n(n + 2) = \(\frac{n(n+1)(2 n+7)}{6}\)
Solution:
when n = 1,
we have 1.3 = 3 = \(\frac{3 \times 6}{6}\)
\(=\frac{1 \times 2 \times 9}{6}=\frac{1(1+1)(2 \times 1+7)}{6}\)
CHSE Odisha Class 11 Math Solutions Chapter 5 Principles Of Mathematical Induction Ex 5 6
CHSE Odisha Class 11 Math Solutions Chapter 5 Principles Of Mathematical Induction Ex 5 7

Question 12.
xn – yn = (x – y)(xn-1 + xn-2 y + … + xyn-2 + yn-1); x, y ∈ R [Hint : Write xn+1 – yn+1 = x(xn – yn) + yn(x – y)]
Solution:
Let p(n) is
xn – yn = (x – y)(xn-1 + xn-2 y + … + xyn-2 + yn-1); x, y ∈ R
Step – 1:
For n = 2
x2 – y2 = (x – y) (x + y) (True)
∴ P(1) is true.
Step – 2:
Let P(k) is true.
i.e., xk – yk = (x – y)(xk-1 + xk-2y + … +xyk-2 + yk-1)
Step – 3:
Let us prove Pk+1 is true.
i.e., xk+1 – yk+1 = (x – y) (xk + xk-1y + … (xyk-1 + yk)
L.H.S. = xk+1 – yk+1
= xk+1 – xyk + xyk – yk+1
= x(xk – yk) + yk (x – y)
= x(x – y)(xk-1 + xk-2 y + … + xyk-2 + yk-1) + yk(x – y) [by (1)]
= (x – y) [xk + xk-1 y + … + xyk-2 + xyk-1 + yk]
= R.H.S.
∴ P(k+1) is true.
Step – 4:
By Principle Of Mathematical Induction P(n) is true for all n ∈ N.

Question 13.
1 + 3 + 5 + ……. +(2n – 1) = n2
Solution:
Let P(n) is : 1 + 3 + 5 + ……. +(2n – 1) = n2.
Step – 1:
For n = 2
L.H.S. = 1 + 3 = 4 = 22 (R.H.S)
∴ P(1) is true.
Step – 2:
Let P(k) is true.
i.e., 1 + 3 + 5 … + (2k – 1) = k2 …(1)
Step – 3:
We will prove that P(k + 1) is true
i.e., we want to prove.
1+ 3 + 5 + … + (2k – 1) + (2k + 1) = (k + 1)2
L.H.S. = 1 + 3 + 5 + … + (2k – 1) + (2k + 1)
= k2 + 2k + 1          [By – (1)]
= (k + 1)2 = R.H.S.
Step – 4:
By the Principle of Mathematical Induction P(n) is true for all n.
i.e., 1 + 3 + 5 ….+ (2n – 1) = n2

CHSE Odisha Class 11 Math Solutions Chapter 5 Principles Of Mathematical Induction Ex 5

Question 14.
n > n; n is a natural number.
Solution:
Let P(n) is 2n > n
Step – 1:
21 > 1 (True)
∴ P(1) is true.
Step – 2:
Let P(k) is true.
⇒ 2k > k
Step – 3:
We shall prove that P(k + 1) is true
i.e., 2k+1 > k + 1
Now 2k+1 = 2.2k > 2k ≥ k + 1 for k ∈ N.
∴ 2k+1 > k + 1
⇒ P(k + 1) is true.
Step – 4:
By the Principle of Mathematical Induction P(n) is true for all n.
i.e., 2n > n for n ∈ N

Question 15.
(1, 2, 3 … n)3  > 8 (13 + 23 + 33 + … + n3), for n > 3.
Solution:
Let P(n) is
(1, 2, 3 … n)3  > 8 (13 + 23 + 33 + … + n3), for n > 3.
Step – 1:
For n = 4
(1. 2. 3. 4)3 = 243 = 13824
8(13+ 23 + 33 + 43) = 808
∴ (1. 2 . 3 . 4)3 > 8(13 + 23 + 33 + 43)
∴ P(4) is true.
Step- 2:
Let P(k) is true.
(1. 2. 3…….k)3 > 8(13 + 23 + 33 + …… + k3)
Step – 3:
We shall prove that P(k+1) is true.
i.e., (1. 2. 3. …….. k(k+1))3 > 8(13 + 23 + … + k3 + (k + 1)3)
Now (1. 2. 3. …….. k(k + 1)3)
= (1. 2. 3 … k)3 (k + 1)3
> 8 (13 + 23 + … k3) (k + 1)3
> 8 (13 + 23 + … k3) + 8(k + 1)3
= 8 (13 + 23 + … + k3 + (k + 1)3)
P(k+1) is true.
Step – 4:
By the Principle of Mathematical Induction P(n) is true for all n ∈ N and n > 3.

Question 16.
\(\frac{1}{n+1}+\frac{1}{n+2}+\ldots+\frac{1}{3 n+1}>\) for every positive integer n.
Solution:
Let P(n) is
\(\frac{1}{n+1}+\frac{1}{n+2}+\ldots+\frac{1}{3 n+1}>\)
CHSE Odisha Class 11 Math Solutions Chapter 5 Principles Of Mathematical Induction Ex 5 8
CHSE Odisha Class 11 Math Solutions Chapter 5 Principles Of Mathematical Induction Ex 5 9
CHSE Odisha Class 11 Math Solutions Chapter 5 Principles Of Mathematical Induction Ex 5 10
Step-4:
By the Principle of Mathematical Induction P(n) is true for all n ∈ N.

BSE Odisha 9th Class English Solutions Chapter 10 Alexander Selkirk

Odisha State Board BSE Odisha 9th Class English Solutions Chapter 10 Alexander Selkirk Textbook Exercise Questions and Answers.

BSE Odisha Class 9 English Solutions Chapter 10 Alexander Selkirk

BSE Odisha 9th Class English Alexander Selkirk Text Book Questions and Answers

E. Let’s Understand The Poem: (ଆସ କବିତାଟିକୁ ବୁଝିବା)
(a) Comprehension Questions for discussion (ଆଲୋଚନା ପାଇଁ ବୋଧଗମ୍ୟ ପ୍ରଶ୍ନ)

Question 1.
Who does ‘I’ refer to?
(‘I’ କାହାକୁ ସୂଚାଯାଉଛି ?)
Answer:
‘I’ refers to Alexander Selkirk.

Question 2.
Who is the monarch here?
(ଏଠି କିଏ ସମ୍ରାଟ ବା ଅଧୀଶ୍ବର ଅଟନ୍ତି ?)
Answer:
Alexander Selkirk is the monarch here.

Question 3.
Who found charm in solitude?
(କେଉଁମାନେ ନିର୍ଜନତାରେ ଆନନ୍ଦ ପାଇଥା’ନ୍ତି ?)
Answer:
The sages found charm in solitude.

Question 4.
Why were the beasts unfamiliar with Selkirk?
(ପଶୁମାନେ ସେଲ୍‌କାର୍କଙ୍କ ସହିତ କାହିଁକି ଅପରିଚିତ ଥିଲେ ?)
Answer:
The beasts were unfamiliar with Selkirk because he had never met them on the island before and the beasts had never seen a human being before.

Question 5.
What did Selkirk appeal to the wind?
(ସେଲ୍‌କାର୍କ ବାୟୁକୁ କ’ଣ ନିବେଦନ କଲେ ?)
Answer:
Selkirk appealed to the wind to convey his message to his friends and relatives whom he could never meet in his life in his native land.

BSE Odisha 9th Class English Solutions Chapter 10 Alexander Selkirk

Question 6.
Which lines in the poem suggest that the island is a no man’s island?
(କବିତାର କେଉଁ ଧାଡ଼ିଗୁଡ଼ିକ ସୂଚାଇଦିଏ ଯେ ଦ୍ବୀପଟି କାହାର ଦ୍ଵୀପ ନୁହେଁ ?)
Answer:
The line “I AM monarch of all I survey, My right there is none to dispute,” and “/ am out of humanity’s reach, I must finish my journey alone,” in the poem suggest that the island is a no man’s island.

Question 7.
What is the meaning of the line – “They are so unacquainted with man” in stanza 2?
(ଦ୍ୱିତୀୟ ପଦରେ ଥ‌ିବା ଧାଡ଼ି, ‘ସେମାନେ ମନୁଷ୍ୟ ସହିତ ଅପରିଚିତ’’ର ଅର୍ଥ କ’ଣ ?)
Answer:
“They are so unacquainted with man” – means the animals were not familiar with man. The animals hadn’t seen a man before. The beasts on the island roam around Alexander Selkirk and ignore his presence.

Question 8.
What hurried Selkirk back to despair?
(କ’ଣ ସେଲକାର୍କଙ୍କୁ ନୈରାଶ୍ୟ ଭିତରକୁ ନେଇଗଲା ?)
Answer:
Selkirk hurried back to despair when he recollected his own present situation that he was alone on the deserted island.

Question 9.
What did Selkirk want to do when evening approached?
(ସନ୍ଧ୍ୟା ଉପନୀତ ହେଲାରୁ ସେଲକାର୍କ କ’ଣ କରିବାକୁ ଚାହୁଁଥିଲେ ?)
Answer:
When evening approached, Selkirk wanted to take a rest in his cabin (resting place).

Question 10.
Can you choose an alternative title for the poem?
(ଏହି କବିତା ପାଇଁ ତୁମେ ଏକ ବିକଳ୍ପ ନାମ ବାଛିପାରିବ କି ?)
Answer:
The alternative title of the poem may be ‘The Solitude of Alexander Selkirk”.

(b) Choosing the appropriate answers: (ସଠିକ୍ ଉତ୍ତର ବାଛ)

Question 1.
The poem is about the plight of a person named.
(a) Shakespeare
(b) William Cowper
(c) Alexander Selkirk
(d) William Wordsworth
Answer:
(c) Alexander Selkirk

Question 2.
I am of all is a survey.
(a) King
(b) Emperor
(c) Landlord
(d) Monarch
Answer:
(d) Monarch

Question 3.
The beasts ______ over the plain.
(a) run
(b) walk
(c) move
(d) roam
Answer:
(d) roam

BSE Odisha 9th Class English Solutions Chapter 10 Alexander Selkirk

Question 4.
0 had I the wings of a ______,How soon would I taste you again.
(a) crow
(d) dove
(e) owl
(d) fowl
Answer:
(b) dove

Question 5.
The ______ itself lags behind, And the swift-winged arrows of light.
(a) tempest
(b) cyclone
(c) blizzard
(d) wind
Answer:
(a) tempest

Question 6.
But the ______ is gone to her nest.
(a) sea horse
(b) sea fowl
(c) sea fish
(d) sea snake
Answer:
(b) sea fowl

F. Let’s Appreciate The Poem: (ଆସ କବିତାଟିର ମୂଲ୍ୟାୟନ କରିବା)

Question 1.
What did the poet survey?
(କବି କ’ଣ ଦେଖ‌ିଲେ ?)
Answer:
The poet surveyed the lonely island and the vast sea around it from the center of the island.

Question 2.
Why did the poet remember the sages?
(କବି କାହିଁକି ମୁନିଋଷିମାନଙ୍କୁ ମନେ ପକାଇଲେ ?)
Answer:
He remembered the sages because they got pleasure in solitude. But he didn’t get any pleasure in solitude in that island.

Question 3.
How does the poet describe the island in the second stanza?
(ଦ୍ଵିତୀୟ ପଦରେ କବି ଦ୍ବୀପକୁ କିପରି ବର୍ଣ୍ଣନା କରିଛନ୍ତି ?)
Answer:
The island is very lonely without human beings. It is far from any human dwelling. Only beasts and birds live there. That is a no man’s island. He didn’t find any charm in the loneliness of the island.

Question 4.
What are the divine qualities bestowed upon man?
(ମନୁଷ୍ୟ ଉପରେ ବୃଷ୍ଟି ହୋଇଥିବା ବା ମନୁଷ୍ୟକୁ ପ୍ରଦାନ କରାଯାଇଥିବା ଈଶ୍ୱରୀୟ ଗୁଣସବୁ କ’ଣ ?)
Answer:
Society, friendship, and love are the divine qualities bestowed upon man by God.

BSE Odisha 9th Class English Solutions Chapter 10 Alexander Selkirk

Question 5.
Why does the poet like the wisdom of age?
(କବି କାହିଁକି ବୟସ୍କମାନଙ୍କର ପ୍ରଜ୍ଞାକୁ ପସନ୍ଦ କରନ୍ତି ?)
Answer:
The poet likes the wisdom of the age because their wisdom gives wise advice so that he can spend his days happily. Their wisdom will bring him pleasure by making his sufferings less painful on the deserted island.

Question 6.
What is the poet’s prayer to the ‘winds’?
(ବାୟୁକୁ କବିଙ୍କର ପ୍ରାର୍ଥନା କ’ଣ ?)
Answer:
The poet prays to the winds to bring the good news of his native place which he can never visit. He also appeals to the wind to convey his message of solitude to his friends whom he can never meet in his life.

Question 7.
Why does the poet say that “the tempest itself lags behind”?
(କାହିଁକି କବି କହିଛନ୍ତି ଯେ, ‘ଝଡ଼ତୋଫାନ ନିଜେ ବହୁ ପଛରେ ରହିଗଲା’’ ?)
Answer:
The poet says that “the tempest itself lags behind” because the flight of the mind is so swift that it can surpass the tempest.

G. Let’s Speak:(ଆସ କଥା ହେବା)

(a) Role-play the following dialogue. (ନିମ୍ନରେ ପ୍ରଦତ୍ତ ସଂଳାପକୁ ଅଭିନୟ ମାଧ୍ୟମରେ ଆବୃତ୍ତି କର ।)
Selkirk  – Why are you so indifferent to me?
Beast    – Because you are a man.
Selkirk  – So what? I am quite friendly.
Beast    – Sorry, I am not acquainted with the man.
Selkirk  – Oh wind! Please listen to me.
Wind    – What can I do for you?
Selkirk  – Please convey my message to my friends as I am far away on this lonely island.
Wind    – It’s not possible. I can’t cross my limit.

H. Let’s Write: (ଆସ ଲେଖୁବା)
Words having sameness of sound of the endings of two or more words are rhyming words. In this poem the words like ‘face ’ and ‘place ’ are rhyming words. Find out at least six pairs of such words from the poem. (ଦୁଇ ବା ତତୋଽଧ୍ଵକ ଶବ୍ଦର ଶେଷ ଉଚ୍ଚାରଣରେ ସାଦୃଶ୍ୟ ଥିଲେ ତାହାକୁ ଯତିପାତ ହେଉଥ‌ିବା ଶବ୍ଦ (Rhyming words) କୁହାଯାଏ । ଏହି କବିତାରେ ‘face’ ଓ ‘place’ ଶବ୍ଦଦ୍ଵୟ ଯତିପାତ ହେଉଥ‌ିବା ଶବ୍ଦ । କବିତାରୁ ଏପରି ଅନ୍ୟୁନ ଛଅଯୋଡ଼ା ଶବ୍ଦ ଖୋଜି ବାହାର କର ।)

Answer:
Other rhyming words (six pairs) are:
1. dispute – brute
2. reach – speech
3. see – me
4. truth – youth
5. send – friend
6. flight – light

Writing task: (ଲିଖନ କାର୍ଯ୍ୟ)
This poem is about a sailor named Alexander Selkirk. He swam to a lonely island after a ship wreck. That was a no man’s island. Only beasts and birds lived there. (ଏହି କବିତାଟି ଆଲେକ୍‌ଜାଣ୍ଡର ସେଲ୍‌କାର୍କ ନାମକ ଜଣେ ନାବିକ ବିଷୟରେ ଲିଖ୍ । ଏକ ଜାହାଜ ଦୁର୍ଘଟଣା ପରେ ସେ ଗୋଟିଏ ନିର୍ଜନ ଦ୍ବୀପକୁ ପହଁରି ଯାଇଥିଲେ । ଏହା ଏକ ମାନବବିହୀନ ଦ୍ଵୀପ ଥିଲା । କେବଳ ପଶୁ ଓ ପକ୍ଷୀମାନେ ସେଠାରେ ବାସ କରୁଥିଲେ ।)
Think yourself as Selkirk and write in about ten lines describing your feeling of loneliness. (ନିଜକୁ ସେଲ୍‌କାର୍କ ମନେକରି ତୁମ ନିର୍ଜନତାର ଅନୁଭୂତିକୁ ବର୍ଣନା କରି ଦଶଟି ବାକ୍ୟରେ ଲେଖ ।)
Answer:
I am a sailor named Alexander Selkirk. Once I was on a sea voyage ( ଜଳଯାତ୍ରା) along with other crews. Unfortunately (ଦୁର୍ଭାଗ୍ୟବଶତଃ ) the ship was wrecked (ଦୁର୍ଘଟଣାଗ୍ରସ୍ତ ହେଲା) during the voyage. I was lucky enough to swim to a lonely island after the wreck. It was an uninhabited island. I felt lonely there. Only beasts and birds lived there. They remained aloof. Because they were not acquainted (ପରିଚିତ ନ ଥିଲେ)with man. I remembered the great sayings of the sages who used to get charms in solitude (ନିର୍ଜନତା). But I myself didn’t get any pleasure in that solitude. I realized that it was better to live in the midst of difficulties than to live in a lonely place like that isolated island. I always remembered my friends and relatives in my native land. I was anxious to hear the voice of my near and dear ones. But my dreams remained unfulfilled. My recollections left me in despair. I prayed to God to rescue me from that difficult situation. God heard my prayers and I was rescued after four years by a passing ship.

BSE Odisha 9th Class English Solutions Chapter 10 Alexander Selkirk

BSE Odisha 9th Class English Alexander Selkirk Important Questions and Answers

Very Short & Objective Questions With Answers.
Answer The Following In A Sentence.

Question 1.
What did the poet survey?
Answer:
The poet surveyed the isolated island and the vast sea around it.

Question 2.
Why did the poet remember the sages?
Answer:
The poet remembered the sages who got pleasure in solitude.

Question 3.
Where does the poet prefer to dwell?
Answer:
The poet thinks that it is better to dwell in the midst of danger than to reign on that horrible island.

Question 4.
How does the poet describe the island in the second stanza?
Answer:
The island is lonely without human beings.

Question 5.
Why does the poet feel that he will meet his end on that island?
Answer:
Due to his bad luck, the poet is on a deserted island.

Question 6.
What are the divine qualities bestowed upon man?
Answer:
Society, friendship, and love are the divine qualities bestowed upon man.

Question 7.
Why does the poet like the wisdom of age?
Answer:
The poet likes the wisdom of age because their wisdom gives wise advice so that he can spend his days happily.

BSE Odisha 9th Class English Solutions Chapter 10 Alexander Selkirk

Question 8.
What is the poet’s prayer to the ‘winds’?
Answer:
The poet prays to the winds to bring the good news about the place which he can never visit.

Question 9.
Why does the poet wish to have the wings of a dove?
Answer:
The poet wishes to have the wings of a dove so that he can fly and cross the sea to see his friends and relatives.

Question 10.
What does the poet want to know?
Answer:
The poet is anxious to know about his friends because they are far away from him.

Question 11.
Why does the poet say that ‘the tempest itself lags behind’?
Answer:
The poet says that ‘the tempest itself lags behind’ because the flight of the mind is so swift that it can win the tempest.

Question 12.
What hurried Selkirk back to despair?
Answer:
Selkirk hurried back to despair when he recollected his past.

Question 13.
What did the poet want to do when evening approached?
Answer:
When evening approached, the poet wanted to take a rest in his resting place.

Answer The Following In A Word Or A Phrase.

Question 1.
Who had made the poet his sport?
Answer:
The wind.

Question 2.
Who is unacquainted with a man?
Answer:
The beasts.

Question 3.
What is shocking to the poet?
Answer:
The tameness of the brutes.

Question 4.
What does the poet want to know?
Answer:
About his friends in his native land.

BSE Odisha 9th Class English Solutions Chapter 10 Alexander Selkirk

Question 5.
Which lines in the poem suggest that the island is “no man’s island”?
Answer:
“I am the lord of the fowl and the brute”.

Question 6.
Who found charm in solitude?
Answer:
The ancient sages.

Question 7.
What are the divine qualities bestowed upon man?
Answer:
Society, Friendship, And Love.

Fill In The Blanks.

1. But the ____________is gone to her nest.
Answer:
sea fowl

2. I am ____________of all I survey.
Answer:
monarch

3. The poem “Alexander Selkirk” reflects the freedom of his spirit in ____________.
Answer:
a lonely island

4. The poem begins with the words, “I am” written in capital letters strengthens the confidence of the abandoned sailor ____________on the lonely island
Answer:
Alexander Selkirk

5. The phrase “now and then” means ____________.
Answer:
frequently

BSE Odisha 9th Class English Solutions Chapter 10 Alexander Selkirk

6. The word ‘dispute’ means ____________.
Answer:
quarrel

7. The word ‘brute’ means ____________.
Answer:
beast

8. The word ‘solitude’ means ____________.
Answer:
loneliness

9. In the poem “Out of humanity’s reach” means ____________.
Answer:
beyond human touch

10. “And reconciles man to his lot.” Here ‘lot’ means ____________.
Answer:
fortune

11. The poet is anxious to know about ____________.
Answer:
his friends

12. Alexander Selkirk finds that the beast is taking rest in ____________.
Answer:
his lair

13. Selkirk hurried back to despair when ____________.
Answer:
he recollected his past

14. “Even here is a ____________of rest.”
Answer:
season

BSE Odisha 9th Class English Solutions Chapter 10 Alexander Selkirk

15. “Might learn from the wisdom of age.” Here the expression ‘wisdom of age’ means the wisdom of the ____________.
Answer:
elderly people

Multiple Choice Questions With Answers.

Question 1.
O solitude! where are the charms, the underlined word means ____________.
(A) silence
(B) lonely place
(C) island
(D) sages
Answer:
(B) lonely place

Question 2.
The poet is unable to hear the sweet speech of ____________.
(A) his friends
(B) his parents
(C) his relatives
(D) man
Answer:
(D) man

Question 3.
Who is unacquainted with a man?
(A) the sages
(B) the beasts
(C) the fowls
(D) the sea fowls
Answer:
(B) the beasts

Question 4.
“Gives even affliction a grace” Here the underlined expression means ____________.
(A) consolation
(B) peace
(C) pleasure
(D) distress
Answer:
(D) distress

Question 5.
The beasts ____________ over the plain.
(A) run
(B) walk
(C) move
(D) roam
Answer:
(D) roam

BSE Odisha 9th Class English Solutions Chapter 10 Alexander Selkirk

Question 6.
O had the wings of a ____________,howsoon would I taste you again.
(A) crow
(B) dove
(C) owl
(D) fowl
Answer:
(B) dove

Question 7.
The ____________ itself lags behind, And the swift-winged arrows of light.
(A) tempest
(B) cyclone
(C) blizzard
(D) wind
Answer:
(A) tempest

Question 8.
But the ____________ is gone to her nest.
(A) sea horse
(B) sea fowl
(C) sea fish
(D) sea snake
Answer:
(B) sea fowl

Question 9.
I am ____________of all I survey.
(A) king
(B) emperor
(C) landlord
(D) monarch
Answer:
(D) monarch

Question 10.
The phrase “now and then” means ____________.
(A) every time
(B) all the time
(C) frequently
(D) very often
Answer:
(C) frequently

Question 11.
The word ‘brute’ means ____________.
(A) beyond
(B) burial
(C) birds
(D) beast
Answer:
(D) beast

Question 12.
The word ‘solitude’ means ____________.
(A) solitary
(B) loneliness
(C) likingness
(D) solidarity
Answer:
(B) loneliness

Question 13.
“And reconciles man to his lot.” Here ‘lot’ means ____________.
(A) a lot of
(B) enough
(C) a lot
(D) fortune
Answer:
(D) fortune

BSE Odisha 9th Class English Solutions Chapter 10 Alexander Selkirk

Question 14.
The poet is anxious to know about ____________.
(A) the place
(B) his parents
(C) his friends
(D) the island
Answer:
(C) his friends

Question 15.
Alexander Selkirk finds that the beast is taking a rest in ____________.
(A) his lair
(B) his cave
(C) his cabin
(D) his nest
Answer:
(A) his lair

Alexander Selkirk Summary in English

Lead-In:
No human being likes to remain in loneliness, without friends, or out of society. This is a human tendency. It is very painful and pathetic to be far away from human habitation. ‘Alexander Selkirk’ is a poem that is based on a real adventure that happened to a sailor. Because of a dispute with the ship’s captain or after a shipwreck, he was deserted on an uninhabited island. There he lived alone for four years and was later rescued by a passing ship. Daniel Defoe’s ‘Robinson Crusoe’ is also based on the same incident. Now read the poem and realize the feeling of loneliness of Alexander Selkirk.

Notes:
loneliness – ଏକାକୀତ୍ୱ/ନିର୍ଜନତା,
tendency – ପ୍ରବୃତ୍ତି,
painful – ଯନ୍ତ୍ରଣାଦାୟକ,
pathetic – କାରୁଣ୍ୟପୂର୍ଣ,
habitation – ବସତି/ବାସସ୍ଥଳୀ,
adventure – ଦୁଃସାହସ,
sailor – ଜାହାଜର ନାବିକ,
dispute – ବିବାଦ,
deserted – ଏକୁଟିଆ ଛାଡ଼ି ଦିଆଗଲା,
island – ଦ୍ବୀପ

ଉପକ୍ରମ :
ବିନା ବନ୍ଧୁରେ ଅଥବା ସମାଜ ବାହାରେ, ନିର୍ଜନତାରେ ରହିବାକୁ କୌଣସି ମାନବ ପସନ୍ଦ କରନ୍ତି ନାହିଁ । ଏହା ହେଉଛି ମାନବୀୟ ସ୍ବଭାବ । ସମସ୍ତେ ବନ୍ଧୁ ଓ ସମ୍ପର୍କୀୟମାନଙ୍କ ଗହଣରେ ରହିବାକୁ ପସନ୍ଦ କରନ୍ତି । ମାନବ ବସତିଠାରୁ ଦୂରରେ ରହିବା ଅତ୍ୟନ୍ତ ଯନ୍ତ୍ରଣାଦାୟକ ଓ ଦୁଃଖଦାୟକ । ‘‘ଆଲେକ୍‌ଜାଣ୍ଡର ସେଲ୍‌କାର୍କ’’ କବିତାଟି ଗୋଟିଏ ବାସ୍ତବ ସାହସିକ କାର୍ଯ୍ୟ ଉପରେ ଆଧାରିତ ଯାହାକି ଜଣେ ନାବିକ ଜୀବନରେ ଘଟିଥିଲା । ଜାହାଜର କ୍ୟାପ୍ଟେନ୍‌ଙ୍କ ସହ ବିବାଦ ହେତୁ କିମ୍ବା ଜାହାଜ ଦୁର୍ଘଟଣା ହେବାରୁ ତାଙ୍କୁ ଏକ ମାନବ ବସତିହୀନ ବିସ୍ତୀର୍ଣ୍ଣ ଦ୍ଵୀପରେ ଛାଡ଼ି ଦିଆଯାଇଥିଲା । ସେଠାରେ ସେ ଏକାକୀ ଚାରି ବର୍ଷ ରହିଲେ ଏବଂ ସେହି ବାଟ ଦେଇ ଯାଉଥ‌ିବା ଅନ୍ୟ ଏକ ଜାହାଜଦ୍ବାରା ଉଦ୍ଧାର ହୋଇଥିଲେ । ଡାନିଏଲ୍‌ ଡେଫୋଙ୍କ ‘ରବିନ୍‌ସନ୍ କୁସୋ’’ ମଧ୍ୟ ସମାନ ଘଟଣା ଉପରେ ଆଧାରିତ । ଏବେ କବିତାଟିକୁ ପଢ଼ ଓ ଆଲେକ୍‌ଜାଣ୍ଡର୍‌ ସେଲ୍‌କାର୍କଙ୍କ ନିଃସଙ୍ଗତାର ଅନୁଭୂତିକୁ ହୃଦୟଙ୍ଗମ କର ।

BSE Odisha 9th Class English Solutions Chapter 10 Alexander Selkirk

Summary:
In the poem, the sailor (Alexander Selkirk) says that he is the sole monarch of the lonely island and there is no one in the world who will fight with him for that right. He is the supreme ruler of the birds and animals there. In his opinion, wise men and philosophers say that there is pleasure in living a lonely life away from the crowds of men. But Selkirk cannot find any joy in his loneliness. He feels that it is better to accept the troubles and anxieties of living in society than to rule that horrible land.

Selkirk cannot hope to return to mankind. He imagines that he must end his life on that lonely island. He is unable to hear the sweet speech of man. He is startled, surprised at his own voice. It seems strange to him as he hasn’t spoken to a man for a long long time. The animals never fear him as they do not know the strength of man. He says that friendship and love are the divine gifts given to a man who lives in society. He thinks if he had the wings of a dove he would cross the ocean and see the faces of his friends and relatives.

As a result, his sorrows and sufferings would be reduced and relaxed and he would spend his days happily following religion and truth. He might learn wise things from wise men and spend his days happily with the young. He is completely disheartened by his loneliness. He has addressed the winds to listen to him. He requests the winds to bring the good news of the place which he can never visit. He also appeals to the winds to convey his message to his near and dear ones whom he can never see. He wants to know if his friends remember and wish to see him. He feels that the movement of the mind is very swift and it visits the whole world in a moment.

The movement of the mind is more swift than the movement of wind and light. Whenever he thinks of his native land, he feels as if he is present there. But when he realizes his present position, his heart is filled with despair. At last, he thinks that it is unwise to think all these things as it brings unhappiness. The birds and beasts have taken rest in their respective resting places. So he feels it proper to have his rest. He hopes that God is omnipresent and sees the sorrows and sufferings of human beings. God will definitely remove his plight as He is very kind and merciful.

Notes:
sole – ଏକମାତ୍ର, right – ଅସ୍କାର monarch – ସମ୍ରାଟି, lonely – ନିର୍ଜନ, wise men – ବିଜ୍ଞ ଲୋକ, philosophers – ଦାର୍ଶନିକ, crowds – ଜନଗହଳି, troubles – ଜଞ୍ଜାଳ anxieties – ଆଶଙ୍କା, horrible – ଭୟଙ୍କର, imagines – କଳ୍ପନା କରେ, startled – ସ୍ତମ୍ଭିତ ହେଲା, strange – ଅଜଣା sorrows and sufferings – ଦୁଃଖ ଏବଂ ଯନ୍ତ୍ରଣା,
strength – ଶକ୍ତି, long long time – ବହୁକାଳ ଧରି, reduced – ହ୍ରାସ ହେଲା/ଅପସରି ଗଲା, disheartened – ହୃଦୟହରା ହେଲେ, loneliness – ନିର୍ଜନତା, addressed –ସମ୍ବୋଧନ କଲେ, clarify – ସ୍ପଷ୍ଟ କରିବା, doubts – ସନ୍ଦେହ, movement -ଗତି, swift – ଦ୍ରୁତ, realises – ହୃଦୟଙ୍ଗମ କରେ, despair – ନୈରାଶ୍ୟ, respective – ନିଜ ନିଜ, omnipresent –ସର୍ବବିଦ୍ୟମାନ, definitely – ନିଶ୍ଚିତ ଭାବରେ, remove – ଦୂର କରିବା, plight – ଦୁଃଖ, merciful – ଦୟାବନ୍ତ, appeal – ନିବେଦନ କରିବା.

ସାରାଂଶ :
କବିତାରେ ନାବିକ (ଆଲେକ୍‌ଜାଣ୍ଡର ସେଲ୍‌କାର୍କ) କହୁଛନ୍ତି ଯେ ସେ ହେଉଛନ୍ତି ସେହି ନିର୍ଜନ ଦ୍ଵୀପର ଅଧୀଶ୍ଵର ଏବଂ ସେହି ଅଧିକାର ଛଡ଼ାଇନେବା ପାଇଁ କେହି ତାଙ୍କ ସହିତ ସେଠାରେ ସଂଗ୍ରାମ କରିବ ନାହିଁ । ସେ ସେହି ଦ୍ଵୀପରେ ଥିବା ସମସ୍ତ ପଶୁପକ୍ଷୀଙ୍କର ମୁଖ୍ୟ ଶାସକ । ବିଦ୍ଵାନ୍‌ମାନେ କହନ୍ତି ଯେ ଜନଗହଳିଠାରୁ ଦୂରରେ, ନିର୍ଜନ ସ୍ଥାନରେ ରହିବାରେ ଏକ ପ୍ରକାର ଆନନ୍ଦ ମିଳିଥାଏ । ମାତ୍ର ସେଲ୍‌କାର୍କ ତାଙ୍କ ନିର୍ଜନତାରେ କୌଣସି ଆନନ୍ଦ ଉପଭୋଗ କରୁନାହାନ୍ତି । ସେ ଅନୁଭବ କରୁଛନ୍ତି ଯେ ସେଭଳି ଏକ ଭୟଙ୍କର ସ୍ଥାନରେ ରାଜତ୍ଵ କରିବା ଅପେକ୍ଷା ସଂସାରରେ ରହି ଦୁଃଖକଷ୍ଟକୁ ବରଣ କରିବା ବରଂ ଭଲ । ସେଲ୍‌କାର୍କ ମଣିଷ ସମାଜକୁ ଫେରିବା ଆଶା ରଖୁପାରୁ ନାହାନ୍ତି । ସେ ଭାବୁଛନ୍ତି ତାଙ୍କ ଜୀବନ ସେହି ଦ୍ବୀପରେ ଶେଷ ହୋଇଯିବ । ମଣିଷ କଣ୍ଠର ସୁମଧୁର ସ୍ୱର ସେ ଆଉ ଶୁଣିବାକୁ ପାଉନାହାନ୍ତି । ତେଣୁ ସେ ତାଙ୍କ ନିଜର ସ୍ବର ଶବ୍ଦ ଶୁଣି ଭୟଭୀତ ଓ ଆଶ୍ଚର୍ଯ୍ୟ ହୋଇଯାଉଛନ୍ତି । ଏହା ତାଙ୍କୁ ଅଦ୍ଭୁତ ଲାଗୁଛି କାରଣ ସେ ବହୁତ ଦିନ ଧରି ମଣିଷ ସହିତ କଥା ହୋଇନାହାନ୍ତି ।

ସେଠାରେ ପଶୁମାନେ ତାଙ୍କୁ ଆଦୌ ଭୟ କରୁନାହାନ୍ତି, ଯେହେତୁ ସେମାନେ ମଣିଷର ପ୍ରଭାବ ଓ ଶକ୍ତି ବିଷୟରେ ସଚେତନ ନୁହନ୍ତି । ସେ ଜାଣନ୍ତି ଯେ ବନ୍ଧୁତା ଓ ସ୍ନେହ ମତତା ଭଳି ସ୍ବର୍ଗୀୟ ଦାନକୁ ମଣିଷକୁ ଦିଆଯାଇଛି ଯିଏ କି ସମାଜରେ ବାସ କରୁଛି । ସେ ଭାବୁଛନ୍ତି ଯଦି ତାଙ୍କର ବିହଙ୍ଗର ପକ୍ଷ ଥାଆନ୍ତା, ତେବେ ସେ ମହାସାଗରକୁ ପାର ହୋଇ ତାଙ୍କର ବନ୍ଧୁ ଓ ପ୍ରିୟଜନମାନଙ୍କୁ ଦେଖିପାରନ୍ତେ । ଯାହାଫଳରେ ତାଙ୍କର ଦୁଃଖ କ୍ଳେଶ ଦୂର ହୋଇଯାଆନ୍ତା ଓ ସେ ସତ୍ୟପଥ ଅନୁସରଣ କରି ସୁଖରେ କାଳାତିପାତ କରିପାରନ୍ତେ । ସେ ସେଠାରେ ଜ୍ଞାନୀ ଲୋକମାନଙ୍କଠାରୁ ଉପଯୁକ୍ତ ଶିକ୍ଷାଲାଭ କରି, ଯୁବକମାନଙ୍କ ସହିତ ସୁଖରେ ଦିନ ଅତିବାହିତ କରନ୍ତେ । ନିଃସଙ୍ଗତା ହେତୁ ସେ ସମ୍ପୂର୍ଣ ହତାଶ ହୋଇପଡ଼ିଛନ୍ତି । ତେଣୁ ସେ ପବନକୁ ତାଙ୍କ କଥା ଶୁଣିବାକୁ କହୁଛନ୍ତି । ସେ ପବନକୁ ଅନୁରୋଧ କରୁଛନ୍ତି ଯେ ଯେଉଁ ସ୍ଥାନକୁ ସେ ଦେଖିପାରିବେ ନାହିଁ ସେହି ସ୍ଥାନର ସୁସମାଚାର ତାଙ୍କୁ ଆଣି ଦିଅନ୍ତୁ । ତାଙ୍କର ବାର୍ତ୍ତାକୁ ତାଙ୍କର ନିକଟତମ ଲୋକ, ଯେଉଁମାନଙ୍କୁ ସେ କଦାପି ଦେଖପାରିବେ ନାହିଁ, ସେହିମାନଙ୍କ ପାଖରେ ପହଞ୍ଚାଇବାପାଇଁ ପବନକୁ ନିବେଦନ କରୁଛନ୍ତି । ତାଙ୍କ ବନ୍ଧୁମାନେ ତାଙ୍କୁ ମନେ ପକାଉଛନ୍ତି କି ନାହିଁ ଓ ତାଙ୍କୁ ଦେଖିବାକୁ ଚାହୁଁଛନ୍ତି କି ନାହିଁ ସେ ଜାଣିବାକୁ ଚାହୁଁଛନ୍ତି ।

ସେ ଅନୁଭବ କରୁଛନ୍ତି ଯେ ମନର ଗତି ଅତି କ୍ଷିପ୍ର ଓ ଏହା ଗୋଟିଏ ମୁହୂର୍ତ୍ତରେ ସାରା ବିଶ୍ଵ ଭ୍ରମଣ କରିପାରିବ । ମଣିଷ ମନର ଗତି ଏପରିକି ପବନ ଓ ଆଲୋକଠାରୁ ମଧ୍ୟ ଦ୍ରୁତତର । ଯେତେବେଳେ ସେ ତାଙ୍କର ଜନ୍ମସ୍ଥାନ କଥା ଭାବନ୍ତି, ସେତେବେଳେ ସେ ଅନୁଭବ କରନ୍ତି ସତେ ଯେମିତି ସେ ସେହିଠାରେ ହିଁ ଉପସ୍ଥିତ ଅଛନ୍ତି । ମାତ୍ର ଯେତେବେଳେ ସେ ତାଙ୍କର ବର୍ତ୍ତମାନର ସ୍ଥିତି କଥା ହୃଦୟଙ୍ଗମ କରନ୍ତି, ତାଙ୍କ ହୃଦୟ ଗଭୀର ଦୁଃଖରେ ଭରପୂର ହୋଇଯାଏ । ଶେଷରେ ସେ ଚିନ୍ତା କରୁଛନ୍ତି ଯେ ଏସବୁ କଥା ଚିନ୍ତା କରିବା ଭୁଲ୍, କାରଣ ଏହା କେବଳ ଦୁଃଖ ଆଣିଦେବ । ଏବେ ସେ ଦେଖୁଛନ୍ତି ଯେ ପଶୁପକ୍ଷୀମାନେ ସେମାନଙ୍କର ବିଶ୍ରାମସ୍ଥଳୀରେ ବିଶ୍ରାମ ନେଲେଣି । ତେଣୁ ସେ ମଧ୍ୟ ତାଙ୍କ ସ୍ଥାନରେ ବିଶ୍ରାମ ନେବା ଉଚିତ ବୋଲି ମନେ କରୁଛନ୍ତି । ସେ ଆଶା କରୁଛନ୍ତି ଯେ ଈଶ୍ବର ସର୍ବବିଦିତ ଏବଂ ସେ ହିଁ ମଣିଷର ସବୁ ଦୁଃଖଯନ୍ତ୍ରଣା ଦେଖନ୍ତି । ଈଶ୍ଵର ତାଙ୍କ ଦୁର୍ଦ୍ଦଶାକୁ ନିଶ୍ଚୟ ଦୂର କରିବେ କାରଣ ସେ ହେଉଛନ୍ତି ଦୟାର ଅବତାର, ଏ ବିଶ୍ୱାସ ସେ ରଖୁଛନ୍ତି ।

BSE Odisha 9th Class English Solutions Chapter 10 Alexander Selkirk

The Text : (ପାଠ୍ୟବିଷୟ)
Stanzawise Analysis.

Stanza-1
I AM monarch of all I survey,
My right there is none to dispute,
From the centre all round to the sea
I am lord of the fowl and the brute.
O Solitude ! where are the charms
That sages have seen in thy face ?
Better dwell in the midst of alarms
Than reign in this horrible place.
ଅନୁବାଦ :
ମୁଁ ଯାହାସବୁ ଦେଖୁଛି, ସେସବୁର ମୁଁ ହେଉଛି ଅଧୀଶ୍ବର । ଏଠାରେ ମୋ ଅଧିକାରକୁ ଛଡ଼ାଇ ନେବାକୁ କେହି ମୋ ସହିତ ସଂଗ୍ରାମ ମଧ୍ଯ କରିବ ନାହିଁ । ମୋ ଚତୁଃପାର୍ଶ୍ଵରେ ନୀଳ ସାଗରଯାଏ ଏଠାରେ ଥିବା ସମସ୍ତ ପଶୁପକ୍ଷୀଙ୍କର ମୁଁ ହେଉଛି ଈଶ୍ବର । ବିଜନତାରେ ମୁନିଗଣ ଆନନ୍ଦ ଉପଲବ୍ଧି କରନ୍ତି; କିନ୍ତୁ ମୁଁ ପାଉ ନାହିଁ । ଯୁଦ୍ଧକ୍ଷେତ୍ରର ଭୟ ମଧ୍ଯରେ ବାସ କରିବା ବରଂ ଭଲ; କିନ୍ତୁ ଏପରି ଭୟଙ୍କର ସ୍ଥାନରେ ରାଜତ୍ଵ କରିବା ଠିକ୍ ନୁହେଁ ।

Stanza – 2
I am out of humanity’s reach,
I must finish my journey alone,
Never hear the sweet music of speech;
I start at the sound of my own.
The beasts that roam over the plain
My form with indifference see;
They are so unacquainted with man,
Their tameness is shocking to me.
ଅନୁବାଦ :
ମୁଁ ମାନବ ଜଗତଠାରୁ ଅଲଗା ହୋଇଯାଇଛି । ମୋର ଜୀବନଯାତ୍ରା ଏହିଠାରେ ହିଁ ଶେଷ ହୋଇଯିବ । ମଧୁମୟ ମନୁଷ୍ୟ କଣ୍ଠର ସ୍ଵର ଆଉ ଶୁଣିପାରିବି ନାହିଁ । ମୋ ନିଜ କଣ୍ଠର ସ୍ବର ଶୁଣି ମୁଁ ଚମକିପଡ଼େ । ଏଠାରେ ଯେଉଁ ପଶୁମାନେ ଭ୍ରମଣ କରୁଛନ୍ତି ସେମାନେ ମୋତେ ଆଦୌ ଭୟ କରୁନାହାନ୍ତି । ସେମାନେ ମଣିଷ ସହିତ ଏତେ ପରିଚିତ ନୁହନ୍ତି କିମ୍ବା ମଣିଷର ପ୍ରଭାବ ଜାଣନ୍ତି ନାହିଁ । ମୋତେ ସେମାନଙ୍କର ବଶତା ଦେଖି ଆଶ୍ଚର୍ଯ୍ୟ ଲାଗେ ।

Stanza-3
Society, friendship, and love
Divinely bestowed upon man,
O had I the wings of a dove.
How soon would I taste you again!
My sorrows I then might assuage
In the ways of religion and truth,
Might learn from the wisdom of age,
And be cheer’d by the sallies of youth.
ଅନୁବାଦ : ଈଶ୍ବର ସମାଜ, ବନ୍ଧୁତା ଓ ସ୍ନେହ ମମତାକୁ କେବଳ ମଣିଷକୁ ହିଁ ଦେଇଛନ୍ତି । ଯଦି ମୋର ଗୋଟିଏ କପୋତ ପରି ଡେଣା ଥାଆନ୍ତା ତେବେ ମୁଁ ଉଡ଼ିଯାଇ ମୋର ପ୍ରିୟଜନମାନଙ୍କୁ ଦେଖୁପାରନ୍ତି ଓ ମୋର ଦୁଃଖ ଦୂର ହୋଇଯାଆନ୍ତା । ମୁଁ ଧର୍ମ ଓ ସତ୍ୟ ପଥକୁ ଅନୁକରଣ କରନ୍ତି, ବିଦ୍ଵାନ୍ ଲୋକଙ୍କଠାରୁ ସଦୁପଦେଶ ଗ୍ରହଣ କରନ୍ତି ଏବଂ ତରୁଣମାନଙ୍କ ସଙ୍ଗରେ ହସଖୁସିରେ ସମୟ ଅତିବାହିତ ହୁଅନ୍ତା ।

BSE Odisha 9th Class English Solutions Chapter 10 Alexander Selkirk

Stanza-4
Ye winds that have made me your spot,
Convey to this desolate shore
Some cordial endearing report
Of a land I shall visit no more;
My friends, do they now and then send
A wish or a thought after me?
O tell me I yet have a friend,
Though a friend I am never to see.
ଅନୁବାଦ :
ରେ ବାୟୁ ! ତୁମେ ମୋତେ କ୍ରୀଡ଼ନକ କରିଦେଇଛ । ଯେଉଁ ସ୍ଥାନକୁ ମୁଁ ଆଉ ଦେଖିପାରିବି ନାହିଁ ସେହି ସ୍ଥାନର ସୁସମାଚାର ମୋତେ ଏହି ନିର୍ଜନ ତଟକୁ ଆଣିଦିଅ । ମୋତେ ମୋର ବନ୍ଧୁମାନେ ଦେଖିବାକୁ ଚାହୁଁଛନ୍ତି କି ? ସେମାନେ ମୋ କଥା ଭାବୁଛନ୍ତି କି ? ହେ ବାୟୁ, ମୋତେ କୁହ ମୋର କ’ଣ କେହି ବନ୍ଧୁ ନାହାନ୍ତି ? ମୁଁ କଦାପି ବନ୍ଧୁଙ୍କୁ ଦେଖୁପାରିବି ନାହିଁ । ମୋର ଏ ସନ୍ଦେହଗୁଡ଼ିକୁ ତୁମେ ଦୂର କର ।

Stanza -5
How fleet is a glance of the mind!
Compared with the speed of its flight,
The tempest itself lags behind,
And the swift-winged arrows of light.
When I think of my own native land
In a moment I seem to be thete;
But, alas! recollection at hand
Soon hurries me back to despair
ଅନୁବାଦ :
ମନର ଗତି କି କ୍ଷିପ୍ର ! ତୁଳନା କଲେ ଏହା ପବନ ଓ ଆଲୋକର ଗତିକୁ ପଛରେ ପକାଇ ଦେଇପାରିବ । ଗୋଟିଏ ମୁହୂର୍ତ୍ତରେ ଏହା ସାରା ବିଶ୍ବ ଦର୍ଶନ କରିପାରିବ । ଯେତେବେଳେ ମୋର ନିଜ ଦେଶ କଥା ମନେପଡ଼େ ସେତେବେଳେ ମୁଁ ଭାବେ ସତେ ଯେପରି ମୁଁ ସେହିଠାରେ ଅଛି । କିନ୍ତୁ ଦୁଃଖର କଥା ଯେତେବେଳେ ମୋ ସ୍ମରଣକୁ ଆସେ, ମୁଁ ଦ୍ବୀପରେ ଅଛି ତାହା ମୋତେ ନୈରାଶ୍ୟରେ ବୁଡ଼ାଇ ଦିଏ ।

Stanza -6
But the seafowl is gone to her nest
The beast is laid down in his lair;
Even here is a season of rest,
And I to my cabin repair
There is mercy in every place,
And mercy, encouraging thought!
Gives even affliction a grace
And reconciles man to his lot.
ଅନୁବାଦ :
ସାମୁଦ୍ରିକ ପକ୍ଷୀ ତା’ର ବସାଘରେ ବିଶ୍ରାମ ନେଇଛି ଓ ପଶୁ ତା’ର ଗହ୍ଵରରେ ଆଶ୍ରୟ ନେଇଛି । ବର୍ତ୍ତମାନ ବିଶ୍ରାମର ସମୟ ଏବଂ ମୁଁ ମଧ୍ୟ ମୋ ସ୍ଥାନରେ ବିଶ୍ରାମ ନେବା ବାଞ୍ଛନୀୟ । ଈଶ୍ବର କରୁଣାମୟ ଓ ଦୟାର ଅବତାର, ସେ ନିଶ୍ଚୟ ତାଙ୍କ ଦୁଃଖ ଦୂର କରିବେ ଏବଂ ସେ ସନ୍ତୋଷ ଲାଭ କରିବେ ।

BSE Odisha 9th Class English Solutions Chapter 10 Alexander Selkirk

About the poet:
William Cowper (1731 AD to 1800 AD) was born at Great Berkharnpstead, in Hertfordshire, where his father was a rector. His poems were published late in life. At the very end of his volume of poems, a few miscellaneous short poems were also included. One of them is the well-known poem containing the reflections of Alexander Selkirk. The poem reflects the freedom of his spirit on a lonely island.

Notes :
rector – ଧର୍ମ ପ୍ରତିଷ୍ଠାନର ଅଧ୍ୟକ୍ଷ, published – ପ୍ରକାଶିତ ହେଲା, miscellaneous – ନାନାପ୍ରକାର/ମିଶ୍ରିତ, reflects – ପ୍ରତିଫଳିତ କରେ, spirit – ଆତ୍ମା

କବିଙ୍କ ସମ୍ପର୍କରେ :
ଉଇଲିୟମ୍ କାଉପର୍ (୧୭୩୧ ଖ୍ରୀ.ଅ.ରୁ ୧୮୦୦ ଖ୍ରୀ.ଅ.) ହର୍ଟଫୋର୍ଡସାୟାରର ଗ୍ରେଟ୍ ବର୍କହାମ୍ପଷ୍ଟ୍ରେଡ୍‌ରେ ଜନ୍ମଗ୍ରହଣ କରିଥିଲେ ଯେଉଁଠାରେ କି ତାଙ୍କ ପିତା ଏକ ଧର୍ମାନୁଷ୍ଠାନର ମୁଖ୍ୟ ଥିଲେ । ତାଙ୍କ କବିତାଗୁଡ଼ିକ ଜୀବନର ଉତ୍ତର ପର୍ଯ୍ୟାୟରେ ପ୍ରକାଶିତ ହୋଇଥିଲା । ତାଙ୍କ କବିତା ସଂକଳନର ଠିକ୍ ଶେଷ ଭାଗରେ କେତେକ କ୍ଷୁଦ୍ର କବିତା ଯୋଗ କରାଯାଇଥିଲା । ଆଲେକ୍‌ଜାଣ୍ଡର୍ ସେଲ୍‌କାର୍କଙ୍କ ହୃଦୟର ପ୍ରତିଫଳନକୁ ଆଧାର କରି ରଚିତ କବିତା ସେଗୁଡ଼ିକ ମଧ୍ୟରେ ଅନ୍ୟତମ । କବିତାଟି ନିର୍ଜନ ଦ୍ଵୀପରେ ତାଙ୍କ ଆଲେକ୍‌ଜାଣ୍ଡର୍ ଆତ୍ମାର ସ୍ବାଧୀନ ଚିନ୍ତାକୁ ପ୍ରତିଫଳିତ କରେ ।

BSE Odisha 9th Class English Solutions Chapter 10 Alexander Selkirk

Glossary And Notes: (ଟିପ୍‌ପଣୀ ଓ କଠିନ ଶବ୍ଦାର୍ଥ)
(Lines— 1 to 8)

I AM — Here ‘AM’ is written in capital letters to emphasize the poet’s feeling of confidence in his new role as the sole monarch of the lonely island— ମୁଁ ସ୍ବୟଂ
monarch (n) — supreme ruler – ସର୍ବୋଚ୍ଚ ଶାସକ
Alexander Selkirk considered him the monarch of the island.
survey (V) — see – ଦେଖୁ
We surveyed the view from the top of the hill.
right (n) — claim, possession — ଅଧିକାର
dispute (v) — argue or quarrel — କଳହ କରିବା
The question was hotly disputed in the Parliament.
fowl (n) — bird — ପକ୍ଷୀ
A large number of fowls are seen in Chilika in winter.
brute (n) — animal – ପଶୁ
It’s not easy to tame the brutes.
solitude (n) — loneliness, lonely place
The sages find pleasure in solitude.
thy (old use) — your — ତୁମର
charm (n) — delight, pleasure — ଆନନ୍ଦ
Lord — supreme commander — ସର୍ବୋଚ୍ଚ କମାଣ୍ଡର
sage (n) — hennit, saint – ମୁନି/ଋଷି
dwell (v) — live — ବାସ କରିବା
The hermits used to dwell in cottages.
alarms (n) — danger — ଭୟ|ଯୁଦ୍ଧସଜ୍ଜାର ଆହ୍ଵାନ
Nobody likes o live in alarms.
reign (v) — rule — ରାଜତ୍ଵ କରିବା
The reign of Ashok is an epoch-making era in the animals of history.
horrible (adj)— full of danger — ଭୟଙ୍କର

(Lines—9to 16)
out of humanity reach — no hope of people o touch it, isolated
finish (v) — complete/end — ସମ୍ପୂର୍ଣ୍ଣ କରିବା
my journey (n) — here journey of life — ଏଠାରେ ଜୀବନଯାତ୍ରା
alone — by himself — ଏକଟିଆ
start at (v) — frighten/startled/surprised — ଆଶ୍ଚର୍ୟ୍ୟ
roam (v) — to wan&r with no very Clear purpose — ଏଣେତେଣେ ମୁକ୍ତ ରୂପେ
The animal’s roar in the forest.
with indifference —lack of interestiindifferently — ଉଦାସୀନ ଭାବରେ
The girl looked at her teacher with indifférence.
my form — my body — ମୋ ଶରୀର
beasts — wild animals — ବନ୍ୟପଶୁ
unacquainted (adj.) — unknown — ଅଜ୍ଞାତ
We’re unacquainted with each other.
tameness (n) — loyalty
I was surprised to see the tameness of the animals at a circus party,
shucking — terrifying, frightening
The news was shocking later.

BSE Odisha 9th Class English Solutions Chapter 10 Alexander Selkirk

(Lines— 17 to 24)
divinely (adj) — heavenly — ସ୍ୱର୍ଗୀୟ
bestow (v) — pour/give as an offering
Semi-gifts were bestowed on the royal visitors.
assuage (v) — make suffering less painful — ଯନ୍ତ୍ରଣା ଲାଘବ କରିବା
He prayed to God to assuage his Sorrows.
be cheer’d — be detighted — ବହୁତ ଖୁସି ହେବା
the wisdom of age — wise sayings of the old people — ବବୃଦ୍ଧ ଲୋକମାନଙ୍କର ବୁଦ୍ଧିମାନ କଥା
sallies (n) — lively or humorous remarks — ଜୀବନ୍ତ ବା ହାସ୍ୟାସ୍ପଦ ମନ୍ତବ୍ୟ |
Her witty sallies made me angry.
dove — a kind of bird — ଏକ ପ୍ରକାର ପକ୍ଷୀ

(lines— 25 to 32)
convey (v) — to inform — ସୂଚନା ଦେବାକୁ
He conveyed his difficulties to his father
taste — meet — ବିଚ୍ଛିନ୍ନ
desolate (adj.) — isolated — ବିଚ୍ଛିନ୍ନ
Nobody likes to live in a desolate place.
cordial — friendly – ବନ୍ଧୁତ୍ଵପୂର୍ଣ୍ଣ
endearing (adj.) — pleasant — ସୁଖଦ
He always expects endearing news from his parents.
report — news —ସମ୍ବାଦ
now and then — frequently — ବାରମ୍ବାର
Uncle comes to our house now and then.

(Lines — 33 to 40)
fled — quick — ଦ୍ରୁତ
A deer is allen footed runner.
tempest (n) – violent storm – ଝଡ଼ ତୋଫାନ
The ship sank due to the tempest.
glance – quick look – ତୀକ୍ଷ୍ଣ ଚାହାଣି
recollection (n) — what is remembered at present / memory – ସ୍ମୃତି | ସ୍ମରଣ
I have no recollection of meeting him.
despair (n) – without hope — ଭରସା ବିନା
His past recollection hurried him back to despair.
swift — winged arrows of light — ତୀବ୍ର ବେଗଗାମୀ ପକ୍ଷ/ ଡେଣା (ଆଲୋକର )
native land — land of birth/motherland — ଜନ୍ମଭୂମି
in a moment — a short period of time, instantly — ତତକ୍ଷଣାତ୍
Wait here! I will be back in a moment.
alas! — sudden emotion of sorrow or grief — ଆହା ! ! (ଏକ ଦୁଃଖଦାୟକ ଅଭିବ୍ଯକ୍ତି)

BSE Odisha 9th Class English Solutions Chapter 10 Alexander Selkirk

(Unes—41 to 48)
seafowl(n) — seabird —ସାମୁଦ୍ରିକ ପକ୍ଷୀ
A sea-fowl is flying over the sea.
lair (n) — wild animals resting place
The animals are taking a rest in their lairs.
repair (v) — to return
mercy (n) — blessing/kindness — ଦୟା
The gene showed no mercy and killed all the enemies.
affliction (n) pain/distress — ଯନ୍ତ୍ରଣା
The affliction of old age is unbearable.
reconcile (v) — bring into harmony — ପ୍ରତିଷ୍ଠା କରିବା | ଶାନ୍ତି କରିବା
How do you reconcile your political principles with your religious beliefs?
at hand — at present/now — ବର୍ତ୍ତମାନ୍
cabin — small room (living) — ଛୋଟ କୋଠରୀ
lot — fate/fortune— ଭାଗ୍ୟ
He has a good lot.
season — time — ସମୟ
encouraging — inspiring/motivating — ଉତ୍ସାହିତ କରିବା
grace (n) — blessings — ଅନୁଗ୍ରହ

CHSE Odisha Class 11 Math Solutions Chapter 8 Permutations and Combinations Ex 8(a)

Odisha State Board Elements of Mathematics Class 11 Solutions CHSE Odisha Chapter 8 Permutations and Combinations Ex 8(a) Textbook Exercise Questions and Answers.

CHSE Odisha Class 11 Math Solutions Chapter 8 Permutations and Combinations Exercise 8(a)

Question 1.
What is the total number of functions that can be defined from the set {1, 2} to the set {1, 2, 3}?
Solution:
The total number of functions that can be defined from the set {1, 2} to the set {1, 2, 3} is 32 = 9.

Question 2.
A die of six faces marked with the integers 1, 2, 3, 4, 5, and 6 one on each face is thrown twice in succession, what is the total number of outcomes thus obtained?
Solution:
A die of six faces marked with the integers 1, 2, 3, 4, 5, and 6 one on each face, is thrown twice in succession.
∴ The total number of outcomes is 62 = 36.

Question 3.
Five cities A, B, C, D, and E are connected to each other by straight roads. What is the total number of such roads?
Solution:
Five cities A, B, C, D, and E are connected to each other by straight roads.
∴ The number of such roads is \(\frac{{ }^5 \mathrm{P}_2}{2 !}\) = 10

Question 4.
What is the total number of different diagonals of a given pentagon?
Solution:
The total number of different diagonals of a given pentagon is
\(\frac{{ }^5 \mathrm{P}_2}{2 !}\) – 5 = 10 – 5 = 5

Question 5.
There are two routes joining city A to city B and three routes joining B to city C. In how many ways can a person perform a journey from A to C?
Solution:
There are two routes joining city A to city B and three routes joining B to city C.
∴ By the fundamental principle of counting, the total number of journeys in which a person can perform from A to C is 2 × 3 = 6.

CHSE Odisha Class 11 Math Solutions Chapter 8 Permutations and Combinations Ex 8(a)

Question 6.
How many different four-lettered words can be formed by using the four letters a, b, c, and d, while the letters can be repeated?
Solution:
The number of different words that can be formed by using the four letters a, b, c, and d, while the letters can be repeated is 44 = 256.

Question 7.
What is the sum of all three-digit numbers formed by using the digits 1, 2, and 3?
Solution:
The 3-digit numbers that can be formed by using the digits 1, 2, and 3 are 123, 132, 213, 231, 312, and 321.
∴ Their sum = 1332.

Question 8.
How many different words with two letters can be formed by using the letters of the word JUNGLE, each containing one vowel and one consonant?
Solution:
The word ‘Jungle’ contains 2 vowels and 4 consonants. Each word contains one vowel and one consonant.
The number of different words formed.
2 × 4P1 × 2P1 = 2 × 4 × 2 = 16

Question 9.
There are four doors leading to the inside of a cinema hall. In how many ways can a person enter into it and come out?
Solution:
There are four doors leading to the inside of a cinema hall. A person can enter into it and come out in 42 = 16 different ways. (By the principle of counting.)

BSE Odisha 10th Class Hindi Solutions Poem 1(b) सूरदास के पद

Odisha State Board BSE Odisha 10th Class Hindi Solutions Poem 1(b) सूरदास के पद Textbook Exercise Questions and Answers.

BSE Odisha Class 10 Hindi Solutions Poem 1(b) सूरदास के पद

प्रश्न और अभ्यास (ପ୍ରଶ୍ନ ଔର୍ ଅଭ୍ୟାସ)

1. निम्नलिखित प्रश्नों के उत्तर दो-तीन वाक्यों में दीजिए।
(ନିମ୍ନଲିଖ ପ୍ରଶ୍ନଗୁଡ଼ିକର ଉତ୍ତର ଦୁଇ-ତିନି ବାକ୍ୟରେ ଦିଅ ।)

(क) कृष्ण यशोदा से क्या शिकायत करते है और क्यों?
(କୃଷ୍ଣ ଯଶୋଦା ସେ କ୍ୟା ଶିକାୟତ୍ କରନେ ହୈ ଔର୍ କେଁ ?)
उत्तर:
कृष्ण यशोदा से यह शिकायत करते हैं कि- माँ! मुझे बलराम भैया चिढ़ाते हैं। वे कहते हैं कि मैं खरीद कर लाया गया हुँ। जसुमति ने तुम्हें जन्म नहीं दिया है। इसलिए मैं उनके साथ खेलने नहीं जाता।

(ख) बलराम कृष्ण से क्या पूछते हैं?
(ବଳରାମ କୃଷ୍ଣ ସେ କ୍ୟା ପୁଛତେ ହୈ ?)
उत्तर:
बलराम कृष्ण से पूछते हैं कि – कौन तेरे माता पिता हैं? नंद गोरे हैं और यशोदा गोरी हैं, क्यों काला है?

(ग) यशोदा किसकी कसम खाती हैं और क्या कहती हैं?
(ଯଶୋଦା କିସ୍‌ କସମ୍ ଖାତୀ ହୈ ଔର୍ କ୍ୟା କହତୀ ହୈ ?)
उत्तर:
यशोदा गोधन की कसम खाती हैं और कहती हैं कि ‘मैं तेरी माता हूँ और तू मेरा पुत्र है। यह बलराम चुगलखोर है और जन्म से शरारती है।

(घ) चुटकी देकर ग्वाल-बालक क्यों नाचते हैं?
(ଚୁଟକୀ ଦେକର୍ ଗ୍ୱାଲା-ବାଳକ ଜ୍ୟୋ ନା ହେଁ ?)
उत्तर:
कृष्ण को बलराम के कहने पर कि नंद गोरे हैं, यशोदा गोरी हैं मगर तू काला क्यों है? तुझे माता यशोदा ने खरीद कर लाया है। यही सब बातें सुनकर कृष्ण को चिढ़ाने के लिए ग्वाल बालक चुटकी बजाकर नाचते हैं।

BSE Odisha 10th Class Hindi Solutions Poem 1(b) सूरदास के पद

2. निम्नलिखित पदों के अर्थ दो-तीन वाक्यों में स्पष्ट कीजिए:
(ନିମ୍ନଲିଖତ୍ ପଦୌ କେ ଅର୍ଥ ଦୋ-ତୀନ୍ ୱାର୍କୋ ମେଁ ସ୍ପଷ୍ଟ କୀଜିଏ: )
(ନିମ୍ନଲିଖ୍ ପଦଗୁଡ଼ିକରେ ଅର୍ଥ ଦୁଇ-ତିନି ବାକ୍ୟରେ ସ୍ପଷ୍ଟ କର: )

(क) पुनि-पुनि कहत कौन है माता, कौन है तुमरो तात।
(ପୁନି-ପୁନି କହତ କୌନ୍ ହୈ ମାତା, କୌନ୍ ହୈ ତୁମରେ ତାତ ।)
उत्तर:
कृष्ण की बाललीला का वर्णन करते हुए कवि ने उसका सुंदर वर्णन किया है। कृष्ण बलराम चिढ़ाने के लिए बारबार कहते हैं कि तुम्हारी माता कौन हैं और पिता कौन हैं? तुम बाबानंद और माता यशोदा के पुत्र नहीं हो। तुम्हें माता यशोदा ने खरीद कर लाया है।

(ख) सूर स्याम मोहि गोधन की सौं हौं माता तू पूत।
(ସୂର୍ ଶ୍ୟାମ ମୋହି ଗୋଧନ କୀ ସୌ ହେଁ ମାତା ତୂ ପୂତ ।)
उत्तर:
जब बालक कृष्ण के मुख पर यशोदा गुस्सा देखती है और कृष्ण के मुख से गुस्सैली वाणी सुनती हैं तो वह प्रसन्न हो जाती हैं। फिर कृष्ण से कहती हैं कि बलराम चुगलखोर है और शरारती है। वह गोधन की कसम खाकर कहती हैं कि कृष्ण ही उनका पुत्र है और वह कृष्ण की माता है।

(ग) तनक – तनक चरननि सौं, नाचत, मनहिं मनहिं रिझावत।
(ନିମ୍ନଲିଖ୍ ପଦଗୁଡ଼ିକରେ ଅର୍ଥ ଦୁଇ-ତିନି ବାକ୍ୟରେ ସ୍ପଷ୍ଟ କର: )
उत्तर:
इस पंक्ति में कवि ने कहा है कि कृष्ण अपने आप कुछ गा रहे हैं। वे गाते-गाते अपने नन्हे चरणों से नाचते हैं और मन-ही-मन खुश हो रहे हैं।

(घ) कबहुँ चितै प्रतिबिम्ब खंभ में, लौनी – लिए खबावत।
(କବହୁ ଚିତୈ ପ୍ରତିବିମ୍ବ ଖମ୍ବ ମେଁ, ଲୌନୀ-ଲିଏ ଖବାୱତ୍।)
उत्तर:
बालक कृष्ण घर के भीतर जाकर थोड़ा मक्खन हाथ में लेकर खाते हैं और कुछ मक्खन अपने मुँह पर भी लगा देते हैं। कभी खम्भे में अपना प्रतिबिंब देखकर उसे भी कुछ मक्खन खिलाते हैं।

BSE Odisha 10th Class Hindi Solutions Poem 1(b) सूरदास के पद

3. निम्नलिखित प्रश्नों के उत्तर एक-एक वाक्य में दीजिए।
(ନିମ୍ନଲିଖୂ ପ୍ରଶ୍ନ କେ ଉତ୍ତର୍ ଏକ୍- ଏକ୍ ୱାକ୍ୟ ମେଁ ଦୀଜିଏ । (ନିମ୍ନଲିଖ ପ୍ରଶ୍ନଗୁଡ଼ିକର ଉତ୍ତର ଗୋଟିଏ-ଗୋଟିଏ ବାକ୍ୟରେ ଦିଅ ।)

(क) बाललीला (पद) के रचयिता कौन हैं?
(ବାଳଲୀଳା (ପଦ) କେ ରଚୟିତା କୌନ୍ ହୈ ।)
उत्तर:
बाललीला (पद) के रचयिता सूरदास हैं।

(ख) कौन कहते हैं कि तुझे मोलकर लाया गया है?
(କୌନ୍ କହତେ ହୈ କି ତୁଝେ ମୋଲ କର ଲାୟା ଗୟା ହୈ?)
उत्तर:
बलराम कहते हैं कि तुम्हें मोल कर लाया गया है।

(ग) बलराम पुनः पुनः क्या कहते हैं?
(ବଳରାମ ପୁନଃ ପୁନଃ କ୍ୟା କହତେ ହୈ ?)
उत्तर:
बलराम पुनः पुनः कहते हैं कि कौन तुम्हारी माता हैं और कौन तुम्हारे पिता हैं।

(घ) ग्वाल बालक किस तरह हँसते हैं?
(ସ୍ଵାଲେ ବାଳକ କିସ୍ ତରହ ହଁସତେ ହେଁ ?)
उत्तर:
ग्वाल बालक चुटकी बजाकर नाचते हैं और हँसते हैं।

(ङ) माँ यशोदा ने किसे मारना सिखा है?
(ମାଁ ଯଶୋଦା ନେ କିସେ ମାର୍‌ନା ସିଖା ହୈ ?)
उत्तर:
माँ यशोदा ने कान्हा को मारना सीखा है।

(च) कौन दाऊ पर नहीं खीझती है?
(କୌନ୍ ଦାଊ ପର ନହୀ ଶୀଝାତୀ ହୈ ?)
उत्तर:
माता यशोदा दाऊ पर नहीं खीझती हैं।

(छ) स्याम शरीर का अर्थ क्या है?
(ଶ୍ୟାମ୍ ଶରୀର କା ଅର୍ଥ କ୍ୟା ହୈ ?)
उत्तर:
स्याम शरीर का अर्थ है ‘काला शरीर’ या श्याम मरंग का शरीर।

(ज) ‘जनमत ही को धूत’ का अर्थ क्या है?
(‘ଜନମତ୍‌ ହୀ କୋ ଧୂତ୍’ କା ଅର୍ଥ କ୍ୟା ହୈ ?)
उत्तर:
‘जनमत ही को धूत’ का अर्थ है जन्म से शरारती।

(झ) माँ यशोदा किसकी सौगंध खाती हैं?
(ମାଁ ଯଶୋଦା କିସ୍‌ ସୌଗନ୍ଧା ଖାତି ହେଁ ?)
उत्तर:
माँ याशोदा गोधन की सौगंध खाती हैं।

(अ) कृष्ण किसे माखन खिलाते हैं?
(ମାଁ ଯଶୋଦା କିସ୍‌ ସୌଗନ୍ଧା ଖାତି ହେଁ ?)
उत्तर:
कृष्ण खंभे में अपने प्रतिबिंब को देखकर उसे माखन खिलाते हैं।

(ट) यशोमति क्या देखकर हर्षित हो जाती हैं?
(ଯଶୋମତି କ୍ୟା ଦେଖ୍କର୍ ହର୍ଷିତ୍ ହୋ ଜାତୀ ହୈ ?)
उत्तर:
यशोमती कृष्ण की बाललीला को देखकर हर्षित हो जाती हैं।

भाषा-ज्ञान (ଭାଷା-ଜ୍ଞାନ)

प्रश्न 1.
निम्नलिखित शब्दों के तत्सम रूप लिखिए:
(ନିମ୍ନଲିଖ୍ ଶବ୍ଦଗୁଡ଼ିକର ତତ୍‌ସମ ରୂପ ଲେଖ)
मोल, सौं, पूत, तनक, धूत, बाँह, मैया, खिझायो, गैयनि, कजरी
उत्तर:
मोल – मूल्य
पूत – पुत्र
धूत – दुष्ट
मैया – माता
गैयनि – गौ
सौं – शपथ
तनक – क्षुद्र
बाँह – हस्त
खिझायो – उपहास
कजरी – श्याम

प्रश्न  2.
निम्नलिखित शब्दों के समानार्थी शब्द लिखिए :
(ନିମ୍ନଲିଖ୍ ଶବ୍ଦଗୁଡ଼ିକର ସମାନାର୍ଥୀ ଶବ୍ଦ ଲେଖ ।)
नित, चरन, कर, बाँह, रिस, तात, जात, बदन, स्याम, धूत, सौं, पूत, शरीर, खीझें, चबाई
उत्तर:
नित – हमेशा/सदैव
चरन – पैर / पाँव
कर – हाथ
बाँह – हाथ
रिस – गुस्सा
तात – पिता
जात – जन्म
बदन – मुँह / चेहरा
स्याम – काला
धूत – धूर्त / शरारती / दुष्ट
सौं – सौगंध/शपथ/कसम
पूत – पुत्र/तनय/बेटा
शरीर – काया/देह
खीझे – गुस्सा
चबाई – चुगलखोर/निंदक

Very Short & Objective type Questions with Answers

A. निम्नलिखित प्रश्नों के उत्तर एक वाक्य में दीजिए।

प्रश्न  1.
भक्तिकाल के सर्वश्रेष्ठ कृष्ण-भक्त कवि किसे माना जाता है?
उत्तर:
भक्तिकाल के सर्बश्रेष्ठ कृष्ण-भक्त कवि सूरदास को माना जाता है।

प्रश्न  2.
सूरदास की प्रमुख प्रामाणिक रचन क्या है?
उत्तर:
सूरदास के प्रमुख प्रामाणिक रचना ‘सूरसागर’ अमूल्य निधि है।

प्रश्न  3.
सूरदास के गुरु कौन थे?
उत्तर:
सूरदास के गुरु बल्लभायार्य थे।

प्रश्न 4.
यशोमति क्या देखकर हर्षित हो जाति है?
उत्तर:
यशोमति कृष्ण की बाललीला को देखकर हर्षित हो जाती है ।

BSE Odisha 10th Class Hindi Solutions Poem 1(b) सूरदास के पद

प्रश्न  5.
‘जनमत ही को धूत’ का अर्थ क्या है?
उत्तर:
‘जनमत ही को धूत’ का अर्थ है जन्म से शरारती।

प्रश्न  6.
श्रीकृष्ण अपने छोटे-छोटे पैरों से क्या करते हैं?
उत्तर:
श्रीकृष्ण अपने छोटे-छोटे पैरों से नाचते हैं।

प्रश्न  7.
श्रीकृष्ण बाँहें उठाकर क्या करते हैं?
उत्तर:
श्रीकृष्ण बाँहें उठाकर कजरी और धौली गायों को बुलाते हैं।

B. निम्नलिखित प्रश्नों के उत्तर एक शब्द/एक पद में दीजिए।

प्रश्न  1.
कौन कान्हा को बहुत खिझाता है?
उत्तर:
दाऊ

प्रश्न  2.
दाऊ के खिझाने से कान्हा के नाराज होने पर माँ क्या कहकर समझाती है?
उत्तर:
मैं माता तू पुत्र

प्रश्न  3.
कान्हा क्यों खेलने नहीं जाते?
उत्तर:
रिस के मारे

प्रश्न  4.
दाऊ किसको खिझाते हैं?
उत्तर:
कृष्ण को

प्रश्न  5.
यशोदा कृष्ण मुँह से क्या सुनकर खुश हो जाती हैं?
उत्तर:
शिकायत

प्रश्न  6.
ग्वाले किस तरह हँसते हैं?
उत्तर:
चुटकी बजाकर

BSE Odisha 10th Class Hindi Solutions Poem 1(b) सूरदास के पद

प्रश्न  7.
यशोमती क्या देखकर हर्षित हो जाती हैं?
उत्तर:
कृष्ण की बाललीला

प्रश्न  8.
माता यशोदा किसकी सौगंध खाती हैं?
उत्तर:
गोधन को

प्रश्न  9.
जो चुटकी बजाकर नाचते हैं, वे कौन हैं?
उत्तर:
ग्वाले

प्रश्न 10.
कौन जन्म से धूर्त हैं?
उत्तर:
बलभद्र

प्रश्न  11.
‘लौनी’ शब्द का अर्थ क्या है?
उत्तर:
मक्खन

C. रिक्त स्थानों की पूर्ति कीजिए।

प्रश्न 1.
…………………. दाऊ पर नहीं खीझती है।
उत्तर:
यशोदा

प्रश्न 2.
बालकृष्ण के हाथ में ………………… है।
उत्तर:
मक्खन

प्रश्न 3.
कृष्ण खंभे में ……………….. देखते हैं।
उत्तर:
प्रतिविम्ब

प्रश्न 4.
बाल कृष्ण ………………. हाथ उठाकर बुलाते हैं
उत्तर:
गायों को

BSE Odisha 10th Class Hindi Solutions Poem 1(b) सूरदास के पद

प्रश्न 5.
………………. अपने आँगन में नाचते-गाते हैं।
उत्तर:
कृष्ण

प्रश्न 6.
कृष्ण ……………… माखन खिलाते हैं।
उत्तर:
प्रतिबिंब को

प्रश्न 7.
मैया मोहि दाउ बहुत दाउ बहुत खिझायो – इस पंक्ति में मोहि पद ……………….. के लिए प्रयोग हुआ है।
उत्तर:
कृष्ण

प्रश्न 8.
कृष्ण खलते समय अपने बदन पर ………………….. लगाते है।
उत्तर:
माखन

प्रश्न 9.
………………….. अपने आँगन में कछु गावत।
उत्तर:
हरी

BSE Odisha 10th Class Hindi Solutions Poem 1(b) सूरदास के पद

प्रश्न 10.
ग्वाले बालक ………………… बजाकर हँसते हैं।
उत्तर:
चुटकी

प्रश्न 11.
दूरी देखति …………………. यह लीला।
उत्तर:
जसुमति

D. ठिक् या भूल लिखिए।

प्रश्न 1.
सूरदास के गुरु वल्लभाचार्य थे।
उत्तर:
ठिक्

प्रश्न 2.
बलराम कहते हैं कि ‘दाउहि कबहुँ न खीझै ‘?
उत्तर:
भूल

प्रश्न 3.
बलराम शरीर का रंग श्याम है
उत्तर:
भूल

प्रश्न 4.
यशोदा गोधन की कसम खाती हैं।
उत्तर:
ठिक्

प्रश्न 5.
माता यशोदा गोपियों को मारना सीखा है।
उत्तर:
भूल

BSE Odisha 10th Class Hindi Solutions Poem 1(b) सूरदास के पद

प्रश्न 6.
मोहन की गुस्सैल वाणी सुनकर यशोमती प्रसन्न हो जाती है।
उत्तर:
ठिक्

प्रश्न 7.
‘गोरे नंद यशोदा गोरी, तू कत स्याम शरीर’ – इस पंक्ति के रचयिता कबीरदास हैं।
उत्तर:
भूल

प्रश्न 8.
कृष्ण बीमारी के कारण खेलने नहीं जाते।
उत्तर:
भूल

प्रश्न 9.
वलराम जन्म से चुगलखोर है।
उत्तर:
ठिक्

प्रश्न 10.
कृष्ण कजरी धौरी गायों को बुलाते हैं।
उत्तर:
ठिक्

प्रश्न 11.
कृष्ण बाँह उठाकर नंद बाबा को बुलाते हैं।
उत्तर:
भूल

Multiple Choice Questions (mcqs) with Answers

सही उत्तर चुनिए : (MCQs)

1. कौन कान्हा को बहुत खिझाता है?
(A) दाऊ
(B) नन्द
(C) यशोदा
(D) ग्वाल बाल
उत्तर:
(A) दाऊ

2. दाऊ के खिझाने से कान्ह के नाराज होने पर माँ क्या कहकर समझाती है?
(A) बलभद्र मेरा पुत्र नहीं है
(B) मैं माता तू पुत्र
(C) मैं बहुत खुश हूँ
(D) तू नाराज न हो
उत्तर:
(B) मैं माता तू पुत्र

3. कान्ह क्यों खेलने नहीं जाते?
(A) दुःख के मारे
(B) रिस के मारे
(C) खुसी के मारे
(D) डर के मारे
उत्तर:
(B) रिस के मारे

4. दाऊ किसको खिझातें हैं?
(A) कृष्ण को
(B) ग्वालों को
(C) गोपियों को
(D) माता यशोदा को
उत्तर:
(A) कृष्ण को

5. यशोदा कृष्ण के मुँह से क्या सुनकर खुश हो जाती हैं?
(A) शिकायत
(B)खेलने न जाने की बात
(C) क्रोधपूर्ण बातें
(D) बलराम के चिढ़ाने की बात
उत्तर:
(A) शिकायत

BSE Odisha 10th Class Hindi Solutions Poem 1(b) सूरदास के पद

6. बाललीला (पद) के रचयिता कौन हैं?
(A) रामदास
(B) हरीदास
(C) सूरदास
(D) भक्तदास
उत्तर:
(C) सूरदास

7. वाले किस तरह हँसते हैं?
(A) चुटकी बजाकर
(B) गाना गाकर
(C) माखन खाकर
(D) तालियाँ बजाकर
उत्तर:
(A) चुटकी बजाकर

8. कौन दाऊ पर नहीं खीझती है?
(A) कृष्ण
(B) बलराम
(C) यशोदा
(D) बिजली कन्या
उत्तर:
(C) यशोदा

9. सूरदास के गुरु कौन थे?
(A) रामानन्द सागर
(B) वल्लभाचार्य
(C) रामकृष्ण परमहंस
(D) विवेकानन्द
उत्तर:
(B) वल्लभाचार्य

10. यशोमती क्या देखकर हर्षित हो जाती हैं?
(A) कृष्ण की बाललीला
(B) अर्जुन की विश्वरुप
(C) कृष्ण की गोपलीला
(D) बिजली कन्या के जन्म
उत्तर:
(A) कृष्ण की बाललीला

पद: (ପଦ)

1. मैया मोहि दाऊ बहुत खिझायो।
मोसों कहत मोल को लीन्हों, तू जसुमति कब जायो॥
कहा कहौं एही रिस के मारे, खेलन हौं नहीं जात।
पुनि-पुनि कहत कौन है माता, कौन है तुमरो तात॥
गोरे नन्द, जसोदा गोरी, तू कत स्याम सरीर।
चुटकी दै दै हँसत ग्वाल सब, सिखै देते बलबीर॥
तू मोही को मारन सीखी, दाउहि कबहूँ न खीझै।
मोहन मुख रिस की ये बातौं, जसुमति सुनि – सुनि रीझै॥
सुनहू कान्ह बलभद्र चबाई, जनमत ही को धूत।
सूर स्याम मोहि गोधन की सौं, हौं माता तू पूत॥

ମୈୟା ମୋହି ଦାଉ ବହୁତ ଖ୍ରୀୟୋ।
ମୋର୍ସ କହତ ମୋଲ୍ କୋ ଲୀକ୍ଷ୍ନୌ, ତୂ ଜସୁମତି କବ ଜାୟେ ॥
କହା କହାଁ ଏହୀ ରିସ କେ ମାତା, ମାରେ, ଖେଲନ ହେଁ ନହିଁ ଜାତ।
ପୁନି-ପୁନି କହତ କୌନ୍ ହୈ କୌନ ହି ତୁମରୋ ତାତ॥
ମାରେ, ଖେଲନ ହେଁ ନହିଁ ଜାତ। ମାତା, କୌନ ହି ତୁମରୋ ତାତ ॥
ଗୋରେ ନନ୍ଦ, ଜସୋଦା ଗୋରୀ, ତୂ କତ ସ୍ୟାମ ସରୀର।
ଚୁଟକୀ ଦୈ ଦୈ ହଁସତ ଗ୍ବାଲ ସବ, ସିଖି ଦେତେ ବଲବୀର॥
ତୂ ମୋହୀ କୋ ମାରନ ସୀଖୀ, ଦାଉହି କବହୁଁ ନ ଖୀର୍ଷେ।
ମୋହନ ମୁଖ ରିସ କୀ ୟେ ବାର୍ଡୋ, ଜସୁମିତ ସୁନି-ସୁନି ରୀର୍ଥେ ॥
ସୁନହ୍ନି କାହ୍ନ ବଲଭଦ୍ର ଚବାଈ, ଜନମତ ହୀ କୋ ଧୂତ।
ସୂର ସ୍ୟାମ ମୋହି ଗୋଧନ କୀ ସୌ, ହେଁ ମାତା ତୃ ପୂତ॥

हिन्दी व्याख्या: इस पद में कृष्ण की बाललीला का वर्णन है। बालक कृष्ण माँ यशोदा के पास शिकायत करते हैं, “माँ! मुझे बलराम भैया चिढ़ाते हैं। वे मुझे कहते हैं कि तुझे खरीद कर लिया गया है। जसुमति ने तुझे जन्म नहीं दिया है। इसलिए मैं उनके साथ खेलने नहीं जाता। वे बार-बार मुझे पूछते हैं कि कौन तेरी माता और कौन तेरे पिता हैं? और कहते हैं कि नंद गोरे हैं, यशोदा गोरी है, तू क्यों श्यामल/काला है। यह सुनकर मुझे चिढ़ाने के लिए ग्वाल बालक चुटकी बजाकर नाचते हैं।

बलराम भैया उन्हें सिखा देते हैं। तूने सिर्फ मुझे मारना सीखा है। बलराम भैया पर खीझती भी नहीं ।” मोहन के मुख पर गुस्सा देखकर और उनकी गुस्सैली वाणी सुनकर यशोमति प्रसन्न हो जाती हैं। माँ कहती है कि कान्हा सुन, यह बलराम चुगलखोर है, वह जन्म से शरारती है। मैं गोधन की कसम खाकर कहती हूँ कि मैं तेरी माता और तू मेरा पुत्र है।

ଓଡ଼ିଆ ଅନୁବାଦ:
ଏହି ପଦରେ କୃଷ୍ଣଙ୍କର ବାଲ୍ୟଲୀଳାର ବର୍ଣ୍ଣନା କରାଯାଇଅଛି। କୃଷ୍ଣ ମାତା ଯଶୋଦା ପାଖରେ ଆପରି କରୁଛନ୍ତି କି ହେ ମାତା! ମୋତେ ବଳରାମ ଭାଇ ଚିଡ଼ାଉଛନ୍ତି। ମୋତେ କହୁଛନ୍ତି ତୋତେ କିଣିକରି ଅଣାଯାଇଅଛି। ମାତା ଯଶୋଦା ତୋତେ ଜନ୍ମ ଦେଇନାହାଁନ୍ତି। ଏଣୁ ମୁଁ ତାଙ୍କ ସହିତ ଖେଳିବାକୁ ଯାଉନାହିଁ। ସେ ବାରମ୍ବାର ମୋତେ ପଚାରୁଛନ୍ତି ତୋ’ ମାତା ପିତା କିଏ?

ନନ୍ଦ-ଯଶୋଦା ତ ଗୋରା, ତୁ କାହିଁକି କଳା ହେଲୁ? ଏହା ଶୁଣି ଗୋପାଳ ପିଲାମାନେ ମଧ୍ଯ ଚୁଟୁକି ମାରି ନାଚୁଛନ୍ତି। ବଳରାମ ଭାଇ ତାଙ୍କୁ ଶିଖାଉଛନ୍ତି। ତୁମେ କେବଳ ମୋତେ ମାରିବା ଜାଣିଛ ମାତା କହୁଛନ୍ତି: କୃଷ୍ଣ ଶୁଣ, ବଳରାମ ମିଛୁଆଟା ଏବଂ ଜନ୍ମରୁ ଦୁଷ୍ଟ। ମୁଁ ଗାଈର ଶପଥ ଖାଇ କହୁଛି ଯେ ତୁ ମୋର ପୁଅ ଏବଂ ମୁଁ ତୋ’ ର ମାଆ

BSE Odisha 10th Class Hindi Solutions Poem 1(b) सूरदास के पद

2. हरि अपने आँगन कछु गाबत।
तनक-तनक चरनन सौं नाचत, मनहिं – मनहिं रिझाबत ॥
बाँह उचाइ काजरी – धौरी, गौयनि टेरि बुलाबत।
कबहुँक बाबा नंद पुकारत, कबहुँक घर मैं आबत॥
माखन तनक आपने कर लै, तनक-बदन मैं नाबत।
कबहुँ चितौ प्रतिबिम्ब खंभ मैं, लौनी लिए खबावत॥
दुरि खति जसुमति यह लीला, हरष आनंद बढ़ावत।
सूर स्याम के बाल – चरित ये, तिन देखन मन भावत॥

ହରି ଅପନେ ଆଗନ କଛୁ ଗାବତ୍।
ତନକ-ତନକ ଚରନନ ସୌ ନାଚତ, ମନହିଁ-ମନହିଁ ରିଝାବତ ॥
ବାହ ଉଚାଇ କାଜରୀ-ଧୌରୀ, ଗୌୟନି ଟେରି ବୁଲାବତ।
କବର୍ଦ୍ଧକ ବାବା ନଂଦ ପୁକାରତ, କବଚ୍ଛୁକ ଘର ମେଁ ଆବତ॥
ମାଖନ ତନକ ଆପନେ କର ଲୈ, ତନକ-ବଦନ ମେଁ ନାବତ।
କବହୁଁ ଚିତୌ ପ୍ରିତବିମ୍ବ ଗଂଭ ମେଁ, ଲୌନୀ ଲିଏ ଖବାୱତ॥
ଦୁରି ଦେଖତି ଜସୁମତି ୟହ ଲୀଲା, ହରଷ ଆନଂଦ ବଢ଼ାୱତ।
ସୂର ସ୍ୟାମ କେ ବାଲ-ଚରିତ ଯେ, ନିତ ଦେଖତ ମନ ଭାବତ॥

हिन्दी व्याख्या: बालक कृष्ण घर के आंगन में अकेले खेल रहे हैं। उनका यह खेल सबके मन को मोह लेता है। यह वर्णन बहुत ही हृदयग्राही है। भगवान कृष्ण अपने आप कुछ गा रहे हैं। वे गाते-गाते नन्हें चरणों से नाचते भी हैं और मन-मन खुश हो रहे हैं। कभी वे हाथ उठाकर काली एवं सफेद गायों को बुलाते हैं, तो कभी नंद बाबा को पुकारते हैं। वे कभी घर के भीतर चले जाते हैं।

घर में जाकर थोड़ा मक्खन हाथ में लेकर खाते हैं, और थोड़ा-सा मुँह में लगा लेते हैं। माता यशोदा दूर से ही खड़ी होकर यह लीला देख रही हैं। और आनंदित हो रही हैं। सूरदास कह रहे हैं कि कन्हैया की यह बाललीला रोज-रोज देखने पर भी प्यारी लगती है। इससे मन तृप्त नहीं होता।

ଓଡ଼ିଆ ଅନୁବାଦ:
କୃଷ୍ଣ ଏକୁଟିଆ ଅଗଣାରେ ଖେଳୁଛନ୍ତି। ତାଙ୍କର ଏହି ଖେଳ ସମସ୍ତଙ୍କ ମନକୁ ମୋହିତ କରୁଅଛି। ଏହା ଅତ୍ୟନ୍ତ ହୃଦୟଗ୍ରାହୀ। କୃଷ୍ଣ ଆପଣା ଛାଏଁ କିଛି ଗୀତ ଗାଇ ଚାଲିଛନ୍ତି। ଗାଉ ଗାଉ ଛୋଟ ପାଦରେ ସେ ନାଚୁଛନ୍ତି ମଧ୍ୟ ଏବଂ ମଗ୍ନ ମଧ୍ୟ ହୋଇଯାଉଛନ୍ତି। କେତେବେଳେ ହାତଠାରି କାଳୀ ଓ ଧଳୀ ଗାଈଙ୍କୁ ଡାକୁଛନ୍ତି ତ କେତେବେଳେ ନନ୍ଦ ବାବାଙ୍କୁ ମଧ୍ୟ ଡାକୁଛନ୍ତି।

କେତେବେଳେ ଘର ଭିତରକୁ ଚାଲିଯାଇ ଲହୁଣି ଖାଉଛନ୍ତି ତ ଲହୁଣି ହାତରେ ଧରି ନିଜ ମୁହଁରେ ବୋଳି ମଧ୍ୟ ବହୁତ ସୁନ୍ଦର ଲାଗୁଛି। ଏତିକିରେ ମନର ତୃପ୍ତି ହେଉନାହିଁ। ଥାଇ ଏହା ଦେଖୁଛନ୍ତି ଏବଂ ଖୁସି ହେଉଛନ୍ତି। ସୁରଦାସ କହୁଛନ୍ତି ଯେ କୃଷ୍ଣଙ୍କର ଏହି ବାଲ୍ୟଲୀଳା ସବୁଦିନ ଦେଖୁଥିଲେ ମଧ୍ୟ ବହୁତ ସୁନ୍ଦର ଲାଗୁଛି। ଏତିକିରେ ମନର ତୃପ୍ତି ହେଉନାହିଁ

शबनार: (ଶରାର୍ଥି)

मैया – माँ (ମା’)

दाऊ – बड़ा भाई बलराम (ବଡ଼ଭାଇ ବଳରାମ)

खिझायो – चिढ़ाया (ବଡ଼ଭାଇ ବଳରାମ)

कहत – कहते है (ଚିଡ଼ାଇଲେ)।

लीन्हों – लाया गया (କୁହନ୍ତି)।

जायो – जन्मा (ଅଣାଯାଇଅଛି)।

एही – यही (ଜନ୍ମ ହେବା)।

खेलन – खेलने (ଏହି)।

पुनि-पुनि – बारबार (ଖେଳିବାକୁ)।

तात – पिता (ବାରମ୍ବାର)।

सरीर – शरीर (ପିତା)।

चुटकी – अंगूठे और पास की अंगुली से बजाना (ଶରୀର)।

दै- देकर (ଦେଇକରି)।

ग्वाल – गोपाल (ଗୋପାଳ)।

बलवीर – बलराम (ବଳରାମ)।

मारन – मारना (ମାରିବା)।

दाउहि – बडे भाई से ( କଥା)।

बातें – बातें (ବଡ଼ଭାଇ)।

सुनहू – सुनकर (ଶୁଣି ଶୁଣି)।

चबाई – चुगलखोर (ମିଛକୁହା)।

धूत – शरारती (ବଦମାସ୍)।

गोधन – गायरूपी धन (ଗୋଧନ)।

मोहि – मुझे (ମୋତେ)।

मोसों – मुझसे (ମୋତେ)।

मोल – खरीद कर (କିଣି କରି)।

जसुमति – यशोदा (ଯଶୋଦା)।

कहैं – कहें (କହିବ)

रिंस – गुस्सा (ରାଗ)।

जात – जाएँ (ଯାଏ)।

तुमरो – तुम्हारा (ତୁମର)।

कत – क्यों (କାହିଁକି)।

स्याम – श्यामल (ଶ୍ୟାମଳ ରଙ୍ଗ)।

सिखै – सिखाने (ଲିବା)।

मोहि – मुझे (ଶିଖାନ୍ତି)।

सीखी – सीखना (ଶିଖିବ)।

कबहूँ – कभी (କେତେ)।

रीझै – प्रसन्न (ଖୁଡି ହେବ)।

कान्ह – कान्हा (କୃଷ୍ଟ)।

जनमत – जन्म (କନ୍ନ)।

पूत – पुत्र (ପୁତ୍ର)।

सौं – सौगंध (ଶପଥ)।

हरि – कृष्ण (କୃଷ୍ଣ)।

कछु – कुछ (କିଛି)।

तनक-तनक – नन्हें-नन्हें (ଛୋଟ ଛୋଟ)।

मनहिं-मनहिं – मन में (ମନେମନେ)।

बाँह – हाथ (ହାଥ)

काजरी – काली (କାଳ)

कबहुँक – कभी (କେବେ)

आवत – आते हैं (ଅପନ୍ତି)

तनक – कुछ (କିଛି)

लै – लेकर (ନେଇକରି)

नावत – लगाते (ଲଗାଇବ)

दुरि – दूर (ହର)

बढ़ावत – बढ़ाना (ଗଢାଇବା)

आँगन – (ଅଗଣା)।

गावत – गाना (ଚାଇବା)।

चरनन – चरण (ପ।ଦ)।

रिझावत – मगन (ମଗ୍ନ)

उचाइ – उठाकर (ହାପଠାରି)

धौ. – सफेद (ଧଳା)

पुकारत – पुकारते हैं (ପାରନ୍ତି)

माखन – मक्खन (ଲତୁଣି)

कर – हाथ (घाथ)। (ତ୍ୱାଥ)

बदन – मुँह (ପୁହିଁ)

खबावत – खिलाते हैं (ଖୁଆନି)

लिए – लेकर (ନେଇ)

भावत – अच्छा लगता (ଭଲ ଲାଗ)

कवि परिचय

भक्तिकाल के श्रेष्ठ कवि सूरदास हिन्दी के सूर्य जैसे तेजस्वी कवि हैं। उनका जन्म सन् 1478 में दिल्ली के निकट सीही गाँव में एक गरीब ब्राह्मण परिवार में हुआ। वे अंधे थे, पर मालूम पड़ता है कि वे जन्मांध नहीं थे। मथुरा और आगरा के बीच यमुना नदी के तटपर स्थित गऊघाट पर उन्होंने संगीत, काव्य और शास्त्र का अभ्यास किया और विनय के भाव से पदों की रचना की। आगे चलकर वे वल्लभाचार्य के शिष्य बन गये और ब्रज जाकर गोवर्धन के पास पारसोली नामक जगह पर अपना स्थायी निवास बनाकर पद लिखते रहे।

सूरदास मानव: मन के बड़े पारखी थे। वात्सल्य भाव के तो वे मर्मज्ञ थे। श्रीमद् भागवत महापुराण के आधार पर रचित उनका विशाल ग्रंथ ‘सूर सागर’ हिंदी की अमूल्य निधि है। ये बच्चों कें, माताओं के, साथियों के, नारी और पुरुषों के मनोभावों के पारंगम कवि थे।

यह पद : (ଏହି ପଦ)
प्रस्तुत पाठ में महाकवि सूरदास द्वारा रचित कृष्ण की बाललीला के दो पदों को रखा गया है। ये पद ‘सूरसागर’ से संकलित हैं।
ପ୍ରସ୍ତୁତ ପାଠରେ ମହାକବି ସୁରଦାସଙ୍କଦ୍ଵାରା ରଚିତ କୃଷ୍ଣଙ୍କର ବାଲ୍ୟଲୀଳାର ଦୁଇଟି ପଦ ରଖାଯାଇଅଛି। ଏହି ପଦ ‘ସୁର ସାଗର’ରୁ ସଙ୍କଳିତ ହୋଇଅଛି।

BSE Odisha 7th Class English Solutions Follow-Up Lesson 5 Loveliest of Trees

Odisha State Board BSE Odisha 7th Class English Solutions Follow-Up Lesson 5 Loveliest of Trees Textbook Exercise Questions and Answers.

BSE Odisha Class 7 English Solutions Follow-Up Lesson 5 Loveliest of Trees

BSE Odisha 7th Class English Follow-Up Lesson 5 Loveliest of Trees Text Book Questions and Answers

Pre-Reading (ପ୍ରାକ୍-ପଠନ):

Pre-reading

Your teacher will introduce the lesson in the following way.

Question 1.
Can you recognize these flowers? (Teacher show the flowers in picture)
( ଛବିରେ ଫୁଲମାନକୁ ଦେଖାଇ) ( ଏ ଫୁଲଗୁଡ଼ିକୁ ଚିହ୍ନି ପାରୁଛ ?)
Answer:
Yes, we can recognize these flowers. They are zinnia, hibiscus (china rose), lotus, and rose flowers respectively.

Question 2.
How do you feel when you see a tree full of flowers?
(ବୃକ୍ଷଟିଏ ଫୁଲରେ ଭରିଥୁବା ଦେଖ‌ିଲେ ତୁମେ କିଭଳି ଅନୁଭବ କର ? )
Answer:
When we see a tree is full of flowers we think the tree is laughing with merriment. We feel pleasure from this sight.
Let’s see how a poet feels when he sees a tree full of flowers.
(ଚାଲ ଦେଖିବା ଗୋଟିଏ ଗଛ ଫୁଲରେ ଭରପୂର ଥ‌ିବା ଦେଖ୍ ଜଣେ କବି କ’ଣ ଅନୁଭବ କରନ୍ତି ?)

BSE Odisha 7th Class English Solutions Follow-Up Lesson 5 Loveliest of Trees

While-Reading (ପଠନକାଳୀନ ):

1. Your teacher will read the poem aloud, and you will listen to him/her without opening your books.
(ତୁମ ଶିକ୍ଷକ କବିତାଟି ଉଚ୍ଚସ୍ବରରେ ପଢ଼ିବେ । ବହି ନଖୋଲି ତୁମେ କେବ ତାଙ୍କୁ ଶୁଣିବ ।)
2. S/he will read the poem aloud for the second time and you will listen to him / her following the poem in your books.
(ତୁମ ଶିକ୍ଷକ ଦ୍ଵିତୀୟବାର ଉଚ୍ଚସ୍ବରରେ ପଢ଼ିବେ ଏବଂ ତୁମେ ବହିରୁ କବିତାଟିକୁ ଧାଡ଼ି ଧାଡ଼ି କରି ଦେଖ ।)
3. Read the poem silently and try to answer the questions asked by your teacher.
(କବିତାଟିକୁ ତୁମେ ନୀରବରେ ପାଠ କର ଏବଂ ଶିକ୍ଷକ ପଚାରିଥିବା ପ୍ରଶ୍ନସବୁର ଉତ୍ତର ଦେବାକୁ ଚେଷ୍ଟାକର ।)

Text (ପାଠ୍ୟବସ୍ତୁ):

Loveliest of trees, the cherry now
Is hung with bloom along the bough.
And stands about the woodland ride
Wearing white for Eastertide

Now my threescore years and ten,
Twenty will not come again,
And take from seventy springs a score,
It only leaves me fifty more.

And since to look at things in bloom
Fifty springs are little room,
About the woodlands, I go
To see the cherry hung with snow.

ଓଡ଼ିଆ ଅନୁବାଦ:
ସୁନ୍ଦରତମ ବୃକ୍ଷରାଜି, ଆଜି ସେହି ଚେରି
ଝୁଲୁଛି ଫୁଟା ଫୁଲଧରି ଶାଖା ସବୁ ଭରି,
ପର୍ବତିଆ କ୍ଷେତ ଧାରେ ଧାରେ ଠିଆ ହୋଇ
ଶୁଭ୍ର ଆଚ୍ଛାଦିତ ଆଭୂଷିତ ଇଷ୍ଟର ଢେଉରେ ।

ଅଧୁନା ମୋ ତିନିକୋଡ଼ି ବର୍ଷ ଏବଂ ଦଶ
କୋଡ଼ିଏ ତ ବାହୁଡ଼ି ନ ଆସେ,
ଏବଂ ଘେନିଯାଏ ସତୁରୀରୁ କୋଡ଼ିଏ ବସନ୍ତ
କେବଳ ସେ ମୋତେ ଛାଡ଼ିଦିଏ ଅଧୂକୁ ପଚାଶ ।

ଏବଂ ସେହିଠାରୁ ଚାହିଁରହେ ଫୁଲ ଜୁଆରକୁ
ପଚାଶ ବସନ୍ତ କିଛି ନୁହେଁ ପରା ତା’ର
ଯେବେ ଯାଏ ମୁଁ ତା’ପାଶେ ପାହାଡ଼ ପ୍ରାନ୍ତରେ
ଚେରିଗଛ ଦେଖ‌ିବାକୁ ବରଫ ଦୋଳିରେ ।

BSE Odisha 7th Class English Solutions Follow-Up Lesson 5 Loveliest of Trees

Notes And Glossary (ଶବ୍ଦାର୍ଥ):

loveliest (ଲଭ୍ଲିଏଷ୍ଟ) – ସୁନ୍ଦରତମ
cherry (ଚେରି) – ନାଲି ରଙ୍ଗର ଚେରିକୋଳି
hung (ହଙ୍ଗ୍) – ଝୁଲି ରହିବା
bloom (ବ୍ଲୁମ୍) – ଫୁଲ ଫୁଟିବା
bough (ବାଓ) – ଶାଖାପ୍ରଶାଖା
ride (ରାଇଡ଼୍) – ଆରୋହଣ କରିବା
woodland (ଉଡଲ୍ୟାଣ୍ଡ୍) – ଜଙ୍ଗଲିଆ ଅଞ୍ଚଳ
wearing (ଓୟରିଙ୍ଗ୍) – ପିନ୍ଧିଥ‌ିବା
tide (ଟାଇଡ୍) – ଡେଉ ବା ଜୁଆର
score (ସ୍କାର) – କୋଡ଼ିଏ
spring (ସ୍ପ୍ରିଙ୍ଗ୍) – ବସନ୍ତ
leaves (ଲିଭସ୍) – ଛାଡିଦିଏ
since (ସିନ୍ସ) – ପରଠାରୁ
snow (ତୁଷାର) – ବରଫ

Comprehension Questions (ବୋଧପରିମାପକ ପ୍ରଶ୍ନବଳୀ):

Question 1.
What is the poem about?
( କବିତାଟି କେଉଁ ସମ୍ବନ୍ଧରେ ?)
Answer:
The poem is about the beauty and life of a cherry tree.

Question 2.
Which word tells that ’cherry with flower’ is the nicest of all trees?
(କେଉଁ ଶବ୍ଦ କହୁଛି ଯେ, ଚେରି ଫୁଲରେ ସଜେଇ ହୋଇ ସବୁ ଗଛ ମଧ୍ୟରେ ସୁନ୍ଦରତମ ?)
Answer:
The phrase “hung with bloom” tells that cherry with flowers is the nicest of all trees.

Question 3.
Where does the tree stand?
((ଚେରି) ଗଛ କେଉଁଠି ଥାଏ ?)
Answer:
The tree stands in woodland.

BSE Odisha 7th Class English Solutions Follow-Up Lesson 5 Loveliest of Trees

Question 4.
What do the trees wear for Eastertide?
((ଚେରି) ଗଛସବୁ କ’ଣ ପିନ୍ଧିଥାଏ ଇଷ୍ଟର ଢେଉ ପାଇଁ ? )
Answer:
‘Easter’ is a Christian festival. The people do merrymaking. So the cherry enjoys the festival wearing white flowers.

Question 5.
What does ‘white’ refer to here?
(ଧଳା ବା ଶୁଭ୍ରତା ଏଠି କାହାକୁ ସୂଚାଏ ?)
Answer:
“White” refers to a white dress. As it is an Easter festival, the cherry wears a white dress.

Question 6.
Why is cherry dressed in white?
(ଚେରିଗଛ କାହିଁକି ଶୁଭ୍ର ବା ଧଳା ପୋଷାକ ପରିଧାନ କରିଥାଏ ?)
Answer:
As it is the Easter festival, the cherry wears white flowers to enjoy the festival.

Question 7.
The first stanza describes the cherry tree. How is the second stanza different from the first stanza?
(ପ୍ରଥମ ପଦ ଚେରି ଗଛ ବିଷୟରେ ବର୍ଣ୍ଣନା କରେ । ଦ୍ୱିତୀୟ ପଦ କିଭଳି ପ୍ରଥମ ପଦଠାରୁ ଭିନ୍ନ ?)
Answer:
The first stanza describes the cherry tree. But the second stanza describes the normal life of man.

Question 8.
How many years are there in a score?
(କୋଡ଼ିରେ କେତେ ବର୍ଷ ଥାଏ ?)
Answer:
There are twenty years in a score.

Question 9.
How many years are there in three scores?
(ତିନି କୋଡ଼ିରେ କେତେ ବର୍ଷ ଥାଏ ? )
Answer:
There are sixty years in three Scores.

Question 10.
What is the normal life span of humans according to the Bible?
(ବାଇବେଲ୍‌ ବା ଖ୍ରୀଷ୍ଟ ଧର୍ମଗ୍ରନ୍ଥ ଅନୁସାରେ ମଣିଷର ସାଧାରଣତ ଜୀବନକାଳ କେତେ ବର୍ଷ ?)
Answer:
According to Bible the normal life span of humans is seventy.

Question 11.
How old is the poet?
(କବିଙ୍କୁ କେତେ ବର୍ଷ ?)
Answer:
The poet is twenty years old.

BSE Odisha 7th Class English Solutions Follow-Up Lesson 5 Loveliest of Trees

Question 12.
Why does he deduct twenty years from seventy years?
(ସେ କାହିଁକି ୭୦ ବର୍ଷରୁ ୨୦ ବର୍ଷ ବାଦ୍ ଦିଅନ୍ତି ?)
Answer:
The poet has deducted twenty years from seventy years because he has already enjoyed twenty years from the normal life of seventy.

Question 13.
How many years does he suppose to live?
(ସେ କେତେ ବର୍ଷ ପର୍ଯ୍ୟନ୍ତ ବନ୍ଧୁ ରହିବାକୁ ଆଶା ରଖନ୍ତି ?)
Answer:
The poet is supposed to live another fifty years.

Question 14.
Is a fifty year life enough to see and enjoy the nature?
(ପଚାଶ ବର୍ଷର ଜୀବନ କ’ଣ ପ୍ରକୃତିକୁ ଦେଖ୍ ଉପଭୋଗ କରିବା ନିମିତ୍ତ ଯଥେଷ୍ଟ ? )
Answer:
No, fifty years is not enough to see and enjoy the nature.

Question 15.
Why is the poet in a hurry to go to the woodland?
(କବି କାହିଁକି ପାହାଡ଼ ପ୍ରାନ୍ତକୁ ଯିବାକୁ ବ୍ୟଗ୍ର ହୁଅନ୍ତି ?)
Answer:
The poet wants more and more to enjoy nature. But fifty years is not enough to enjoy the beauties of nature. So he is in a hurry to go to the woodland to enjoy beauties nature.

Question 16.
Does the third stanza start from the second stanza? How?
(ତୃତୀୟ ପଦ କ’ଣ ଦ୍ଵିତୀୟ ପଦଠାରୁ ଆରମ୍ଭ ହୋଇଛି ? କିପରି ?)
Answer:
Yes, the third stanza starts from the second stanza. The third stanza begins with the word ‘And’ and this means it is a continuation of the 2nd stanza.

Question 17.
Is the poet a lover of nature? How do you know?
(କବି କ’ଣ ପ୍ରକୃତିପ୍ରେମୀ ? ତୁମେ କିପରି ଜାଣୁଛ ?)
Answer:
Yes, the poet is a lover of nature. We know this from his hurries to go to the woodland to enjoy cherry hung with blossom.

Question 18.
What does ‘springs’ mean?
(ବସନ୍ତଗୁଡ଼ିକ କହିଲେ କ’ଣ ବୁଝୁଛ ?)
Answer:
Spring refers to one year. Because spring comes after one year. So here springs refer to years.

BSE Odisha 7th Class English Solutions Follow-Up Lesson 5 Loveliest of Trees

Question 19.
When cherry blooms, it does not have any leaf. Name a flower plant in our country similar to cherry.
(ଯେତେବେଳେ ଚେରି ଫୁଟେ, ତା’ର କୌଣସି ପତ୍ର ନଥାଏ । ଆମ ଦେଶରେ ଥ‌ିବା ଚେରି ଭଳି ଏକ ଫୁଲଗଛର ନାମ କୁହ ।)
Answer:
Lily is similar to cherry.

Word Note:
(The words/phrases have been defined mostly on their contextual meanings)

beams (ବିମ୍ସ) – sunlight (ସୂର୍ଯ୍ୟକିରଣ)
boughs (ବାଓଜ୍) – branches (ଗଛର ଶାଖା ବା ଡାଳ)
cherry (ଚେରୀ) – a small sweet fruit (ଚେରିକୋଳି)
drowsy (ଡ୍ରୋଜି) – sleepy (ନିଦ୍ରାଳୁ ବା ନିଦ୍ରା ବିଜଡ଼ିତ ଭାବ)
Eastertide (ଇଷ୍ଟରଟାଇଡ୍) – Eastertime, Easter festival time of the Christians (ଖ୍ରୀଷ୍ଟଧର୍ମୀମାନଙ୍କର ଇଷ୍ଟର ପର୍ବ ସମୟ)
floats (ଫ୍ଲୋସ୍) – moves in the sky (ଆକାଶରେ ଭାସେ ବା ଦେଖାଯାଏ )
gather (ଗ୍ୟାଦର) – collect (ଏକତ୍ରିତ କରେ-ପକ୍ଷୀମାନେ ବସା ବାନ୍ଧି ରୁହନ୍ତି)
harm (ହାର୍ମ) – hurt, damage (କ୍ଷତି କରିବା)
hum (ହମ୍) – sing in very low voice (ଗୁଣୁଗୁଣୁ ହୋଇ ଗାଇବା)
hung with bloom (ହଙ୍ଗ୍ ଉଇଥ୍ ବ୍ଲମ୍) – ripe cherry hanging from the tree (ବୃକ୍ଷର ଶାଖାପ୍ରଶାଖାରେ ପାଚି ଓହଳିଥିବା ଚେରିକୋଳି)
lullaby (ଲୁଆବେ) – song to make children to sleep (ଶିଶୁକୁ ଶୁଆଇବା ପାଇଁ ଗୀତ-ଧୋରେ ବାଇଆ ଧୋ ପରି)
score (ସ୍କୋର) – twenty (କୋଡିଏ)
three scores years and ten (ଥ୍ରି ସ୍କୋର୍‌ସ୍ ଇୟର୍‌ସ ଆଣ୍ଡ୍ ଟେନ୍) – 70 years (the normal life span (time) of man).
woodland (ଉଲ୍ୟାଣ୍ଡ୍ ) – forest area (ବନଭୂମି)

BSE Odisha 7th Class English Solutions Follow-Up Lesson 5 Loveliest of Trees Important Questions and Answers

(A) Choose the right answer from the options.

Question 1.
The poem is about the
(a) nature
(b) beauties of nature
(c) cherry trees
(d) human life
Answer:
(c) cherry trees

Question 2.
The poet of this poem is _____________.
(a) A. E. Housman
(b) W. Wordsworth
(c) Lord Tennyson
(d) none of these
Answer:
(a) A.E. Housman

BSE Odisha 7th Class English Solutions Follow-Up Lesson 5 Loveliest of Trees

Question 3.
The cherry hung with bloom
(a) under the bough
(b) along the bough
(c) on the top branches of the tree
(d) on the lower branches of the tree.
Answer:
(b) along the bough

Question 4.
What is the age of the poet now?
(a) 20
(b) 50
(c) 70
(d) 90
Answer:
(a) 20

Question 5.
In the woodland cherry hung _____________.
(a) with snow
(b) with dust
(c) in snow
(d) none of these
Answer:
(a) with snow

(B) Answer the following questions.

Question 1.
Which line tells that the poet has already enjoyed twenty years of age?
Answer:
The line “Twenty will not come again”. This line shows that the poet has already enjoyed twenty years of age.

Question 2.
“Fifty springs are little room”. Explain.
Answer:
The man nowadays lives for seventy years on average. The poet expects to live another fifty years. But it is not much for him to enjoy the beauties of nature.

BSE Odisha 7th Class English Solutions Lesson 5 The Kind Tree

Odisha State Board BSE Odisha 7th Class English Solutions Lesson 5 The Kind Tree Textbook Exercise Questions and Answers.

BSE Odisha Class 7 English Solutions Lesson 5 The Kind Tree

BSE Odisha 7th Class English Lesson 5 The Kind Tree Text Book Questions and Answers

Session – 1 (ପ୍ରଥମ ପର୍ଯ୍ୟାୟ):
Pre-Reading (ପ୍ରାକ୍-ପଠନ):

→ Do you like trees?
(ତୁମେ କ’ଣ ଗଛସବୁକୁ ଭଲ ପାଅ ?)
Answer:
Yes we like trees very much.

→ What do trees give people?
(ଗଛସବୁ ମଣିଷକୁ କ’ଣ ଦିଏ ?)
Answer:
Trees give people things to live in. These are food, fuel, oxygen, etc.

→ Do you think they are kind? Why?
(ତୁମେ କ’ଣ ଭାବୁଛ ବୃକ୍ଷ ଦୟାଳୁ ? କାହିଁକି ?)
Answer:
Yes, we think trees are kind. They give us food, fuel, and other necessary things in life. They give shade to animals and men and shelter to birds. So they are kind to all animals.

BSE Odisha 7th Class English Solutions Lesson 5 The Kind Tree

While-Reading (ପଠନକାଳୀନ ):
Text (ପାଠ୍ୟବସ୍ତୁ):

  • Read the poem silently and answer the questions that follow.
    (କବିତାଟିକୁ ନୀରବରେ ପାଠ କର ଏବଂ ନିମ୍ନ ପ୍ରଶ୍ନଗୁଡ଼ିକର ଉତ୍ତର ଦିଅ ।)
    Read the poem silently and answer the questions that follow

Trees are the kindest things I know,’
They don’t harm, and they simply grow.
And spread shade for sleepy cows,
And gather birds among the boughs.

They are the first when the day’s begun.
To touch the beams of the morning sun.
They are the last to hold the light.
When evening changes into night.

And when a moon floats on the sky,
They hum a drowsy lullaby
of sleepy children long ago,
Trees are the kindest things I know

ଓଡ଼ିଆ ଅନୁବାଦ :
ବୃକ୍ଷରାଜି ସବୁଠୁ ଦୟାଳୁ ମୁଁ ଜାଣେ
କରନ୍ତି ନାହିଁ ସେ କ୍ଷତି, କେବଳ ସରଳେ ବୃଦ୍ଧି ।
ବିଛାଇ ଦିଅନ୍ତି ଛାଇ ତଳେ ଶୋଇ ରହିବାକୁ ଗାଈ
ସଂଗ୍ରହ କରନ୍ତି ପକ୍ଷୀରାଜି ସବୁ ଡାଳେ ରହିବାକୁ ଛାଇ ।

ସେହିମାନେ ହିଁ ପ୍ରଥମ ଦିନ ଯେବେ ହୁଏ ଆରମ୍ଭ
ଛୁଇଁବାରେ ସେ ସୂର୍ଯ୍ୟକିରଣକୁ ବେଗୁ ବେଗ
ସେହିମାନେ ହିଁ ତ ଶେଷ ଧରି ରଖନ୍ତି ଆଲୋକ
ଯେତେବେଳେ ସନ୍ଧ୍ୟା ବଦଳେ କରି ରାତ୍ରିର ଡାକ ।

ଯେତେବେଳେ ଭାସେ ଜହ୍ନ ବିଶାଳ ଆକାଶେ
ସେମାନେ ଗାଆନ୍ତି ଗୀତ ଝୁମ୍ପୁରା ନାନାବାୟାର
ସୁପ୍ତପ୍ରାୟ କୋମଳ ପିଲା ପାଇଁ ଶୀଘ୍ର ଶୀଘ୍ର
ଯେଣୁ ମୁଁ ଜାଣେ ବୃକ୍ଷରାଜି ସଦୟରୁ ସଦୟତମ ।

BSE Odisha 7th Class English Solutions Lesson 5 The Kind Tree

Notes And Glossary (ଶବ୍ଦାର୍ଥ):

Trees (ଟ୍ରିଜ୍) – ଗଛ
kindest ( କାଇଣ୍ଡେସ୍) – ସବୁଠାରୁ ଅଧିକ ଦୟାଳୁ
harm (ହାର୍ମ) – କ୍ଷତି କରିବା
simply (ସିମ୍ପଲି) – କେବଳ ମାତ୍ର
grow (ଗ୍ରୋ) – ବୃଦ୍ଧି ପାଆନ୍ତି
spread (ଗ୍ରେଡ୍) – ବିଛାଇ ଦିଅନ୍ତି
shade (ସେଡ୍) – ଛାଇ
gather (ଗ୍ୟାଦର୍)– ସଂଗ୍ରହ କରନ୍ତି
boughs (ବାଓଜ୍) – ଡାଳ ବା ଶାଖାପ୍ରଶାଖାସବୁ
touch (68) – ଛୁଇଁବା
beams (ବିମ୍ସ) – କିରଣ ସବୁ
moon (ମୁନ୍) – ଜହ୍ନ ବା ଚନ୍ଦ୍ର
floats (ପ୍ଲେଟସ୍) – ଭାସେ
drowsy (ଡ୍ରୋଜି) – ନିଦୁଆ | ଢୁଳାଇବା
lullaby (ଲୁଲାବି)– ନାନାବାୟା ଗୀତ
long ago (ଲଙ୍ଗ ଏଗୋ ) – ବହୁସମୟ ପୂର୍ବରୁ

  • Your teacher reads the poem aloud. You listen to him/her without opening the book.
    (ତୁମ ଶିକ୍ଷକ କବିତାଟିକୁ ବଡ଼ ପାଟିକରି ପଢ଼ିବେ । ଏହି ନଖୋଲି ତୁମେ ଖାଲି ତାଙ୍କୁ ଶୁଣିବ ।)
  • Your teacher asks you: What are described in the poem?
    (ତୁମ ଶିକ୍ଷକ ତୁମକୁ ପଚାରିବେ – କବିତାରେ କ’ଣ ସବୁ ବର୍ଷିତ ?)
  • Your teacher reads the poem aloud a second time. You listen to him/her and at the same time see the poem.
    (ତୁମ ଶିକ୍ଷକ ଦ୍ବିତୀୟବାର ବଡ଼ ପାଟିକରି କବିତା ପଠନ କରିବେ ଏବଂ ତୁମେ ବହିକୁ ଖୋଲି କବିତାଟିକୁ ଧାଡ଼ିଧାଡ଼ି କରି ଦେଖୁବ ।)
  • You read the poem silently and answer the following questions.
    (ତୁମେ କବିତାଟିକୁ ନୀରବତାର ସହ ପାଠ କରୁ ଏବଂ ନିମ୍ନୋକ୍ତ ପ୍ରଶ୍ନଗୁଡିକର ଉତ୍ତର ଦିଅ ।)

Comprehension Questions (ବୋଧପରିମାପକ ପ୍ରଶ୍ନବଳୀ):

Question 1.
What is the poem about ?
(କବିତାଟି କେଉଁ ବିଷୟରେ ?)
Answer:
The poem is about the kindness and usefulness of the trees.

Question 2.
What are the trees like – crudest or kindest?
(ଗଛଗୁଡ଼ିକ କିଭଳିଆ – ନିଷ୍ଠୁର ନା ଦୟାଳୁ ?)
Answer:
The trees are kindest of all.

BSE Odisha 7th Class English Solutions Lesson 5 The Kind Tree

Question 3.
Who knows that trees are kind?
(କିଏ ଜାଣେ ଯେ ବୃକ୍ଷରାଜି ଦୟାଳୁ ?)
Answer:
The poet knows that trees are kind.

Question 4.
Why does the poet say that trees are kind?
( କବି କାହିଁକି କହନ୍ତି ଯେ ବୃକ୍ଷସବୁ ଦୟାଳୁ ?)
Answer:
The poet says that trees are kind because they don’t harm others. Instead, they give shade to sleepy cows and shelter to birds.

Question 5.
What do trees do for the cows?
(ବୃକ୍ଷସବୁ ଗୋରୁଗାଈମାନଙ୍କ ପାଇଁ କ’ଣ କରନ୍ତି ?)
Answer:
Trees spread a shade for sleepy cows.

Question 6.
Where do birds gather?
(କେଉଁଠି ପକ୍ଷୀସବୁ ଠୁଳ ହୁଅନ୍ତି ?)
Answer:
The birds gather among the boughs of trees.

Question 7.
Who is T in the first stanza?
(ପ୍ରଥମ ପଦରେ ଥ‌ିବା ‘I’ (ମୁଁ) କିଏ ?)
Answer:
T refers to the poet in the first stanza.

Question 8.
What time of the day is described in the first stanza?
(ପ୍ରଥମ ପଦରେ ଦିନର କେଉଁ ସମୟ ବିଷୟରେ ବର୍ଣ୍ଣନା କରାଯାଇଛି ? )
Answer:
The noon time of the day is described in the first stanza.

Question 9.
Who does ‘they’ refer to in the second stanza?
(ଦ୍ଵିତୀୟ ପଦରେ ‘they’ (ସେମାନେ) କାହାକୁ ସୂଚାଏ ?)
Answer:
‘They’ refers to trees in the second stanza.

Question 10.
Who touches the beams of the morning sun first?
(ସକାଳ ସୂର୍ଯ୍ୟର କିରଣକୁ କିଏ ପ୍ରଥମେ ଛୁଏଁ ?)
Answer:
The tree touches the beams of the morning sun first.

BSE Odisha 7th Class English Solutions Lesson 5 The Kind Tree

Question 11.
Who holds the last light of the setting sun?
(ଅସ୍ତମିତ ସୂର୍ଯ୍ୟର ଆଲୋକକୁ ଶେଷ ପର୍ଯ୍ୟନ୍ତ କିଏ ଧରିରଖେ ? )
Answer:
The tree holds last light of the setting sun.

Question 12.
Do trees sing a song for children? Why?
(ବୃକ୍ଷରାଜି କ’ଣ ଛୋଟ ପିଲାଙ୍କ ପାଇଁ ଗୀତ ଗାଏ ? କାହିଁକି ?)
Answer:
Yes, trees sing a song for children. When the moon floats in the sky they hum a drowsy lullaby out of kindness.

Question 13.
What is the mood of the poet – happy, unhappy, or grateful?
(କବିଙ୍କର ମନୋଭାବ କ’ଣ – ଖୁସି, ଦୁଃଖ କିମ୍ବା କୃତଜ୍ଞ ?)
Answer:
The mood of the poet is grateful.

Question 14.
Can trees do something good for human beings ? Read the poem again and list all things trees can do.
(ବୃକ୍ଷରାଜି କ’ଣ ମାନବ ଜାତି ପାଇଁ କିଛି ଭଲ କାମ କରନ୍ତି ? କବିତାଟିକୁ ବାରମ୍ବାର ପାଠ କର ଏବଂ ଗଛ କ’ଣ କ’ଣ କରିପାରେ ତାହାର ଏକ ଚିଠା ପ୍ରସ୍ତୁତ କର ।)
Answer:
Yes, trees do something good for human beings.
According to the poem trees can do the following things :
(i) They spread shade for sleepy cows.
(ii) They gather birds among the boughs.
(iii) They first touch the beams of the morning sun.
(iv) They hold the last light of the day.
(v) They hum a drowsy lullaby for sleepy children on a moonlit night.

Question 15.
The poet in this poem likes trees too much. Does it mean he likes nature? Why? (for its beauty and usefulness)
(କବି ଏ କବିତାରେ ବୃକ୍ଷରାଜିକୁ ଅତି ଭଲ ପାଇଛନ୍ତି । ଏହା କ’ଣ ସେ ପ୍ରକୃତିକୁ ଭଲ ପାଉଥିବା କଥା ବୁଝାଏ ? କାହିଁକି ?)
Answer:
The poet likes trees. It means he likes nature. He likes nature for its beauty, usefulness, and kindness.

BSE Odisha 7th Class English Solutions Lesson 5 The Kind Tree

Session – 2 (ଦ୍ବିତୀୟ ପର୍ଯ୍ୟାୟ):
Post-Reading (ପଠନ ପରବର୍ତ୍ତୀ):

1. Visual Memory Development Technique (VMDT) :
(ଦୃଶ୍ୟ ସ୍ମୃତି ବିକାଶ କୌଶଳ)
Whole: birds among the boughs, trees are the kindest things, lullaby, evening changes into night
Part: Stanza-1: kindest, sleepy cows, birds, etc.

2. Comprehension Activities (ବୋଧପରିମାପକ କାର୍ଯ୍ୟାବଳୀ):
(a) Match the sentences under ‘A’ using the right phrases given under ‘B’. Write the serial numbers of A in the boxes of B. One has been done for you. (Question with Answer)
Comprehension Activities 1
Answer:
Comprehension Activities 2

BSE Odisha 7th Class English Solutions Lesson 5 The Kind Tree

(b) Answer the following questions choosing the most appropriate answers from the options.

Question 1.
The poem is about _____________.
(A) human beings
(B) birds
(C) cows
(D) trees
Answer:
(D) trees

Question 2.
Trees are described as _____________.
(A) kindest things
(B) simplest things
(C) nicest things
(D) tallest things
Answer:
(A) kindest things

Question 3.
T in the poem is used for the _____________.
(A) poet
(B) bird
(C) cow
(D) tree
Answer:
(A) poet

Question 4.
The cows sleep _____________.
(A) in the field
(B) in the room
(C) in the shade
(D) in the sun
Answer:
(C) in the shade

Question 5.
‘They” in the last stanza of the poem is used for the _____________.
(A) poet
(B) birds
(C) cows
(D) trees
Answer:
(D) trees

BSE Odisha 7th Class English Solutions Lesson 5 The Kind Tree

Question 6.
Who are the last to hold the light?
(A) The poet
(B) The birds
(C) The cow
(D) The tree
Answer:
(D) The tree

Session – 3 (ତୃତୀୟ ପର୍ଯ୍ୟାୟ):
3. Listening (ଶ୍ରବଣ):

(a) Listen to the last stanza of the poem and fill in the gaps.
(କବିତାର ଶେଷ ପଦଟିକୁ ଶୁଣ ଏବଂ ଶୂନ୍ୟସ୍ଥାନ ପୂରଣ କର ।)
Teacher reads aloud the poem two times.
And when a _______ ________on the sky,
They _________ a drowsy _________,
of _________ children _________ ago,
_________ are the _________ things I know.
Answer:
And when a moon floats on the sky,
They hum a drowsy lullaby,
of sleepy children long ago,
Trees are the kindest things I know.

(b) Your teacher will say some words. Listen to him/her carefully. Tick (✓) the words he/she reads aloud.
trees, kindest, sleepy, spread, gather, shade,
boughs, touch, beams, moon, float, drowsy,
lullaby, change, harm

Session – 4 (ଚତୁର୍ଥ ପର୍ଯ୍ୟାୟ):
4. Speaking (କହିବା):

(a) Reading aloud
(i) Teacher reads aloud one line, and students repeat after him/her in chorus. Then two lines at a time.
(ଶିକ୍ଷକ ଉଚ୍ଚ ସ୍ବରରେ ଗୋଟିଏ ଧାଡ଼ି ପଢ଼ନ୍ତୁ, ପିଲାମାନେ ତା’ପରେ ପୁନରାବୃତ୍ତି କରନ୍ତୁ । ତା’ପରେ ଏକାଥରକେ ଦୁଇଧାଡ଼ି ପଢ଼ନ୍ତୁ ।)
(ii) Teacher reads out the following pairs of rhyming words and students listen. Then, the teacher reads out one word and students read aloud its rhyming word.
(ଶିକ୍ଷକ ଯତିପାତ କରୁଥିବା ଯୋଡ଼ା ଶବ୍ଦଗୁଡିକୁ ପଢ଼ିବେ ଏବଂ ଶିକ୍ଷାର୍ଥୀମାନେ ଶୁଣିବେ । ତା’ପରେ ଶିକ୍ଷକ ଗୋଟିଏ ଶବ୍ଦ ପଢ଼ିବେ ଏବଂ ଶିକ୍ଷାର୍ଥୀମାନେ ତା’ସହ ଯତିପାତ କରୁଥିବା ଶବ୍ଦଟିକୁ ବଡ଼ପାଟିରେ ପଢ଼ିବେ ।)

know     cows      begun   light       sky         ago

grow      boughs sun         night      lullaby   know

(iii) Read the first stanza. Draw student’s attention to the rhyme scheme. Write the rhyme scheme on the board horizontally.
(iv) Students say the rhyme scheme of the other stanzas. Write them on the board.
(v) Ask the students “Which word has a similar rhyme scheme but has different spelling in the first stanza ?” Why?
Answer:
In the first stanza, the word ‘boughs’ has a similar rhyme scheme to the word ‘cows’ but has a different spelling. It is so because -ough’ is pronounced as /au/ in ‘boughs’.
(iv) Help them know the pronunciation of “-ough” differs from word to word. It is pronounced as / ou / as in ‘dough’ and / f / as in ‘enough’ / au / as in bough and / u: / as in ‘through’ and / f / as in cough.

(b) Chain-drill (ଶୃଙ୍ଖଳ-ଅଭ୍ୟାସ):
Trees are the kindest things.
They simply grow and give.

BSE Odisha 7th Class English Solutions Lesson 5 The Kind Tree

Session – 5 (ପଞ୍ଚମ ପର୍ଯ୍ୟାୟ):
5. Vocabulary(ଶବ୍ଦସମ୍ଭାର):

(a) Match the following items in column A with items in column B. The first one is done for you.
Vocubulary 1
Answer:
Vocubulary 2

(b) Match the following words in column A with words in column B to give a similar meaning. The first one is done for you.
Vocubulary 3
Answer:
Vocubulary 4

Session – 6 (ଷଷ୍ଠ ପର୍ଯ୍ୟାୟ):
6. Usage (ପ୍ରଚଳିତ ପ୍ରୟୋଗ):
(a) Mark the following sentences. See how ‘not’ is used in the following examples.
Examples –
1. The tree is tall. The tree is not tall.
2. A lamb is docile. A lamb is not docile.

Rewrite the following sentences using ‘not’. (Question with Answer)
1. It is a nice day. It is not a nice day.
2. It is a beautiful garden. It is not a beautiful garden.
3. It is a lovely doll. It is not a lovely doll.
4. It is a fine building. It is not a fine building.
5. It is a useful book. It is not a useful book.

(b) Rewrite the following sentences like the example given below. Example :
I met the dove yesterday. > I meet the dove every day.
(Question with Answer)
1. I went to school yesterday. > I go to school every day.
2. I did my homework yesterday. > I do my homework every day.
3. I played cricket yesterday. > I play cricket every day.
4. I watched TV yesterday. > I watch TV. everyday.

BSE Odisha 7th Class English Solutions Lesson 5 The Kind Tree

Session – 7 ( ସପ୍ତମ ପର୍ଯ୍ୟାୟ):
7. Writing (ଲିଖନାତ୍ମକ):
(a) Answer the following questions.

Question 1.
What is the poem about?
(କବିତାଟି କେଉଁ ବିଷୟରେ ?)
Answer:
The poem is about the usefulness of trees.

Question 2.
Which line in the first stanza tells that he was unmindful?
(ସେ ଅନ୍ୟମନସ୍କ ଥିଲେ ବୋଲି ପ୍ରଥମ ପଦର କେଉଁ ଧାଡ଼ି କହୁଛି ? )
Answer:
“Trees are the kindest things I know”. This line in the first stanza tells that he was unmindful.

Question 3.
Are the first stanza and second stanza similar or different? How?
(ପ୍ରଥମ ପଦ ଓ ଦ୍ବିତୀୟ ପଦ ଏକାଭଳି କିମ୍ବା ଭିନ୍ନ ? କିପରି ?)
Answer:
The first stanza and second stanza are different. The first stanza shows the inactiveness of the trees whereas the second stanza shows their activeness.

Question 4.
Who does ‘You’ in the 3rd stanza refer to?
(ତୃତୀୟ ପଦର ‘You’ (ତୁମେ) କାହାକୁ ବୁଝାଉଛି ? )
Answer:
‘You’ is not used in the 3rd stanza.

Question 5.
What advice does the poet give us through this poem?
( କବିତା ମାଧ୍ୟମରେ କବି ଆମକୁ କି ଉପଦେଶ ଦେଉଛନ୍ତି ?)
Answer:
The poet advises us that as trees are useful to all men and animals, we should be careful to let them grow.

BSE Odisha 7th Class English Solutions Lesson 5 The Kind Tree

Session – 8 (ଅଷ୍ଟମ ପର୍ଯ୍ୟାୟ):

(b) For the poet, trees are the kindest things s/he knows but another poet sees trees are the loveliest things. Fill in The gaps using words from the box to complete the poet’s views against trees.

Last, gather, sleepy, simply, first, night

Examples:
Trees are the loveliest things I know,
They don’t harm, they ………………….grow
And spread a shade for ………………….cows,
And ………………….birds from the boughs.
They are the ………………….when the day’s begun
To touch the beams of the morning sun,
They are the …………………… to hold the light
When evening changes into ………………….

Answer:
Trees are the loveliest things I know,
They don’t harm, they simply grow
And spread shade for sleepy cows,
And gather birds from the boughs,
they are the first when the day’s begun
To touch the beams of the morning sun,
They are the last to hold the light
When evening changes into night.

(c) What are the other kindest things you know? Write your answer in a paragraph.
Answer:
Water is life. We drink and wash our clothes in water. Water is life for all animals and plants. No water no crops and no crops no life.

BSE Odisha 7th Class English Solutions Lesson 5 The Kind Tree

8. Mental Talk (ମାନସ କଥନ):
Trees are the kindest things. They only give, give, give

9. Let’s Think (ଚାଲ ଚିନ୍ତାମଗ୍ନ ହେବା) :
Trees are kind but we are cruel to cut them more than we need.

BSE Odisha 7th Class English Solutions Lesson 5 The Kind Tree Important Questions and Answers

(A) Answer the following Questions.

Question 1.
How does a tree grow?
Answer:
The trees grow simply by getting air from the sky and light from the sun.

Question 2.
Does it harm anybody?
Answer:
No, it does not harm anybody. It spreads branches to give shed to the tired cows and gather birds among their boughs.

Question 3.
Who rises first in the dawn?
Answer:
The tree rises first before dawn. It spreads its branches to touch the beams of the morning sun.

Question 4.
When does evening change into night who holds light?
Answer:
When evening changes into night, the trees hold the light.

BSE Odisha 7th Class English Solutions Lesson 5 The Kind Tree

Question 5.
When does the tree sing lullaby?
Answer:
When the moon floats in the sky, the tree sings a lullaby for the sleepy children.

(B) Choose the right answer from the options.

Question 1.
The trees are _____________.
(a) cruel
(b) kind
(c) harmful
(d) musician
Answer:
(b) kind

Question 2.
The trees grow _____________.
(a) simply
(b) in difficulty
(c) easily
(d) with care
Answer:
(a) simply

Question 3.
The cows take rest _____________.
(a) on the tree
(b) under the branches of the tree
(c) at the root of the trees
(d) a distance away from a tree
Answer:
(b) under the branches of the tree

BSE Odisha 7th Class English Solutions Lesson 5 The Kind Tree

Question 4.
The tree sings a lullaby when _____________.
(a) a child is going to sleep
(b) the evening comes
(c) the night advances
(d) the moon floats in the sky
Answer:
(d) the moon floats in the sky

CHSE Odisha Class 11 Math Solutions Chapter 8 Permutations and Combinations Ex 8(c)

Odisha State Board Elements of Mathematics Class 11 Solutions CHSE Odisha Chapter 8 Permutations and Combinations Ex 8(c) Textbook Exercise Questions and Answers.

CHSE Odisha Class 11 Math Solutions Chapter 8 Permutations and Combinations Exercise 8(c)

Question 1.
Compute the following :
(i) 12C3
Solution:
12C3 = \(\frac{(12) !}{3 ! 9 !}=\frac{12 \cdot 11 \cdot 10}{3 \cdot 2}\) = 220

(ii) 15C12
Solution:
15C12 = \(\frac{(15) !}{(12) ! 3 !}=\frac{15 \cdot 14 \cdot 13}{3 \cdot 2}\)
= 5.7.13 = 455

(iii) 9C4 + 9C5
Solution:
9C4 + 9C5 = \(\frac{9 !}{4 ! 5 !}+\frac{9 !}{5 ! 4 !}\)
\(=\frac{9 \cdot 8 \cdot 7 \cdot 6}{4 \cdot 3 \cdot 2 \cdot 1}\) × 2 = 252

(iv) 7C3 + 6C4 + 6C3
Solution:
7C3 + 6C4 + 6C3 = 7C3 + 6C4 + 6C4-1
= 7C3 + 6+1C4 = 7C3 + 7C4
(∴ ncr + nCr-1– = n+1cr)
= 7C4 + 7C4-1 = 7+1C4
= 8C4 = \(\frac{8 !}{4 !(8-4) !}=\frac{8 \cdot 7 \cdot 6 \cdot 5}{4 \cdot 3 \cdot 2 \cdot 1}\) = 70

(v) 8C0 + 8C1 + …….. + 8c8
Solution:
8C0 + 8C1 + …….. + 8c8 = 28 = 256

CHSE Odisha Class 11 Math Solutions Chapter 8 Permutations and Combinations Ex 8(c)

Question 2.
Solve :
(i) nC4 = nC11 ;
Solution:
nC4 = nC11 ;  (∴ n = 4 + 11 = 15)

(ii) 2nC3 : nC3 = 44: 5
Solution:
2nC3 : nC3 = \(\frac{44}{5}\)
⇒ \(\frac{2 n !}{2 n-3 !} / \frac{n !}{n-3 !}=\frac{44}{5}\)
CHSE Odisha Class 11 Math Solutions Chapter 8 Permutations and Combinations Ex 8(c)

Question 3.
Find n and r if nPr = 1680, nCr = 70.
Solution:
nPr = 1680, nCr = 70
∴ \(\frac{{ }^n \mathrm{P}_r}{{ }^n \mathrm{C}_r}=\frac{1680}{70}\)
or, r ! = 24 = 4!
∴ r = 4
Again, nCr = 70 or nC4 = 70
or, \(\frac{n !}{4 !(n-4) !}=70\)
or, n(n – 1) (n – 2) (n – 3)
= 70 × 4! = 7 × 10 × 4 × 3 × 2
= 8 × 7 × 6 × 5
or, n(n – 1) (n – 2) (n – 3)
or, 8(8 – 1) (8 – 2) (8 – 3)
∴ n = 8

Question 4.
How many diagonals can an n-gon(a polygon with n sides) have?
Solution:
A polygon of n – sides has n vertices.
∴ The number of st. lines joining the n-vertices is nC2.
∴ The number of diagonals is nC2 – n
CHSE Odisha Class 11 Math Solutions Chapter 8 Permutations and Combinations Ex 8(c) 1

Question 5.
If a set A has n elements and another set B has m elements, what is the number of relations from A to B?
Solution:
If |A| = n, |B| = m
then |A × B| = mn
∴ The number of possible subsets of
A × B = 2mn
∴ The number of relations from A to B is 2mn.

CHSE Odisha Class 11 Math Solutions Chapter 8 Permutations and Combinations Ex 8(c)

Question 6.
From five consonants and four vowels, how many words consist of three consonants and two vowels?
Solution:
Words of consisting of 3 consonants and 2 vowels are to be formed from five consonants and 4 vowels.
∴ The number of ways = 5C3 × 4C2
Again, 5 letters can be arranged among themselves in 5! ways.
∴ The total number of ways
= 5C3 × 4C2 × 5! = 10 × 6 × 120 = 7200.

Question 7.
In how many ways can a committee of four gentlemen and three ladies be formed out of seven gentlemen and six ladies?
Solution:
A committee of 4 gentlemen and 3 ladies is to be formed out of 7 gentlemen and 6 ladies.
∴ The number of ways in which the committee can be formed.
7C4 × 6C3 = \(\frac{7 \cdot 6 \cdot 5}{3.2} \times \frac{6 \cdot 5 \cdot 4}{3 \cdot 2}\) = 700

Question 8.
A bag contains 4 black and 5 white balls out of which 6 balls are drawn arbitrarily. In how many ways can this be done? Find also the number of ways such that at least 3 black balls can be drawn.
Solution:
A bag contains 4 black and 5 white balls out of which 6 balls are drawn arbitrarily.
∴ The number of ways in which balls are drawn \({ }^9 \mathrm{C}_6=\frac{9 \cdot 8 \cdot 7}{3 \cdot 2 \cdot 1}\) = 84 as the total number of balls is 9. If at least 3 black balls are drawn, then the drawing can be made as follows.

Black(4) White(5)
3 3
4 2

The number of ways in which at least 3 black balls are drawn
= (4C3 × 5C3) + (4C4 × 5C2)
= (4 × 10) + (1 × 10) = 50

Question 9.
How many triangles can be drawn by joining the vertices of a decagon?
Solution:
A decagon has 10 vertices and 3 noncollinear points are required to be a triangle.
∴ The number of triangles formed by the joining of the vertices of a decagon is
10C3 = \(\frac{10 !}{3 ! 7 !}=\frac{10 \cdot 9 \cdot 8}{3 \cdot 2 \cdot 1}\) = 120

Question 9.
How many triangles can be drawn by joining the vertices and the center of a regular hexagon?
Solution:
A regular hexagon has six vertices. Triangles are to be formed by joining the vertices and center of the hexagon. So there is a total of 7 points. So the number of triangles formed.
7C3 = \(\frac{7 !}{3 ! 4 !}=\frac{7 \cdot 6 \cdot 5}{3 \cdot 2 \cdot 1}\) = 35
As the hexagon has 3 main diagonals, which pass through the center hence can not form 3 triangles.
∴ The required number of triangles 35 – 3 = 32

Question 11.
Sixty points lie on a plane, out of which no three points are collinear. How many straight lines can be formed by joining pairs of points?
Solution:
Sixty points lie on a plane, out of which no. 3 points are collinear. A straight line required two points. The number of straight lines formed by joining 60 points is
60C2 = \(\frac{60 !}{2 \times 58 !}=\frac{60 \times 59}{2}\) = 1770

Question 12.
In how many ways can 10 boys and 10 girls sit in a row so that no two boys sit together?
Solution:
10 boys and 10 girls sit in a row so that no two boys sit together. So a boy is to be seated between two girls or at the two ends of the row. So the boys are to be sitted in 11 positions in 11C10 ways. Again 10 boys and 10 girls can be arranged among themselves in 10! and 10! ways respectively.
∴ The total number of ways = 11C10 × 10! × 10! = (11)! × (10)!

Question 13.
In how many ways can six men and seven girls sit in a row so that the girls always sit together?
Solution:
Six men and seven girls sit in a row so that the girls always sit together. Considering the 7 girls as one person, there are a total of 7 persons who can sit in 7! ways. Again the 7 girls can be arranged among themselves in 7! ways.
∴ The total number of arrangements
= 7! × 7!
= (7!)2

CHSE Odisha Class 11 Math Solutions Chapter 8 Permutations and Combinations Ex 8(c)

Question 14.
How many factors does 1155 have that are divisible by 3?
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 8 Permutations and Combinations Ex 8(c) 2
∴ In order to be a factor of 1155 divisible by 3, we have to choose one or two of 5, 7, and 11 along with 3 or 3 alone.
∴ The number of ways = 3C1 + 3C2 + 3C0 = 23 – 1 = 7
∴ The number of factors is 7 excluding 1155 itself.

Question 15.
How many factors does 210 have?
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 8 Permutations and Combinations Ex 8(c) 3
∴ We can choose at least one 2, 3, 5, or 7  to be a factor of 210.
∴ The number of factors.
= 4C1 + 4C2 + 4C3 + 4C4 = 24 – 1 = 15
∴ The number of factors is 210 is 15. (Including 215 itself and excluding 1).

Question 16.
If n is a product of k distinct primes what is the total number of factors of n?
Solution:
n is a product of k distinct primes.
∴ In order to be a factor, of n, we have chosen at least one of k distinct primes.
∴ The number of ways = kC1 + kC2 + ……… kCk-1 = 2k  – 1 – 1
∴ The number of factors of n is 2k – 2.
(Excluding 1 as 1 is not prime. It is also not include n.)

Question 17.
If m has the prime factor decomposition P1r1, P2r2 ….. Pnrn, what is the total number of factors of m (excluding 1)?
Solution:
m has the prime factor decomposition P1r1, P2r2 ….. Pnrn,
∴ m = P1r1, P2r2 ….. Pnrn,
P1 is a factor of m which occurs r1 times. Each of the factors P1r1 will give rise to (r1 + 1) factors.
Similarly
P2r2 gives (r2 + 1) factors and so on.
∴ The total number of factors (r1 + 1) (r2 + 1) ….. (rn + 1) – 1 (including m).

Question 18.
If 20! were multiplied out, how many consecutive zeros would it have on the right?
Solution:
If 20! were multiplied out, then the number of consecutive zeros on the right is 4. due to the presence of 4 x 5, 10, 14 x 15,20.

Question 19.
How many factors of 10,000 end with a 5 on the right?
Answer:
We have 1000 = 24 × 54 The factors of 10000 ending with 5 are 5, 5 × 5 = 25, 5 × 5 × 5 = 125
5 × 5 × 5 × 5 = 625
∴ There are 4 factors ending With 5.

Question 20.
A man has 6 friends. In how many ways can he invite two or more to a dinner party?
Solution:
A man has 6 friends. He can invite 2 or more of his friends to a dinner party.
∴ He can invite 2, 3, 4, 5, or 6 of his friends in
6C2 + 6C3 + 6C4 + 6C5 + 6C6 = 266C06C1
= 64 – 7 = 57 ways.

Question 21.
In how many ways can a student choose 5 courses out of 9 if 2 courses are compulsory?
Solution:
A student is to choose 5 courses out of 9 in which 2 courses are compulsory. as 2 courses are compulsory, he is to choose 3 courses out of 7 courses in 7C3 = 35 ways.

Question 22.
In how many ways can a student choose five courses out of the courses? C1, C2, …………. C9 if C1, C2 are compulsory and C6, C8 cannot be taken together?
Solution:
A student chooses five courses out of the courses? C1, C2, …………. C9 if C1, C2 are compulsory and C6, C8 cannot be taken together.
∴ He is to choose 3 courses out of C3, C4, ………… ,C8, C9.
Without taking any restrictions 3 courses out of C3, C4, …… C9, i.e. from 7 courses in 7C3 ways. If C6, C8 are taken together then one course only to be choosen from C3, C4, C5, C7, C9 by 5C1 ways. Hence required number of ways.
= 7C35C1
= \(\frac{7 \times 6 \times 5}{3 \times 2 \times 1}\) – 5
= 35 – 5 = 30 ways.

CHSE Odisha Class 11 Math Solutions Chapter 8 Permutations and Combinations Ex 8(c)

Question 23.
A cricket team consisting of 11 players is to be chosen from 8 batsmen and 5 bowlers. In how many ways can the team be chosen so as to include at least 3 bowlers?
Solution:
A cricket team consisting of 1 1 player is to be chosen from 8 batsmen and 5 bowlers, as to include at least 3 bowlers.
The selection can be made as follows :

Batsmen(8) Bowlers(5)
8 3
7 4
6 5

The number of selections is
(8C8 × 5C3) + (8C7 × 5C4) + (8C6 × 5C5)
= (1 × 10) + (8 × 5) + (28 × 1)
= 10 + 40 + 28 = 78

Question 24.
There are n + r points on a plane out of which n points lie on a straight line L and out of the remaining r points that lie outside L, no three points are collinear. What is the number of straight lines that can be formed by joining pairs of their points?
Solution:
There are n + r points on a plane out of which n points are collinear and out of which r points are not collinear.
∴ We can form a straight line by joining any two points.
n-collinear points form one line and r-non-collinear points form rC2 lines.
Again, each of the r non-collinear points when joined to each of the noncollinear points, forms n lines.
∴ The number of such limes is r x n.
∴ The total number of lines
CHSE Odisha Class 11 Math Solutions Chapter 8 Permutations and Combinations Ex 8(c) 4

Question 25.
There are 10 books in a shelf with different titles; five of these have red covers and others have green covers. In how many ways can these be arranged so that the red books are placed together?
Solution:
There are 10 books in a shelf with different titles, 5 of these are red covers and others are green covers considering 5 red-covered books as one book, we have a total of 6 books which can be arranged in 6! ways. The five red cover books are arranged among themselves in 5! ways.
∴ The total number of arrangements
= 5! x 6!

BSE Odisha 6th Class English Solutions Follow-Up Lesson 1 I Like Bats

Odisha State Board BSE Odisha 6th Class English Solutions Follow-Up Lesson 1 I Like Bats Textbook Exercise Questions and Answers.

BSE Odisha Class 6 English Solutions Follow-Up Lesson 1 I Like Bats

BSE Odisha 6th Class English Follow-Up Lesson 1 I Like Bats Text Book Questions and Answers

Session – 1 (ପ୍ରଥମ ପର୍ଯ୍ୟାୟ):
I. Pre-Reading (ପ୍ରାକ୍-ପଠନ):

→ Socialisation (ସାମାଜିକୀକରଣ):
→ The teacher thinks of a pre-reading activity.
(ଶିକ୍ଷକ ଏକ ପଢ଼ିବା ପୂର୍ବବର୍ତ୍ତୀ କାର୍ଯ୍ୟ ବିଷୟରେ ଚିନ୍ତା କରନ୍ତୁ ।)
Pre-reading
→ You may use pictures. You may also link the poem with the poem of the main lesson.
(ତୁମେ ଛବିଗୁଡ଼ିକୁ ବ୍ୟବହାର କରିପାର । ତୁମେ କବିତାଟିକୁ ମୁଖ୍ୟପାଠର କବିତା ସହ ଯୋଡ଼ିପାର ।)

→ What are there in the picture? What do they look like? That’s how bats sleep and rest hanging upside down. What an interesting way of resting and relaxing! Do you like to rest like bats hanging upside down?
(ଛବିରେ କ’ଣ ଅଛି ? ସେମାନେ କିପରି ଦେଖାଯାଉଛନ୍ତି ? ସେହିପରି ଭାବରେ ବାଦୁଡ଼ିମାନେ ଉପରୁ ତଳକୁ ଝୁଲିରହି ଶୁଅନ୍ତି ଏବଂ ବିଶ୍ରାମ ନିଅନ୍ତି । ବିଶ୍ରାମ ନେବା ଓ ନିଦ୍ରାଯିବାର କି କୌତୂହଳଜନକ ଉପାୟ ! ତୁମେ ବାଦୁଡ଼ିମାନଙ୍କ ପରି ଉପରୁ ତଳକୁ ଝୁଲିରହି ବିଶ୍ରାମ କରିବାକୁ ଭଲ ପାଅ କି ?)

→ In the poem ‘Mice’ the poet likes mice. Let’s read this poem to see if the poet likes bats.
(‘Mice” କବିତାରେ, କବି ମୂଷାମାନଙ୍କୁ ଭଲ ପାଇଛନ୍ତି । ଆସ ଆମେ ଏହି କବିତାଟି ପଢ଼ିବା ଏବଂ କବି ବାଦୁଡ଼ିମାନଙ୍କୁ ଭଲ ପାଆନ୍ତି କି ନାହିଁ ଦେଖୁବା ।)

BSE Odisha 6th Class English Solutions Follow-Up Lesson 1 I Like Bats

II. While-Reading (ପଢ଼ିବା ସମୟରେ ):
Follow the steps of the main lesson.
(ମୁଖ୍ୟ ବିଷୟର ସୋପାନଗୁଡ଼ିକୁ ଅନୁସରଣ କର ।)
TEXT (ବିଷୟବସ୍ତୁ):
Read the poem silently and answer the questions that follow.
(କବିତାଟିକୁ ନୀରବରେ ପଢ଼ ଏବଂ ପରବର୍ତ୍ତୀ ପ୍ରଶ୍ନଗୁଡ଼ିକର ଉତ୍ତର ଦିଅ ।)

textI like bats
Hanging upside down
Like rats. Like silk-cotton fruits
Swinging in wind
What a way to relax and rewind.
I wish I could
Do that
Like a bat
A way to find
After a day’s work
To relax and rewind
Upside down
Hang like bats.
I like bats
Hanging upside down
Like rats.
text 1
ଓଡ଼ିଆ ଉଚ୍ଚାରଣ :
ଆଇ ଲାଇକ୍ ବ୍ୟାଟ୍‌ସ୍
ହ୍ୟାଙ୍ଗିଙ୍ଗ୍ ଅପସାଇଡ୍ ଡାଉନ୍
ଲାଇକ୍ ମ୍ୟାଟ୍‌ସ୍ । ଲାଇକ୍ ସିଲ୍‌କ୍-କଟନ୍ ଫୁସ୍
ସୁଇଙ୍ଗିଙ୍ଗ୍ ଇନ୍ ଉଇଣ୍ଡ୍
ଦ୍ଵାଟ୍ ଏ ୱେ ଟୁ ରିଲାକ୍ସ ଆଣ୍ଡ ରିୱାଇଣ୍ଡ୍ ।
ଆଇ ଉଇସ୍ ଆଇ କୁଡ଼୍
ଡୁ ଦ୍ଯାଟ୍
ଲାଇକ୍ ଏ ବ୍ୟାଟ୍
ଏ ୱେ ଟୁ ଫାଇଣ୍ଡ୍
ଆଫ୍‌ଟର୍ ଏ ଡେ’ଜ୍ ୱାର୍କ
ଟୁ ରିଲାକ୍ସ ଆଣ୍ଡ ରିୱାଇଣ୍ଡ୍
ଅପ୍‌ସାଇଡ୍ ଡାଉନ୍
ଆଇ ଲାଇକ୍ ବ୍ୟାଟ୍‌ସ୍ ।
ହ୍ୟାଙ୍ଗିଙ୍ଗ୍ ଅଫ୍‌ସାଇଡ୍ ଡାଉନ୍
ଲାଇକ୍ ଗ୍ୟାସ୍ ।

BSE Odisha 6th Class English Solutions Follow-Up Lesson 1 I Like Bats

Knowing The Key Words (ମୁଖ୍ୟ ଶବ୍ଦଗୁଡ଼ିକୁ ଜାଣିବା):

like – ସଦୃଶ
bats – ବାଦୁଡି
hanging – ଫାଶୀ
upside – ଓଲଟା |
down – ତଳକୁ
like – ପରି
rats – ମୂଷା
silk – cotton – ଶିମିଳି-ତୁଳା
fruits – ଫଳ
swinging – ସୁଇଙ୍ଗ୍
in wind — ପବନରେ
could — କରିପାରନ୍ତି |
What a way — କି ଉପାୟ |
find — ଖୋଜିବା
relax — ବିଶ୍ରାମ କରିବା
day’s work — ଦିନର କାମ
rewind – ରିଭାଇଣ୍ଡ୍ |
wish — ଇଚ୍ଛା

ସାରକଥା | ଓଡ଼ିଆ ଅନୁବାଦ:
ମୁଁ ବାଦୁଡ଼ିମାନଙ୍କୁ ଭଲପାଏ
ସେମାନେ ଉପର ପାଖ ତଳକୁ କରି ଝୁଲୁଥା’ନ୍ତି ମୂଷାମାନଙ୍କ ସଦୃଶ । | ସେମାନେ ପବନରେ ଦୋଳି ଖେଳୁଥା’ନ୍ତି ଶିମିଳି ତୁଳା ଫଳଗୁଡ଼ିକ ପରି । | କି ସୁନ୍ଦର ଉପାୟ ବିଶ୍ରାମ କରିବାର ଏବଂ ପବନରେ ଦୋହଲିବାର । | ମୁଁ ଭାବୁଛି ମୁଁ ସେହିପରି କରି ପାରିଥା’ନ୍ତି ଏକ ବାଦୁଡ଼ି ପରି । | ଗୋଟିଏ ଦିନକର କାମ ପରେ ଏକ ଉପାୟ ଖୋଜି ପାଇବାକୁ ବିଶ୍ରାମ କରିବାକୁ ଏବଂ ପବନରେ ଦୋହଲିବାକୁ । | ଉପର ପାଖ ତଳକୁ କରି ଝୁଲୁଥା’ନ୍ତି ବାଦୁଡ଼ିମାନଙ୍କ ସଦୃଶ । ମୁଁ ଭଲପାଏ ବାଦୁଡ଼ିମାନଙ୍କୁ ଯେଉଁମାନେ ଉପର ପାଖ ତଳକୁ କରି ଝୁଲୁଥା’ନ୍ତି ମୂଷାମାନଙ୍କ ଭଳି ।

Comprehension Questions : (ବୋଧମୂଳକ ପ୍ରଶ୍ନବଳୀ)

The teacher is to try to frame his/her own questions. Here are some for him/her.
(ଶିକ୍ଷକ ତାଙ୍କର ନିଜର ପ୍ରଶ୍ନଗୁଡ଼ିକ ତିଆରି କରିବାକୁ ଚେଷ୍ଟା କରିବେ । ଏଠାରେ କେତେକ ତାଙ୍କ (ପୁ/ସ୍ତ୍ରୀ) ପାଇଁ ଅଛି ।)

Question 1.
How do bats hang?
(ବାଦୁଡ଼ିମାନେ କିପରି ଝୁଲୁଥା’ନ୍ତି ?)
Answer:
Bats hang upside down.

Question 2.
What are bats compared to ?
(ବାଦୁଡ଼ିମାନଙ୍କୁ କାହା ସହିତ ତୁଳନା କରାଯାଇଛି ?)
Answer:
Bats are compared to rats.

BSE Odisha 6th Class English Solutions Follow-Up Lesson 1 I Like Bats

Question 3.
Have you seen bats hanging upside down on trees in great numbers?
(ଗଛଗୁଡ଼ିକରେ ବାଦୁଡ଼ିମାନେ ବହୁ ସଂଖ୍ୟାରେ ଝୁଲି ରହିଥ‌ିବାର ତୁମେ ଦେଖୁଛ କି ?)
Answer:
Yes, we have seen bats hanging upside down on trees in great numbers.

Question 4.
Have you seen silk-cotton fruit hanging in great numbers? Do they look alike?
(ଶିମିଳି-ତୁଳା ଫଳ ବହୁ ସଂଖ୍ୟାରେ ଝୁଲୁଥ‌ିବା ତୁମେ ଦେଖୁଛ କି ? ସେଗୁଡ଼ିକ ଏକାପରି ଦେଖାଯାଆନ୍ତି କି ?)
Answer:
Yes, we have seen silk-cotton fruit hanging in great numbers. Really, they look alike.

Question 5.
What is the meaning of the word ‘rewind’? See the dictionary at the end of this lesson.
(‘ରିୱାଇଣ୍ଡ୍’ ଶବ୍ଦର ଅର୍ଥ କ’ଣ ? ଏହି ଅଧ୍ୟାୟର ଶେଷରେ ଥ‌ିବା ଅଭିଧାନ ବା ଶବ୍ଦାର୍ଥ ଦେଖ ।)
Answer:
The meaning of the word ‘rewind’ is taking a rest with occasional backward movement.
Teacher is to frame some questions from the second stanza.
(ଶିକ୍ଷକ ଦ୍ଵିତୀୟ ପଦରୁ କିଛି ପ୍ରଶ୍ନ ତିଆରି କରିବେ ।)

Session – 2 (ସୋପାନ – ୨)
III. Post-Reading (ପଢ଼ିସାରିବା ପରେ):
6. Writing (ଲେଖିବା ):

(a) Answer the following questions.
(ନିମ୍ନଲିଖ ପ୍ରଶ୍ନଗୁଡ଼ିକର ଉତ୍ତର ଦିଅ ।)

(i) How do bats hang ?
(ବାଦୁଡ଼ିମାନେ କିପରି ଝୁଲନ୍ତି ?)
Bats hang ______________________________________.
Answer:
Bats hang upside down.

(ii) What are bats compared to ?
(ବାଦୁଡ଼ିମାନଙ୍କୁ କାହା ସହ ତୁଳନା କରାଯାଇଛି ?)
Bats are ______________________________________.
Answer:
Bats are compared to rats.

BSE Odisha 6th Class English Solutions Follow-Up Lesson 1 I Like Bats

(iii) What swings in the wind?
(ପବନରେ କ’ଣ ଝୁଲିଥାଏ ?)
The silk – ______________________________________.
Answer:
The silk-cotton fruits swing in the wind.

(iv) Why does the poet like to hang like bats upside down?
(କବି କାହିଁକି ବାଦୁଡ଼ିମାନଙ୍କ ପରି ଉପରପାଖ ତଳକୁ କରି ଝୁଲିବାକୁ ଭଲପାଆନ୍ତି ?)
______________________________________to relax and ____________________________.
Answer:
The poet likes to hang like a bats upside down because it is a nice way to relax and rewind.

(b) Let us summarise the poem. Fill in the gaps.
(ଆସ ଆମେ କବିତାର ସାରାଂଶ ବାହାର କରିବା । ଶୂନ୍ୟସ୍ଥାନଗୁଡ଼ିକୁ ପୂରଣ କର ।) (Question with Answer)

The poet _____________________to see bats. _____________________. Bats hang like _____________. This is a good way to relax and ____________. The poet wants to_____________ _____________bats to relax ________________ ________________after the day’s ________________.
Answer:
The poet likes to see bats. They are hanging upside down. Bats hang like rats and like silk-cotton fruits swinging in wind. This is a good way to relax and rewind. The poet wants to hang upside down like a bat to relax and rewind after the day’s work.

(c) Think of writing a poem. Start with replacing ‘bats’ with some fruits and make minimum changes in the poem. Change the title accordingly.
(ଗୋଟିଏ କବିତା ଲେଖିବା କଥା ଭାବ । ‘ବାଦୁଡ଼ିମାନଙ୍କ’’ ବଦଳରେ କେତେକ ଫଳକୁ ନେଇ ଏବଂ କବିତାରେ ସ୍ଵଳ୍ପ ପରିବର୍ତ୍ତନ କରି ଆରମ୍ଭ କର । ସେହି ଅନୁସାରେ କବିତାର ଶିରୋନାମା ପରିବର୍ତ୍ତନ କର ।)

APPLES
Answer:
I like apples
Hanging upside down
Like rats. Like silk-cotton fruits
Swinging in wind
What a way to relax and rewind.
I wish I could
Do that
Like an apple
A way to find
After a day’s work
To relax and rewind
Upside down Hang like apples.
I like apples
Hanging upside down
Like rats.

BSE Odisha 6th Class English Solutions Follow-Up Lesson 1 I Like Bats

Knowing The Key Words (ମୁଖ୍ୟ ଶବ୍ଦଗୁଡ଼ିକୁ ଜାଣିବା):
(The words/phrases have been defined mostly on contextual meanings.)

Nibble – gentle and playful bite of a mouse. ମୂଷାର କୁଟ୍ କୁଟ୍ କରି କାଟି ଖାଇବା
Pink – (colour) pale red, ଫିକା ନାଲି |
Swinging – hanging and moving (bats have)
relax and rewind – taking rest (with occassional backward movement) ଆରାମରେ ବିଶ୍ରାମ ନେବା
upside down – legs upward and head downward. ଗୋଡ଼ ଉପରକୁ ଓ ମୁଣ୍ଡ ତଳକୁ କରି ଓଲଟା ରହିବା ।

BSE Odisha 6th Class English Solutions Lesson 1 Mice

Odisha State Board BSE Odisha 6th Class English Solutions Lesson 1 Mice Textbook Exercise Questions and Answers.

BSE Odisha Class 6 English Solutions Lesson 1 Mice

BSE Odisha 6th Class English Lesson 1 Mice Text Book Questions and Answers

Session – 1 (ପ୍ରଥମ ପର୍ଯ୍ୟାୟ):
I. Pre-Reading (ପ୍ରାକ୍-ପଠନ):

→ Your teacher will introduce the poem in the following way.
S/he will ask the following questions:
Don’t you like a mouse? Why / Why not? Give reasons. Here is a poem on mice. Let us read, enjoy and see whether the poet likes or dislikes mice.
(ତୁମ ଶିକ୍ଷକ କବିତାଟିକୁ ନିମ୍ନଲିଖ୍ ଭାବରେ ଉପସ୍ଥାପନ କରିବେ । ସେ (ପୁ | ସ୍ତ୍ରୀ) ନିମ୍ନଲିଖିତ ପ୍ରଶ୍ନଗୁଡ଼ିକ ପଚାରିବେ : ତୁମେ ଗୋଟିଏ ମୂଷାକୁ ଭଲ ପାଅ ନାହିଁ କି ? କାହିଁକି | କାହିଁକି ନୁହେଁ ? କାରଣ ଦର୍ଶାଅ । ଏଠାରେ ମୂଷାମାନଙ୍କ ବିଷୟରେ ଗୋଟିଏ କବିତା ଅଛି । ଆସ ଆମେ ପଢ଼ିବା, ଉପଭୋଗ କରିବା ଏବଂ ଦେଖିବା କବି ମୂଷାମାନଙ୍କୁ ଭଲ ପାଆନ୍ତି କିମ୍ବା ଭଲପାଆନ୍ତି ନାହିଁ ।)

BSE Odisha 6th Class English Solutions Lesson 1 Mice

II. While-Reading (ପଠନକାଳୀନ ):

1. Your teacher will read the poem aloud, and you will listen to him/her without opening your books.
(ତୁମ ଶିକ୍ଷକ କବିତାଟିକୁ ବଡ଼ପାଟିରେ ପଢ଼ିବେ, ତୁମେ ତୁମ ବହି ନ ଖୋଲି ତାଙ୍କୁ (ପୁ | ସ୍ତ୍ରୀ) ମନଦେଇ ଶୁଣିବ ।)
2. S/he will read the poem aloud for the second time and you will listen to him / her following the poem in your books.
(ସେ (ପୁ | ସ୍ତ୍ରୀ) କବିତାଟିକୁ ଦ୍ଵିତୀୟ ଥର ପାଇଁ ବଡ଼ପାଟିରେ ପଢ଼ିବେ ଏବଂ ତୁମେ ତୁମ ବହିରେ କବିତାଟିକୁ ଅନୁସରଣ କରି ତାଙ୍କୁ (ପୁ | ସ୍ତ୍ରୀ) ମନଦେଇ ଶୁଣିବ ।)
3. Read the poem silently and try to answer the questions asked by your teacher.
(କବିତାଟିକୁ ନୀରବରେ ପଢ଼ ଏବଂ ତୁମ ଶିକ୍ଷକ ପଚାରିଥିବା ପ୍ରଶ୍ନଗୁଡ଼ିକର ଉତ୍ତର ଦେବାକୁ ଚେଷ୍ଟା କର ।)

Text (ପାଠ୍ୟବସ୍ତୁ):
ratI think mice
Are rather nice.
Their tails are long
Their faces small,
They haven’t any
Skins at all.
Their ears are pink,
Their teeth are white,
They run about
The house at night
They nibble things
They shouldn’t touch
And no one seems
To like them much.
But I think mice
Are nice.

ଓଡ଼ିଆ ଉଚ୍ଚାରଣ | କବିତା ପଠନ :
ଆଇ ଥ୍କ୍ ମାଇସ୍
ଆର୍ ରାଦର୍ ନାଇସ୍ ।
ଦେଆର୍ ଟେଲସ୍ ଆର୍ ଲଙ୍ଗ୍
ଦେଆର୍ ଫେସେସ୍ ସ୍କୁଲ୍,
ଦେ ହାଭଣ୍ଟ୍ ଏନି
ସ୍କିନସ୍ ଆଟ୍ ଅଲ୍ ।
ଦେଆର୍ ଇଅରସ୍ ଆର୍ ପିକ୍,
ଦେଆର୍ ଟିଥ୍ ଆର୍ ଦ୍ଵାଇଟ୍,
ଦେ ରନ୍ ଏବାଉଟ୍
ଦି ହାଉସ୍ ଆଟ୍ ନାଇଟ୍
ଦେ ନିବଲ୍ ଥ୍ଙ୍ଗସ୍
ଦେ ସୁଡ଼ଣ୍ଟ ଟଚ୍
ଆଣ୍ଡ୍ ନୋ ୱାନ୍ ସିମ୍‌
ଟୁ ଲାଇକ୍ ଦେମ୍ ମଚ୍ ।
ବଟ୍ ଆଇ ଥ୍ ମାଇସ୍
ଆର୍ ନାଇସ୍ ।

BSE Odisha 6th Class English Solutions Lesson 1 Mice

Knowing The Key Words (ମୁଖ୍ୟ ଶବ୍ଦଗୁଡ଼ିକୁ ଜାଣିବା):

think – କରିବା
mice – ମୂଷା
rather – ବରଂ
nice – ସୁନ୍ଦର
tails – ଲାଙ୍ଗୁଡ଼
long – ଲମ୍ବା
faces – ଚେହେରା
small – ଛୋଟ
any – କୌଣସି
skins – ଚର୍ମ
at all – ଆଦୌ
ears – କାନ
pink – ଗୋଲାପୀ |
teeth – ଦାନ୍ତ
white – ଧଳା
run about – ଚଲାନ୍ତୁ
house – ଘର
at night – ରାତିରେ
nibble – ନିବଲ୍
things – ଜିନିଷ
shouldn’t – ଉଚିତ ନୁହେଁ |
touch – ସ୍ପର୍ଶ କରନ୍ତୁ |
seems – ମନେହୁଏ |
like – ପରି
much – ବହୁତ

କବିତାର ସାରକଥା | ଓଡ଼ିଆ ଅନୁବାଦ:
ମୁଁ ଭାବୁଛି ମୂଷାମାନେ ବରଂ ସୁନ୍ଦର । ସେମାନଙ୍କର ଲାଞ୍ଜଗୁଡ଼ିକ ଲମ୍ବା । ସେମାନଙ୍କର ମୁହଁସବୁ ଛୋଟ । ସେମାନଙ୍କର ଆଦୌ ଚର୍ମ ନାହିଁ । ସେମାନଙ୍କର କାନଗୁଡ଼ିକ ପାଟଳ ରଙ୍ଗ । ସେମାନେ ରାତିରେ ଘରର ଏଣେତେଣେ ଘୂରିବୁଲନ୍ତି । ସେମାନେ ଜିନିଷଗୁଡ଼ିକୁ ଟିକେ ଟିକେ କାମୁଡ଼ନ୍ତି ଯେଉଁଗୁଡ଼ିକ ସେମାନେ ଛୁଇଁବା ଉଚିତ ନୁହେଁ । କେହି ବୋଧହୁଏ ସେମାନଙ୍କୁ ବେଶୀ ଭଲ ପାଆନ୍ତି ନାହିଁ ।
କିନ୍ତୁ ମୁଁ ଭାବୁଛି ମୂଷାମାନେ ସୁନ୍ଦର ଅଟନ୍ତି ।

Comprehension Questions (ବୋଧପରିମାପକ ପ୍ରଶ୍ନବଳୀ):

Question 1.
What is the poem about ?
(କବିତାଟି କେଉଁ ବିଷୟରେ ଆଧାରିତ ?)
Answer:
The poem is about mice.

Question 2.
Who is “I” in the first line of the poem?
(କବିତାର ପ୍ରଥମ ଧାଡ଼ିରେ ‘ମୁଁ’ (I) କିଏ ଅଟେ ?)
Answer:
In the first line of the poem ‘I’ means the poet.
Or, The poet is I in the first line of the poem.

BSE Odisha 6th Class English Solutions Lesson 1 Mice

Question 3.
What are the tails of mice like?
(ମୂଷାମାନଙ୍କର ଲାଞ୍ଜସବୁ କିପରି ଅଟେ ?)
Answer:
The tails of mice are long.

Question 4.
“They have no skin at all”. Does this mean that they have no skins or do they have very thin skins?
(‘‘ସେମାନଙ୍କର ପ୍ରାୟ ଆଦୌ ଚର୍ମ ନାହିଁ ।’’ ଏହା କ’ଣ ସେମାନଙ୍କର ଚର୍ମ ନଥିବା କିମ୍ବା ପତଳା ଚର୍ମ ଥ‌ିବାକୁ ବୁଝାଏ ?)
Answer:
They have no skin at all.’ It means that they have very thin skins.

Question 5.
What is the color of their ears?
(ସେମାନଙ୍କ କାନର ରଙ୍ଗ କିପରି ଅଟେ ?)
Answer:
The colour of their ears is pink.

Question 6.
Where do they run about at night ?
(ସେମାନେ ରାତିରେ କେଉଁଠି ଘୂରି ବୁଲନ୍ତି ?)
Answer:
They run about the house at night.

Question 7.
Which things do they nibble ?
(କେଉଁ ଜିନିଷଗୁଡ଼ିକୁ ସେମାନେ ଟିକିଟିକି କରି କାମୁଡ଼ି ଦିଅନ୍ତି ?)
Answer:
They nibble everything they find in the house. Those are cakes, vegetables, fruits, clothes, etc.

Question 8.
Do most people like mice? Why?
(ଅଧିକାଂଶ ଲୋକ ମୂଷାମାନଙ୍କୁ ଭଲ ପାଆନ୍ତି କି ? କାହିଁକି ?)
Answer:
No, most people do not like mice. Because they destroy many valuable things.

Question 9.
Does the poet like mice?
(କବି ମୂଷାମାନଙ୍କୁ ଭଲ ପାଆନ୍ତି କି ?)
Answer:
Yes, the poet likes mice.

BSE Odisha 6th Class English Solutions Lesson 1 Mice

Question 10.
Which line tells you so?
(କେଉଁ ଧାଡ଼ିଟି ତୁମକୁ ସେପରି କହେ ?)
Answer:
The last line, “But I think mice are nice” tells us so.

Question 11.
Which lines are repeated in this poem?
(ଏହି କବିତାରେ କେଉଁ ଧାଡ଼ିଗୁଡ଼ିକ ପୁନରାବୃତ୍ତି ହୋଇଛି ?)
Answer:
The first and last lines in this poem are repeated. They are “I think mice are rather nice.”

Session – 2 (ଦ୍ବିତୀୟ ପର୍ଯ୍ୟାୟ):
III. Post-Reading (ପଠନ ପରବର୍ତ୍ତୀ):

1. Visual Memory Development Technique (VMDT) :
(ଦୃଶ୍ୟ ସ୍ମୃତି ଉନ୍ନୟନ କୌଶଳ (VMDT))
Take a photograph of the poem in your eye cameras. Then put your index finger on the words/phrases your teacher says. Open your eyes and see whether your finger is on the right place. Repeat this activity for other words/phrases your teacher says.
(ତୁମ ଆଖ୍ ରୂପକ କ୍ୟାମେରାରେ କବିତାଟିର ଫଟୋଗ୍ରାଫ୍ ଉଠାଇନିଅ । ତା’ପରେ ତୁମ ବିଶି ଆଙ୍ଗୁଠିଟିକୁ ତୁମ ଶିକ୍ଷକ କହିଥିବା ଶବ୍ଦ | ଖଣ୍ଡବାକ୍ୟ ଉପରେ ରଖ । ତୁମ ଆଖ୍ ଖୋଲ ଏବଂ ଦେଖ ତୁମର ଆଙ୍ଗୁଠି ଠିକ୍ ସ୍ଥାନ ଉପରେ ଅଛି କି ନାହିଁ । ତୁମ ଶିକ୍ଷକ କହିଥିବା ଅନ୍ୟ ଶବ୍ଦ ବା ଖଣ୍ଡବାକ୍ୟ ପାଇଁ ଏହି କାର୍ଯ୍ୟ ପୁନରାବୃତ୍ତି କର ।)
Whole Text: Pink, nibble things, faces small, like them much, The lines repeated.

2. Comprehension Questions (ବୋଧପରିମାପକ ପ୍ରଶ୍ନବଳୀ) :

(a) MCQs: Choose the correct alternatives. (ସଠିକ୍ ବିକଳ୍ପଟିକୁ ବାଛ ।)
i. Mice don’t have ___________.
(a) thick skins.
(b) long tails.
(c) small faces.
(d) pink ears.
Answer:
(a) thick skins.

ii. Which of the following is not true?
(ନିମ୍ନଲିଖ ମଧ୍ୟରୁ କେଉଁଟି ଠିକ୍ ନୁହେଁ ?)
(a) The poet likes mice.
(b) very thin skins.
(c) No one likes mice.
(d) black skins.
Answer:
(b) Everyone likes mice.

BSE Odisha 6th Class English Solutions Lesson 1 Mice

iii. ‘They haven’t any skins at all’ means they have
(‘ସେମାନଙ୍କର ଚର୍ମ ଆଦୌ ନଥାଏ’ ବୁଝାଏ ଯେ ସେମାନଙ୍କର ______________ ଥାଏ ।)
(a) thick sinks.
(b) very thin skins.
(c) no skins at all.
(d) black skins.
Answer:
(b) very thin skins.

(b) Match items under column A with items under column B. Join them with lines. The first one is done for you.
(ସ୍ତମ୍ଭ ‘A’ ତଳେ ଥିବା ଶବ୍ଦ ସହ ସ୍ତମ୍ଭ ‘B’ ତଳେ ଥ‌ିବା ଶବ୍ଦକୁ ମିଳାଅ । ସେଗୁଡ଼ିକୁ ଗାର ଟାଣି ଯୋଗ କର । ପ୍ରଥମଟି ତୁମପାଇଁ କରିଦିଆଯାଇଛି ।)
(Question with Answer)
reading
Answer:
reading 1

Session – 3 (ତୃତୀୟ ପର୍ଯ୍ୟାୟ)
3. Listening (ମନଯୋଗ ସହକାରେ ଶୁଣିବା):
(a) Tick the words / phrases your teacher reads aloud.
(ତୁମ ଶିକ୍ଷକ ବଡ଼ ପାଟିରେ ପଢ଼ୁଥ‌ିବା ଶବ୍ଦ ବା ଖଣ୍ଡବାକ୍ୟଗୁଡ଼ିକୁ ଟିକ୍ ( ✓) ଚିହ୍ନ ଦିଅ ।)
mice, tails, skins, ears, pink, teeth, white, nibble, nice (Listen to your teacher and tick the words/phrases.)

(b) Your teacher reads aloud the first six lines of the poem. Fill in the gaps while listening to him/her.
(ତୁମ ଶିକ୍ଷକ କବିତାର ପ୍ରଥମ ଛଅ ଧାଡ଼ିକୁ ବଡ଼ପାଟିରେ ପଢ଼ିବେ । ତାଙ୍କୁ ଶୁଣିବା ସମୟରେ ଶୂନ୍ୟସ୍ଥାନଗୁଡ଼ିକୁ ପୂରଣ କର ।)
(Question with Answer)
I think _________.
Are rather _________
Their tails are _________
Their _________ small
They haven’t any
_________ at all.
Answer:
I think mice
Are rather nice
Their tails are long
Their faces small
They haven’t any
skins at all.

BSE Odisha 6th Class English Solutions Lesson 1 Mice

Session – 4 (ସୋପାନ — ୪)
4. Speaking (କହିବା):

  • Your teacher will read aloud one line, and you will repeat it after him/her. This is done twice.
    (ତୁମ ଶିକ୍ଷକ ଗୋଟିଏ ଧାଡ଼ି ପଢ଼ିବେ, ତୁମେ ତାଙ୍କ (ପୁ/ସ୍ତ୍ରୀ) ପଛରେ ପୁନରାବୃତ୍ତି କରିବ । ଏହିପରି ଦୁଇଥର କରାଯିବ ।)
  • Your teacher will read one line, you will read the next line, and so on.
    (ତୁମ ଶିକ୍ଷକ ଗୋଟିଏ ଧାଡ଼ି ପଢ଼ିବେ, ତୁମେ ତା’ପର ଧାଡ଼ି ପଢ଼ିବ ଏବଂ ଏହିପରି ଚାଲୁରହିବ ।)
  • Students sitting on the right side will read one line and students sitting on the left will read the next line and so on.
    (ଡାହାଣ ପାର୍ଶ୍ଵରେ ବସିଥିବା ଶିକ୍ଷାର୍ଥୀମାନେ ଗୋଟିଏ ଧାଡ଼ି ପଢ଼ିବେ ଏବଂ ବାମପାର୍ଶ୍ଵରେ ବସିଥିବା ଶିକ୍ଷାର୍ଥୀମାନେ ତା’ର ପରବର୍ତ୍ତୀ ଧାଡ଼ିଟି ପଢ଼ିବେ ଏବଂ ଏହିପରି ଚାଲୁ ରହିବ ।)

(b) Chaindrill: “I think mice are nice.”
(ଶୃଙ୍ଖଳ-ଅଭ୍ୟାସ : ‘‘ମୁଁ ଭାବୁଛି ମୂଷାମାନେ ସୁନ୍ଦର ।’’)

5.Vocabulary (ଶବ୍ଦସମ୍ଭାର):
Match the words/phrases under A with their opposite words under B. Join them with lines. The first one is done for you.
(ସ୍ତମ୍ଭ ‘A’ ତଳେ ଥିବା ଶବ୍ଦ | ଖଣ୍ଡବାକ୍ୟଗୁଡ଼ିକ ସହ ସ୍ତମ୍ଭ ‘B’ ତଳେ ଥ‌ିବା ସେମାନଙ୍କର ବିପରୀତ ଅର୍ଥବୋଧକ ଶବ୍ଦଗୁଡ଼ିକ ସହ ମିଳାଅ । ସେମାନଙ୍କୁ ଗାର ଟାଣି ଯୋଗ କର । ତୁମ ପାଇଁ ପ୍ରଥମଟି କରି ଦିଆଯାଇଛି ।)
vocubulary
Answer:
vocubulary 1

Session – 5 (ପଞ୍ଚମ ପର୍ଯ୍ୟାୟ)
6. Usage (ପ୍ରଚଳିତ ପ୍ରୟୋଗ):
(a) When we talk about one person, it is singular. But when we talk about more than one person or thing, it is plural. A thing or a person is made plural in the following ways :
(ଯେତେବେଳେ ଆମେ ଜଣେ ବ୍ୟକ୍ତି ବିଷୟରେ କହୁ, ଏହା ଏକବଚନ ଅଟେ । କିନ୍ତୁ ଯେତେବେଳେ ଆମେ ଏକାଧ୍ଵକ ବ୍ୟକ୍ତି କିମ୍ବା ଜିନିଷଗୁଡ଼ିକ ବିଷୟରେ କହୁ, ଏହା ବହୁବଚନ ଅଟେ । ଗୋଟିଏ ଜିନିଷ ବା ଜଣେ ବ୍ୟକ୍ତି ନିମ୍ନଲିଖିତ ଭାବରେ ବହୁବଚନରେ ପରିଣତ କରାଯାଏ ।)

(i) By adding “s” to the word: (ଶବ୍ଦରେ ‘s’ ଯୋଗକରି )
Singular      Plural
( ଏକବଚନ )   (ବହୁବଚନ)
cat (ବିରାଡ଼ି)   cats (ବିଲେଇମାନେ)
dog (କୁକୁର)  dogs (କୁକୁରମାନେ)

(ii) By adding “es” to the word: (ଶବ୍ଦରେ ‘es’ ଯୋଗକରି)
bus (ଯାତ୍ରୀଗାଡ଼ି)  buses (ଯାତ୍ରୀଗାଡ଼ିସବୁ)
bush (ବୁଦା)       bushes (ବୁଦାଗୁଡ଼ିକ)
mango (ଆମ୍ବ)   mangoes (ଆମ୍ବଗୁଡ଼ିକ)
box (ବାକ୍ସ)         boxes (ବାକ୍ସଗୁଡ଼ିକ)

(iii) By changing the spelling of the word :(ଶବ୍ଦର ବନାନରେ ପରିବର୍ତ୍ତନ କରି)
mouse (ମୂଷା)    mice (ମୂଷାମାନେ)
tooth (ଦାନ୍ତ)      teeth (ଦାନ୍ତଗୁଡ଼ିକ)

(iv) By not changing the word : (ଶବ୍ଦକୁ ପରିବର୍ତ୍ତନ ନକରି)
deer (ହରିଣ)    deer (ହରିଣମାନେ)
sheep (ମେଣ୍ଢା) sheep (ମେଣ୍ଢାଗୁଡ଼ିକ)

BSE Odisha 6th Class English Solutions Lesson 1 Mice

(b) Given below are some singular forms of some words used in this poem. Find out the plural forms of these words from the poem and write them against each of the words. (ନିମ୍ନରେ ଏହି କବିତାରେ ବ୍ୟବହାର କରାଯାଇଥିବା କେତେକ ଶବ୍ଦର ଏକବଚନ ରୂପଗୁଡ଼ିକ ଦିଆଯାଇଛି । କବିତାରୁ ଏହି ଶବ୍ଦଗୁଡ଼ିକର ବହୁବଚନ ରୂପଗୁଡ଼ିକୁ ଖୋଜି ବାହାର କର ଏବଂ ସେଗୁଡ଼ିକୁ ପ୍ରତ୍ୟେକ ଶବ୍ଦ ପାର୍ଶ୍ଵରେ ଲେଖ ।)
Match the following
Answer:
Match the following 1

Session – 6 (ଷଷ୍ଠ ପର୍ଯ୍ୟାୟ)
7. Writing (ଲିଖନାତ୍ମକ):
(a) Based on your matching above in-2 (b), Comprehension Activities, write some sentences. One is done for you. (ଉପରିସ୍ଥ ବୋଧମୂଳକ କାର୍ଯ୍ୟାବଳୀର 2 (b) ବିଭାଗରେ ତୁମର ମେଳକକୁ ଭିଭିକରି କେତେକ ବାକ୍ୟ ଲେଖ । ଗୋଟିଏ ତୁମ ପାଇଁ କରି ଦିଆଯାଇଛି ।)

Tails …………………………………… long
Tails of mice are long. (Question with Answer)
Face __________________________
Skin __________________________
Ear __________________________
Teeth __________________________.
Run about __________________________
Nibble things __________________________

Answer:
Face Faces of mice are small.
Skin Mice haven’t any skins at all.
Ear Ears of mice are pink.
Teeth  Teeth of mice are white.
Run about They run about the house at night.
Nibble things They nibble things they shouldn’t touch.

BSE Odisha 6th Class English Solutions Lesson 1 Mice

(b) Fill in the gaps using the words given. The first one is done for you. (ଦିଆଯାଇଥ‌ିବା ଶବ୍ଦଗୁଡ଼ିକୁ ବ୍ୟବହାର କରି ଶୂନ୍ୟସ୍ଥାନଗୁଡ଼ିକୁ ପୂରଣ କର । ପ୍ରଥମଟି ତୁମ ପାଇଁ କରି ଦିଆଯାଇଛି ।)
(Do not see the poem while doing this task)
(ଯେତେବେଳେ ଏହି କାର୍ଯ୍ୟଟି କରୁଛ, କବିତାଟିକୁ ଦେଖ ନାହିଁ ।)
writing
Answer:
writing 1

Session – 7 (ସୋପାନ – ୭):
(c) The poet likes mice. However, you don’t like them. Rewrite the poem expressing your dislikes. The first two lines are done for you.
(କବି ମୂଷାମାନଙ୍କୁ ଭଲ ପାଆନ୍ତି । ଯାହା ହେଉନା କାହିଁକି, ତୁମେ ସେମାନଙ୍କୁ ପସନ୍ଦ କରନାହିଁ । ତୁମର ନାପସନ୍ଦଗୁଡ଼ିକୁ ପ୍ରକାଶ କରି କବିତାଟିକୁ ଆଉଥରେ ଲେଖ । ପ୍ରଥମ ଦୁଇଟି ଧାଡ଼ିକୁ ତୁମ ପାଇଁ କରି ଦିଆଯାଇଛି ।)
I think mice
Are not nice.
_____________________________________________
_____________________________________________
_____________________________________________
_____________________________________________
_____________________________________________
_____________________________________________
_____________________________________________
_____________________________________________
Answer:
Their tails are long.
Their faces small.
They haven’t any skins at all.
Their ears are pink.
Their teeth are white.
They run about
The house at night
They nibble things
They shouldn’t touch
And no one seems
To like them much.
And I also think
mice Are not nice.

BSE Odisha 6th Class English Solutions Lesson 1 Mice

Session – 8 (ସୋପାନ – ୮):
(d) Write the answers to the following questions.
(ନିମ୍ନଲିଖତ ପ୍ରଶ୍ନଗୁଡ଼ିକର ଉତ୍ତର ଲେଖ ।)

(i) What is the poem about?
(କବିତାଟି କେଉଁ ବିଷୟରେ ଆଧାରିତ ? )
Answer:
The poem is about mice.

(ii) Who is “I” in the first line of the poem?
(କବିତାଟି ପ୍ରଥମ ଧାଡ଼ିରେ ‘ମୁଁ’ (I) କିଏ ?)
Answer:
In the first line of the poem, the word T is the poet.

(iii) What does the tail of a mouse look like?
(ଗୋଟିଏ ମୂଷାର ଲାଞ୍ଜଟି ଦେଖିବାକୁ କିପରି ଅଟେ ?)
Answer:
The tail of a mouse looks long.

(iv) Where do they run about at night?
(କେଉଁଠାରେ ସେମାନେ ରାତିରେ ଧାଆଁନ୍ତି ?)
Answer:
They run about the house at night.

(v) Which things do they nibble?
(କେଉଁ ଜିନିଷଗୁଡ଼ିକୁ ସେମାନେ ଟିକିଟିକି କରି କାମୁଡ଼ନ୍ତି ?)
Answer:
They nibble everything they find in the house. Those are cakes, vegetables, fruits, clothes, and books.

BSE Odisha 6th Class English Solutions Lesson 1 Mice

8. Mental Talk (ମାନସିକ କଥୋପକଥନ):
Mentally repeat the following line of the poem :
(ମନେ ମନେ କବିତାଟିର ନିମ୍ନଲିଖିତ ଧାଡ଼ିଟିକୁ ପୁନରାବୃତ୍ତି କର ।)
“I think mice are rather nice.”

9. Let Us Think (ଆସ ଆମେ ଭାବିବା ):
The poet likes mice. Do we like his / her attitude? Why?
(କବି ମୂଷାମାନଙ୍କୁ ଭଲ ପାଆନ୍ତି । ଆମେ ତାଙ୍କର (ପୁ/ସ୍ତ୍ରୀ) ମନୋଭାବକୁ ପସନ୍ଦ କରୁ କି ? କାହିଁକି ?)

CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a)

Odisha State Board Elements of Mathematics Class 11 CHSE Odisha Solutions Chapter 10 Sequences and Series Ex 10(a) Textbook Exercise Questions and Answers.

CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Exercise 10(a)

Question 1.
Which of the following in a sequence?
(i) f(x) = [x], x ∈ R
(ii) f(x) = |x|, x ∈ R
(iii) f(x) = \(\sqrt[n]{\pi}\) ,n∈ N
Solution:
(iii) f(x) = \(\sqrt[n]{\pi}\) ,n∈ N is a sequence f(n) : N → X, X ⊂ R.

Question 2.
Determine if (tn) is an arithmetic sequence if :
(i) tn = an2 + bn
Solution:
tn = an2 + bn
⇒ tn+1 = a(n + 1)2 + b(n – 1)
⇒ tn+1 – tn = a{(n + 1)2 – n2} + b{n + 1 – n}
= a(2n + 1) + b
Which is not independent of n.
∴ (tn) is not an A.P.

(ii) tn = an + b
Solution:
tn = an + b
⇒ tn+1 = a(n + 1) + b
Now tn+1 – tn
= {a(n + 1) + b} – {an + b}
= a (constant)
∴ (tn) is an arithmetic sequence.

(iii) tn = an2 + b
Solution:
tn = an2 + b
⇒ tn+1 = a(n + 1)2 + b
∴ tn+1 – tn = a[(n + 1)2 – n2] + b – b
= a(2n + 1)
(does not independent of n)
∴ (tn) is not an arithmetic sequence.

Question 3.
If a geometric series converges which of the following is true about its common ratio r?
(i) r > 1
(ii) -1 < r < 1
(iii) r > 0
Solution:
(ii) -1 < r < 1

Question 4.
If an arithmetic series ∑tn converges, which of the following is true about tn?
(i) tn < 1
(ii) |tn| < 1
(iii) tn = 0
(iv) tn → 0
Solution:
(iii) tn = 0

CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a)

Question 5.
Which of the following is an arithmetic-geometric series?
(i) 1 + 3x + 7x2 + 15x3+ ….
(ii) x + \(\frac{1}{2}\)x + \(\frac{1}{3}\)x2 + ….
(iii) x + (1 + 2)x2 + (1 + 2 + 3)x3 +…
(iv) x + 3x2 + 5x3 + 7x4 + …
Solution:
(iv) x + 3x2 + 5x3 + 7x4 + … is an arithmetic geometric series with a = 1, d = 2, r = x.

Question 6.
For an arithmetic sequence (tn) tp = q, tq = p, (p ≠ q), find tn.
Solution:
tp = q ⇒ a + (p – 1)d = q    ……(1)
tq = p ⇒ a + (q – 1)d = p    ……(2)
From (1) and (2) we have (p – q)d = q – p
⇒ d = (-1)
Putting d = (-1) in (1)
we have a = p + q – 1
∴ tn = a + (n – 1)d
= (P + q – 1) + (n – 1) (-1)
= p + q – n

Question 7.
For an arithmetic series, ∑an Sp = q and Sq = p (p ≠ q) find Sp+q
Solution:
Sp = q and Sq = p
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a)
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 1

Question 8.
The sum of a geometric series is 3. The series of squares of its terms have a sum of 18. Find the series.
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 2
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 3

Question 9.
The sum of a geometric series is 14, and the series of cubes of its terms have a sum of 392 find the series.
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 4
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 5
∴ The series is \(\sum_{n=1}^{\infty} \frac{7}{2^{n-1}}\)

CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a)

Question 10.
Find the sum as directed
(i) 1 + 2a + 3a2 + 4a3 + …..(first n terms(a ≠ 1))
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 6

(ii) 1 + (1 + x)y + (1 + x + x2)y2 + …..(to infinity)
Solution:
Let S = 1 + (1 + x)y + (1x + x2)y2 + …
⇒ Sn = 1 + (1 + 1 + x)y + (1 + x + x2)y2 + ……+(1 + x + …. xn-1)yn-1
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 7

(iii) 1 + \(\frac{3}{5}\) + \(\frac{7}{25}\) + \(\frac{15}{125}\) + \(\frac{31}{625}\) + …..(to infinity)
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 8
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 9

(iv) 1 + 4x + 8x2 + 13x3 + 19x4 + …..(to infinity). Assuming that the series has a sum for |x| < 1.
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 10

(v) 3.2 + 5.22 + 7.23 + …..(first n terms)
Solution:
Sn = 3.2 + 5.22 + 7.3 + ….n terms = 2[3 + 5.2 + 7.22 + ….n terms]
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 11

Question 11.
Find the sum of the infinite series.
(i) \(\frac{1}{1 \cdot 2}+\frac{1}{2 \cdot 3}+\frac{1}{3 \cdot 4}+\ldots\)
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 12
= 1 – \(\frac{1}{n+1}\)
∴ \(S_{\infty}=\lim _{n \rightarrow \infty} S_n=1\)

(ii) \(\frac{1}{1 \cdot 2 \cdot 3}+\frac{1}{2 \cdot 3 \cdot 4}+\frac{1}{3 \cdot 4 \cdot 5}+\ldots\)
Solution:
\(\frac{1}{1 \cdot 2 \cdot 3}+\frac{1}{2 \cdot 3 \cdot 4}+\frac{1}{3 \cdot 4 \cdot 5}+\ldots\)
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 13

(iii) \(\frac{1}{2 \cdot 5 \cdot 8}+\frac{1}{5 \cdot 8 \cdot 11}+\frac{1}{8 \cdot 11 \cdot 14}+\ldots\)
Solution:
Here tn = \(\frac{1}{(3 n-1)(3 n+2)(3 n+5)}\)
The denominator of tn is the product of 3 consecutive terms of A.P. Now multiplying and dividing by (3n + 5) – (3n – 1) we have
\(t_n=\frac{(3 n+5)-(3 n-1)}{6(3 n-1)(3 n+2)(3 n+5)}\)
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 14

(iv) \(\frac{3}{1^2 \cdot 2^2}+\frac{5}{2^2 \cdot 3^2}+\frac{7}{3^2 \cdot 4^2}+\ldots\) [Hint : take tn = \(\frac{2 n+1}{n^2(n+1)^2}=\frac{(n+1)^2-n^2}{n^2(n+1)^2}\)]
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 15

(v) \(\frac{1}{1 \cdot 5}+\frac{1}{3 \cdot 7}+\frac{1}{5 \cdot 9}+\ldots .\)
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 16
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 17
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 18

CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a)

Question 12.
Find Sn for the series.
(i) 1.2 + 2.3 + 3.4 + ….
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 19

(ii) 1.2.3 + 2.3.4 + 3.4.5 + …
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 20

(iii) 2.5.8 + 5.8.11 + 8.11.14 +…
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 21
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 22

(iv) 1.2.3.4 + 2.3.4.5 + 3.4.5.6 + …
[Hint : tn = (3n – 1) (3n + 2)(3n + 5)]
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 23

(v) 1.5 + 2.6 + 3.7 + …
[Hint: tn = n(n + 4) is not a product of two successive terms of an A.P. for the term following n should be n+1, not n+4. So the method of previous exercises is not applicable. Instead, write tn = n2 + 4n and find Sn = \(\sum_{k=1}^n k^2+4 \sum_{k=1}^n k\) applying formulae]
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 24
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 25

(vi) 2.3 + 3.6 + 4.11 + …
[Hint : Take tn = (n + 1) (n2 + 2)]
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 26

(vii) 1.32 + 2.52 + 3.72 + ….
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 27

Question 13.
Find the sum of the first n terms of the series:
(i) 5 + 6 + 8 + 12 + 20 + …
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 28
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 29

(ii) 4 + 5 + 8 + 13 + 20 + …
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 30

Question 14.
(i) Find the sum of the product of 1,2,3….20 taken two at a time. [Hint: Required sum = \(\frac{1}{2}\left\{\left(\sum_{k=1}^{20} k\right)^2-\sum_{k=1}^{20} k^2\right\}\)]
Solution:
We know that
(x1 + x2 + x3 + …. + xn)2
= (x21 + xn2 + … + x2n) + 2 (Sum of all possible Products taken two at a time)
∴ 2 (Sum of products of 1. 2, 3,…… 20 taken two at a time)
= (1 + 2 + 3 + … 20)2 – (12 + 22 + … + 202)
\(=\left(\frac{20 \times 21}{2}\right)^2-\frac{20(20+1)(40+1)}{6}\)
= (210)2 – 70 × 41
= 44100 – 2870 = 41230
∴ The required sum = \(\frac{41230}{2}\) = 20615

(ii) Do the same for 1, 3, 5, 7,….19.
Solution:
Here the required sum
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 31

Question 15.
If a = 1 + x + x2 + ….. and b = 1 + y + y2 + ….|x| <  1 and |y| <  1, then prove that 1 – xy + x2y2 + x3y3 + ….. =  \(\frac{a b}{a+b-1}\)
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 32

CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a)

Question 16.
If a, b, c are respectively the pth, qth, rth terms of an A.P., then prove that a(q – r) + b(r – p) + c(p – q) = 0
Solution:
Let the first term of an A.P. = A and the common difference = D.
According to the question
tP = a, tq = b, tr = c
⇒ A + (p – q)D = a      …..(1)
A + (q – 1)D = b           …..(2)
A + (r – 1)D = c            …..(3)
L.H.S = a(q – r) + b (r – p) + c (p – q)
= (A + (p – 1)D) (q – r) + (A + (q – 1)D)
(r- p) + (A + (r – 1)D) (p – q)
= A (q – r + r – p + p – q) + D [(p – 1)
(q – r) + (q – 1) (r – p) + (r – 1) (p – q)]
= D (pq – pr + qr – pq + pr – qr) – D (q – r + r – p + p – q) = 0

Question 17.
If \(\frac{1}{a}, \frac{1}{b}, \frac{1}{c}\) are in A.P. and a + b + c ≠ 0, prove that \(\frac{\mathbf{b}+\mathbf{c}}{\mathbf{a}}, \frac{\mathbf{c}+\mathbf{a}}{\mathbf{b}}, \frac{\mathbf{a}+\mathbf{b}}{\mathbf{c}}\) are in A.P.
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 33

Question 18.
If a2, b2, c2 are in A.P. Prove that \(\frac{1}{b+c}, \frac{1}{c+a}, \frac{1}{a+b}\) are in A.P.
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 34

Question 19.
If \(\frac{b+c}{a}, \frac{c+a}{b}, \frac{\mathbf{a}+\mathbf{b}}{c}\) are in A.P.,prove that \(\frac{\mathbf{1}}{\mathbf{a}}, \frac{\mathbf{1}}{\mathbf{b}}, \frac{\mathbf{1}}{\mathbf{c}}\) are inA.P.given a + b + c ≠ 0
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 35

Question 20.
If (b – c)2, (c – a)2, (a – b)2 are in A.P., prove that \(\frac{1}{b-c}, \frac{1}{c-a}, \frac{1}{a-b}\) are in A.P.
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 36

Question 21.
If a, b, c are respectively the sum of p, q, r terms of an A.P., prove that \(\frac{a}{p}(q-r)+\frac{b}{q}(r-p)+\frac{c}{r}(p-q)\) = 0
Solution:
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 37
CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a) 38

CHSE Odisha Class 11 Math Solutions Chapter 10 Sequences and Series Ex 10(a)

Question 22.
If a, b, c,d are in G.P., prove that (a2 + b2 + c2)(b2 + c2 + d2) = (ab + bc + cd)2.
Solution:
Let a, b, c, and d are in G.P.
Let the common ratio = r
⇒ b = ar, c = ar2, d = ar3
LHS = (a2 + b2 + c2) (b2 + c2 + d2)
= (a2 + a2r2 + a2r4) (a2r2 + a2r4 + a2r6)
= a4r2 (1 + r2 + r4)2
= (a2r + a2r3 + a2r5)2
= (a.ar + ar.ar2 + ar2.ar3)2
= (ab + bc + cd)2 = R.H.S. (proved)