Regular revision with Class 7 Maths MCQ with Answers and Ganita Prakash Class 7 Maths Chapter 3 A Peek Beyond the Point MCQ improves accuracy in objective exams.
MCQ on A Peek Beyond the Point Class 7
A Peek Beyond the Point MCQ Class 7
Class 7 Maths A Peek Beyond the Point MCQ
Question 1.
How many tenths make a unit?
(a) \(\frac{1}{10}\)
(b) 10
(c) 100
(d) 1
Solution:
(b) 10
We know, 1 unit = 10 one-tenths.
Question 2.
The value of \(4 \frac{4}{10}+7 \frac{3}{10}\) is:
(a) \(7 \frac{7}{10}\)
(b) \(11 \frac{7}{10}\)
(c) \(10 \frac{1}{10}\)
(d) \(7 \frac{17}{10}\)
Solution:
(b) \(11 \frac{7}{10}\)
We can write, \(4 \frac{4}{10}=\frac{44}{10} \text { and } 7 \frac{3}{10}=\frac{73}{10}\)
Now, \(4 \frac{4}{10}+7 \frac{3}{10}=\frac{44}{10}+\frac{73}{10}\)
= \(\frac{117}{10}=\frac{110}{10}+\frac{7}{10}=11+\frac{7}{10}=11 \frac{7}{10}\)
Question 3.
How is one-hundredth represented in decimal form?
(a) 0.01
(b) 0.001
(c) 1.0
(d) 0.1
Solution:
(a) 0.01
One-hundredth represents 100 parts of a unit, i.e. \(\frac{1}{100}=\frac{01}{100}\)
Here, number of zeros in denominator is 2.
So, putting decimal point in the numerator 2 places to the left, we get 0.01.
Thus, the decimal representation of one- hundredth is 0.01.
Question 4.
The place value of 5 in the decimal 11.485 is:
(a) Five-tenths
(b) Five-hundredths
(c) Five-thousandths
(d) Five-ones
Solution:
(c) Five-thousandths
The expanded form of 11.485 is:
11.485 = 10 × 1 + 1 × 1 + \(\left(4 \times \frac{1}{10}\right)\) + \(\left(8 \times \frac{1}{100}\right)+\left(5 \times \frac{1}{1000}\right)\)
Thus, the place value of 5 in the decimal 11.485 is five-thousandths, i.e. 0.005.
Question 5.
The decimal form of 729 hundredths is:
(a) 729
(b) 72.9
(c) 7.29
(d) None of these
Solution:
(c) 7.29
The decimal form of 729 hundredths is \(\frac{729}{100}\) = 7.29.
Question 6.
The decimal representation of \(\frac{3}{4}\) is:
(a) 0.75
(b) 0.85
(c) 0.65
(d) 0.95
Solution:
(a) 0.75
We have, \(\frac{3}{4}=\frac{3 \times 25}{4 \times 25}=\frac{75}{100}\) = 0.75
Question 7.
The place value of the digit 7 in the number 3.476 is:
(a) 7 ones
(b) 7 tenths
(c) 7 hundredths
(d) 7 thousandths
Solution:
(c) 7 hundredths
3.476 can he represented in the decimal place value chart as:
| Tens | Ones | . | Tenths | Hundredths | Thousandths |
| 3 | . | 4 | 7 | 6 |
Hence, the place value of the digit 7 in the number 3.476 is 7 hundredths, i.e. 0.07.
Question 8.
If a number line is divided into 10 equal parts between 3 and 4, then the decimal number at the 7th division is:
(a) 3.07
(b) 3.7
(c) 3.17
(d) 37
Solution:
(b) 3.7
The number line, divided into 10 equal parts between 3 and 4, is given as:
Thus, the decimal number at the 7th division is 3.7.
Question 9.
The greatest decimal number among the following is:
(a) 1.2
(b) 1.02
(c) 1.22
(d) 1.21
Solution:
(c) 1.22
The given decimal numbers are: 1.2, 1.02, 1.22, 1.21
Converting them to like decimals, we get 1.20, 1.02, 1.22, 1.21
Now, as the whole number part of all the decimal numbers is the same, i.e. 1, we compare the digits after the decimal point from left to right.
As 1.02 has 0 at the tenths place while other decimals have 2, 1.02 is the smallest.
Now, comparing the hundredths place of 1.20, 1.22, 1.21, we get
1.22 > 1.21 > 1.20 (As 2 >1 > 0)
Thus, 1.22 is the greatest among the given numbers.
Question 10.
Which of the following sequence is decreasing?
(a) 4.5, 4.55, 4.6
(b) 2.3, 2.2, 2.1
(c) 3.1, 3.0, 3.1
(d) 1.01,2.001,3.0001
Solution:
(b) 2.3, 2.2, 2.1
A sequence is decreasing if each term is smaller
than the one before it.
2.3, 2.2, 2.1 → each term decreases by 0.1 i.e. (2.3 > 2.2 > 2.1).
Thus, 2.3, 2.2, 2.1 is the decreasing sequence.
Question 11.
How can we express 0.5 hours in minutes?
(a) 50 minutes
(b) 45 minutes
(c) 25 minutes
(d) 30 minutes
Solution:
(d) 30 minutes
We know, 1 hour = 60 minutes
Thus, 0.5 hours = 0.5 × 60 = \(\frac{5}{10}\) × 60
= 30 minutes
Question 12.
Which of the following pairs of decimal numbers are equivalent?
(i) 0.5 and 0.500
(ii) 0.05 and 0.0500
(iii) 1.06 and 1.060
(iv) 0.06 and 0.600
Choose the correct option from the following:
(a) (i) and (iv)
(b) (ii) and (iii) only
(c) (i), (ii) and (iii)
(d) (i) and (iii) only
Solution:
(c) (i), (ii) and (iii)
We know that adding trailing zeros after the last non-zero digit of a decimal does not change its value. Thus,
(i) 0.5 and 0.500 are equivalent.
(ii) 0.05 and 0.0500 are equivalent.
(iii) 1.06 and 1.060 are equivalent.
(iv) 0.06 and 0.600 are not equivalent as 0.06 represents 6-hundredths, while 0.600 represents 6-tenths.
Question 13.
Which of these are correct comparisons of decimals?
(i) 0.70 = 0.7
(ii) 0.701 > 0.7
(iii) 0.65 < 0.605
(iv) 0.506 < 0.56
Choose the correct option from the following:
(a) (i) and (iii) only
(b) (ii) and (iv) only
(c) (i), (ii) and (iv)
(d) (i), (iii) and (iv)
Solution:
(c) (i), (ii) and (iv)
(i) 0.70 and 0.7 are equal in value, i.e. 7 tenths. Thus, this comparison is correct.
(ii) 0.701 is greater than 0.7 because it has a 1 in the thousandths place, while 0.7 has 0. Thus, this comparison is correct.
(iii) 0.65 is greater than 0.605, since 0.65 = 0.650. So, this comparison is incorrect.
(iv) 0.506 < 0.56, since 0.506 = 506 thousandths, and 0.56 = 560 thousandths. Thus, this comparison is correct.
Question 14.
Which of the following statements are true?
(i) The decimal number with the greater whole number part is greater.
(ii) Milligrams are used for measuring heavier weights like bags of rice, etc. while kilograms are used for very light weights like medicine dosage, etc.
(iii) 3.5 feet means 3 feet and 5 inches.
(iv) 2.4 hours means 2 hours 24 minutes.
Choose the correct option from the following:
(a) (ii) and (iv)
(b) (ii) and (iii)
(c) (i) and (iv)
(d) (i) and (iii)
Solution:
(c) (i) and (iv)
The decimal number with greater whole number part is greater. For example, 7.1 > 6.99 because 7 > 6.
Kilograms are used for heavier things (like bags of rice) while milligrams are used for very tiny weights (like medicine).
Since 1 foot =12 inches, 0.5 feet = 6 inches. So, 3.5 feet = 3 feet 6 inches.
0.4 hours = 0.4 × 60 = 24 minutes. So, 2.4 hours = 2 hours 24 minutes.
Thus, statements (i) and (iv) are true.
A Peek Beyond the Point Class 7 Assertion and Reason Questions
The following questions are Assertion and Reason based questions. Two statements are given, one labelled as Assertion (A) and the other is labelled as Reason (R). Select the correct answer to these questions from the codes (a), (b), (c) and (d) as given below.
(a) Both A and R are true and R is the correct explanation of A.
(b) Both A and R are true but R is not the correct explanation of A.
(c) A is true but R is false.
(d) A is false but R is true.
Question 1.
(A): Fractional part of a number is always less than 1.
(R): Decimal places represent values like
\(\frac{1}{10}, \frac{1}{100}, \frac{1}{1000},\) and so on. These are all parts of a whole.
Solution:
(a) Both A and R are true and R is the correct explanation of A.
Decimal places represent values like \(\frac{1}{10}, \frac{1}{100}, \frac{1}{1000},\)
and so on. These are a parts of a whole, they are less than 1.
That’s why fractional part of a number is always less than 1.
Thus, both Assertion (A) and Reason (R) are true, and Reason (R) is the correct explanation of Assertion (A).
Question 2.
(A): \(3 \frac{6}{100}\) is greater than \(3 \frac{6}{10}\).
(R): \(\frac{6}{100}\) has a larger denominator than \(\frac{6}{10}\).
Solution:
(d) A is false but R is true.
We can write \(3 \frac{6}{100}=\frac{306}{100}\) and \(3 \frac{6}{10}=\frac{36}{10}=\frac{360}{100}\)
Clearly, 360 > 306 ⇒ \(\frac{360}{100}>\frac{306}{100}\)
⇒ \(3 \frac{6}{10}>3 \frac{6}{100}\)
Thus, Assertion (A) is false.
Now, as 100 > 10, \(\frac{6}{100}\) has larger denominator than \(\).
Thus, Reason (R) is true.
Question 3.
(A): If we subtract 47.38 from 89.62, the whole number parts differ by 42, and the actual result is more than 41 and less than 43.
(R): When subtracting two decimal numbers, the result lies between one less than and one more than the difference of their whole number parts.
Solution:
(a) Both A and R are true and R is the correct explanation of A.
Whole number part of 89.62 = 89
Whole number part of 47.38 = 47
Difference of whole number parts
= 89 – 47 = 42
Actual difference: 89.62 – 47.38 = 42.24
Now, (42 – 1) < 42.24 < (42 + 1) i.e.
41 < 42.24 < 43.
Thus, both Assertion (A) and Reason (R) are true, and Reason (R) is the correct explanation of Assertion (A).
Question 4.
(A): 38 paise = ₹0.38
(R): One rupee =100 paise
Solution:
(a) Both A and R are true and R is the correct explanation of A.
We know that 1 rupee = 100 paise.
So, 1 paisa = \(\frac{1}{100}\) rupee
Therefore, 38 paise = ₹ \(\frac{38}{100}\) = ₹0.38
Hence, both Assertion (A) and Reason (R) are true, and Reason (R) is the correct explanation of Assertion (A).
A Peek Beyond the Point Class 7 Fill in the Blanks
Question 1.
The length \(2\frac{7}{10}\) cm is read as _____.
Solution: two and seven- tenths centimetres
The length \(2\frac{7}{10}\) cm is read as two and seven- tenths centimetres.
Question 2.
Kashvi cuts a 1-metre ribbon into 10 equal pieces. The length of one piece is ______ metre.
Solution: \(\frac{1}{10}\) or one-tenth
Given, length of ribbon is 1 metre and number of equal pieces is 10.
∴ Length of each piece = \(\frac{1}{10}\) metre
Thus, the length of one piece is \(\frac{1}{10}\) or one-tenth metre.
Question 3.
Fill in the blanks:
(i) __________ mm = 42.9 cm
(ii) 826 cm = ________ m
(iii) _____ g = 9.5 kg
(iv) 1834 mm = _____ cm
(v) 1749 g = ____ kg
(vi) ₹7 = _____ paise
(vii) ₹ 18.75 = ______ paise
(viii) ₹ _______ = 4250 paise
Solution: 429, 8.26, 9500, 183.4, 1.749, 700, 1875, 42.50
(i) We know that 1 cm = 10 mm.
Therefore, 42.9 cm = 42.9 × 10 mm
= \(\frac{429}{10}\) × 10 mm = 429 mm
(ii) We know that 1 cm = \(\frac{1}{100}\) m
Therefore, 826 cm = \(\frac{826}{100}\) m = 0.86 m
(iii) We know that 1 kg = 1000 g.
Therefore, 9.5 kg = 9.5 × 1000 g 95
= \(\frac{95}{10}\) × 1000 g = 9500 g
(iv) We know that 1 mm = \(\frac{1}{10}\) cm.
Therefore, 1834 mm = \(\frac{1834}{10}\) cm = 183.4 cm
(v) We know that 1 g = \(\frac{1}{1000}\) kg.
Therefore, 1749 g = \(\frac{1749}{100}\) kg = 1.749 kg
(vi) We know that 1 rupee = 100 paise.
Therefore, 7 rupees = 7 × 100 paise
= 700 paise
(vii) We know that 1 rupee =100 paise.
Therefore, ₹ 18.75 = 18.75 × 100 paise
= \(\frac{1875}{100}\) × 100 = 1875 paise
(viii) We know that 1 paise = \(\frac{1}{100}\) rupee
4250 paise = \(\frac{4250}{100}\) rupees = 42.50 rupees