# BSE Odisha 9th Class Maths Solutions Algebra Chapter 3 ବୀଜଗାଣିତିକ ପରିପ୍ରକାଶ ଓ ଅଭେଦ Ex 3(e)

Odisha State Board BSE Odisha 9th Class Maths Solutions Algebra Chapter 3 ବୀଜଗାଣିତିକ ପରିପ୍ରକାଶ ଓ ଅଭେଦ Ex 3(e) Textbook Exercise Questions and Answers.

## BSE Odisha Class 9 Maths Solutions Algebra Chapter 3 ବୀଜଗାଣିତିକ ପରିପ୍ରକାଶ ଓ ଅଭେଦ Ex 3(e)

Question 1.
ଠିକ୍ ଉକ୍ତି ପାର୍ଶ୍ୱସ୍ଥ କୋଠରି ମଧ୍ୟରେ ‘✓’ ଚିହ୍ନ ଓ ଭୁଲ ଉକ୍ତି ପାର୍ଶ୍ୱସ୍ଥ କୋଠରି ମଧ୍ୟରେ ‘✗’ ଚିହ୍ନ ଦିଅ ।

(i) $$\frac{x}{2}+\frac{y}{3}=\frac{x+y}{5}$$
ସମାଧାନ:

(ii) $$\frac{x}{y-z}-\frac{x}{z-y}$$ = 0
ସମାଧାନ:

(iii) $$\frac{1}{x-y}+\frac{1}{y-x}$$ = 0
ସମାଧାନ:

(iv) $$\frac{x-y}{z}+\frac{y-z}{x}+\frac{z-x}{y}$$ = 0
ସମାଧାନ:

(v) $$\frac{x-1}{x}+\frac{y-1}{y}=\frac{1}{y}-\frac{1}{x}$$
ସମାଧାନ:

(vi) $$\frac{1}{x-y}+\frac{1}{y-z}+\frac{1}{z-x}$$ = 0
ସମାଧାନ:

Question 2.
ସରଳ କର :

(i) $$\frac{1}{x+y}+\frac{1}{x-y}$$
ସମାଧାନ:
= $$\frac{x-y+x+y}{(x+y)(x-y)}=\frac{2 x}{x^2-y^2}$$

(ii) $$\frac{x}{x-y}-\frac{y}{x+y}$$
ସମାଧାନ:

(iii) $$\frac{a-b}{a b}+\frac{b-c}{b c}+\frac{c-a}{c a}$$
ସମାଧାନ:

(iv) $$\frac{x-y}{x+y}-\frac{x+y}{x-y}$$
ସମାଧାନ:

(v) $$\frac{1}{x^2-y^2}-\frac{1}{(x-y)^2}$$
ସମାଧାନ:

(vi) $$\frac{a^2}{a+b}$$ – a + b
ସମାଧାନ:

(vii) $$\frac{1}{x+2 y}+\frac{1}{x-2 y}+\frac{2 x}{4 y^2-x^2}$$
ସମାଧାନ:

(viii) $$\frac{a+b}{a-b}+\frac{a-b}{a+b}+\frac{a^2+b^2}{b^2-a^2}$$
ସମାଧାନ:

(ix) $$\frac{1}{x-1}-\frac{1}{x-1}+\frac{1}{x+2}-\frac{1}{x+2}$$
ସମାଧାନ:

(x) $$\frac{3 x+1}{x-3}-\frac{x-3}{3 x+9}-\frac{5 x^2+24 x}{2 x^2-18}$$
ସମାଧାନ:

Question 3.
ସରଳ କର :

(i) $$\frac{x^3 y}{a z^2} \times \frac{y^3 z}{b x^2} \times \frac{z^3 x}{c y^2}$$
ସମାଧାନ:
= $$\frac{x^4 y^4 z^4}{a b c x^2 y^2 z^2}=\frac{x^2 y^2 z^2}{a b c}$$

(ii) $$\frac{x-y}{x+y} \times \frac{x^2+x y}{x^2 y-y^3}$$
ସମାଧାନ:

(iii) $$\frac{x^3+y^3}{x^2-y^2} \times \frac{x^3-y^3}{x^4+x^2y^3+y^4}$$
ସମାଧାନ:

(iv) $$\frac{x^2-7 x+10}{x^2-5 x-14} \times \frac{x^3+8}{x^3-8}$$
ସମାଧାନ:

(v) $$\left(1+\frac{x}{y^2}+\frac{x^2}{y^2}\right)\left(1-\frac{x^2}{y^2}+\frac{x^2}{y^2}\right)\left(1-\frac{x^2}{y^2}\right)$$
ସମାଧାନ:

ବିକଳ୍ପ ସଣାଳା –

(vi) $$\frac{x^2-y^2}{x-z} \times \frac{x^2-z^2}{x y+y^2} \times\left(x+\frac{x y}{x-y}\right)$$
ସମାଧାନ:

(vii) $$\left(\frac{a+b}{a-b}-\frac{a-b}{a+b}\right) \times \frac{a^2-b^2}{2\left(a^2+b^2\right)}$$
ସମାଧାନ:

(viii) $$\left(\frac{\mathbf{x}}{\mathbf{x}+\mathbf{y}}+\frac{\mathbf{y}}{\mathbf{x}-\mathbf{y}}\right) \div\left(\frac{\mathbf{x}}{\mathbf{x}-\mathbf{y}}-\frac{\mathbf{y}}{\mathbf{x}+\mathbf{y}}\right)$$
ସମାଧାନ:

(ix) $$\frac{x^3+y^3}{(x-y)^2+3 x y} \div \frac{(x+y)^2-3 x y}{x^3-y^3} \times \frac{x y}{x^2-y^2}$$
ସମାଧାନ:

(x) $$\frac{(a+b)^2+(a-b)^2}{(a+b)^2-(a-b)^2} \div \frac{a^4-b^4}{2 a b(a-b)} \times \frac{a^2-b^2}{a}$$
ସମାଧାନ:

(xi) $$\frac{a^2+3 a-18}{a^2-4} \div \frac{a^2-36}{a^2-5 a-14}$$
ସମାଧାନ:

(xii) $$\frac{3 a^2+a-4}{2 a^2-a-3} \div \frac{3 a^2-2 a-8}{2 a^2-7 a+6}$$
ସମାଧାନ:

Question 4.
ସରଳ କର :

(i) $$\frac{1}{1+\frac{1}{1+\frac{1}{1-\frac{1}{x}}}}$$
ସମାଧାନ:

(ii) $$\frac{a}{a-\frac{a-1}{1-\frac{1}{a+1}}}$$
ସମାଧାନ:

(iii) $$\frac{y}{y^2-\frac{y^3-1}{y+\frac{1}{y+1}}}$$
ସମାଧାନ:

(iv) $$\frac{\mathbf{x}}{\mathbf{x}-\frac{1}{\mathbf{x}-\frac{\mathbf{x}}{\mathbf{1}+\mathbf{x}}}}$$
ସମାଧାନ: