Regular revision with Class 7 Maths MCQ with Answers and Ganita Prakash Class 7 Maths Chapter 1 Large Numbers Around Us MCQ improves accuracy in objective exams.
MCQ on Large Numbers Around Us Class 7
Large Numbers Around Us MCQ Class 7
Class 7 Maths Large Numbers Around Us MCQ
Question 1.
Which of the following numbers has 7 at the lakhs place?
(a) 7,50,812
(b) 70,15,902
(c) 5,74,210
(d) 52,08,701
Solution:
(a) 7,50,812
In 7,50,812, the digit 7 is at lakhs place.
In 70,15,902, the digit 7 is at ten lakhs place.
In 5,74,210, the digit 7 is at ten thousands place.
In 52,08,701, the digit 7 is at hundreds place.
Question 2.
(20 × 10,000) + (53 × 1,000) + (1 × 100) + (2 × 1) represents the number:
(a) 53,20,102
(b) 20,53,102
(c) 2,53,102
(d) 5,20,301
Solution:
(c) 2,53,102
(20 × 10,000) + (53 × 1,000) + (1 × 100) + (2 × 1) = 2,00,000 + 53,000 + 100 + 2
= 2,53,102
Question 3.
The correct way of writing ‘sixty five lakh nine thousand four hundred twenty two’ in numbers is:
(a) 65,90,422
(b) 65,09,422
(c) 6,59,422
(d) 65,40,922
Solution:
(b) 65,09,422
Sixty five lakh nine thousand four hundred twenty two = 65,09,422
Question 4.
10 million is equal to:
(a) 100 crore
(b) 1 lakh
(c) 100 lakh
(d) 10,000 lakh
Solution:
(c) 100 lakh
We know,
1 million = 10 lakh
Thus, 10 million =10 × 10 lakh = 100 lakh
Question 5.
The estimated difference of 1,76,346 and 3,865 rounded off to the nearest thousand is:
(a) 1,70,000
(b) 1,72,000
(c) 1,90,000
(d) 1,54,000
Solution:
(b) 1,72,000
1,76,346 is rounded off to nearest thousands as
1,76,000. [∵ At hundreds place, 3 < 5] 3,865 is rounded off to nearest thousands as 4.000. [∵ At hundreds place, 8 > 5]
Thus, estimated difference = 1,76,000 – 4,000
= 1,72,000
Question 6.
The product 974 × 95 will likely have:
(a) 3 digits
(b) 4 digits
(c) 6 digits
(d) 5 digits
Solution:
(d) 5 digits
Rounding 974 to nearest hundreds we get
1,0 and rounding 95 to nearest tens we get 100.
Thus, estimated product = 1,000 × 100
= 1,00,000.
So, the product will likely have five digits and it will be less than 1,00,000 as the numbers are rounded up and 1,00,000 is the smallest 6-digit number.
Verification: 974 × 95 = 92,530, which has five digits.
Question 7.
The estimated sum of 5,47,86,326 and 45,56,767 rounded off to the nearest lakhs is:
(a) 5,94,00,000
(b) 59,40,000
(c) 54,90,000
(d) 9,47,000
Solution:
(a) 5,94,00,000
5,47,86,326 is rounded off to nearest lakhs as
5,48,0,000. [∵ At ten thousands place, 8 > 5]
45,56,767 is rounded off to nearest lakhs as
46,0,000. [∵ At ten thousands place, 5 = 5]
Thus, estimated sum
= 5,48,00,000 + 46,00,000 = 5,94,00,000
Question 8.
The product 105 × 93 will likely have:
(a) 3 digits
(b) 4 digits
(c) 6 digits
(d) 5 digits
Solution:
(b) 4 digits
Rounding off 105 to nearest hundreds, we get 100 and rounding off 93 to nearest tens we get 90,
Thus, estimated product = 100 × 90 = 9,000
So, the product will likely have four digits and it will be close to 9,000.
Verification: 105 × 93 = 9,765, which has four digits.
Question 9.
1 billion is equal to:
(i) 100 crore
(ii) 100 million
(iii) 100 lakh
(iv) 10,000 lakh
Choose the correct option from the following:
(a) (i) and (iii)
(b) (ii) and (iii)
(c) (i) and (iv)
(d) (ii) and (iv)
Solution:
(c) (i) and (iv)
We know, 1 million = 10 lakh
And, 1 billion = 1,000 million
Thus, 1 billion = 1,000 × 10 lakh
= 10,000 lakh =100 crore [∵ 1 crore = 100 lakh]
Question 10.
In which of the following numbers the comma is placed incorrectly according to the Indian Number System?
(i) 23,56,76,145
(ii) 123,98,34,67
(iii) 780,444,112
(iv) 56,12,34,889
Choose the correct option from the following:
(a) (i) and (iv)
(b) (ii) and (iv)
(c) (i) and (iii)
(d) (ii) and (iii)
Solution:
(d) (ii) and (iii)
We know that while writing a number in Indian Number System, the commas are placed in 3-2-2-2… pattern from right to left.
In 23,56,76,145 and 56,12,34,889, the commas are placed in 3-2-2-2… pattern from right to left. They are written correctly according to Indian Number System.
However, in 123,98,34,67 the commas are not placed in 3-2-2-2… pattern from right to left.
Also, in 780,444,112 the commas are placed according to the International Number System,
i. e. in 3-3-3… pattern from right to left.
Thus, the commas are not placed correctly according to the Indian Number System in 123,98,34,67 and 780,444,112.
Large Numbers Around Us Class 7 Assertion and Reason Questions
The following questions are Assertion and Reason based questions. Two statements are given, one labelled as Assertion (A) and the other is labelled as Reason (R). Select the correct answer to these questions from the codes (a), (b), (c) and (d) as given below.
(a) Both A and R are true and R is the correct explanation of A.
(b) Both A and R are true but R is not the correct explanation of A.
(c) A is true but R is false.
(d) A is false but R is true.
Question 1.
(A): 1,000 notes of ₹100 are needed to make ₹ 1,00,000.
(R): Place value helps us break large numbers into smaller, meaningful parts.
Solution:
(b) Both A and R are true but R is not the correct explanation of A.
As ₹1 ,00,000 ÷ 100 = 1,000,
1,000 notes of ₹100 are needed to make ₹1,00,000.
Thus, Assertion (A) is true.
And we know that place value helps us to express larger numbers into smaller, meaningful parts.
Thus, Reason (R) is true, but Reason (R) is not the correct explanation of Assertion (A).
Question 2.
(A): The digit 6 in the number 9,645,123 has a place value of 600,000 in the International Number System.
(R): The place value of a digit is the product of the digit and its position value.
Solution:
(a) Both A and R are true and R is the correct explanation of A.
We know that the place value of a digit in the number system is found by multiplying the
digit with the value of the position it occupies.
Thus, in 9,645, 123, the place value of 6 is 6 × 100,000 = 600,000.
Hence, both Assertion (A) and Reason (R) are true, and Reason (R) is tile correct explanation of Assertion (A).
Question 3.
(A): When rounding 3,42,765 to the nearest lakhs, we get 4,00,000.
(R): Rounding to the nearest lakhs depends on the digit in the ten thousands place.
Solution:
(d) A is false but R is true.
When rounding 3,42,765 to nearest lakhs, we check the digit on the just right of lakhs place, i.e. the digit at the ten thousands place.
In 3,42,765, 4 is at ten thousands place and 4 < 5. So, the digit at the lakhs place, i.e. 3 remains unchanged.
Hence, if 3,42,765 is rounded off to nearest lakhs, we get 3,00,000.
Thus, Assertion (A) is false, but Reason (R) is true.
Question 4.
(A): If 98 × 102 is calculated, then the product will be very close to 10,000.
(R): Both numbers 98 and 102 are close to 100.
Solution:
(a) Both A and R are true and R is the correct explanation of A.
98 is rounded off to nearest tens as 100 and 102 is rounded off to nearest hundreds as 100. Thus, the product is estimated as 100 × 100 = 10,000.
This means that the actual product will be close to 10,000.
Thus, both Assertion (A) and Reason (R) are true, and Reason (R) is the correct explanation of Assertion (A).
Large Numbers Around Us Class 7 Fill in the Blanks
Question 1.
In one lakh, 1 is follwed by _____________________ zeros.
Solution: five
We know, 1 lakh = 1,00,000, where the digit 1 is followed by five zeros.
∴ In one lakh, 1 is followed by five zeros.
Question 2.
In the Indian Number Svswm, the correct way to write the number 9625084 is __________.
Solution: 96,25,084
In the Indian Number System, commas are placed in a 3-2-2-2… pattern from the right to left. This helps to separate the digits into hundreds, thousands, lakhs, crores, and so on.
Therefore, in the Indian Number System, the correct way to write the number 9625084 is 96,25,084.
Question 3.
The smallest 7—digit number is _______ lakh.
Solution: ten
The smallest 7-digit number is 10,00,000 i.e. ten lakh.
Question 4.
The largest 8—digit number is _________
Solution: 9,99,99,999
The largest 8-digit number is 9,99,99,999.
Question 5.
The place value of 5 in 7,005,380 is _________.
Solution: 5000
Given number is 7,005,380, which is represented in International Number System.
| Periods | Millions | Thousands | Ones | ||||||
| Place Name | HM | TM | M | HTh | TTh | Th | H | T | O |
| 7,005,380 | 7 | 0 | 0 | 5 | 3 | 8 | 0 | ||
Thus, the place value of 5 in 7,005,380 is 5 thousand = 5 × 1000 = 5000.
Question 6.
The expanded form of the number 76,70,905 is _________.
Solution: (7 × 10,00,000) + (6 × 1,00,000) + (7 × 10,000) + (9 × 100) + (5 × 1)
The expanded form of the number 76,70,905 is
(7 × 10,00,000) + (6 × 1,00,000) + (7 × 10,000) + (9 × 100) + (5 × 1).
Question 7.
In a crore, 1 is followed by ________ zeros.
Solution: seven
We know that 1 crore = 1,00,00,000, where 1 is followed by seven zeros.
∴ In a crore, 1 is followed by seven zeros.
Question 8.
If 728 is rounded off to the nearest hundreds, we get ________.
Solution: 700
In 728, the tens digit is 2 and 2 < 5. So, 7 at the hundreds place remains unchanged while rounded off to the nearest hundreds.
Thus, if 728 is rounded off to the nearest hundreds, we get 700.