CHSE Odisha Class 12 Alternative English Grammar Linking Devices

Odisha State Board CHSE Odisha Class 12 Alternative English Solutions Grammar Linking Devices Exercise Questions and Answers.

CHSE Odisha Class 12 Alternative English Grammar Linking Devices

What is linking devices?
The devices or tricks or principles that are used to link the sentences in a paragraph by suitable connectives is called linking devices.
Here, linking means connecting and devices means tricks of principles or methods.
There are different types of connectives, such as
(i) By the use of numbering system.
(ii) By the use of personal pronouns.
(iii) By the use of demonstrative.
(iv) By the use of adverbs or conjunctions.

CHSE Odisha Class 12 Alternative English Solutions Linking Devices

(i) By the use of numbering system.
We can link sentences by the use of words taken from numbering system. Such as – first, second, third etc. or numbering words like firstly, secondly, thirdly etc.
Example:
Trees help us many ways, firstly they provide us food, secondly they provide us shelter, thirdly we use tree branches as fire wood. We can link sentences by the use of personal pronouns like he, she, it, they etc.

(ii) By the use of personal pronouns.
Example:
Vivekananda began a whirlwind tour of India, he urged the necessity ofending the poverty of the masses.

(iii) By the use of demonstrative.
We can also link sentences by the use of demonstrative like this, that, these, those etc.
Example:
Have you visited Netaji’s birth place at Odia Bazar? This place attracts thousands of patriots each year.

(iv) By the use of adverbs or conjunctions.
We can also link sentences by the use of adverbs or conjunctions like at present, at the sometime, above, below in front of, however, therefore etc.
Example:
Our friend Pratap has secured 90% of marks in the +2 Arts, therefore, he should be welcomed in our college Annual Function.

CHSE Odisha Class 12 Alternative English Solutions Linking Devices

Some Common Connectives:
Some common connectives are given below:
as a result – on the other hand
for this – beside
in addition – either … or
of course – neither nor
in contrast – not only, but also

1. Addition:
also : 1 went to the lèstival with Mr. Patra, Mr. Patra’s son was also with us.
and : She was cooking and her baby was crying.
besides : Besides his salary, he got an allowance of Rs 5,OOO/ from his grand – ther.
further : He is not such a man who will help you. Further he is not present now.
moreover : I am not in a mood to take with them, moreover I am not well.
in addition (to): Mr. Ratha donated Rs 1,00,000/- lÓr the repairing of our game field. In addition to that he had promised to bear the cost of a gallery.

2. Contrast:
yet : I drove first yet, I could not reach the station in time.
Iit : I can’t do you work, but I can engage my friend. Who can help you to complete it.
still : It is true that he is not good still as a near one you must come forward to help ham
though : Though, he is poor, he is honest.
while : He is cruel while his brother is kind.
in spite of : In spite of his illness, he attended the examination in time.

3. Time:
till : He is determined to appear the examination till he passes it.
urtil : You should wait until his arrival.
aller : Police came after the thief has escaped.
when. : 1 saw him when he was playing cricket.
before : I was already there much before the guest arrived.
at last : He worked hard for many years. At least success and fame came to him.
by the time : By the time the doctor arrived, the patient was dead.
finally : At last, we admitted him in the village dispensaiy, finally we took him to district hospital.

4. Choice:
either…. or : Either he or my friend could attend the meeting.
neither …not : Neither Hari nor his sister is present in the school today.

5. Examples:
for example : Odisha is always neglected by the centre. For example, we can take the negligance of Ministry of Railways.
particularly : I like the plays of Shakespeare, particularly, the Macbeth, for instance : Some bacteria help us in many ways. For instance, milk is changed to curd by such a bacteria.
such as : Poets such as Gangadhar Meher, Gopabandhu, Madhusudan as famous in Odisha.

CHSE Odisha Class 12 Alternative English Solutions Linking Devices

6. Clarification
in other words : Our Principal is a strict disciplinarian. In other words, he wants his students to behave properly.

7. Cause:
because : He did not pass the examination, because he had not read mindfully,
as : Akash could not attend the meeting as he was ill.
since : Since he was sick, he could not attend the Governing Body Meeting,
for : The manager called him on last Sunday for he had an important discussion with him.

8. Intention:
in order that : The baby cried loudly in order that her mother would hurry to her.
so that : The baby who fell into the well shouted loudly so that others could hear him.

9. Effect/Consequence:
thus : Mukesh was selected in the district level in cricket.
so : Last night is rained heavily, so the road is muddy.
consequently : My bike was out of order in the way, Consequently I could not attend the meeting in time.
as a result : He has laboured hard, as a result he will fetch attractive marks.
therefore : You are doing exercise everyday, therefore, we expect a good health from you.

10. Purpose:
so that : We eat so that we can live.

11. Similarity:
likewise : Pratap studied hard, likewise, his brother also studied hard.
similarly : Mr. Mahapatra, purchased a Hero Honda Splendor, similarly, Mr. Panda purchased a similar one.

Task – 1
Read the following carefully. Underline the linking devices present in the text.

CHSE Odisha Class 12 Alternative English Solutions Linking Devices

Text:
Smoking which may be a pleasure for some people is a source of serious discomfort for their fellows. Further medical authorities express their concern about the effect of smoking on the health not only of those who smoke but also those who must involuntarily inhale the contribution of smokers to the atmosphere. As you are dull, lessly aware a considerable number of our students have joined together in an effort to persuade the university to ban smoking in the classrooms. I believe they are entirety right in their aim. However, I would hope that it is possible to achieve this by an appeal to reason and to concern for other rather than by regulation. Smoking is prohibited by city bye – laws in theatres and in halls used for showing .films as’ well as laboratories where there may be a fire hazard. Elsewhere it is upto our own good sense. I am therefore, asking you to maintain “No Smoking” in the auditorium, classroom and seminar rooms where you teach. This proof of your interest for their health and well – being is very important to a large number of students.

Answer:
Smoking which may be a pleasure for some people is a source of serious discomfort for; their fellows. Further medical authorities express their concern about the effect of smoking on the health not only of those who smoke but also those who must involuntarily inhale the contribution of smokers to the atmosphere. As you are dull, less aware a considerable number of our students have joined together in an effort to persuade the university to ban smoking in the classrooms. I believe they are entirely right in their aim.

However. I would hope that it is possible to achieve this by an appeal to reason and to concern for other rather than by regulation. moking is prohibited by city bye – laws in theatres and in halls used for showing films as well as laboratories where there may be a fire hazard. Elsewhere it is upto our own good sense. I am, therefore, asking you to maintain “No Smoking” in the auditorium, classroom and seminar rooms where you teach. This proof of your interest for their health and well – being is very important to a large number of students.

Task-2
Fill in the blanks by choosing the most appropriate connective from the alternatives given in brackets.
1. She is intelligent ____________ she is beautiful, (so, and, as a result).
2. He was indifferent to his friend’s needs ____________ there was a lot of bad feeling, (but, consequently, in other words)
3. She did not work hard ____________ she came out first in the final examination, (yet, consequently, in other words).
4. I rarely watch T. V. must programmes are terrible, (because, therefore, further)
5. Ramesh first called on his friend. He ____________ went to this station to receive his uncle, (then, till by that time)
6. Trees help us in many ways ____________ it provides us oxygen, (in other words, for example, further).
7. The party didn’t go all that well ____________ it was a disaster (likewise, moreover, in other words)

Answer:
1; She is intelligent and she is beautiful.
2. He was indifferent to his friend’s needs consequently there was a lot of bad feeling.
3. She did not work hard yet she came out first in the final examination.
4. I rarely watch T. V. because most programs are terrible,
5. Ramesh first called on his friend. He then went to this station to receive his uncle.
6. Trees help us in many ways. For example, it provides us with oxygen.
7. The party didn’t go all that well In other words it was a disaster

Task – 3
Use suitable linking devices (connectives) from the box to complete the text below.
also but meanwhile and
but also not only and however
since because in this way
Sita’s sister is an air hostess for a famous International Airline ____________. Sita wants to become one too ____________ She is still too young, the minimum age for an air hostess is twenty ____________. Sita is just over sixteen
____________ she has taken up a job in an office ____________ she ____________ attends evening classes ____________ she wants to improve her French and Japanese. ____________ foreign languages are an essential qualification for an air hostess.
She is gaining experience through her present job ____________ the office where she works is a travel agency. She is learning ____________ how to deal with people ____________ quite a lot about the places she one day hopes to visit.
Answer:
Sita’s sister is an air hostess for a famous International Airline and. Sita wants to become one too but she is still too young, the minimum age for an air hostess is twenty and. Sita is just over sixteen However she has taken up a job in an office meanwhile she also attends evening classes In this way she wants to improve her French and Japanese. Because foreign languages are an essential qualification for an air hostess.
She is gaining experience through her present job since the office where she works is a travel agency. She is learning not only how to deal with people but also quite a lot about the places she one day hopes to visit.

CHSE Odisha Class 12 Alternative English Solutions Linking Devices

Exercises

1. Linking words and phrases:
In the following letter, the linking words and phrases are missing. Choose the most appropriate phrase from the ones given below and use them appropriately.
Dear Akash,
Remember that I told you I was trying to get a job at ICTL? (1) ____________I finally managed to get one! Of course, I haven’t been working there long, (2) ____________ I can already tell that it’s a wonderful place to work. All the staff, (3) ____________ the directors are very friendly with everybody and (4) ____________ they have marvelous facilities for the employees, (5) ____________ there’s a bar and gum and lots of other things. I’m called the Safety Equipment Officer. It (6) ____________ sounds like an impressive title, but it’s not a very accurate description of what I do. My main job is to provide protective clothing, (7) ____________ overalls, helmets, and so on. I estimate what the different departments will need and (8) ____________ I order it from the suppliers, (9) ____________ I make sure that the various departments have everything they want. (10) ____________ stationery is also my responsibility. (11) ____________ I have the job very interesting. (12) ____________ I get the chance to go all over the factory and to meet everybody. ____________ (13) the play is a lot better than in my old job. (14) ____________ that’s my news. What about you? Drop me a line when you have time. Regards to your family, and best wishes to you.

1. (a) then (b) well (c) and
2. (a) but (b) because (c) so
3. (a) until (b) and (c) even
4. (a) so (b) what’smore (c) on the other hand
5. (a) for instance (b) however (c) even
6. (a) can (b) could (c) may
7. (a) such as (b) namely (c) as
8. (a) then (b) after (c) so
9. (a) by the way (b) anyway (c) in this way
10. (a) however (b) although (c) but
11. (a) secondly (b) in other words (c) also
12. (a) why (b) because (c) then
13. (a) besides (b) besides (c) on the other hand
14. (a) at the end (b) any way (c) after all

Answer:
DearAkash,
Remember that I told you I was trying to get a job at ICTL? (1) Well I finally managed to get one! Of course, I haven’t been working there long, (2) but I can already tell that it’s a wonderful place to work. All the staff, (3) even the directors are very friendly with everybody and (4) what’s more they have excellent facilities for the employees, (5) for instance there’s a bar and gum and lots of other things. I’m called the Safety Equipment Officer. It (6) may sound like an impressive title, but it’s not a very accurate description of what I do. My main job is to provide protective clothing, (7) such as overalls, helmets, and so on. I estimate what the different departments will need and (8) then I order it from the suppliers, (9) In this way I make sure that the various departments have everything they want. (10) however stationary is also my responsibility. (11) In other words I have the job very interesting. (12) Because I get the chance to go all over the factory and to meet everybody (13) Besides the play is a lot better than in my old job. (14) At the end that’s my news. What about your? Drop me a line when you have time. Regards to your family, and best wishes to you.

CHSE Odisha Class 12 Alternative English Solutions Linking Devices

2. Each of the following sentences has a blank where there should be a linking word or phrase. Put in one of the above words and phrases so that the relation between the two statements is made clear.
1. The pay and conditions are very good ____________ it’s only five minutes walk from where I live.
2. I didn’t apply for the job ____________ I didn’t think I had much chance of getting it.
3. A lot of professional groups, ____________ doctors and lawyers have strong associates that protest
members rights.
4. The hours are short, the pay’ is excellent and the people I work with the very nice ____________ it’s a great job.
5. You ____________ think it’s bring, but in fact, it’s very interesting.
6. All my relatives were at the wedding ____________ my cousins from Australia.
7. At first I didn’t feel happy with so much responsibility ____________ now I feel quite confident that I can manage.
8. There are several things that make it a nice place to live ____________ there’s a park right across the road.

Answer:
1. The pay and conditions are very good. Besides, it’s only five minutes walk from where I live.
2. I didn’t apply for the job, anyway I didn’t think I had much chance of getting it.
3. A lot of professional groups, such as doctors and lawyers have strong associates that protest members’ rights.
4. The hours are short, the pay is excellent, and the people I work with the very nice in other words it’s a great job.
5. You may think it’s boring, but in fact, it’s very interesting.
6. All my relatives were at the wedding. Even my cousins from Australia.
7. At first I didn’t feel happy with so much responsibility but now I feel quite confident that I can manage.
8. There are several things that make it a nice place to live what’s more there’s a park right across the road.

CHSE Odisha Class 12 Alternative English Solutions Linking Devices

3. Here are words or phrases to indicate logical relationship of thought. Use them in sentences of your own and explain what each signals to the reader.

so besides on the contrary
yet because in sum
though anyhow but
furthermore on the other hand for example

Answer:
So: Last night it rained heavily and the river flooded. So, I have to say back. Here, ‘so’ signals effect.
Yet: She prepared hard, yet she failed. Here ‘yet’ signals contrast.
though : Though he is poor he is always first to contribute for any social work. Here ‘though’ signals addition.
furthermore : He was honest, educated, furthermore he is rich. Here ‘furthermore’ signals addition.
besides : The company offers me an alluring salary. Besides it is very close to my dwelling place. Here ‘besides’ signals addition.
because : He could not come to our party, because his fàther was sick. Here ‘because’ signals cause.
any how : I know the work is difficult, but any how we have to accomplish it. Here ‘anyhow’ signals cause.
on the other hand : This talcum power is costly, on the other hand, its quality is poor. ‘Here’ on the other hand signals contrast.
on the contrary : Akash approached Mr. Patra for help, but on the contrary, Mr. Pratap scolded him. Here ‘on the contrary’ signals opposition.
in sum : Mr. Mahapatra has a scooter, a moped and a motor – cycle, in sum, he has three bikes with him. Here ‘in sum’ signals conclusion.
But : He is an honest man, but he is not punctual. Here ‘but’ signals contrast.
for example : Trees are our best friends, our survival completely depend on them, for example, they provide us with oxygen to breath, fruits, leaves and roots and food and cause rain. Here ‘for example’ signals clarification.

CHSE Odisha Class 12 Alternative English Grammar Phrasal Verbs

Odisha State Board CHSE Odisha Class 12 Alternative English Solutions Grammar Phrasal Verbs Exercise Questions and Answers.

CHSE Odisha Class 12 Alternative English Grammar Phrasal Verbs

Phrasal Verbs:
We have to remember the phrasal verbs with their meaning perfectly. Let us discuss some important phrasal verbs.

Intransitive:

1. break down: stop working.
Ex:-. My car broke down twice during our journey.
2. break out: start suddenly
Ex:- Cholera has broken out in our locality.
3. burst out: begin to do something suddenly
Ex:- The children burst out laughing.
4. come about: happen
Ex:- How did the accident come about?
5. come out: published, become known
Ex:- This magazine comes out once in a week. Our results came out yesterday.
6. come off: happen, take place
Ex:- My sister’s wedding came off in a grand way.
7. come on: say to encourage
Ex:- Come on, let’s try again.
8. come round: regain consciousness, cure, recover
Ex:- He is still unconscious. He has not come around.

CHSE Odisha Class 12 Alternative English Solutions Phrasal Verbs

9. die away: become weak, disappear gradually
Ex:- The noise gradually died away.
10. draw up: approach and stop
Ex:- A car drew up beside me.
11. drop in: call on somebody
Ex:- Why don’t you drop in and see me sometime?
12. drop out: withdraw
Ex:- Ajit has dropped out (of the team)
13. fall out: quarrel
Ex:- You should not fall out for such a trivial problem.
14. getaway: escape
Ex:- Two of the thieves got away.
15. get along: image
Ex:- It is very difficult to get along without money.
16. get on: make progress
Ex:- How are you getting on at college?
17. go off: explode
Ex:- Many people died when a bomb went off in the busy market area.
18. goon: continue
Ex:- The two friends, went on talking for hours.
19. go out: extinguish
Ex:- The lamp went out in the wind.
20. get up: the rise
Ex:- I get up early in the morning.
21. give in: surrender, accept defeat
Ex:- The tired soldiers finally gave in to their enemy.
22. give out: come to an end
Ex:- Our food supply gave out after a week.
23. give up: cease, stop, abandon
Ex:- I have given up smoking
24. hold on: maintain one’s position
Ex:- Out troops held on resolutely refusing to yield an inch.
25. look out: pay attention, be careful
Ex:- Look out: there is a heavy truck coming very fast behind us.
26. lookup: become better
Ex:- The weather is looking up now.

CHSE Odisha Class 12 Alternative English Solutions Phrasal Verbs

27. makeup: replace a loss
Ex: It will take a long time to make up the loss.
28. pull up: come to a stop
Ex:- The driver pulled up at the traffic lights.
29. put up: stay, live
Ex:- We are putting up in a small house.
30. run down: lose a store of energy
Ex:- The battery has run down.
31. run out: to come to an end
Ex:- All our food has run out.
32. set out / off: begin a journey
Ex:- We set out / off our journey early in the morning.
33. set in: begin
Ex:- The trains have set in early this year.
34. shut up: be quiet
Ex:- Shut up and leave me alone.
35. take off: leave the ground
Ex:- The airplane took off at 70’ clock.
36. turn up: come usually to a meeting
Ex:- The meeting was postponed, as only Haifa do-can people turned up.
37. wear out: became unfit for use
Ex:- This part of the machine has worn out. Cheap shoes wear out easily.

Transitive:

1. account for: give a reason for
Ex:- You must account for your absence at college yesterday.
2. agree with: be good for health.
Ex:- Egg does not agree with me.
3. break into: enter by force
Ex:- Thieves broke into our house last night.
4. (i) burst into: a sudden show of emotion.
Ex:- She burst into tears on getting the bad news.
(ii) to come in suddenly
Ex:- The angry men burst into my room and shouted at me.
5. call on: visit
Ex:- We called on our new neighbor yesterday.
6. come across: meet, find by chance.
Ex:- I come across some friends in the marketplace yesterday.

CHSE Odisha Class 12 Alternative English Solutions Phrasal Verbs

7. come over: influence
Ex:- He looks very sad, what has come over him?
8. count on: rely on
Ex:- Can I count on your help during my difficulties?
9. do without: manage without
Ex:- He can’t do without tea.
10. get on: progress, conduct
Ex:- How are you getting on with your study?
11. get over: to recover from an illness/loss/difficulty?
Ex:- Leena has not got over the shock of her husband’s death.
12. go into: investigate
Ex:- The auditors have gone into our accounts.
13. go through: read
Ex:- I have gone through this novel.
14. jump at: accept eagerly
Ex: The children jumped at the proposal of visiting Nandakanan.
15. keep off: remain at a distance
Ex:- Keep off the grass
16. live on: have as food
Ex:- A baby lives on milk only.
17. look after: take care of
Ex:- The old man has nobody to look after him.
18. look after: to consider
Ex:- I look up to Rajesh as my own brother.
19. look into: examine carefully
Ex:- The police are looking into the theft at present.
20. look for: try to find
Ex:- I looked for my lost pen but found it nowhere
21. standby: help
Ex:- If they trouble you we’ll stand by you.

CHSE Odisha Class 12 Alternative English Solutions Phrasal Verbs

22. stand for: represent
Ex:- M.O. stands for a money order.
23. take after: resemble, look alike
Ex:- The baby takes after its mother.
24. take to: start a habit
Ex:- Rahul has taken to drinking after his wife’s death.

Verb + Object + Particle

1. answer back: reply rudely
Ex:- It is not good to answer your parent’s back.
2. count in: include
Ex:- If you are going to the circus, count me in.
3. order about: call to do something
Ex:- Don’t try to order me about, I am not your servant.
4. take for: mistake
Ex:- My aunt took me forAnil.
5. fell apart: consider separate
Ex:- I have never been able to fall the two brothers apart.
6. try on: put on a garment to see whether it fits
Ex:- You must try these shoes on before you buy them.

Verb + Particle + Object
(Or)
Verb + Object + Practical

1. blow up: break into pieces by an explosion
Ex:- The bridge was blown up by enemy soldiers.
2. bring about: cause to happen
Ex:- The new principal brought about several changes in the college.
3. bring out: Publish
Ex:- My father will bring out a new book next week.
4. bring up: rear, educate
Ex:- The mother worked hard to bring up her children.
5. call off: cancel
Ex:- We called off the strike after an agreement with the government.
6. carry on: Continue
Ex:- Smita carried on singing for a long time.

CHSE Odisha Class 12 Alternative English Solutions Phrasal Verbs

7. carry out: obey, do successfully
Ex:- You should carry out the order of your parents.
8. cut down: diminish, reduce
Ex:-You should cut down your expenses.
9. give up: stop
Ex:- You should give up smoking.
10. keep up: maintain, retain
Ex:- You should keep up the glory of your motherland.
11. keep away: remain at a distance Ex:- Keep away the children from fire.
12. lay by: keep for future use
Ex:- You should lay by something for old age.
13. leave out: omit
Ex:- You can leave out the questions you can not answer.
14. let down: opposite of back up.
Ex:- You have promised to stand by me. You won’t let me down, will you?
15. let off: not punish
Ex:- I’ll let you off this time, but I’ll punish you if you do it again.
16. lookup: search for a word in a dictionary.
Ex:- Look up a word in a dictionary, if you do not know its meaning.
17. make out: understand
Ex:- Can you make out the meaning of this sentence?
18. makeup: replace a loss
Ex:- It will take a long time to make up for the loss.
19. make over: to hand over charges
Ex:- The outgoing Principal made over the charge to the new Principal
20. pack up: stop working
Ex:- It is time to pack up and go home.
21. pick out: choose
Ex:- She picked out a frock that she liked most.
22. pulldown: Destroy
Ex:- The old building was pulled down.
23. put on: begin to wear, and dress oneself.
Ex:- Don’t forget to put your coat on.
24. put down: suppress by force
Ex:- The violent agitation was put down in no time.

CHSE Odisha Class 12 Alternative English Solutions Phrasal Verbs

25. put off: postpone, keep for a later time.
Ex:- Don’t put off today’s work for tomorrow.
26. put out: extinguish
Ex:- Put out the light before you sleep.
27. run over: knockdown – by traffic.
Ex:- Hundreds of pedestrians are run over in the streets every year.
28. setup: establish
Ex:- The government has set up a hospital in our village.
29. take in: cheat
Ex:- He was taken in by the shopkeeper.
30. takeoff: remove clothes, hat, etc.
Ex:- Take off your shoes before entering a temple.
31. take over: accept the duty
Ex:- Ramesh, took over the business from his father.
32. turndown: reject
Ex:- He turned down my request.
33. turn on: start the flow of
Ex:- I turned on the tap.
34. turnoff: stop the flow of
Ex:- Please turn off all lights before going to bed.
35. windup: bring to an end
Ex:- It is time for him to wind up his speech.
36. workout: calculate correctly
Ex:- An intelligent child can work out this sum.

Verb + Adverb Particle + Preposition + Object

1. catch up with: come from behind and reach someone in front by going faster.
Ex:- Drive fester, they are catching up with us.
2. do away with: abolish, get rid of
Ex:- You can’t do away with violence by using violence.
3. get up with: make progress in something you are doing.
Ex:- How are you getting on with your business?
4. go back on: fail to keep.
Ex:- I can’t go back on my word.

CHSE Odisha Class 12 Alternative English Solutions Phrasal Verbs

5. go in for: choose something as your job or interest.
Ex:- I thought of going in for teaching.
6. grow out of: became too big for
Ex:- He has grown out of that shirt.
7. look forward to: to be excited and pleased about something that is going to happen.
Ex:- We are looking forward to our uncle’s visit.
8. look down upon/on: hate, despise
Ex:- We should not look down upon the poor.
9. make up for: compensate for
Ex: – Hard work can often make up for lack of intelligence.
10. put up with: tolerate, bear
Ex:- I can’t put up with your rudeness any.
11. run out of: use all of something
Ex:-We have run out of sugar
12. watch out for: Keep looking and waiting for something/someone
13. keep up with: manage to go or learn as far as someone.
Ex:- The new boy can’t keep up with the class.

Exercise For Practice
1. Use appropriate phrasal verbs for the underlined verbs in the following sentences:

1. My brother has read this novel.
2. I can’t tolerate his insulting words.
3. His grandfather died yesterday.
4. He has postponed the meeting.
5. I can’t understand his speech.
6. We would not hate uncivilized people.
7. You should not try to cheat me.
8. Cholera has began in our locality.
9. The boy resembles his father.
10. That book has been published.
11. You should obey the words of the elders.
12. Pramila belongs to a royal family.
13. You should rise early in the morning.
14. Our Principal distributed the prizes.
15. You should maintain the prestige of your parents.
16. Stop the computer.
17. He has solved all the sums.
18. He has established a factory.
19. The police followed the thief.
20. The Pakistan army had to yield.

CHSE Odisha Class 12 Alternative English Solutions Phrasal Verbs

Answer:
1. My brother has gone through this novel.
2. I can’t put up with his insulting words.
3. His grandfather passed away yesterday.
4. He has called off the meeting.
5. I can’t make out his speech.
6. We would not look down upon uncivilized people.
7. You should not try to take me in.
8. Cholera has broken out in our locality.
9. The boy takes after his father.
10. That book has been brought out.
11. You should carry out the words of the elders.
12. Pramila comes of a royal family.
13. You should get up early in the morning.
14. Our Principal gave away the prizes.
15. You should keep the prestige of your parents.
16. Turn off the computer.
17. He has worked out all the sums.
18. He has set up a factory.
19. The police ran after the thief.
20. The Pakistan army had to give in.

Exercise For Practice
2. Supply a phrasal verb of the same meaning as indicated in the brackets.

1. All the lights __________ when the power supply was cut off. (stopped giving light).
2. Please check if you have __________ any name. (omitted).
3. The workers __________ working for a long time. (continued)
4. You should __________ something for your children’s education. (save for future use).
5. Priya has __________ her illness only recently. (recovered from)
6. It is dishonest to __________ one’s words. (fail to keep a promise)
7. Ranjit was __________ by a car. (hit).
8. The tires of my cycle have __________. (become unfit for use)
9. Mr. Patra has __________ a school in his village. (established)
10. You should __________ wild animals in a jungle. (be careful of)
11. This clock has __________. (stopped working)
12. You must __________ your misbehavior. (give a reason for)
13. I __________ and an old friend at a shop. (met by chance)
14. The new boy __________ with almost everybody in the class. (quarrel)

CHSE Odisha Class 12 Alternative English Solutions Phrasal Verbs

Exercise For Practice
3. Choose the correct particles to make the sentences meaningful.

1. I called __________ my friend, (off / on)
2. We took a long time to work __________ the problem, (out / at)
3. The minister has promised to think the __________ matter. (about / over)
4. It is hard to make __________ their purpose, (out / upon)
5. We are looking __________ the problem carefully, (at/into/for)
6. Always keep __________ from danger, (out/away)
7. The thief got __________ with my car. (out / away)
8. An accident brought __________ a change in his life, (about / out)
9. It is bad manners to answer __________. (to, at, back)
10. The robbers broke __________ the bank at night, (down / into)
11. Take __________ the dirty clothes, (of / off / out)
12. The child is looking __________ the birds, (to/at/ for)
13. I rang __________ Aju in the morning, (to / up / for)
14. They are bringing __________ a new book, (about / out / to)
15. Would you care __________ a tea? (for/to / on)
16. They pulled __________ the old house, (off / top/down)
17. The reporters took __________ the speech, (down/off/to)
18. I am looking __________ your problem (to with/up with/in with)
19. I can’t put __________ rude people (to with / up with / in with)
20. The soldiers blew __________ the bridge, (down / off / up)
21. I can’t make __________ the meaning of this word, (to/of / out)
22. She carried __________ singing for a long time, (into/of / on)

CHSE Odisha Class 12 Alternative English Grammar Tense and Aspect

Odisha State Board CHSE Odisha Class 12 Alternative English Solutions Grammar Tense and Aspect Exercise Questions and Answers.

CHSE Odisha Class 12 Alternative English Grammar Tense and Aspect

We have already discussed about ”Tense” in the 1 st year. Let us do some exercises now.
Exercise For Practice (Solved):

1. Fill in the blanks with the correct very forms (Present Tense) from those in brackets.
1. My brother _________ (read) a play by Kalidas.
2. The students _________ (play) much attention to their studies.
3. Who _________ (say), I am the wrong.
4. _________ the birds not _________ (chirp) early in the morning?
5 _________ the students _________ (swim) in the river?
6 _________ your mother not _________ (keep) fit these days?
7 _________ they _________ (refuse) to help you?
8. Puspa _________ not _________ I (iron) her clothes.
9. _________ your sister know how to swim?
10. Rakesh _________ not _________ (take) coffee without sugar.
11. _________ we not _________ (see) many ups and downs in the life?
12. I _________ drop a five rupee note somewhere.
13. _________ I not _________ (invite) him to dinner?
14. Pinki _________ not _________ (keep) awake till midnight these days.
15. Rajeswari _________ (travel) round the world.
16 _________ it _________ (drizzle) since room?
17. She _________ (withdraw) her name from the debate.
18. She _________ (wait) for you for an hour.
19 _________ the maidservant _________ (wash) the floor?
20. It _________ no _________ (rain) her for the last two days.

CHSE Odisha Class 12 Alternative English Solutions Tense and Aspect

Answer:
1. My brother is reading a play by Kalidas.
2. The students are playing much attention to their studies.
3. Who says. I am the wrong.
4. Do the birds not chirp early in the morning?
5. Are the students swimming in the river?
6. Does your mother not keep fit these days?
7. Have they refused to help you?
8. Puspa is not ironing her clothes.
9. Does your sister know how to swim?
10. Rakesh does not take coffee without sugar.
11. Have we not seen many ups and downs in the life?
12. I have dropped a five rupee note somewhere.
13. Am I not inviting him to dinner?
14. Pinki does not keep awake till midnight these days.
15. Rajeswari has traveled round the world.
16. Has it been drizzling since the room?
17. She has withdrawn her name from the debate.
18. She has been waiting for you for an hour.
19. Has the maidservant washed the floor?
20. It has not raining her for the last two days.

Exercise For Practice:
2. Fill in the blanks with correct verb forms (Present Tense) from those in brackets.

1. _________ God not _________ (protect) us all?
2. _________ you sister _________ (pass) the examination?
3. Hari _________ recently _________ (sell) his house.
4. I _________ (read) English for eight years.
5 _________ you _________ graze the cattle since morning?
6. Malaria _________ (rage) in the city for two years.
7. Vegetables and fruits _________ not _________ (harm) us in any way.
8 she not _________ (visit) her home every year?
9. She _________ not _________ (bathe) in hot water during summer.
10. Whom _________ you _________ (like) the most?
11. I _________ (learn) the verses from the Gita.
12. _________ they _________ (travel) by train?
13. Seema _________ not _________ (wash) her clothes.
14. _________ the police not _________ (chose) the thieves?
15. _________ those forests, not _________ (look) green?
16. How _________ you _________ (pull) on with your brother?
17. Who _________ (teach) you since morning?
18. _________ they been _________ (boil) since for ten minutes?
19. Tap _________ not _________ (run) for an hour.
20. Whose umbrella _________ you _________ (use) since last two days?

CHSE Odisha Class 12 Alternative English Solutions Tense and Aspect

Exercise For Practice:
3. Fill in the blanks with correct verb forms (Past Tense) from those in brackets.

1. My father _________ (give) me this present on my birthday.
2. When I _________ (visit) her house, she _________(sleep).
3 _________ Suraj _________ (write) a romantic novel?
4. We _________ (reach) the station before the train _________ (leave).
5. She _________ (sleep) since 8 p.m.
6 _________ Gandhi always _________ (speak) the truth?
7. It _________ (drizzle) since 4 o’ clock.
8. It _________ (rain) heavily at 10 o’ clock.
9. Hari _________ (try) to grind his own axe.
10. The teacher _________ (not) _________ (punish) the naughty boys.
11. I _________ not _________ (talk) to Rahim the other day.
12. He _________ (go) to the post office after the rain _________ (stop).
13. I _________ (wait) for you when the bell _________(ring).
14. _________ the old man _________ (cross) the road very carefully.
15. Mother _________ (prepare) tea for five minutes.
16. Shakil _________ not _________(entertain) the guests with her titbits.
17. The train _________ (run) continuously for four hours.
18. Which God _________ you _________ (worship) in the temple?
19. Ranjana _________ not _________(call) on me last night.
20. In whose house _________ Sheela _________ (stay)?

Answer:
1. My father gave me this present on my birthday.
2. When I visited her house, she was sleeping.
3. Was Suraj writing a romantic novel?
4. We had reached the station before the train left.
5. She had been sleeping since 8 p.m.
6. Did Gandhi always speak the truth?
7. It had been drizzling since 4 o’clock.
8. It had been raining heavily at 10 o’clock.
9. Hari was trying to grind his own axe.
10. The teacher did not punish the naughty boys.
11. I was not talking to Rahim the other day.
12. He want to go to the post office after the rain has stopped.
13. I was waiting for you when the bell rang.
14. Did the old man cross the road very carefully?
15. Mother had been preparing tea for five minutes.
16. Shakil was not entertaining the guests with her titbits.
17. The train had been running continuously for four hours.
18. Which God had you worshipping in the temple?
19. Ranjana did not call on me last night.
20. In whose house was Sheela staying?

CHSE Odisha Class 12 Alternative English Solutions Tense and Aspect

Exercise For Practice:
4. Fill in the blanks with correct verb forms (Past Tense) from those in brackets.

1. You _________ (listen) to Radio for half an hour.
2. Whose clothes _________ you _________ (fold)?
3. Whom _________ you _________ (teach) Grammar?
4. When I _________ (teach), he _________ (doze).
5. It _________ not _________ (rain) when we _________ (leave) for.
6 _________ it _________ heavily at 10 o ’ clock yesterday (rain)?
7. I _________ (read) a novel the whole day long.
8. When you _________ (send) her a telegram?
9 _________ an accident not _________ (take) place here yesterday?
10. The police _________ not _________ (arrest) the thieves knowingly?
11. _________ I _________ (lend) her some money yesterday?
12. He _________ (solve) the difficult sum at once.
13. Mohan _________ not _________ (work) in the worship for several days.
14. _________ he not _________ (knock) at the door for five minutes?
15. Where _________ he _________ (hide) for two days?
16. Which book _________ you _________ (land) _________ to me ?
17. _________ the sun not _________ (set) when the farmers _________ (return) home ?
18. I _________ not _________ (receive) any letter from my uncle.
19. Whose like _________ (fly) high?
20. Who _________ (shatter) this glass into pieces?

CHSE Odisha Class 12 Economics Chapter 15 Objective Questions in Odia Medium

Odisha State Board CHSE Odisha Class 12 Economics Solutions Chapter 15 ବ୍ୟାଙ୍କ Objective Questions.

CHSE Odisha 12th Class Economics Chapter 15 Objective Questions in Odia Medium

ବସ୍ତୁନିଷ୍ଠ ଓ ଅତିସଂକ୍ଷିପ୍ତ ଉତ୍ତରମୂଳକ ପ୍ରଶ୍ନୋତ୍ତର
A. ସମ୍ଭାବ୍ୟ ଚାରୋଟି ଉତ୍ତର ମଧ୍ୟରୁ ଠିକ୍ ଉତ୍ତରଟି ବାଛି ଲେଖ ।

1. ଚଳନ୍ତି ଜମାର ଅନ୍ୟ ନାମ ହେଉଛି :
(A) ଚାହିଦା ଜମା
(B) ମିଆଦି ଜମା
(C) ସ୍ଵୟ ଜମା
(D) ପୌନଃପୁନିକ ଜମା
Answer:
(A) ଚାହିଦା ଜମା

2. କେଉଁ ଜମା ସର୍ବାଧ‌ିକ ସୁଧ ପ୍ରଦାନ କରେ ?
(A) ଚଳନ୍ତି ଜମା
(B) ସଞ୍ଚୟ ଜମା
(C) ସ୍ଥାୟୀ ଜମା
(D) ପୌନଃପୁନିକ ଜମା
Answer:
(C) ସ୍ଥାୟୀ ଜମା

3. ମିଆଦି ଜମା କେଉଁ ଜମାର ଅନ୍ୟ ନାମ ?
(A) ଚଳନ୍ତି ଜମା
(B) ସଞ୍ଚୟ ଜମା
(C) ଚାହିଦା ଜମା
(D) ସ୍ଥାୟୀ ଜମା
Answer:
(A) ଚଳନ୍ତି ଜମା

4. କେଉଁ ଜମା ସୁଧ ଅର୍ଜନ କରେ ନାହିଁ ?
(A) ଚାହିଦା ଜମା
(B) ସଞ୍ଚୟ ଜମା
(C) ମିଆଦି ଜମା
(D) ଉପରୋକ୍ତ କୌଣସିଟି ନୁହେଁ
Answer:
(A) ଚାହିଦା ଜମା

CHSE Odisha Class 12 Economics Chapter 15 Objective Questions in Odia Medium

5. କେଉଁ ବ୍ୟାଙ୍କ୍ ମୁଦ୍ରା ସୃଜନ କରିପାରେ ?
(A) ରିଜର୍ଭ ବ୍ୟାଙ୍କ୍
(B) ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍
(C) ବିନିମୟ ବ୍ୟାଙ୍କ
(D) ସଞ୍ଚୟ ବ୍ୟାଙ୍କ
Answer:
(B) ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍

6. ନିମ୍ନଲିଖତ ବ୍ୟାଙ୍କମାନଙ୍କ ମଧ୍ୟରୁ କେଉଁ ବ୍ୟାଙ୍କ ସ୍ଵଳ୍ପକାଳୀନ ଋଣ ପ୍ରଦାନ କରେ ?
(A) ରିଜର୍ଭ ବ୍ୟାଙ୍କ୍
(B) କୃଷି ବ୍ୟାଙ୍କ୍
(C) ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍
(D) ସଞ୍ଚୟ ବ୍ୟାଙ୍କ୍
Answer:
(C) ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍

7. ନିମ୍ନୋକ୍ତ କେଉଁ ଋଣ ପଦ୍ଧତି ବ୍ୟବସାୟୀଙ୍କଦ୍ୱାରା ସବୁଠାରୁ ଅଧିକ ଆଦୃତ ?
(A) ନଗଦୀ ଋଣ
(B) ପ୍ରତ୍ୟକ୍ଷ ଋଣ
(C) ଅତିରିକ୍ତ ଉଠାଣ
(D) ଉପରୋକ୍ତ କୌଣସିଟି ନୁହେଁ
Answer:
(A) ନଗଦୀ ଋଣ

8. ନିମ୍ନଲିଖ ମଧ୍ୟରୁ କେଉଁଟି ବାଣିଜ୍ୟ ବ୍ୟାଙ୍କର କାର୍ଯ୍ୟ ନୁହେଁ ?
(A) ଋଣ ପ୍ରଦାନ
(B) ଜମା ଗ୍ରହଣ
(C) ଋଣ ସୃଷ୍ଟି
(D) ନୋଟ୍ ପ୍ରଚଳନରେ ଏକାଧିକାର
Answer:
(D) ନୋଟ୍ ପ୍ରଚଳନରେ ଏକାଧିକାର

9. ଋଣ ଦେବାବେଳେ ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍ ସୃଷ୍ଟି କରୁଥିବା ଜମାକୁ କ’ଣ କୁହାଯାଏ ?
(A) ପ୍ରାଥମିକ ଜମା
(B) ବ୍ୟୁତ୍ପନ୍ନ ଜମା
(C) ମିଆଦି ଜମା
(D) ଚଳନ୍ତି ଜମା
Answer:
(C) ମିଆଦି ଜମା

10. ଋଣ ପ୍ରଦାନ ଓ ଜମା ଗ୍ରହଣ ପ୍ରକ୍ରିୟାରେ ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍ ସୃଷ୍ଟି କରୁଥିବା ମୁଦ୍ରାକୁ କ’ଣ କୁହାଯାଏ ?
(A) ଋଣ ମୁଦ୍ରା
(B) ବ୍ୟାଙ୍କ୍ ମୁଦ୍ରା
(C) ଜମା ମୁଦ୍ରା
(D) ଉପରୋକ୍ତ କୌଣସିଟି ନୁହେଁ
Answer:
(B) ବ୍ୟାଙ୍କ୍ ମୁଦ୍ରା

11. ଯଦି ନଗଦୀ ସଂରକ୍ଷଣ ଅନୁପାତ 10% ତେବେ 1000 ଟଙ୍କାର ମୂଳ ଜମା ସର୍ବାଧ‌ିକ କେତେ ଟଙ୍କା ହେବ ?
(A) 8000 ଟଙ୍କା
(B) 9000 ଟଙ୍କା
(C) 10,000 ଟଙ୍କା
(D) 11,000 ଟଙ୍କା
Answer:
(C) 10,000 ଟଙ୍କା

12. ନଗଦୀ ସଂରକ୍ଷଣ ଅନୁପାତ 20% ହେଲେ ଋଣ ଗୁଣାଙ୍କ କେତେ ହେବ ?
(A) 20
(B) 10
(C) 15
(D) 5
Answer:
(D) 5

CHSE Odisha Class 12 Economics Chapter 15 Objective Questions in Odia Medium

13. ଗ୍ରାହକମାନଙ୍କ ଅବଗତି ନିମନ୍ତେ ପ୍ରତ୍ୟେକ ଆର୍ଥିକ ବର୍ଷର ଶେଷଭାଗରେ ବ୍ୟାଙ୍କ୍ ନିଜ ଆୟ ବ୍ୟୟ ସଂକ୍ରାନ୍ତୀୟ
ବିବରଣୀ ଯେଉଁ ପତ୍ର ମାଧ୍ୟମରେ ପ୍ରକାଶ କରିଥାଏ ତାହାକୁ କ’ଣ କୁହାଯାଏ ?
(A) ଦେୟତା
(B) ପରିସମ୍ପରି
(C) ସନ୍ତୁଳନ ପତ୍ର
(D) ପୁଞ୍ଜି
Answer:
(C) ସନ୍ତୁଳନ ପତ୍ର

14. କେଉଁ ବ୍ୟାଙ୍କ୍‌ ସମଗ୍ର ବ୍ୟାକ୍ ବ୍ୟବସ୍ଥାର ଶୀର୍ଷ ଅନୁଷ୍ଠାନ ?
(A) ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍
(B) ବିନିମୟ ବ୍ୟାଙ୍କ୍
(C) କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍
(D) କେନ୍ଦ୍ରୀୟ ସମବାୟ ବ୍ୟାଙ୍କ୍
Answer:
(C) କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍

15. ପୃଥ‌ିବୀର ପ୍ରାଚୀନତମ କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍‌ର ନାମ କ’ଣ ?
(A) ରିକ୍ ବ୍ୟାଙ୍କ୍
(B) ବ୍ୟାଙ୍କ୍ ଅଫ୍ ଇଂଲଣ୍ଡ
(C) ଭାରତୀୟ ରିଜର୍ଭ ବ୍ୟାଙ୍କ୍
(D) ଫେଡ଼େରାଲ ରିଜର୍ଭ ସିଷ୍ଟମ
Answer:
(A) ରିକ୍ ବ୍ୟାଙ୍କ୍

16. କେଉଁ ମସିହାରେ ଭାରତୀୟ ରିଜର୍ଭ ବ୍ୟାଙ୍କ୍ ସ୍ଥାପିତ ହେଲା ?
(A) 1950
(B) 1951
(C) 1947
(D) 1935
Answer:
(D) 1935

17. କେଉଁ ଅନୁଷ୍ଠାନ ରାଷ୍ଟ୍ରର ମୁଦ୍ରାନୀତି ପ୍ରଣୟନ କରେ ?
(A) ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍
(B) ବିତ୍ତ ମନ୍ତ୍ରଣାଳୟ
(C) କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍
(D) ଉପରୋକ୍ତ କୌଣସିଟି ନୁହେଁ
Answer:
(C) କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍

18. ଭାରତରେ ଏକଟଙ୍କିଆ ନୋଟ କିଏ ପ୍ରଚଳନ କରେ ?
(A) କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍
(B) ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍
(C) ବିତ୍ତ ମନ୍ତ୍ରଣାଳୟ
(D) ଉପରୋକ୍ତ କୌଣସିଟି ନୁହେଁ
Answer:
(C) ବିତ୍ତ ମନ୍ତ୍ରଣାଳୟ

19. କେଉଁ ଅନୁଷ୍ଠାନ ଋଣ ନିୟନ୍ତ୍ରଣ କରେ ?
(A) ସମବାୟ ବ୍ୟାଙ୍କ୍
(B) କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍
(C) ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍
(D) ବିନିମୟ ବ୍ୟାଙ୍କ୍
Answer:
(B) କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍

20. କେଉଁ ବ୍ୟାକୁ ପୁନଃ ଅବମୂଲ୍ୟାୟନ ବ୍ୟାଙ୍କ୍ ମଧ୍ଯ କୁହାଯାଏ ?
(A) ବିନିମୟ ବ୍ୟାଙ୍କ୍
(B) ଔଦ୍ୟୋଗିକ ବ୍ୟାଙ୍କ୍
(C) କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍
(D) ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍
Answer:
(C) କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍

21. ନିମ୍ନୋକ୍ତ କେଉଁଟି ଗୁଣାତ୍ମକ ଋଣ ନିୟନ୍ତ୍ରଣ ପଦ୍ଧତିରେ ଏକ ଆୟୁଧ ?
(A) ବ୍ୟାଙ୍କ୍ ହାର
(B) ଖୋଲା ବଜାର କାରବାର
(C) ପରିବର୍ତ୍ତନଶୀଳ ନଗଦୀ ସଂରକ୍ଷଣ ଅନୁପାତ
(D) ପ୍ରଚାର
Answer:
(D) ପ୍ରଚାର

22. କେଉଁ ବ୍ୟାଟ୍ ସରକାରଙ୍କୁ ଋଣ ଦିଏ ?
(A) ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍
(B) ଉନ୍ନୟନ ବ୍ୟାଙ୍କ୍
(C) କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍
(D) କେନ୍ଦ୍ରୀୟ ସମବାୟ ବ୍ୟାଙ୍କ୍
Answer:
(C) କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍

CHSE Odisha Class 12 Economics Chapter 15 Objective Questions in Odia Medium

23. ନିମ୍ନୋକ୍ତ କେଉଁଟି ପରିମାଣାତ୍ମକ ଋଣ ନିୟନ୍ତ୍ରଣ ପଦ୍ଧତିର ଏକ ଆୟୁଧ ?
(A) ବ୍ୟାଙ୍କ୍ ସୁଧ ହାର
(B) ଖୋଲା ବଜାର କାରବାର
(C) ନଗଦ ସଂରକ୍ଷିତ ଅନୁପାତରେ ପରିବର୍ଭନ
(D) ଉପରୋକ୍ତ ସମସ୍ତ
Answer:
(D) ଉପରୋକ୍ତ ସମସ୍ତ

24. କେଉଁ ବ୍ୟାଙ୍କ୍‌କୁ ଅନ୍ତିମ ଋଣଦାତା ବ୍ୟାଙ୍କ୍ କୁହାଯାଏ
(A) କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍
(B) ଉନ୍ନୟନ ବ୍ୟାଙ୍କ୍
(C) ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍
(D) ଭାରତୀୟ ଷ୍ଟେଟ୍ ବ୍ୟାଙ୍କ୍
Answer:
(A) କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍

(B) ଶୂନ୍ୟସ୍ଥାନ ପୂରଣ କର ।

1. ଯେଉଁ ଅନୁଷ୍ଠାନରେ ଋଣସମୂହ ଲୋକମାନଙ୍କର ପରସ୍ପର ଋଣ ପରିଶୋଧ ନିମିତ୍ତ ବ୍ୟାପକ ଭାବରେ ଗୃହୀତ ହୁଏ, ସେହି ଅନୁଷ୍ଠାନକୁ ___________ କୁହାଯାଏ ।
Answer:
ବ୍ୟାଙ୍କ୍

2. ବ୍ୟାଙ୍କ୍ ଶବ୍ଦ ଇଟାଲାର ___________ ଶବ୍ଦରୁ ଉଦ୍ଧୃତ ।
Answer:
ବ୍ୟାଙ୍କା

3. ଇଟାଲୀ ଭାଷାରେ ‘ବ୍ୟାଙ୍କୋ’ ଶବ୍ଦର ଅର୍ଥ ହେଲା ___________ ।
Answer:
ବେଞ୍ଚ

4. ଯେଉଁ ଜମାକୁ ଜମାକାରୀ ଯେକୌଣସି କାର୍ଯ୍ୟକାରୀ ଦିନରେ ପୂର୍ବରୁ କୌଣସି ନୋଟିସ୍ ନ ଦେଇ ନିଜର ଆବଶ୍ୟକ ମୁତାବକ ମୁଦ୍ରା ଚେକ୍ ସାହାଯ୍ୟରେ ବ୍ୟାଙ୍କୁରୁ ଉଠାଇ ପାରନ୍ତି, ତାହାକୁ ___________ ଜମା କୁହାଯାଏ ।
Answer:
ଚଳନ୍ତି

5. ଯେଉଁ ଜମାକୁ ଜମାକାରୀ ନିର୍ଦ୍ଧାରିତ ସମୟକାଳ ପୂର୍ବରୁ ବିନା ନୋଟିସ୍‌ରେ ବ୍ୟାଙ୍କୁରୁ ଉଠାଇପାରେ ନାହିଁ, ତାହାକୁ ___________ ଜମା କୁହାଯାଏ ।
Answer:
ମିଆଦି

6. ସ୍ଵଳ୍ପ ସଞ୍ଚୟକାରୀ ଓ ନିମ୍ନ ଆୟକାରୀ ଲୋକମାନଙ୍କ ପାଇଁ ବ୍ୟାଙ୍କ୍ ___________ ଜମା ସୁବିଧା ପ୍ରଦାନ କରିଥାଏ ।
Answer:
ସଞ୍ଚୟ

7. ଯେଉଁ ଜମା ହିସାବରେ ଜମାକାରୀ ପ୍ରତି ମାସରେ ଏକ ନିର୍ଦ୍ଦିଷ୍ଟ ପରିମାଣର ମୁଦ୍ରା କିଛି ବର୍ଷ ପାଇଁ ଜମାଖାତାରେ ପୈଠ କରିଥା’ନ୍ତି, ତାହାକୁ ___________ ଜମା କୁହାଯାଏ ।
Answer:
ପୌନଃପୁନିକ

8. ଯେଉଁ ଋଣଗୁଡ଼ିକ ଗ୍ରାହକମାନଙ୍କର ପ୍ରତିଶ୍ରୁତି ପତ୍ର ବଦଳରେ ପ୍ରଦାନ କରାଯାଏ, ତାହାକୁ ___________ ଋଣ କୁହାଯାଏ ।
Answer:
ନଗଦୀ

9. ଯେଉଁ ବ୍ୟବସ୍ଥାଦ୍ୱାରା ଜମାକାରୀ ନିଜର ଚାହିଦା ଜମାଖାତାରେ ଥିବା ପରିମାଣଠାରୁ ଅଧିକ ମୁଦ୍ରା ବ୍ୟାଙ୍କରୁ ଉଠାଇବାକୁ ବ୍ୟବସ୍ଥା ସକ୍ଷମ ହୋଇଥାଏ, ତାହାକୁ ___________ କୁହାଯାଏ ।
Answer:
ଓଭରଡ୍ରାଫ୍‌ଟ

10. ବ୍ୟାଙ୍କ୍ ଯେଉଁ ଅର୍ଥ ନଗଦ ଜମା ଆକାରରେ ପ୍ରାପ୍ତ ହୋଇଥା’ନ୍ତି, ତାହାକୁ ___________ କୁହାଯାଏ ।
Answer:
ପ୍ରାଥମିକ ଜମା

11. ଋଣ ଦାନ ସମୟରେ ବ୍ୟାକ୍ ଜଣେ ଋଣଗ୍ରହୀତାଙ୍କୁ ଜମାକାରୀରେ ପରିଣତ କରେ, ବ୍ୟାକ୍ ଏପରି ଯେଉଁ ଜମା ସୃଷ୍ଟି କରେ ତାହାକୁ ___________ କୁହାଯାଏ ।
Answer:
ବ୍ୟୁତ୍ପନ୍ନ

CHSE Odisha Class 12 Economics Chapter 15 Objective Questions in Odia Medium

12. ବ୍ୟାଙ୍କ୍ ସୃଷ୍ଟି କରୁଥିବା ମୁଦ୍ରା ନଗଦ ମୁଦ୍ରା ନୁହେଁ, ଏହା ଦୃଶ୍ୟ ହୋଇନଥାଏ, ଏହା କାଗଜ କଲମରେ ସୃଷ୍ଟ, ଏହାକୁ ___________ ମୁଦ୍ରା କୁହାଯାଏ ।
Answer:
ବ୍ୟାଙ୍କ୍

13. ନଗଦୀ ସଂରକ୍ଷଣ ଅନୁପାତ ଓ ରଣାଙ୍କ ମଧ୍ୟରେ ___________ ସମ୍ପର୍କ ରହିଛି ।
Answer:
ପରୋକ୍ଷ ଆନୁପାତିକ

14. ନଗଦୀ ସଂରକ୍ଷଣ ଅନୁପାତ 10% ହେଲେ ଋଣ ଗୁଣାଙ୍କ ___________ ହେବ ।
Answer:
10

15. ଖୁବ୍ କମ୍ ସମୟ ପାଇଁ ପ୍ରଦାନ କରାଯାଉଥ‌ିବା ଏକ ସ୍ଵତନ୍ତ୍ର ଋଣ ହେଉଛି ଚାହିଁବା ମାତ୍ରେ ଫେରସ୍ତଯୋଗ୍ୟ ମୁଦ୍ରା ବା ଋଣ ଯାହାକୁ ନୋଟିସ୍ ଦେବାର 24 ଘଣ୍ଟାରୁ ___________ ଦିନ ମଧ୍ୟରେ ବ୍ୟାଙ୍କ୍ ଋଣକାରୀଠାରୁ ଏହି ଋଣ ଫେରସ୍ତ ଆଣିପାରେ ।
Answer:
14

16. ମିଆଦୀ ଜମା କ୍ଷେତ୍ରରେ, ମିଆଦ କାଳ ଯେତେ ଦୀର୍ଘତର ହୋଇଥାଏ, ସୁଧ ହାର ସେତିକି ___________ ହୋଇଥାଏ ।
Answer:
ଅଧ୍ୟା

17. ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କଗୁଡ଼ିକ ଗ୍ରାହକମାନଙ୍କର ___________ ହିସାବରେ ସେମାନଙ୍କ ତରଫରୁ ଅନେକ କାର୍ଯ୍ୟ କରିଥାଏ ।
Answer:
ପ୍ରତିନିଧ୍ଵ

18. ସନ୍ତୁଳନ ପତ୍ରରେ ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କର ଆର୍ଥିକ ଅବସ୍ଥା ଅର୍ଥାତ୍ ଦେୟତା ଓ ___________ ପ୍ରତିଫଳିତ ହୋଇଥାଏ ।
Answer:
ପରି ସମ୍ପତ୍ତି

19. ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍ ଅନ୍ୟମାନଙ୍କୁ ଯେଉଁ ପାଉଣା ଆଇନତଃ ଦେବାକୁ ବାଧ୍ୟ, ତାହା ହେଉଛି ବ୍ୟାଙ୍କ୍‌ର ___________ ।
Answer:
ଦେୟତା

20. ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍ ଅନ୍ୟମାନଙ୍କଠାରୁ ଆଇନତଃ ଯେଉଁ ପାଉଣା ପାଇବାକୁ ହକ୍‌ର, ତାହା ହେଉଛି ବ୍ୟାଙ୍କ୍‌ର ___________ ।
Answer:
ପରି ସମ୍ପତ୍ତି

21. ଅଂଶୀଦାରମାନେ ଯେଉଁ ପରିମାଣର ବ୍ୟାଙ୍କର ଅଂଶ କ୍ରୟ କରିବାକୁ ସ୍ବୀକୃତି ଦେଇଥା’ନ୍ତି, ___________ ପୁଞ୍ଜି କୁହାଯାଏ ।
Answer:
ଅଭିଦର

22. ଅଭିଦତ୍ତ ପୁଞ୍ଜିର ଯେଉଁ ଅଂଶ ନଗଦ ମୁଦ୍ରା ଦେଇ ଅଂଶୀଦାରମାନେ କ୍ରୟ କରିଥା’ନ୍ତି, ତାକୁ ___________ ପୁଞ୍ଜି କହନ୍ତି ।
Answer:
ପ୍ରଦତ୍ତ

23. ଲାଭର ଯେଉଁ ଅଂଶ ଅଂଶୀଦାରମାନଙ୍କ ମଧ୍ୟରେ ବଣ୍ଟନ କରା ନ ଯାଇ ଭବିଷ୍ୟତ ନିରାପତ୍ତା ପାଇଁ ସଂରକ୍ଷିତ ହୋଇଥାଏ, ତାହାକୁ ___________ ପାଣ୍ଠି କୁହାଯାଏ ।
Answer:
ସଂରକ୍ଷିତ

24. ଜମା ବ୍ୟାଙ୍କର ସର୍ବବୃହତ୍ ___________ ଅଟେ ।
Answer:
ଦେୟ

25. ପ୍ରତ୍ୟେକ ବ୍ୟାଙ୍କ୍ ଗ୍ରାହକମାନଙ୍କ ଚାହିଦା ମାତ୍ରକେ ସେମାନଙ୍କ ଆବଶ୍ୟକତା ପୂରଣ କରିବାପାଇଁ ନିଜ ପାଖେ କିଛି ନଗଦ ମୁଦ୍ରା ରଖନ୍ତି, ଏହାକୁ ___________ ମୁଦ୍ରା କୁହାଯାଏ ।
Answer:
ହସ୍ତସ୍ଥ

26. ପରମ୍ପରାଗତ ଭାବେ ହେଉ ବା ଆଇନ ଯୋଗୁଁ ହେଉ, ବାଣିଜ୍ୟିକ ବ୍ୟାଟ୍ସମାନେ କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍ ମାର୍ସତରେ ମୋଟ ଜମାର କିଛି ଶତାଂଶ ନଗଦ ଆକାରରେ ଗଚ୍ଛିତ ରଖୁଥା’ନ୍ତି, ଯାହାକୁ ___________ କୁହାଯାଏ ।
Answer:
ଗଚ୍ଛିତ ଅନୁପାତ

27. ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କର ସନ୍ତୁଳନ ପତ୍ରର ___________ ପାର୍ଶ୍ଵରେ ଦେୟତା ରହିତାଏ ।
Answer:
ବାମ

CHSE Odisha Class 12 Economics Chapter 15 Objective Questions in Odia Medium

28. ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କର ସନ୍ତୁଳନ ପତ୍ରର ___________ ପାର୍ଶ୍ବରେ ପରିସମ୍ପଭି ରହିଥାଏ ।
Answer:
ଡାହାଣ

29. ସରକାରଙ୍କର ପ୍ରଧାନ ଆର୍ଥିକ କାରବାରମାନ ସମ୍ପାଦନ କରୁଥିବା, ଏହାର କାର୍ଯ୍ୟ ପରିଚାଳନା ଓ ଅନ୍ୟ ଉପାୟରେ ସରକାରଙ୍କ ଆର୍ଥିକ ନୀତିକୁ ସମର୍ଥନ କରୁଥିବା ଓ ଆର୍ଥିକ ଅନୁଷ୍ଠାନମାନଙ୍କର କାର୍ଯ୍ୟାବଳୀକୁ ପ୍ରଭାବିତ କରୁଥିବା ବ୍ୟାଙ୍କ୍ ହିଁ ___________ ବ୍ୟାକ୍ ।
Answer:
କେନ୍ଦ୍ରୀୟ

30. ___________ ବ୍ୟାଙ୍କର ନୋଟ୍ ପ୍ରଚଳନ କ୍ଷେତ୍ରରେ ଏକାଧିକାର ରହିଛି ।
Answer:
କେନ୍ଦ୍ରୀୟ

31. ପ୍ରତ୍ୟେକ ଦେଶରେ କେବଳ ___________ ମାତ୍ର କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ ଥାଏ ।
Answer:
ଗୋଟିଏ

32. ___________ ବ୍ୟାଙ୍କ୍ ଅର୍ଥନୈତିକ ବିକାଶର ବାହକ ।
Answer:
କେନ୍ଦ୍ରୀୟ

33. ___________ ବ୍ୟାଙ୍କ୍ ସର୍ବଦା ଲାଭ ଅର୍ଜନ ପାଇଁ କାର୍ଯ୍ୟ କରିଥା’ନ୍ତି ।
Answer:
ବାଣିଜ୍ୟିକ

34. ନିର୍ଦ୍ଦିଷ୍ଟ କ୍ଷେତ୍ରରେ ଋଣ ନିୟନ୍ତ୍ରଣ ପାଇଁ କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍ ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍ଗ୍‌ମାନଙ୍କ ପ୍ରତି ___________ ଜାରି କରେ ।
Answer:
ନିର୍ଦ୍ଦେଶନାମା

35. କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍ କେତେକ ନିର୍ଦ୍ଦିଷ୍ଟ କ୍ଷେତ୍ରରେ ଋଣ ନିୟନ୍ତ୍ରଣ ପାଇଁ ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କମାନଙ୍କ ଉପରେ ___________ ସୃଷ୍ଟି କରେ ।
Answer:
ନୈତିକ ଚାପ

36. ଗୁଣାତ୍ମକ ଋଣ ନିୟନ୍ତ୍ରଣ ପଦ୍ଧତିକୁ ___________ ଋଣ ନିୟନ୍ତ୍ରଣ ପଦ୍ଧତି ମଧ୍ୟ କୁହାଯାଏ ।
Answer:
ଚୟନାତ୍ମକ

37. କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍ ବାଣିଜ୍ୟିକ ବ୍ୟାଟ୍ସମାନଙ୍କୁ ଯେଉଁ ହାରରେ ଋଣ ଦେଇଥାଏ, ତାହାକୁ ___________ କୁହାଯାଏ ।
Answer:
ବ୍ୟାଙ୍କ ହାର

38. ଜମାର ଯେଉଁ ଅନୁପାତ ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍ ଋଣ ଦେଇପାରେ ନାହିଁ, ତାହାକୁ ___________ ଅନୁପାତ କୁହାଯାଏ ।
Answer:
ନଗଦୀ ସଂରକ୍ଷଣ

39. ଅସ୍ଥାୟୀ ଆର୍ଥିକ ଅସୁବିଧା ଦୂର କରିବାପାଇଁ କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କୁ ସରକାରଙ୍କୁ ସ୍ୱଳ୍ପକାଳୀନ ଋଣ ଓ ଅଗ୍ରିମ ଋଣ ପ୍ରଦାନ ଋଣ କରେ, ଏହି ଋଣକୁ ___________ କୁହାଯାଏ ।
Answer:
କାମଚଳା

40. ସରମାନଙ୍କ ___________ ସ୍ଵରୂପ କାର୍ଯ୍ୟକରି କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍ ସରକାରଙ୍କୁ ଦେଶର ମୁଦ୍ରାନୀତି ଓ ଆର୍ଥିକ ନୀତି ଉପରେ ମଧ୍ୟ ପରାମର୍ଶ ଦେଇଥାଏ ।
Answer:
ଉପଦେଷ୍ଟା

41. ଦେୟତା ପରିଶୋଧ କରିବାପାଇଁ ବ୍ୟାଙ୍କ୍-ବ୍ୟାଙ୍କ୍ ମଧ୍ୟରେ ନଗଦ ମୁଦ୍ରା ଚଳପ୍ରଚଳ ନ କରି କେବଳ କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍ ନିକଟରେ ଥିବା ହିସାବରେ ପରିବର୍ତ୍ତନ କରି ଏହା କରାଯାଏ, ତେଣୁ କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍ ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍ସସମୂହ ପାଇଁ ଏକ ___________ ବ୍ୟାଙ୍କ୍ ।
Answer:
ଶୋଧନ

42. ___________ ନିୟନ୍ତ୍ରଣ କରି ଦେଶରେ ଦରଦାମ୍ କ୍ଷେତ୍ରରେ ସ୍ଥିରତା ରକ୍ଷା କରିବା କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କର ହିଁ ମୁଖ୍ୟ ଦାୟିତ୍ୱ ।
Answer:
ଋଣ

C. ନିମ୍ନଲିଖ ଉକ୍ତିଗୁଡ଼ିକ ଭୁଲ୍ କି ଠିକ୍ ଲେଖ । ରେଖାଙ୍କିତ ଅଂଶର ପରିବର୍ତ୍ତନ ନ କରି ଆବଶ୍ୟକ ସ୍ଥଳେ ସଂଶୋଧନ କର ।

1. ସମବାୟ ବ୍ୟାଙ୍କୁ କୃଷି ପାଇଁ ଦୀର୍ଘକାଳୀନ ଋଣ ଦେଇଥାଏ ।
Answer:
ଭୁଲ୍ ।
ଠିକ୍ – ସମବାୟ ବ୍ୟାଙ୍କ୍ କୃଷି ପାଇଁ ସ୍ବଳ୍ପକାଳୀନ ଋଣ ଦେଇଥାଏ !

2. ଭାରତରେ ଏକକ ବ୍ୟାଙ୍କ ବ୍ୟବସ୍ଥା ପ୍ରଚଳିତ ।
Answer:
ଭୁଲ୍ ।
ଠିକ୍ – ଆମେରିକାରେ ଏକକ ବ୍ୟାଙ୍କ୍ ବ୍ୟବସ୍ଥା ପ୍ରଚଳିତ ।

CHSE Odisha Class 12 Economics Chapter 15 Objective Questions in Odia Medium

3. ସ୍ଥାୟୀ ଜମାର ଅନ୍ୟନାମ ଚାହିଦା ଜମା ।
Answer:
ଭୁଲ୍ ।
ଠିକ୍ – ସ୍ଥାୟୀ ଜମାର ଅନ୍ୟନାମ ମିଆଦି ଜମା ।

4. ନଗଦୀ ସଂରକ୍ଷଣ ଅନୁପାତ ଓ ଋଣ ପରିମାଣ ମଧ୍ଯରେ ପ୍ରତ୍ୟକ୍ଷ ସମ୍ପର୍କ ରହିଛି ।
Answer:
ଭୁଲ୍ ।
ଠିକ୍ – ନଗଦୀ ସଂରକ୍ଷଣ ଅନୁପାତ ଓ ଋଣ ପରିମାଣ ମଧ୍ଯରେ ପରୋକ୍ଷ ସମ୍ପର୍କ ରହିଛି ।

5. କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍ ଋଣ ସୃଷ୍ଟି କରେ ।
Answer:
ଭୁଲ୍ ।
ଠିକ୍ – ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍ ଋଣ ସୃଷ୍ଟି କରେ ।

6. ମିଆଦି ଜମା ନଗଦ ମୁଦ୍ରା ସହିତ ସମାନ ।
Answer:
ଭୁଲ୍ ।
ଠିକ୍ – ଚାହିଦା ଜମା ନଗଦ ମୁଦ୍ରା ସହିତ ସମାନ ।

7. ବ୍ୟାଙ୍କ୍ ଅଫ ଇଂଲଣ୍ଡ ବିଶ୍ବର ପ୍ରଥମ କେନ୍ଦ୍ରୀୟ ବ୍ୟାକ୍ ।
Answer:
ଭୁଲ୍ ।
ଠିକ୍ – ରିକ୍ ବ୍ୟାଙ୍କ୍ ଅଫ୍ ସ୍ବିଡ଼େନ୍ ବିଶ୍ବର ପ୍ରଥମ କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍ ।

8. 1947 ମସିହାରେ ଭାରତୀୟ ରିଜର୍ଭ ବ୍ୟାଙ୍କ ସ୍ଥାପିତ ହୋଇଥିଲା ।
Answer:
ଭୁଲ୍ ।
ଠିକ୍ – 1935 ମସିହାରେ ଭାରତୀୟ ରିଜର୍ଭ ବ୍ୟାଙ୍କୁ ସ୍ଥାପିତ ହୋଇଥିଲା ।

9. ଭାରତରେ ଏକ ଟଙ୍କିଆ ନୋଟ୍ ଭାରତୀୟ ରିଜର୍ଭ ବ୍ୟାଙ୍କ୍ ପ୍ରଚଳନ କରେ ।
Answer:
ଭୁଲ୍ ।
ଠିକ୍ – ଭାରତରେ ଏକ ଟଙ୍କିଆ ନୋଟ୍, ଭାରତ ସରକାରଙ୍କ ବିତ୍ତ ମନ୍ତ୍ରଣାଳୟ ପ୍ରଚଳନ କରେ ।

10. ଭାରତରେ ପାଞ୍ଚଶହ ଟଙ୍କିଆ ନୋଟ୍ ଭାରତୀୟ ରିଜର୍ଭ ବ୍ୟାଦ୍ୱାରା ପ୍ରଚଳିତ ହୁଏ ।
Answer:
ଠିକ୍ ।

11. ବାଣିଜ୍ୟିକ ବ୍ୟାକ୍ ସରକାରଙ୍କ ବ୍ୟାଙ୍କ୍ ।
Answer:
ଭୁଲ୍ ।
ଠିକ୍ – କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍ ସରକାରଙ୍କ ବ୍ୟାଙ୍କ୍ ।

12. ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍ ଋଣ ନିୟନ୍ତ୍ରଣ କରିଥାଏ ।
Answer:
ଭୁଲ୍ ।
ଠିକ୍ – କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍ ଋଣ ନିୟନ୍ତ୍ରଣ କରିଥାଏ ।

13. ମିଆଦି ଜମାର ଉଠାଣ ଚାହିଁବା ମାତ୍ରେ ସମ୍ଭବ ।
Answer:
ଭୁଲ୍ ।
ଠିକ୍ – ଚାହିଦା ଜମାର ଉଠାଣ ଚାହିଁବା ମାତ୍ରେ ସମ୍ଭବ ।

14. ଭାରତୀୟ ଷ୍ଟେଟ୍ ବ୍ୟାକ୍ ବ୍ୟାକ୍‌ମାନଙ୍କର ବ୍ୟାକ୍ ଅଟେ ।
Answer:
ଭୁଲ୍ ।
ଠିକ୍ – ଭାରତୀୟ ରିଜର୍ଭ ବ୍ୟାଙ୍କ୍ ବ୍ୟାଟ୍ସମାନଙ୍କର ବ୍ୟାଙ୍କ୍ ଅଟେ ।

CHSE Odisha Class 12 Economics Chapter 15 Objective Questions in Odia Medium

15. ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍ ଅନ୍ତିମ ଋଣଦାତା ।
Answer:
ଭୁଲ୍ ।
ଠିକ୍ – କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍ ଅନ୍ତିମ ଋଣଦାତା ।

16. ବ୍ୟାଙ୍କ୍ ରେଟ ବୃଦ୍ଧି ଘଟିଲେ ଋଣ ପରିମାଣ ବୃଦ୍ଧି ପାଏ ।
Answer:
ଭୁଲ୍ ।
ଠିକ୍ – ବ୍ୟାଙ୍କ୍ ରେଟ ବୃଦ୍ଧି ଘଟିଲେ ଋଣ ପରିମାଣ ହ୍ରାସ ପାଏ ।

17. ଭାରତୀୟ ଷ୍ଟେଟ୍ ବ୍ୟାଟ୍ ଭାରତର କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍।
Answer:
ଭୁଲ୍ ।
ଠିକ୍ – ଭାରତୀୟ ରିଜର୍ଭ ବ୍ୟାଙ୍କୁ ଭାରତର କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍ ।

18. କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କୁ ଜନସାଧାରଣଙ୍କ ସହ ଋଣ କାରବାର କରିଥାଏ ।
Answer:
ଭୁଲ୍ ।
ଠିକ୍ – କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କୁ ସରକାରଙ୍କ ସହ ଋଣ କାରବାର କରିଥାଏ ।

19. ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କମାନେ ଦୀର୍ଘକାଳୀନ ଋଣ ପ୍ରଦାନ କରନ୍ତି ।
Answer:
ଭୁଲ୍ ।
ଠିକ୍ – ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କମାନେ ସ୍ଵଳ୍ପକାଳୀନ ଋଣ ପ୍ରଦାନ କରନ୍ତି ।

20. ଲାଭ ଅର୍ଜନ କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କର ସର୍ବପ୍ରଧାନ ନୀତି ।
Answer:
ଭୁଲ୍ ।
ଠିକ୍ – ସାଧାରଣ କଲ୍ୟାଣ ସାଧନ କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କର ସର୍ବପ୍ରଧାନ ନୀତି ।

D. ଗୋଟିଏ ବାକ୍ୟରେ ଉତ୍ତର ଦିଅ ।

1. ବାଣିଜ୍ୟ ବ୍ୟାଙ୍କ୍ କାହାକୁ କହନ୍ତି ?
Answer:
ଯେଉଁ ବିତ୍ତୀୟ ଅନୁଷ୍ଠାନ ଜନସାଧାରଣଙ୍କଠାରୁ ଜମା ଗ୍ରହଣ, ଋଣ ପ୍ରଦାନ, ମୁଦ୍ରା ଯୋଗାଣ, ମୁଦ୍ରା ସୃଜନ, ଅନ୍ତର୍ଦେଶୀୟ ଓ ବୈଦେଶିକ ବାଣିଜ୍ୟିକ ସୁବନ୍ଦୋବସ୍ତ ସହିତ ବିନିମୟ ପତ୍ରର ପୂର୍ବପ୍ରାପଣ କରନ୍ତି, ସେହି ଅନୁଷ୍ଠାନକୁ ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ କୁହାଯାଏ ।

2. ବିନିମୟ ବ୍ୟାଟ୍‌ର ମୁଖ୍ୟ କାର୍ଯ୍ୟ କ’ଣ ?
Answer:
ବିନିମୟ ବ୍ୟାଙ୍କ୍ ବୈଦେଶିକ ବାଣିଜ୍ୟ ପାଇଁ ଆବଶ୍ୟକ ହେଉଥ‌ିବା ଅର୍ଥ ଋଣ ଆକାରରେ ପ୍ରଦାନ କରେ ।

3. କେଉଁ ବ୍ୟାଙ୍କ୍ କୃଷି ପାଇଁ ଦୀର୍ଘକାଳୀନ ଋଣ ଦିଏ ?
Answer:
ଭୂବନ୍ଧକ ବ୍ୟାଙ୍କ କୃଷି ପାଇଁ ଦୀର୍ଘକାଳୀନ ଋଣ ଦିଏ ?

4. ଆଞ୍ଚଳିକ ଗ୍ରାମ୍ୟ ବ୍ୟାଙ୍କ୍ ଭାରତରେ କେବେ ସ୍ଥାପିତ ହୋଇଥିଲା ?
Answer:
1975 ମସିହାରେ ଭାରତରେ ଆଞ୍ଚଳିକ ଗ୍ରାମ୍ୟ ବ୍ୟାଙ୍କ୍ ସ୍ଥାପିତ ହୋଇଥିଲା ।

5. ଚଳନ୍ତି ଜମାକୁ କାହିଁକି ଚାହିଦା ଜମା ମଧ୍ୟ କୁହାଯାଏ ?
Answer:
ଚାହିଁବା ମାତ୍ରେ ଚଳନ୍ତି ଜମାର ଉଠାଣ ସମ୍ଭବ ହେଉଥ‌ିବାରୁ ଏହାକୁ ଚାହିଦା ଜମା ମଧ୍ୟ କୁହାଯାଏ ।

6. ସ୍ଥାୟୀ ଜମାର ଅନ୍ୟ ନାମ କ’ଣ ?
Answer:
ସ୍ଥାୟୀ ଜମାର ଅନ୍ୟ ନାମ ହେଲା ମିଆଦି ଜମା ।

CHSE Odisha Class 12 Economics Chapter 15 Objective Questions in Odia Medium

7. ଅତିରିକ୍ତ ଉଠାଣ କାହାକୁ କହନ୍ତି ?
Answer:
ଯେତେବେଳେ ଜଣେ ଜମାକାରୀଙ୍କୁ ତାଙ୍କ ଜମାରାଶିଠାରୁ ଅଧିକ ଉଠାଣ ପାଇଁ ବ୍ୟାଙ୍କ୍ ଯେଉଁ ଅନୁମତି ପ୍ରଦାନ କରିଥାଏ, ତାହାକୁ ଅତିରିକ୍ତ ଉଠାଣ କୁହାଯାଏ ।

8. ବ୍ୟାକ୍ ମୁଦ୍ରା କ’ଣ ?
Answer:
ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍ ସୃଷ୍ଟି କରୁଥିବା ଋଣମୁଦ୍ରାକୁ ବ୍ୟାଙ୍କ ମୁଦ୍ରା କୁହାଯାଏ ।

9. ନଗଦୀ ସଂରକ୍ଷଣ ଅନୁପାତ ଓ ଋଣ ଗୁଣାଙ୍କ ମଧ୍ୟରେ କି ସମ୍ପର୍କ ରହିଛି ?
Answer:
ନଗଦୀ ସଂରକ୍ଷଣ ଅନୁପାତ ଓ ଋଣ ଗୁଣାଙ୍କ ମଧ୍ୟରେ ପରୋକ୍ଷ-ଆନୁପାତିକ ସମ୍ପର୍କ ରହିଛି ।

10. ନଗଦୀ ସଂରକ୍ଷଣ ଅନୁପାତ 20% ହେଲେ ଋଣ ଗୁଣାଙ୍କ କେତେ ହେବ ?
Answer:
ନଗଦୀ ସଂରକ୍ଷଣ ଅନୁପାତ 20% ହେଲେ ଋଣ ଗୁଣାଙ୍କ 5 ହେବ ।

11. ଯଦି ନଗଦୀ ସଂରକ୍ଷଣ ଅନୁପାତ 5% ତେବେ ପାଞ୍ଚ ହଜାର ଟଙ୍କାର ଜମା କେତେ ଟଙ୍କାର ସର୍ବାଧ‌ିକ ଋଣ ସୃଷ୍ଟି କରିପାରିବ ?
Answer:
ଯଦି ନଗଦୀ ସଂରକ୍ଷଣ ଅନୁପାତ 5% ତେବେ ପାଞ୍ଚ ହଜାର ଟଙ୍କାର ଜମା 95,000 ଟଙ୍କାର ସର୍ବାଧ‌ିକ ଋଣ ସୃଷ୍ଟି କରି ପାରିବ ।

12. ବିଶ୍ବର ପ୍ରଥମ କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କର ନାମ କ’ଣ ?
Answer:
ସ୍ବିଡ଼େନ୍‌ର ରିକ୍ ବ୍ୟାଙ୍କ୍ ବିଶ୍ବର ପ୍ରଥମ କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍ !

13. ଭାରତୀୟ ରିଜର୍ଭ ବ୍ୟାଙ୍କ୍ କେବେ ପ୍ରତିଷ୍ଠିତ ହୋଇଥିଲା ?
Answer:
1935 ମସିହାରେ ଭାରତୀୟ ରିଜର୍ଭ ବ୍ୟାଙ୍କ୍ ପ୍ରତିଷ୍ଠିତ ହୋଇଥିଲା ।

14. ଭାରତରେ ଏକଟଙ୍କିଆ ନୋଟ୍ କିଏ ପ୍ରଚଳନ କରିଥାଏ ?
Answer:
ଭାରତ ସରକାରଙ୍କ ବିତ୍ତ ମନ୍ତ୍ରଣାଳୟ, ଭାରତରେ ଏକ ଟଙ୍କିଆ ନୋଟ୍ ପ୍ରଚଳନ କରିଥାଏ ।

15. ଇଂଲଣ୍ଡର କେନ୍ଦ୍ରୀୟ ବ୍ୟାକ୍ଚର ନାମ କ’ଣ ?
Answer:
ଇଂଲଣ୍ଡର କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କର ନାମ ହେଲା ବ୍ୟାଙ୍କ୍ ଅଫ୍ ଇଂଲଣ୍ଡ ।

16. କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍‌କୁ ଅନ୍ତିମ ଋଣଦାତା ବୋଲି କାହିଁକି କୁହାଯାଏ ?
Answer:
କୌଣସି ଆର୍ଥିକ ସଙ୍କଟ ସମୟରେ ଯଦି ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ ଅନ୍ୟ କୌଣସି ସୂତ୍ରରୁ ଅର୍ଥ ଯୋଗାଡ଼ କରିବାପାଇଁ ଅସମର୍ଥ ହୁଏ, ତେବେ ଏହା ପରିଶେଷରେ କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କର ଦ୍ବାରସ୍ଥ ହୋଇଥାଏ ଏବଂ କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍ ଆର୍ଥିକ ସହାୟତା ପ୍ରଦାନ କରେ । ତେଣୁ କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍‌କୁ ଅନ୍ତିମ ଋଣଦାତା କୁହାଯାଏ ।

17. କେଉଁ ସଂସ୍ଥା ଋଣ ନିୟନ୍ତ୍ରଣ କରିଥାଏ ?
Answer:
କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍ ଋଣ ନିୟନ୍ତ୍ରଣ କରିଥାଏ ।

18. ବ୍ୟାଙ୍କ୍ ହାର କାହାକୁ କହନ୍ତି ?
Answer:
କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍ ବାଣିଜ୍ୟିକ ବ୍ୟାଟ୍ସମାନଙ୍କୁ ଯେଉଁ ହାରରେ ଋଣ ଦେଇଥାଏ, ତାହାକୁ ବ୍ୟାଙ୍କ ହାର କୁହାଯାଏ ।

19. କେଉଁ ବ୍ୟାଙ୍କ୍ ପରିଶୋଧନର ମାଧ୍ୟମ ?
Answer:
କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ୍ ପରିଶୋଧନର ମାଧ୍ୟମ ।

20. ରାଷ୍ଟ୍ରରେ ବୈଦେଶିକ ବିନିମୟ ମୁଦ୍ରାର ତତ୍ତ୍ବାବଧାନ କିଏ କରିଥାଏ ?
Answer:
ରାଷ୍ଟ୍ରରେ କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କ ବୈଦେଶିକ ବିନିମୟ ମୁଦ୍ରାର ତତ୍ତ୍ୱାବଧାନ କରିଥାଏ ।

21. ଗୁଣାତ୍ମକ ଋଣ ନିୟନ୍ତ୍ରଣ ପଦ୍ଧତିର ଅନ୍ୟ ନାମ କ’ଣ ?
Answer:
ଗୁଣାତ୍ମକ ଋଣ ନିୟନ୍ତ୍ରଣ ପଦ୍ଧତିର ଅନ୍ୟ ନାମ ହେଉଛି ଚୟନାତ୍ମକ ଋଣ ନିୟନ୍ତ୍ରଣ ।

22. ଗୁଣାତ୍ମକ ଋଣ ନିୟନ୍ତ୍ରଣ ପାଇଁ ଉଦ୍ଦିଷ୍ଟ ଦୁଇଟି ଆୟୁଧର ନାମ ଲେଖ ।
Answer:
ଗୁଣାତ୍ମକ ଋଣ ନିୟନ୍ତ୍ରଣ ପାଇଁ ଉଦ୍ଦିଷ୍ଟ ଦୁଇଟି ଆୟୁଧର ନାମ ହେଲା – (i) ପ୍ରତ୍ୟକ୍ଷ କାର୍ଯ୍ୟାନୁଷ୍ଠାନ, (ii) ନୈତିକ ପ୍ରବର୍ତ୍ତନ ।

23. ଖୋଲାବଜାର କାରବାର କହିଲେ କ’ଣ ବୁଝ ?
Answer:
କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କଦ୍ୱାରା ଖୋଲା ବଜାରରେ ସରକାରୀ ପ୍ରତିଭୂତିର କ୍ରୟ ବିକ୍ରୟ ପ୍ରକ୍ରିୟାକୁ ଖୋଲା ବଜାର କାରବାର କୁହାଯାଏ ।

24. ବ୍ୟାକ୍ ହାର ଓ ଋଣ ପରିମାଣ ମଧ୍ଯରେ କି ସମ୍ପର୍କ ରହିଛି ?
Answer:
ବ୍ୟାଙ୍କ୍ ହାର ଓ ଋଣ ପରିମାଣ ମଧ୍ଯରେ ପରୋକ୍ଷ ସମ୍ପର୍କ ରହିଛି ।

CHSE Odisha Class 12 Economics Chapter 15 Objective Questions in Odia Medium

25. କେଉଁ ଜମା ଚାହିଁବାମାତ୍ରେ ପରିଶୋଧନୀୟ ନୁହେଁ ?
Answer:
ମିଆଦୀ ଜମା ଚାହିଁବାମାତ୍ରେ ପରିଶୋଧନୀୟ ନୁହେଁ ।

26. ବ୍ୟାଟ୍ସମାନଙ୍କର ସର୍ବବୃହତ୍ ଦେୟ କ’ଣ ?
Answer:
‘ଜମା’ ବ୍ୟାଙ୍କମାନଙ୍କର ସର୍ବବୃହତ୍ ଦେୟ ।

27. ପ୍ରଦତ୍ତ ପୁଞ୍ଜି ବା ପରିଶୋଧ ପୁଞ୍ଜି କ’ଣ ?
Answer:
ଅଭିଦତ୍ତ ପୁଞ୍ଜିର ଯେଉଁ ଅଂଶ ନଗଦ ମୁଦ୍ରାଦେଇ ଅଂଶୀଦାରମାନେ କ୍ରୟ କରିଥା’ନ୍ତି, ତାହାକୁ ପ୍ରଦତ୍ତ ପୁଞ୍ଜି ବା ପରିଶୋଧ ପୁଞ୍ଜି
କୁହାଯାଏ ।

28. ଅଭିଦତ୍ତ ପୁଞ୍ଜି କ’ଣ ?
Answer:
ଅଂଶୀଦାରମାନେ ଯେଉଁ ପରିମାଣର ଅଂଶ କ୍ରୟ କରିବାକୁ ସ୍ବୀକୃତି ଦେଇଥା’ନ୍ତି, ତାହାକୁ ଅଭିଦତ୍ତ ପୁଞ୍ଜି କୁହାଯାଏ ।

29. ସଂରକ୍ଷିତ ପାଣ୍ଠି କ’ଣ ?
Answer:
ଲାଭର ଯେଉଁ ଅଂଶ ଅଂଶୀଦାରମାନଙ୍କ ମଧ୍ୟରେ ବଣ୍ଟନ କରା ନ ଯାଇ ଭବିଷ୍ୟତ ନିରାପତ୍ତା ପାଇଁ ସଂରକ୍ଷିତ ହୋଇଥାଏ, ତାହାକୁ ସଂରକ୍ଷିତ ପାଣ୍ଠି କୁହାଯାଏ ।

30. ହସ୍ତସ୍ଥ ମୁଦ୍ରା କ’ଣ ?
Answer:
ପ୍ରତ୍ୟେକ ବ୍ୟାଙ୍କ୍ ଗ୍ରାହକମାନଙ୍କ ଚାହିଦାମାତ୍ରକେ ସେମାନଙ୍କ ଆବଶ୍ୟକତା ପୂରଣ କରିବା ପାଇଁ ନିଜ ପାଖେ କିଛି ନଗଦ ମୁଦ୍ରା ରଖନ୍ତି, ଏହାକୁ ହସ୍ତସ୍ଥ ମୁଦ୍ରା କୁହାଯାଏ ।

31. ବ୍ୟାଙ୍କ୍‌ ସର୍ବାଧ୍ଵକ ତରଳ ପରିସମ୍ପତ୍ତି କିଏ ?
Answer:
ନଗଦ ମୁଦ୍ରା ବ୍ୟାଙ୍କର ସର୍ବାଧ‌ିକ ତରଳ ପରିସମ୍ପତ୍ତି ।

32. କେଉଁ ଜମା ନିର୍ଦ୍ଦିଷ୍ଟ ସମୟ ଅତିବାହିତ ହେବା ପୂର୍ବରୁ ପ୍ରତ୍ୟାହାର ହୋଇପାରେ ନାହିଁ ?
Answer:
ମିଆଦୀ ଜମା ନିର୍ଦ୍ଦିଷ୍ଟ ସମୟ ଅତିବାହିତ ହେବା ପୂର୍ବରୁ ପ୍ରତ୍ୟାହାର ହୋଇପାରେ ନାହିଁ ।

CHSE Odisha Class 12 Economics Chapter 15 Objective Questions in Odia Medium

33. ସନ୍ତୁଳନ ପତ୍ର କାହାକୁ କୁହାଯାଏ ?
Answer:
ବାଣିଜ୍ୟିକ ବ୍ୟାଙ୍କ୍ସର ପରିସମ୍ପତ୍ତି ଓ ଦେୟତାର ଏକ ବାର୍ଷିକ ବିବରଣୀକୁ ତା’ର ସନ୍ତୁଳନ ପତ୍ର କୁହାଯାଏ ।

34. ଦେୟତା କାହାକୁ କୁହାଯାଏ ?
Answer:
ଅଂଶୀଦାରମାନଙ୍କୁ ଓ ଜମାକାରୀମାନଙ୍କୁ ଯାହା ବ୍ୟାଙ୍କ୍ ଦେବାକୁ ବାଧ୍ୟ ହୋଇଥାଏ ତାହା ହେଉଛି ଦେୟତା ।

35. ପରିସମ୍ପତ୍ତି କ’ଣ ?
Answer:
ବ୍ୟାଙ୍କୁ ବିଭିନ୍ନ ସୂତ୍ରରୁ ମିଳୁଥିବା ପୁଞ୍ଜି ଓ ଅନ୍ୟାନ୍ୟ ସାମଗ୍ରୀକୁ ପରିସମ୍ପତ୍ତି କୁହାଯାଏ ।

36. କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କର ପୁନଃ ଅବମୂଲ୍ୟାୟନ ହାରର ଅନ୍ୟନାମ କ’ଣ ?
Answer:
କେନ୍ଦ୍ରୀୟ ବ୍ୟାଙ୍କର ପୁନଃ ଅବମୂଲ୍ୟାୟନ ହାରର ଅନ୍ୟ ନାମ ହେଉଛି ବ୍ୟାଙ୍କ୍ ହାର ।

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b)

Odisha State Board CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Textbook Exercise Questions and Answers.

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Exercise 12(b)

Question 1.
Each question given below has four possible answers, out of which only one is correct. Choose the correct one.
(i) (2î – 4ĵ) . (î + ĵ + k̂) = _______.
(a) -3
(b) +2
(c) -1
(d) -2
Solution:
(d) -2

(ii) If a = î + 2ĵ – k̂, b = î + ĵ + 2k̂, c = 2î – ĵ; then
(a) \(\vec{a} \perp \vec{b}\)
(b) \(\vec{b} \perp \vec{c}\)
(c) \(\vec{a} \perp \vec{c}\)
(d) no pair of vectors are perpendicular.
Solution:
(c) \(\vec{a} \perp \vec{c}\)

(iii) (-3, λ, 1) ⊥ (1, 0, -3) ⇒ λ = _______.
(a) 0
(b) 1
(c) impossible to find
(d) any real number
Solution:
(c) impossible to find

(iv) If \(\vec{a} \cdot \vec{b}=\vec{c} \cdot \vec{a}\) for all vectors \(\vec{a}\), then
(a) \(\vec{a} \perp(\vec{b}-\vec{c})\)
(b) \(\vec{b}-\vec{c}\) = 0
(c) \(\vec{b} \neq \vec{c}\)
(d) \(\vec{b}+\vec{c}=\overrightarrow{0}\)
Solution:
(b) \(\vec{b}-\vec{c}\) = 0

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b)

Question 2.
Find the scalar product of the following pairs of vectors and the angle between them.
(i) 3î – 4ĵ and -2î + ĵ
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.2(1)

(ii) 2î – 3ĵ + 6k̂ and 2î – 3ĵ – 5k̂
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.2(2)

(iii) î – ĵ and ĵ + k̂
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.2(3)

(iv) \(\vec{a}\) = (2, -2, 1) and \(\vec{b}\) = (0, 2, 4)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.2(4)

Question 3.
If A, B, C are the points (1, 0, 2), (0, 3, 1) and (5, 2, 0) respectively, find m∠ABC.
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.3

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b)

Question 4.
Find the value of λ so that the vectors \(\vec{a}\) and \(\vec{b}\) are perpendicular to each other.
(i) \(\vec{a}\) = 3î + 4ĵ, \(\vec{b}\) = -5î + λĵ
Solution:
If \(\vec{a}\) and \(\vec{b}\) are perpendicular \(\vec{a} \cdot \vec{b}\) = 0
⇒ (3î + 4ĵ) . (-5î + λĵ) = 0
⇒ -15 + 4λ = 0
⇒ λ = \(\frac{15}{4}\)

(ii) \(\vec{a}\) = î + ĵ + λk̂, \(\vec{b}\) = 4î – 3k̂
Solution:
If \(\vec{a}\) and \(\vec{b}\) are perpendicular \(\vec{a} \cdot \vec{b}\) = 0
⇒ ( î + ĵ + λk̂) . (4î – 3k̂) = 0
⇒ 4 + 0 – 3λ = 0
⇒ λ = \(\frac{4}{3}\)

(iii) \(\vec{a}\) = 2î – ĵ – k̂, \(\vec{b}\) = λî + ĵ + 5k̂
Solution:
If \(\vec{a}\) and \(\vec{b}\) are perpendicular \(\vec{a} \cdot \vec{b}\) = 0
⇒ (2î – ĵ – k̂) . (λî + ĵ + 5k̂) = 0
⇒ 2λ – 1 – 5 = 0
⇒ 2λ = 6
⇒ λ = 3

(iv) \(\vec{a}\) = (6, 2, -3), \(\vec{b}\) = (1, -4, λ)
Solution:
If \(\vec{a}\) and \(\vec{b}\) are perpendicular \(\vec{a} \cdot \vec{b}\) = 0
⇒ (6, 2, -3) . (1, -4, λ) = 0
⇒ 6 – 8 – 3λ = 0
⇒ -2 – 3λ = 0
⇒ λ = –\(\frac{2}{3}\)

Question 5.
Find the scalar and vector projections of \(\vec{a}\) on \(\vec{b}\).
(i) \(\vec{a}\) = î, \(\vec{b}\) = ĵ
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.5(1)

(ii) \(\vec{a}\) = î + ĵ, \(\vec{b}\) = ĵ + k̂
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.5(2)

(iii) \(\vec{a}\) = î – ĵ – k̂, \(\vec{b}\) = 3î + ĵ + 3k̂
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.5(3)

Question 6.
In each of the problems given below, find the work done by a force \(\overrightarrow{F}\) acting on a particle, such that the particle is displaced from a point A to a point B.
(i) \(\overrightarrow{F}\) = 4î + 2ĵ + 3k̂
A (1, 2, 0), B (2, -1, 3)
Solution:
Displacement of the particle \(\overrightarrow{S}=\overrightarrow{AB}\)
= (2 – 1)î + (-1 – 2)ĵ + (3 – 0)k̂
=î – 3ĵ + 3k̂
Work done = \(\overrightarrow{F} \cdot \overrightarrow{S}\)
= (4î + 2ĵ + 3k̂) . (î – 3ĵ + 3k̂)
= 4 – 6 + 9
= 7 units.

(ii) \(\overrightarrow{F}\) = 2î + ĵ – k̂
A (0, 1, 2), B (-2, 3, 0)
Solution:
Displacement
\(\vec{S}\) = (-2 – 0)î + (3 – 1)ĵ + (0 – 2)k̂
= -2î + 2ĵ – 2k̂
Work done = \(\overrightarrow{F} \cdot \overrightarrow{S}\)
= (2î + ĵ – k̂) . (-2î + 2ĵ – 2k̂)
= -4 + 2 + 2
= 0 units.

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b)

(iii) \(\overrightarrow{F}\) = 4î – 3k̂
A (1, 2, 0), B (0, 2, 3)
Solution:
Displacement \(\vec{S}\) = -î + 3k̂
Work done = \(\overrightarrow{F} \cdot \overrightarrow{S}\)
= (4î – 3k̂) . (-î + 3k̂)
= -4 – 9
= -13 units.

(iv) \(\overrightarrow{F}\) = 3î – ĵ – 2k̂
A (-3, -4, 1), B (-1, -1, -2)
Solution:
Displacement \(\vec{S}\) = 2î + 3ĵ – 3k̂
Work done \(\overrightarrow{F} \cdot \overrightarrow{S}\)
= (3î – ĵ – 2k̂) . (2î + 3ĵ – 3k̂)
= 6 – 3 + 6
= 9 units.

Question 7.
If \((\vec{a}+\vec{b}) \cdot(\vec{a}-\vec{b})\) = 0 show that \(|\vec{a}|=|\vec{b}|\).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.7

Question 8.
(i) If a and b are perpendicular vectors show that
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.8
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.8.1

(ii) Prove that two vectors are perpendicular iff \(|\vec{a}+\vec{b}|^2=|\vec{a}|^2+|\vec{b}|^2\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.8.2

Question 9.
If \(\vec{a}, \vec{b}, \vec{c}\) are mutually perpendicular vectors of equal magnitude, show that \(\vec{a}+\vec{b}+\vec{c}\) is equally inclined to \(\vec{a} \cdot \vec{b} \cdot \vec{c}\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.9

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b)

Question 10.
Prove the following by vector method.
(i) Altitudes of a triangle are concurrent;
Solution:
Let ABC be a triangle.
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.10(1)
⇒ CF is perpendicular to AB.
Hence the altitudes of a triangle are concurrent.

(ii) Median to the base of an isosceles triangle is perpendicular to the base;
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.10(2)
⇒ OD is perpendicular to the base AB.
Hence the median to the base of an isosceles triangle is perpendicular to the base. (Proved)

(iii) The parallelogram whose diagonals are equal is a rectangle;
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.10(3)
⇒ m∠COA = 90°
Hence OABC is a rectangle. (Proved)

(iv) The diagonals ofa rhombus are at right angles;
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.10(4)
Hence the diagonals of a rhombus are at right angles. (Proved)

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b)

(v) An angle inscribed in a semi-circle is a right angle;
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.10(5)
∴ m∠ABC = 90°
Hence the angle inscribed in a semi-circle is a right-angle. (Proved)

(vi) In any triangle ABC; a = b cos C + c cos B;
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.10(6)

(vii) In a triangle AOB, m∠AOB = 90°. If P and Q are the points of trisection of AB, prove that OP2 + OQ2 = \(\frac{5}{9}\) AB2;
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.10(7)

(viii) Measure of the angle between two diagonals of a cube is cos-1\(\frac{1}{3}\).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(b) Q.10(8)

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c)

Odisha State Board CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Textbook Exercise Questions and Answers.

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Exercise 12(c)

Question 1.
Each question given below has four possible answers out of which only one is correct. Choose the correct one.
(i) (î + k̂) × (î + ĵ + k̂) = ______.
(a) î – k̂
(b) k̂ – î
(c) k̂ – 2î – ĵ
(d) 2
Solution:
(î + k̂) × (î + ĵ + k̂) = \(\left|\begin{array}{ccc}
\hat{i} & \hat{j} & \hat{k} \\
1 & 0 & 1 \\
1 & 1 & 1
\end{array}\right|\)
= î (0 – 1) – ĵ (1 – 1) + k̂ (1 – 0)
= -î + k̂ = k̂ – î

(ii) A vector perpendicular to the vectors î + ĵ and î + k̂ is ______.
(a) î – ĵ – k̂
(b) ĵ – k̂ + î
(c) k̂ – ĵ – î
(d) ĵ + k̂ + î
Solution:
A vector perpendicular to the vectors î + ĵ and î + k̂ is
(î + ĵ) × (î + k̂) = \(\left|\begin{array}{ccc}
\hat{i} & \hat{j} & \hat{k} \\
1 & 1 & 0 \\
1 & 0 & 1
\end{array}\right|\)
= î (1 – 0) – ĵ (1 – 0) + k̂ (0 – 1)
= î – ĵ – k̂

(iii) The area of the triangle with vertices (1, 0, 0), (0, 1, 0) and (0, 0, 1) is ______.
(a) \(\frac{1}{2}\)
(b) 1
(c) \(\frac{\sqrt{3}}{2}\)
(d) 2
Solution:

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.1

(iv) If â and b̂ are unit vectors such that â × b̂ is a unit vector, then the angle between â and b̂ is ______.
(a) of any measure
(b) \(\frac{\pi}{4}\)
(c) \(\frac{\pi}{2}\)
(d) π
Solution:
|a × b| = ab sin θ = sin θ
⇒ sin θ = 1
⇒ θ = \(\frac{\pi}{2}\)

(v) If \(\vec{a}, \vec{b} \text { and } \vec{c}\) are non-zero vectors, then \(\vec{a} \times \vec{b}=\vec{a} \times \vec{c}\) ______.
(a) \(\vec{b}=\vec{c}\)
(b) \(\vec{a} \|(\vec{b}-\vec{c})\)
(c) \(\vec{b} \| \vec{c}\)
(d) \(\vec{b} \perp \vec{c}\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.1(1)

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c)

Question 2.
Let \(\vec{a}\) = 2î + ĵ, \(\vec{b}\) = -î + 3ĵ + k̂ and \(\vec{c}\) = î + 2ĵ + 5k̂ be three vectors. Find
(i) \(\vec{c} \times \vec{a}\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.2(1)

(ii) \(\vec{a} \times(-\vec{b})\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.2(2)

(iii) \((\vec{a}-2 \vec{b}) \times \vec{c}\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.2(3)

(iv) \((\vec{a}-\vec{c}) \times \vec{c}\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.2(4)

(v) \((\vec{a}-\vec{b}) \times(\vec{c}-\vec{a})\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.2(5)

Question 3.
Find the unit vectors perpendicular to the vectors
(i) î, k̂
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.3(1)

(ii) î + ĵ, î – k̂
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.3(2)

(iii) 2î + 3k̂, î – 2ĵ
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.3(3)

(iv) 2î – 3ĵ + k̂, -î + 2ĵ – k̂
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.3(4)

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c)

Question 4.
Determine the area of parallelogram whose adjacent sides are the vectors
(i) 2î, ĵ
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.4(1)

(ii) î + ĵ, -î + 2ĵ
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.4(2)

(iii) 2î + ĵ + 3k̂, î – ĵ
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.4(3)

(iv) (1, – 3, 1), (1, 1, 1).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.4(4)

Question 5.
Calculate the area of the traingle ABC (by vector method) where
(i) A (1, 2, 4), B (3, 1, -2), C (4, 3, 1)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.5(1)

(ii) A (1, 1, 2), B (2, 2, 3), C (3, -1, -1).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.5(2)

Question 6.
Determine the sine of the angle between the vectors
(i) 5î – 3ĵ, 3î – 2k̂
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.6(1)

(ii) î – 3ĵ + k̂, î + ĵ + k̂
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.6(2)

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c)

Question 7.
Show that \((\vec{a} \times \vec{b})^2\) = a2b2 – \((\vec{a}, \vec{b})^2\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.7

Question 8.
If \(\vec{a} \times \vec{b}=\vec{b} \times \vec{c} \neq \overrightarrow{0}\), prove that \(\vec{a}+\vec{c}=m \vec{b}\), where m is a scalar.
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.8

Question 9.
If \(\vec{a}\) = 2î + ĵ – k̂, \(\vec{b}\) = -î + 2ĵ – 4k̂, \(\vec{c}\) = î + ĵ + k̂, find \((\vec{a} \times \vec{b}) \cdot(\vec{a} \times \vec{c})\).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.9

Question 10.
If \(\vec{a}\) = 3î + ĵ – 2k̂, \(\vec{b}\) = 2î – 3ĵ + 4k̂ then verify that \(\vec{a} \times \vec{b}\) is perpendicular to both \(\vec{a}\) and \(\vec{b}\).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.10

Question 11.
Find the area of the parallelogram whose diagonals are vectors 3î + ĵ – 2k̂ and î – 3ĵ + 4k̂.
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.11

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c)

Question 12.
Show that \((\vec{a}-\vec{b}) \times(\vec{a}+\vec{b})=2(\vec{a} \times \vec{b})\). Interpret this result geometrically.
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(c) Q.12
= Vector area of the parallelogram ABCD.
Hence twice the vector area of a parallelogram ABCD is equal to the vector area of the parallelogram whose adjacent sides are the diagonals of the parallelogram ABCD.

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise

Odisha State Board Elements of Mathematics Class 12 Solutions CHSE Odisha Chapter 11 Differential Equations Additional Exercise Textbook Exercise Questions and Answers.

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise

(A) Multiple Choice Questions (Mcqs) With Answers

Question 1.
If f is an odd function, then write the value of \(\int_{-a}^a \frac{f(\sin x)}{f(\cos x)+f\left(\sin ^2 x\right)}\) dx
(a) 1
(b) 0
(c) -1
(d) 2
Solution:
(b) 0

Question 2.
If p and q are respectively degree and order of the differential equation y = edy/dx then write the relation between p and q.
(a) p ≠ q
(c) p ≡ q
(b) p = q
(d) None of these
Solution:
(b) p = q

Question 3.
Write the value of \(\int_0^1\){x} dx where {x} stands for fractional part of x.
(a) \(\frac{1}{2}\)
(b) \(\frac{3}{2}\)
(c) \(\frac{1}{4}\)
(d) \(\frac{2}{3}\)
Solution:
(a) \(\frac{1}{2}\)

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise

Question 4.
Write the value of:
\(\int_0^{\pi / 2} \frac{\sin x}{\sin x+\cos x}\) dx – \(\int_0^{\pi / 2} \frac{\cos x}{\sin x+\cos x}\) dx
(a) 1
(b) 2
(c) 0
(d) π
Solution:
(c) 0

Question 5.
Write the value of \(\int_{\frac{\pi}{4}}^{\frac{\pi}{4}}\)sin5 x cos x dx
(a) 0
(b) 1
(c) cos x
(d) sin x
Solution:
(a) 0

Question 6.
Write the particular solution of the equation \(\frac{d y}{d x}\) = sin x given that y(π) = 2
(a) y = cos x + 1
(b) y = -cos x + 1
(c) y = -cos x – 1
(d) y = -sin x + 1
Solution:
(b) y = -cos x + 1

Question 7.
Write the degree of the following differential equation:
\(\frac{\mathrm{d}^2 \mathrm{y}}{\mathrm{dx}^2}\) = \(\frac{2 y^3+\left(\frac{d y}{d x}\right)^4}{\sqrt{\frac{d^2 y}{d x^2}}}\)
(a) 0
(b) 1
(c) 2
(d) 3
Solution:
(d) 3

Question 8.
Write the order ofthe following differential equation:
\(\frac{d^2 y}{d x^2}\) = \(\frac{2 y^3+\left(\frac{d y}{d x}\right)^4}{\sqrt{\frac{d^2 y}{d x^2}}}\)
(a) 0
(b) 1
(c) 2
(d) 3
Solution:
(c) 2

Question 9.
What is F(x) if F(x) = \(\int_0^x\)e2t sin 3t dt?
(a) e2x sin 3x
(b) e2x cos 3x
(c) ex sin 3x
(d) e2x sin x
Solution:
(a) e2x sin 3x

Question 10.
\(\int \frac{d x}{\cos ^2 x \sin ^2 x}\) = ?
(a) -2 cos 2x + C
(b) -2 cot 2x + C
(c) -2 sin 2x + C
(d) 2 cot 2x + C
Solution:
(b) -2 cot 2x + C

Question 11.
If \(\int_1^2\)f(x) dx= λ, then what is the value of \(\)f(3 – x) dx?
(a) λ
(b) λ2
(c) 1λ
(d) 2λ
Solution:
(a) λ

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise

Question 12.
What is the value of \(\int_{-1}^1 \frac{d x}{1+x^2}\)?
(a) \(\frac{2 \pi}{2}\)
(b) 2π
(c) π
(d) \(\frac{\pi}{2}\)
Solution:
(d) \(\frac{\pi}{2}\)

Question 13.
Write the order of the following differential equation:
\(\frac{d^3 y}{d x^3}\) = \(\left(\frac{d^2 y}{d x^2}\right)^2\) + \(\left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)^4\) + y
(a) 1
(b) 3
(c) 2
(d) 0
Solution:
(b) 3

Question 14.
Write the degree of the following differential equation:
\(\frac{d^3 y}{d x^3}\) = \(\left(\frac{d^2 y}{d x^2}\right)^2\) + \(\left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)^4\) + y
(a) 1
(b) 2
(c) 3
(d) 0
Solution:
(a) 1

Question 15.
Write the particular solution of \(\frac{\mathrm{dy}}{\mathrm{dx}}\) = (1 + x)4, y = 0 when x = -1.
(a) y = \(\frac{(1+x)^2}{5}\)
(b) y = \(\frac{(2+x)^5}{5}\)
(c) y = \(\frac{(1-x)^5}{5}\)
(d) y = \(\frac{(1+x)^5}{5}\)
Solution:
(d) y = \(\frac{(1+x)^5}{5}\)

Question 16.
Evaluate the integral ∫2x cosec2 x2 dx?
(a) cot x2 + C
(b) -cot x2 + C
(c) -cot 2x2 + C
(d) cot 2x2 + C
Solution:
(b) -cot x2 + C

Question 17.
What is the value of \(\frac{d}{d x} \int_{250}^{300}\left(x^4+5 x^3\right)^2\) dx
(a) 0
(b) 1
(c) -1
(d) 2
Solution:
(a) 0

Question 18.
Write down the integral of ∫\(e^{x^2}\) 2x dx.
(a) \(e^{2 x^2}\)
(b) 2\(e^{2 x^2}\)
(c) \(e^{x^2}\)
(d) None of the above
Solution:
(c) \(e^{x^2}\)

Question 19.
What is the integral of ∫log ex dx?
(a) \(\frac{2 x^2}{2}\) + C
(b) \(\frac{2 x^2}{3}\) + C
(c) \(\frac{x^2}{2}\) + C
(d) None of the above
Solution:
(c) \(\frac{x^2}{2}\) + C

Question 20.
What is the value of \(\int_{-2}^2\)|x| dx?
(a) 0
(b) 1
(c) 2
(d) 3
Solution:
(a) 0

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise

Question 21.
\(\int_{-1}^1\)|1 – x| dx = ______.
(a) 0
(b) 1
(c) 2
(d) -1
Solution:
(c) 2

Question 22.
If ∫x3\(e^{c x^4}\)dx = \(\frac{1}{20} \mathrm{e}^{\mathrm{cx}}\) then C = ______.
(a) 0
(b) 2
(c) 4
(d) 5
Solution:
(d) 5

Question 23.
\(\int_a^b\)f(x) dx = 1 ⇒ \(\int_a^b\)k f(t)dt ______.
(a) k
(b) -k
(c) 2k
(d) None of the above
Solution:
(b) -k

Question 24.
\(\int_{-1}^1\)f(x) dx = k and f is an even function then \(\int_{-1}^1\)f(x) = ______.
(a) k
(b) -k
(c) 2k
(d) None of the above
Solution:
(c) 2k

Question 25.
If ∫\(\int_0^1\)f(x) dx = 4, \(\int_0^2\)f(t) dt and \(\int_4^2\)f(u) du = 1 then \(\int_1^4\)f(x) dx = ______.
(a) 0
(b) 1
(c) 3
(d) -3
Solution:
(d) -3

Question 26.
I(f) = \(\int_a^x\)f(t) dt and Df = f'(x) then (ID – DI) f = ______.
(a) -f(a)
(b) 2f(a)
(c) f(a)
(d) None of the above
Solution:
(a) -f(a)

Question 27.
\(\int_0^\pi\)cos101 x dx = ______.
(a) 0
(b) 1
(c) -1
(d) 101
Solution:
(a) 0

Question 28.
Let f satisfies all the conditions of Rolle’s theorem in [1, 6] then \(\int_1^6\)f'(x) dx = ______.
(a) 0
(b) 1
(c) -1
(d) 6
Solution:
(a) 0

Question 29.
\(\int_{-2}^2\)|x| dx = ______.
(a) 1
(b) 2
(c) 3
(d) 4
Solution:
(d) 4

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise

Question 30.
Integrate ∫log x dx
(a) x. log x + x + C
(b) x. log x – x + C
(c) log x – x + C
(d) None of these
Solution:
(b) x. log x – x + C

Question 31.
Evaluate \(\int_0^2\)[x – 1] dx
(a) 0
(b) 1
(c) -1
(d) 2
Solution:
(b) 1

Question 32.
What is the value of: ∫\(\frac{f^{\prime}(x)-f(x)}{e^x}\) dx?
(a) ex f(x) + C.
(b) e2x f(x) + C.
(c) e-x f(x) + C.
(d) None of the above
Solution:
(c) e-x f(x) + C.

Question 33.
What is the value of \(\int_0^1\)x(1 – x)99 dx?
(a) \(\frac{1}{100}\)
(b) \(\frac{1}{10}\)
(c) \(\frac{1}{1010}\)
(d) \(\frac{1}{10100}\)
Solution:
(d) \(\frac{1}{10100}\)

Question 34.
Solution of \(\frac{\mathrm{dy}}{\mathrm{dx}}\) = xy + x + y + 1 is ______.
(a) 2x + \(\frac{x^2}{2}\) + C
(b) x + \(\frac{x}{2}\) + C
(c) x + \(\frac{2 x^2}{2}\) + C
(d) x + \(\frac{x^2}{2}\) + C
Solution:
(d) x + \(\frac{x^2}{2}\) + C

Question 35.
f(x) = \(\int_0^x\)t sin t dt then f ‘(x) = ______.
(a) x cos x
(b) x sin t
(c) x sin x
(d) x tan x
Solution:
(c) x sin x

Question 36.
What is the value of the integral \(\int_a^b \frac{|x|}{x}\)dx?
(a) |b| – |a|
(b) |a| – |b|
(c) |b| + |a|
(d) |a| + |b|
Solution:
(a) |b| – |a|

Question 37.
What is the value of ∫xx (1 + ln x) dx?
(a) x2x + C
(b) xx + C
(c) 2xx + C
(d) x2 + C
Solution:
(b) xx + C

Question 38.
Evaluate: \(\int_0^{\mathrm{p} / 2}\)ln(cot x) dx.
(a) 0
(b) 1
(c) cot x
(d) sin x
Solution:
(a) 0

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise

Question 39.
Evaluate: \(\int_{-3}^4\)|x| dx
(a) \(\frac{2}{25}\)
(b) \(\frac{25}{2}\)
(c) \(\frac{25}{4}\)
(d) \(\frac{25}{-3}\)
Solution:
(b) \(\frac{25}{2}\)

Question 40.
Evaluate: \(\int_0^{\frac{\pi}{2}}\)(cos x – sin x) dx
(a) 0
(b) 1
(c) -1
(d) π
Solution:
(a) 0

Question 41.
Evaluate: \(\int_0^{\frac{\pi}{2}}\)log tan x dx.
(a) 1
(b) -1
(c) 0
(d) π
Solution:
(c) 0

Question 42.
Integrate: \(\frac{d x}{3 e^x-1}\)
(a) \(\ln \left(\frac{e^{3 x}-1}{e^x}\right)\) + C
(b) \(\ln \left(\frac{3 e^x+1}{e^x}\right)\) + C
(c) \(\ln \left(\frac{3 e^x-1}{e^x}\right)\) + C
(d) \(\ln \left(\frac{3 e^x+1}{e^{3 x}}\right)\) + C
Solution:
(c) \(\ln \left(\frac{3 e^x-1}{e^x}\right)\) + C

Question 43.
Evaluate: \(\int_0^1 \ln \left(\frac{1}{x}-1\right)\)dx
(a) 1
(b) 2
(c) 0
(d) -1
Solution:
(c) 0

Question 44.
Evaluate: ∫ex\(\left(\frac{1-\sin x}{1-\cos x}\right)\)dx
(a) -ex cot\(\frac{x}{2}\) + C
(b) ex tan\(\frac{x}{2}\) + C
(c) ex cot\(\frac{x}{2}\) + C
(d) -ex sin\(\frac{x}{2}\) + C
Solution:
(a) -ex cot\(\frac{x}{2}\) + C

Question 45.
Evaluate: \(\int_0^1\)x log(1 + x) dx
(a) \(\frac{1}{2}\)
(b) \(\frac{1}{4}\)
(c) \(\frac{1}{3}\)
(d) \(\frac{2}{3}\)
Solution:
(b) \(\frac{1}{4}\)

Question 46.
What is the integrating factor of the equation y’ + y cot x = cosec x?
(a) cot x
(b) sin x
(c) cos x
(d) cosec x
Solution:
(b) sin x

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise

(B) Very Short Type Questions With Answers

Question 1.
Write the order of the differential equation whose solution is given by
y = (c1 + c2) cos (x + c3) + c4\(e^{x+c_5}\) where c1, c2, c4 and c5 are arbitrary constants.
Solution:
y = (c1 + c2) cos (x + c3) + c4\(e^{x+c_5}\)
y = (c1 + c2) cos (x + c3) + c4\(e^{c_5}\).ex
= A cos(x + c3) + Bex
Where c1 + c2 = A, c4\(e^{c_5}\) = B
As there are 3 independent constants the order of the differential equation is 3.

Question 2.
If p and q are respectively degree and order of the differential equation y = edy/dx, then write the relation between p and q.
Solution:
Given differential equation is
y = \(e^{\frac{d y}{d x}}\) ⇒ \(\frac{d y}{d x}\) = ln y
Whose order = 1 = p
Degree = 1 = q
∴ p = q

Question 3.
Write the value of \(\int_0^1\){x} dx where {x} stands for fractional part of x.
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise Q.3

Question 4.
Write the order of the differential equation of the family of circles
ar2 + ay2 + 2gx + 2fy + c = 0
ax2 + ay2 + 2gx + 2fy + c = 0
Solution:
As there are 3 independent constants, the order of the differential equation is 3.

Question 5.
If p and q are the order and degree of the differential equation
y\(\left(\frac{d y}{d x}\right)^2\) + x2 \(\frac{d^2 y}{d x^2}\) + xy = sin x, then choose the correct statement out of (i) p > q, (ii) p = q, (iii) p < q.
Solution:
Order of the given differential = p = 2
Degree of the given differential equation = q = 1
∴ p > q

Question 6.
Write the order of the differential equation of the system of ellipses:
\(\frac{x^2}{a^2}\) + \(\frac{y^2}{b^2}\) = 1
Solution:
As there are two unknown constants in the system of ellipses \(\frac{x^2}{a^2}\) + \(\frac{y^2}{b^2}\) = 1 the order of the differential equation is 2.

Question 7.
What do you mean by integration? Write your answer in one sentence.
Solution:
Integration is the antiderivative of a function.

Question 8.
Write the differential equation of the family of straight lines parallel to the y-axis.
Solution:
\(\frac{d x}{d y}\) = 0 is the differential equation of family of lines parallel to y-axis.

Question 9.
Write the value of ∫\(\int_{-\pi / 4}^{\pi / 4}\)sin5 x cos x dx.
Solution:
Let f(x) = sin5 x cos x
f(-x) = sin5 (-x) cos (-x)
= -sin5 x cos x = -f(x)
i.e. f is an odd function.
Thus \(\int_{-\pi / 4}^{\pi / 4}\)sin5 x cos x dx = 0

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise

Question 10.
Write the degree of the differential equation ln\(\left(\frac{\mathrm{d}^2 \mathrm{y}}{\mathrm{dx}^2}\right)\) = y
Solution:
The degree of the differential equation ln\(\left(\frac{\mathrm{d}^2 \mathrm{y}}{\mathrm{dx}^2}\right)\) = y is 1.

Question 11.
What is F'(t) if F(t) = \(\int_a^t\)e3x .cos 2x dx ?
Solution:
F(t) = \(\int_a^t\)e3x .cos 2x dx
⇒ F'(t) = e3x cos 2t

Question 12.
Write the order and degree of the following differential equation:
\(\frac{d^2 y}{d x^2}\) = \(\frac{2 y^3+\left(\frac{d y}{d x}\right)^4}{\sqrt{\frac{d^2 y}{d x^2}}}\)
Solution:
Order = 2, Degree = 3

Question 13.
∫\(\frac{\cot x d x}{\ln \sin x}\) = ?
Solution:
∫\(\frac{\cot x d x}{\ln \sin x}\) = ln(ln sin x) + C

Question 14.
What is F'(x) if F(x) = \(\int_0^{\mathbf{x}}\)e2t sin 3t dt?
Solution:
If F(x) = \(\int_0^{\mathbf{x}}\)e2t sin 3t dt then F'(x) = e2x sin 3x

Question 15.
∫\(\frac{d x}{\cos ^2 x \sin ^2 x}\) = ?
Solution:
∫\(\frac{d x}{\cos ^2 x \sin ^2 x}\) = 4∫\(\frac{d x}{\sin ^2 2 x}\)
= 4∫cosec2 2x dx = -2 cot 2x + C

Question 16.
What is the value of ∫\(\frac{d}{d x}\)f(x) dx – \(\frac{d}{d x}\)(∫f(x) dx)?
Solution:
∫\(\frac{d}{d x}\)f(x) dx – \(\frac{d}{d x}\)(∫f(x) dx)
= f(x) + C – f(x) = C (constant)

Question 17.
If \(\int_1^2\)f(x) dx = λ, then what is the value \(\int_1^2\)f(3 – x) dx?
Solution:
If \(\int_1^2\)f(x) dx = λ, then \(\int_1^2\)f(3 – x) dx = λ

Question 18.
What is the value of \(\int_{-1}^1 \frac{d x}{1+x^2}\)?
Solution:
\(\int_{-1}^1 \frac{d x}{1+x^2}\) = \(\left[\tan ^{-1} x\right]_{-1}^1\)
= tan-1 1 – tan-1 (-1)
= tan-1 1 + tan-1 1
= 2tan-1 (1) = 2 . \(\frac{\pi}{4}\) = \(\frac{\pi}{2}\)

Question 19.
Write the order and the degree of the following differential equation:
\(\frac{d^3 y}{d x^3}\) = \(\left(\frac{d^2 y}{d x^2}\right)^2\) + \(\left(\frac{d y}{d x}\right)^4\) + y
Solution:
Order = 3
Degree = 1

Question 20.
Write the particular solution of \(\frac{d y}{d x}\) = (1 + x)4, y = 0 when x = -1.
Solution:
\(\frac{d y}{d x}\) = (1 + x)4 ⇒ \(\frac{(1+x)^5}{5}\) + C
Given y = 0 for x = -1
⇒ o = o + c ⇒ c = o
∴ The particular solution is y = \(\frac{(1+x)^5}{5}\)

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise

(C) Short Type Questions With Answers

Question 1.
Evaluate: ∫\(\frac{2 x+1}{\sqrt{x^2+10 x+29}}\)dx
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise Q.1

Question 2.
Evaluate: \(\int_0^{\pi / 2} \frac{\cos x d x}{(2-\sin x)(3+\sin x)}\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise Q.2

Question 3.
Evaluate: ∫\(\frac{d x}{(1+x) \sqrt{1-x^2}}\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise Q(3)

Question 4.
Solve: cosec x \(\frac{d^2 y}{d x^2}\) = x.
Solution:
cosec x \(\frac{d^2 y}{d x^2}\) = x => \(\frac{d^2 y}{d x^2}\) = x sin x
⇒ \(\frac{d y}{d x}\) = ∫x sin x dx + A
= x (-cos x) – ∫(-cos x) dx + A
= -x cos x + sin x + A
⇒ y = -∫x cos x dx + ∫sin x dx + A∫dx + B
= [x sin x – ∫sin x dx] – cos x + Ax = B
⇒ y = -x sin x – 2 cos x + Ax + B is the solution.

Question 5.
Find the particular solution of the following differential equation:
\(\frac{d y}{d x}\) = \(\frac{1+y^2}{1+x^2}\) given that y = √3 when x = 1
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise Q.5
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise

Question 6.
Evaluate: \(\int_0^a x^2\left(a^2-x^2\right)^{5 / 2}\) dx
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise Q.6

Question 7.
Evaluate: \(\int_0^a \frac{d x}{e^{4 x}-5}\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise Q.7

Question 8.
Evaluate: ∫x2 tan-1 x dx.
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise Q.8

Question 9.
If f(x) = ex + \(\frac{1}{1+x^2}\) and f(0) = 1, then find f(x).
Solution:
f(x) = ex + \(\frac{1}{1+x^2}\)
⇒ f(x) = ∫\(\left(e^x+\frac{1}{1+x^2}\right)\)dx + C
= ex + tan-1 x + C
f(0) = 1
⇒ 1 = 1 + 0 + C => C = 0
Thus f(x) = ex + tan-1 x

Question 10.
Evaluate: ∫(log x)2 dx
Solution:
I = ∫(log x)2 dx
= (log x)2. x – 2∫(log x) . \(\frac{1}{x}\) . x . dx
= x (log x)2 – 2 ∫log x. dx
= x (log x)2 – 2 {(log x) x – ∫dx}
= x (log x)2 – 2x log x + 2x + C
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise

Question 11.
Evaluate: ∫\(\frac{2 x+9}{(x+3)^2}\)dx
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise Q.11

Question 12.
Solve: ydy + e-y x sin x dx = 0
Solution:
ydy = e-y x sin x dx = 0
⇒ y ey dy + x sin x dx = 0
⇒ ∫y ey dy + ∫x sin x dx =C
⇒ y ey – ey + (-x cos x) + sin x = C
⇒ ey (y – 1) – x cos x + sin x = C is the general solution.

Question 13.
Evaluate: ∫\(\frac{d x}{x \ln x \sqrt{(\ln x)^2-4}}\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise Q.13

Question 14.
Find the particular solution of the differential equation \(\frac{d^2 y}{d x^2}\) = 6x given that y = 1 and \(\frac{d y}{d x}\) = 2 when x = 0.
Solution:
\(\frac{d^2 y}{d x^2}\) = 6x ⇒ \(\frac{d y}{d x}\) = 6 . \(\frac{x^2}{2}\) + A
\(\frac{d y}{d x}\) = 3x2 + A ⇒ y = x3 + Ax + B
Using the givne conditions x = 0, \(\frac{d y}{d x}\) = 2, y = 1, we get
2 = 0 + A ⇒ A = 2
and 1 = 0 + 0 + B ⇒ B = 1
The particular solution is y = x3 + 2x + 1

Question 15.
Evaluate: \(\int_0^{\frac{3}{2}}\)[x2] dx
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise Q.15
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise

Question 16.
Find the differential equation whose general solution is ax2 + by = 1, where a and b are arbitrary constants.
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise Q.16

Question 17.
Integrate: ∫\(\frac{\sin 6 x+\sin 4 x}{\cos 6 x+\cos 4 x}\) dx.
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Additional Exercise Q.17

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a)

Odisha State Board CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Textbook Exercise Questions and Answers.

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Exercise 12(a)

Question 1.
Each question given below has four possible answers out of which only one is correct. Choose the correct one.
(i) \(\vec{a}\) = î + 2ĵ + k̂, \(\vec{b}\) = 2î – 2ĵ + 2k̂ and \(\vec{c}\) = -î + 2 ĵ + k̂ then
(a) \(\vec{a}\) and \(\vec{b}\) have the same direction
(b) \(\vec{a}\) and \(\vec{c}\) have opposite directions.
(c) \(\vec{b}\) and \(\vec{c}\) have opposite directions
(d) no pair of vectors have same direction
Solution:
(d) no pair of vectors have same direction

(ii) If the vectors \(\vec{a}\) = 2î + 3ĵ – 6k̂ and \(\vec{b}\) = -α î – ĵ + 2k̂ are parallel, then α = ______.
(a) 2
(b) \(\frac{2}{3}\)
(c) –\(\frac{2}{3}\)
(d) \(\frac{1}{3}\)
Solution:
(c) –\(\frac{2}{3}\)

(iii) If the position vectors of two points A and B are 3î + k̂, and 2î + ĵ – k̂, then the vector \(\overrightarrow{BA}\) is
(a) -î + ĵ – 2k̂
(b) î + ĵ
(c) î – ĵ + 2k̂
(d) î – ĵ – 2k̂
Solution:
(c) î – ĵ + 2k̂

(iv) If \(|k \vec{a}|\) = 1, then
(a) \(\vec{a}=\frac{1}{k}\)
(b) \(\vec{a}=\frac{1}{|k|}\)
(c) \(k=\frac{1}{|\vec{a}|}\)
(d) \(k=\frac{+1}{|\vec{a}|}\)
Solution:
(d) \(k=\frac{+1}{|\vec{a}|}\)

(v) The direction cosines of the vectors \(\overrightarrow{PQ}\) where \(\overrightarrow{OP}\) = (1, 0, -2) and \(\overrightarrow{OQ}\) = (3, -2, 0) are
(a) 2, -2, 2
(b) 4, -2, -2
(c) \(\frac{1}{\sqrt{3}},-\frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}\)
(d) \(\frac{2}{\sqrt{6}},-\frac{1}{\sqrt{6}},-\frac{1}{\sqrt{6}}\)
Solution:
(c) \(\frac{1}{\sqrt{3}},-\frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}\)

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a)

Question 2.
Rectify the mistakes, if any
(i) \(\vec{a}-\vec{a}\) = 0
Solution:
\(\overrightarrow{0}\)

(ii) The vector \(\overrightarrow{0}\) has unique direction.
Solution:
indefinite direction

(iii) All unit vectors are equal.
Solution:
equal magnitude

(iv) \(|\vec{a}|=|\vec{b}| \Rightarrow \vec{a}=\vec{b}\)
Solution:
\(\vec{a}=\vec{b} \Rightarrow|\vec{a}|=|\vec{b}|\)

(v) Subtraction of vectors is not commutative.
Solution:
true

Question 3.
(i) If \(\vec{a}\) = (2, 1), \(\vec{b}\) = (-1, 0), find \(3 \vec{a}+2 \vec{b}\).
Solution:
\(3 \vec{a}+2 \vec{b}\) = 3 (2, 1) + 2 (-1, 0)
= (6 – 2, 3 + 0)
= (4, 3 )

(ii) If \(\vec{a}\) = (1, 1, 1) , \(\vec{b}\) = (-1, 3, 0) and \(\vec{c}\) =(2, 0, 2), find \(\vec{a}+2 \vec{b}-\frac{1}{2} \vec{c}\).
Solution:
\(\vec{a}+2 \vec{b}-\frac{1}{2} \vec{c}\)
= (1, 1, 1) + 2 (-1, 3, 0) – \(\frac{1}{2}\)(2, 0, 2)
= (1 – 2 – 1, 1 + 6 – 0, 1 + 0 – 1)
= (-2, 7, 0)

Question 4.
If A, B, C and D are the vertices of a square, find \(\overrightarrow{AB}+\overrightarrow{BC}+\overrightarrow{CD}+\overrightarrow{DA}\).
Solution:
Let ABCD be a square.
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.4

Question 5.
The given points A, B, C are the vertices of a triangle. Determine the vectors \(\overrightarrow{A B}, \overrightarrow{B C} \text { and } \overrightarrow{C A}\) and the lengths of these vectors in the following cases.
(i) A (4, 5, 5), B (3, 3, 3), C (1, 2, 5)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.5(1)

(ii) A (8, 6, 1), B (2, 0, 1), C (-4, 0, -5)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.5(2)

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a)

Question 6.
Find the vector from origin to the midpoint of the vector \(\overrightarrow{{P}_1 {P}_2}\) joining the points P1(4, 3) and P2(8, -5).
Solution:
P1 = (4, 3) and P2 = (8, -5)
If P is the mid-point of P1P2 then P = (6, -1).
Position vector of P = \(\overrightarrow{{OP}}\) = 6î – ĵ

Question 7.
Find the vectors from the origin to the points of trisection the vector \(\overrightarrow{{P}_1 {P}_2}\) joining P1 (-4, 3) and P2 (5, -12).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.7

Question 8.
Find the vector from the origin to the intersection of the medians of the triangle whose vertices are A (5, 2, 1), B(-4, 7, 0) and C (5, -3, 5).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.8

Question 9.
Prove that the sum of all the vectors drawn from the centre of a regular octagon to its vertices is the null vector.
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.9

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a)

Question 10.
Prove that the sum of the vectors represented by the sides of a closed polygon taken in order is a zero vector.
Solution:
Consider a closed polygon ABCDEFA.
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.10

Question 11.
(a) Prove that:
(i) \(|\overrightarrow{a}+\overrightarrow{{b}}| \leq|\overrightarrow{a}|+|\overrightarrow{b}|\)
State when the equality will hold;
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.11(1)

(ii) \(|\overrightarrow{a}-\overrightarrow{b}| \geq|\overrightarrow{a}|-|\overrightarrow{b}|\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.11(2)

(b) What is the geometrical significance of the relation \(|\overrightarrow{a}+\overrightarrow{b}|=|\overrightarrow{a}-\overrightarrow{b}|\)?
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.11.1

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a)

Question 12.
Find the magnitude of the vector \(\overrightarrow{PQ}\), its scalar components and the component vectors along the coordinate axes, if P and Q have the coordinates.
(i) P (-1, 3), Q (1, 2)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.12(1)

(ii) P (-1, -2), Q (-5, -6)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.12(2)

(iii) P (1, 4, -3), Q (2, -2, -1).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.12(3)

Question 13.
In each of the following find the vector \(\overrightarrow{PQ}\), its magnitude and direction cosines, if P and Q have co-ordinates.
(i) P (2, -1, -1), Q (-1, -3, 2);
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.13(1)

(ii) P (3, -1, 7), Q (4, -3, -1).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.13(2)

Question 14.
If \(\vec{a}\) = (2, -2, 1), \(\vec{b}\) = (2, 3, 6) and \(\vec{c}\) = (-1, 0, 2), find the magnitude and direction of
\(\vec{a}-\vec{b}+2 \vec{c}\).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.14

Question 15.
Determine the unit vector having the direction of the given vector in each of the following problems:
(i) 5î – 12ĵ
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.15(1)

(ii) 2î + ĵ
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.15(2)

(iii) 3î + 6ĵ – k̂
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.15(3)

(iv) 3î + ĵ – 2k̂
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.15(4)

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a)

Question 16.
Find the unit vector in the direction of the vector \(\overrightarrow{r_1}-\overrightarrow{r_2}\), where \(\vec{r}_1\) = î + 2ĵ + k̂ and \(\vec{r}_2\) = 3î + ĵ – 5k̂.
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.16

Question 17.
Find the unit vector parallel to the sum of the vectors \(\vec{a}\) = 2î + 4ĵ – 5k̂ and \(\vec{b}\) = î + 2ĵ + 3k̂. Also find its direction cosines.
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.17

Question 18.
If the sum of two unit vectors is a unit vector, show that the magnitude of their difference is √3.
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.18

Question 19.
The position vectors of the points A, B, C and D are 4î + 3ĵ – k̂, 5î + 2ĵ + 2k̂, 2î – 2ĵ – 3k̂ and 4î – 4ĵ + 3k̂ respectively. Show that AB and CD are parallel.
Solution:
Given that the
position vector of A = 4î + 3ĵ – k̂
position vector of B = 5î + 2ĵ + 2k̂
position vector of C = 2î – 2ĵ – 3k̂
position vector of D = 4î – 4ĵ + 3k̂
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.19

Question 20.
In each of the following problems, show by vector method that the given points are collinear.
(i) A (2, 6, 3), B (1, 2, 7) and C (3, 10, -1)
Solution:
Given that A = (2, 6, 3), B = (1, 2, 7) and C = (3, 10, -1)
Then
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.20(1)

(ii) P (2, -1, 3), Q (3, -5, 1) and R (-1, 11, 9).
Solution:
Given that P = (2, -1, 3) Q = (3, -5, 1) and R = (-1, 11, 9)
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.20(2)
Hence the points P, Q, R are collinear. (Proved)

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a)

Question 21.
Prove that the vectors 2î – ĵ + k̂, î – 3ĵ – 5k̂, 3î – 4ĵ – 4k̂ are the sides of a right angled triangle.
Solution:
Let A, B and C be the points whose position vectors are 2î – ĵ – k̂, î – 3ĵ – 5k̂ and 3î – 4ĵ – 4k̂ respectively.
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.21

Question 22.
Prove by vector method that:
(a) the medians of a triangle are concurrent;
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.22(1)
The symmetry of the result shows that the point G also lies on the other two medians.
Hence the medians are concurrent. (Proved)

(b) the diagonals of a parallelogram bisect each other;
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.22(2)

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a)

(c) the line segment joining the midpoints of two sides of a triangle is parallel to the third and half of it;
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.22(3)

(d) the lines joining the midpoints of consecutive sides of a quadrilateral is a parallelogram;
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.22(4)
⇒ SR = PQ and SR || PQ
Hence PQRS is a parallelogram.
(Proved)

(e) in any triangle ABC, the point P being on the side \(\overrightarrow{B C} \text {; if } \overrightarrow{P Q}\) is the resultant of the vectors \(\overrightarrow{A P}, \overrightarrow{P B}\) and \(\overrightarrow{P C}\) then ABQC is a parallelogram;
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.22(5)
Hence ABQC is parallelogram. (Proved)

(f) In a parallelogram, the line joining a vertex to the midpoint of an opposite side trisects the other diagonal.
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(a) Q.22(6)
⇒ P divides BD into the ratio 1 : 2.
Similarly we can show that Q divides BD into the ratio 2 : 1.
Hence P, Q are the points of trisection of the diagonal BD. (Proved)

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b)

Odisha State Board Elements of Mathematics Class 12 Solutions CHSE Odisha Chapter 11 Differential Equations Ex 11(b) Textbook Exercise Questions and Answers.

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Exercise 11(b)

Solve the following differential equations.
Question 1.
\(\frac{d y}{d x}\) + y = e-x
Solution:
Given equation is \(\frac{d y}{d x}\) + y = e-x … (1)
This is a linear differential equation.
Here P = 1, Q = e-x
So the integrating factor
I.F. = e∫P dx = e∫dx = ex
The solution of (1) is given by
yex = ∫e-x . ex dx = ∫dx = x + C
⇒ y – xe-x + Ce-x

Question 2.
(x2 – 1)\(\frac{d y}{d x}\) + 2xy = 1
Solution:
Given equation is (x2 – 1)\(\frac{d y}{d x}\) + 2xy = 1
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b) Q.2

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b)

Question 3.
(1 – x2)\(\frac{d y}{d x}\) + 2xy = x \(\sqrt{1-x^2}\)
Solution:
Given equation is
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b) Q.3

Question 4.
x log x \(\frac{d y}{d x}\) + y = 2 log x
Solution:
Given equation is
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b) Q.4

Question 5.
(1 + x2)\(\frac{d y}{d x}\) + 2xy = cos x
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b) Q.5

Question 6.
\(\frac{d y}{d x}\) + y sec x = tan x
Solution:
Given equation is
\(\frac{d y}{d x}\) + y sec x = tan x
This is a linear equation where
P = sec x, Q = tan x
I.F. = e∫sec dx
= e(sec x + tan x) = sec x + tan x
The solution is y . (sec x + tan x)
= ∫(sec x + tan x) tan x dx
= ∫(sec x tan x + tan2 x) dx
= ∫(sec x . tan x + sec2 x – 1) dx
= ∫(sec x + tan x) – x + C
⇒ (y – 1) (sec x + tan x) + x = C

Question 7.
(x + tan y) dy = sin 2y dx
Given equation can be written as
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b) Q.7

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b)

Question 8.
(x + 2y3)\(\frac{d y}{d x}\) = y
Solution:
Given equation can be written as
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b) Q.8

Question 9.
sin x\(\frac{d y}{d x}\)+ 3y = cos x
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b) Q.9
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b) Q.9.1

Question 10.
(x + y + 1)\(\frac{d y}{d x}\) = 1
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b) Q.10

Question 11.
(1 + y2) dx + (x – \(e^{-\tan ^{-1} y}\)) dy = 0
Solution:
Given equation can be written as
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b) Q.11

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b)

Question 12.
x\(\frac{d y}{d x}\) + y = xy2
Solution:
Given equation can be written as
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b) Q.12
⇒ z = -x ln x + Cx
⇒ \(\frac{1}{y}\) = -x ln x + Cx
⇒ 1 = -xy ln x + Cxy
∴ The solution is (C – ln x) xy = 1

Question 13.
\(\frac{d y}{d x}\) + y = y2 log x
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b) Q.13

Question 14.
(1 + x2)\(\frac{d y}{d x}\) = xy – y2
Solution:
The given equation can be written as
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b) Q.14
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b) Q.14.1

Question 15.
\(\frac{d y}{d x}\) + \(\frac{y}{x-1}\) = \(x y^{\frac{1}{2}}\)
Solution:
The given equation can be written as
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b) Q.15

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b)

Question 16.
\(\frac{d y}{d x}\) + \(\frac{y}{x}\) = x2, y(1) = 1
Solution:
The given equation can be written as
\(\frac{d y}{d x}\) + \(\frac{y}{x}\) = x2, y(1) = 1 … (1)
This is a linear equation.
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b) Q.16

Question 17.
\(\frac{d y}{d x}\) + 2y tan x = sin x, y\(\left(\frac{\pi}{3}\right)\) = 0.
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(b) Q.17

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a)

Odisha State Board Elements of Mathematics Class 12 Solutions CHSE Odisha Chapter 11 Differential Equations Ex 11(a) Textbook Exercise Questions and Answers.

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Exercise 11(a)

Question 1.
Determine the order and degree of each of the following differential equations.
(i) y sec2 x dx + tan x dy = 0
Solution:
Order: 1, Degree: 1

(ii) \(\left(\frac{d y}{d x}\right)^4\) + y5 = \(\frac{d^3 y}{d x^3}\)
Solution:
Order: 3, Degree: 1

(iii) a\(\frac{d^2 y}{d x^2}\) = \(\left\{1+\left(\frac{d y}{d x}\right)^2\right\}^{\frac{3}{2}}\)
Solution:
Order: 2, Degree: 2

(iv) tan-1\(\sqrt{\frac{d y}{d x}}\) = x
Solution:
Order: 1, Degree: 1

(v) ln\(\left(\frac{d^2 y}{d x^2}\right)\) = y
Solution:
Order: 2, Degree: 1

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a)

(vi) \(\frac{\frac{d y}{d t}}{y+\frac{d y}{d t}}\) = \(\frac{y t}{d y}\)
Solution:
Order: 1, Degree: 2

(vii) \(\frac{d^2 y}{d u^2}\) = \(\frac{3 y+\frac{d y}{d u}}{\sqrt{\frac{d^2 y}{d u^2}}}\)
Solution:
Order: 2, Degree: 3

(viii) \(e^{\frac{d z}{d x}}\) = x2
Solution:
Order: 1, Degree: 1

Question 2.
Form the differential equation by eliminating the arbitrary constants in each of the following cases.
(i) y = A sec x
Solution:
y = A sec x
Then \(\frac{d y}{d x}\) = A sec x tan x = y tan x

(ii) y = C tan-1 x
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.2(2)

(iii) y = Aet + Be2t
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.2(3)

(iv) y = Ax2 + Bx
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.2(4)

(v) y = -acos x + b sin x
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.2(5)

(vi) y = a sin-1 x + b cos-1 x
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.2(6)

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a)

(vii) y = at + bet
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.2(7)

(viii) y = a sin t + bet
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.2(8)

(ix) ax2 + by = 1
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.2(9)

Question 3.
Find the general solution ofthe following differential equations.
(i) \(\frac{d y}{d x}\) = \(\frac{e^{2 x}+1}{e^x}\)
Solution:
\(\frac{d y}{d x}\) = \(\frac{e^{2 x}+1}{e^x}\)
⇒ y = ∫(ex + e-x) dx = ex – e-x + C

(ii) \(\frac{d y}{d x}\) = x cos x
Solution:
\(\frac{d y}{d x}\) = x cos x
⇒ y = ∫x cos x dx
= x . sin x – ∫sin x dx – x sin x + cos x + C

(iii) \(\frac{d y}{d x}\) = t5 log t
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.3(3)

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a)

(iv) \(\frac{d y}{d x}\) = 3t2 + 4t + sec2 t
Solution:
\(\frac{d y}{d x}\) = 3t2 + 4t + sec2 t
⇒ y = t3 + 2t2 + tan t + C

(v) \(\frac{d y}{d x}\) = \(\frac{1}{x^2-7 x+12}\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.3(5)

(vi) \(\frac{d y}{d u}\) = \(\frac{u+1}{\sqrt{3 u^2+6 u+5}}\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.3(6)

(vii) (x2 + 3x + 2) dy – dx = 0
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.3(7)

(viii) \(\frac{d y}{d t}\) = \(\frac{\sin ^{-1} t e^{\sin ^{-1} t}}{\sqrt{1-t^2}}\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.3(8)

Question 4.
Solve the following differential equations.
(i) \(\frac{d y}{d x}\) = y + 2
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.4(1)

(ii) \(\frac{d y}{d t}\) = \(\sqrt{1-y^2}\)
Solution:
\(\frac{d y}{d t}\) = \(\sqrt{1-y^2}\)
⇒ \(\frac{d y}{\sqrt{1-y^2}}\) = dt
⇒ sin-1 y = t + C

(iii) \(\frac{d y}{d z}\) = sec y
Solution:
\(\frac{d y}{d z}\) = sec y
⇒ cos y dy = dz
⇒ sin y = z + C

(iv) \(\frac{d y}{d x}\) = ey
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.4(4)

(v) \(\frac{d y}{d x}\) = y2 + 2y
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.4(5)

(vi) dy + (y2 + 1) dx = 0
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.4(6)

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a)

(vii) \(\frac{d y}{d x}\) + \(\frac{e^y}{y}\) = 0
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.4(7)

(viii) dx + cot x dt = 0
Solution:
dx + cot x dt = 0
⇒ tan x dx + dt = 0
⇒ ∫tan x dx + ∫dt = C1
⇒ In sec x + t = C1
⇒ In sec x = C1 – t
⇒ sec x = \(e^{C_1}\) . e-t
⇒ cos x = \(e^{-C_1}\) . et
⇒ cos x = Cet where C = \(e^{-C_1}\)

Question 5.
Obtain the general solution of the following differential equations.
(i) \(\frac{d y}{d x}\) = (x2 + 1) (y2 + 1)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.5(1)

(ii) \(\frac{d y}{d t}\) = e2t+3y
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.5(2)
⇒ 2e-3y + 3e2t + 6C1 = 0
⇒ 2e-3y + 3e2t = C
where C = -6C1

(iii) \(\frac{d y}{d z}\) = \(\frac{\sqrt{1-y^2}}{\sqrt{1-z^2}}\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.5(3)

(iv) \(\frac{d y}{d z}\) = \(\frac{x \log x}{3 y^2+4 y}\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.5(4)

(v) x2\(\sqrt{y^2+3}\) dx + y\(\sqrt{x^3+1}\) dy = 0
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.5(5)

(vi) tan y dx + cot x dy = 0
Solution:
tan y dx + cot x dy = 0
⇒ tan x . dx + cot y dy = 0
⇒ ∫tan x dx + ∫cot y dy = 0
⇒ -ln cos x + ln siny = ln C
⇒ ln\(\frac{\sin y}{\cos x}\) = ln C
⇒ \(\frac{\sin y}{\cos x}\) = C
⇒ sin y = C cos x

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a)

(vii) (x2 + 7x + 12) dy + (y2 – 6y + 5) dx = 0
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.5(7)

(viii) y dy + e-y x sin x dx = 0
Solution:
y dy + e-y x sin x dx = 0
⇒ yey dy + x sin x dx = 0
⇒ ∫yey dy + ∫x sin dx = C
[Integrating by parts.
⇒ yey – ∫ey dy + x(-cos x) – ∫(-cos x) dx = C
⇒ yey – ey – x cos x + sin x = C
⇒ (y – 1) ey – x cos x + sin x = C

Question 6.
Solve the following second order equations.
(i) \(\frac{d^2 y}{d x^2}\) = 12x2 + 2x
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.6(1)

(ii) \(\frac{d^2 y}{d t^2}\) =e2t +e-t
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.6(2)

(iii) \(\frac{d^2 y}{d \vartheta^2}\) = -sin υ + cos υ + sec2 υ
Solution:
\(\frac{d^2 y}{d \vartheta^2}\) = -sin υ + cos υ + sec2 υ
Integrating we get
\(\frac{d y}{d υ}\) = ∫sin υ dυ + ∫cos υ dυ + ∫sec2 υ dυ
= cos υ + sin υ + tan υ + A
Again integratingwe get
y = ∫(cos υ + sin υ + tan υ + A)dυ + B
where A, B are arbritrary constants.
⇒ y = sin υ – cos υ + ln |sec υ| + A.υ. + B

(iv) cosec x \(\frac{d^2 y}{d x^2}\) = x
Solution:
cosec x \(\frac{d^2 y}{d x^2}\) = x
\(\frac{d^2 y}{d x^2}\) = x sin x
Integrating we get
\(\frac{d y}{d x}\) = ∫x sin x dx + A
= x . (-cos x) – ∫(-cos x) dx + A
= -x cos x + ∫cos x dx + A
= -x cos x + sin x + A
Again integrating we get
y = -∫x cos x dx + ∫sin x + ∫A dx + B
= -{x sin x -∫1 . sin x dx} – cos x + Ax + B
= -x sin x – 2cos x + Ax + B

(v) x2\(\frac{d^2 y}{d x^2}\) + 2 = 0
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.6(5)

(vi) sec x \(\frac{d^2 y}{d x^2}\) = sec 3x
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.6(6)

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a)

(vii) \(\frac{d^2 y}{d x^2}\) = sec2 x + cos2 x
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.6(7)

(viii) e-x\(\frac{d^2 y}{d x^2}\) = x
Solution:
ex\(\frac{d^2 y}{d x^2}\) = x
⇒ \(\frac{d^2 y}{d x^2}\) = xex
Integrating we get
\(\frac{d y}{d x}\) = ∫xex dx = ∫ex dx + Ax + B
= xex – ex – ex + Ax + B
= (x – 2)ex + Ax + B

Question 7.
Find the particular solutions of the following equations subject to the given conditions.
(i) \(\frac{d y}{d x}\) = cos x, given that y = 2 when x = 0.
Solution:
\(\frac{d y}{d x}\) = cos x
Integrating we get
y = ∫cos x dx = sin x + C
Given that when x = 0, y = 2
So 2 = C
∴ The particular solution is y = sin x + 2

(ii) \(\frac{d y}{d t}\) = cos2 y subject to y = \(\frac{\pi}{4}\) when t = 0.
Solution:
\(\frac{d y}{d t}\) = cos2 y
⇒ sec2 y dy = dt
∫sec2 dy = ∫dt
⇒ tan y = t + C
When t = 0, y = \(\frac{\pi}{4}\)
So tan \(\frac{\pi}{4}\) = C ⇒ C = 1
∴ The particular solution is tan y = t + 1

(iii) \(\frac{d y}{d x}\) = \(\frac{1+y^2}{1+x^2}\) given that y = √3 when x = 1.
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.7(3)

(iv) \(\frac{d^2 y}{d x^2}\) = 6x given that y = 1 and \(\frac{d y}{d x}\) = 2 when x = 0.
Solution:
\(\frac{d^2 y}{d x^2}\) = 6x ⇒ \(\frac{d y}{d x}\) = 3x2 + 2
When x = 0, \(\frac{d y}{d x}\) = 2
So 2 = A
∴ \(\frac{d y}{d x}\) = 3x2 + 2
Again integrating we get
y = x3 + 2x + B
When x = 0, y = 1
So B = 1.
∴ The particular solution is y = x3 + 2x + 1

Question 8.
(i) Solve : \(\frac{d y}{d x}\) = sec (x + y)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.8(1)

(ii) Solve : \(\frac{d y}{d x}\) = sin(x + y) + cos(x + y)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.8(2)

CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a)

(iii) Solve : \(\frac{d y}{d x}\) = cos (x + y)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.8(3)

(iv) Solve : \(\frac{d y}{d x}\) + 1 = ex+y
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 11 Differential Equations Ex 11(a) Q.8(4)

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(d)

Odisha State Board CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(d) Textbook Exercise Questions and Answers.

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Exercise 12(d)

Question 1.
Each question given below has four possible answers out of which only one is correct. Choose the correct one.
(i) \(\vec{a} \cdot \vec{b} \times \vec{a}\) = _______.
(a) \(\overrightarrow{0}\)
(b) 0
(c) 1
(d) \(\vec{a}^2 \vec{b}\)
Solution:
\(\vec{a} \cdot(\vec{b} \times \vec{a})\) = \((\vec{b} \times \vec{a}) \cdot \vec{a}\)
= \(\vec{b} \cdot(\vec{a} \times \vec{a})\) = \(\vec{b} \cdot \overrightarrow{0}\)
= 0 [∴ Dot product is commutative and in the scalar triple product the dot and cross can be interchanged.]

(ii) \((-\vec{a}) \cdot \vec{b} \times(-\vec{c}))\) = _______.
(a) \(\vec{a} \times \vec{b} \cdot \vec{c}\)
(b) \(-\vec{a} \cdot(\vec{b} \times \vec{c})\)
(c) \(\vec{a} \times \vec{c} \cdot \vec{b}\)
(d) \(\vec{a} \cdot(\vec{c} \times \vec{b})\)
Solution:
\((-\vec{a}) \cdot \vec{b} \times(-\vec{c})\) = \(\vec{a} \cdot(\vec{b} \times \vec{c})\)

(iii) For the non-zero vectors \(\vec{a}, \vec{b}\) and \(\vec{c}, \vec{a} \cdot(\vec{b} \times \vec{c})\) = 0 if
(a) \(\vec{b} \perp \vec{c}\)
(b) \(\vec{a} \perp \vec{b}\)
(c) \(\vec{a} \| \vec{c}\)
(d) \(\vec{a} \perp \vec{c}\)
Solution:
\(\vec{a} \cdot(\vec{b} \times \vec{c})\) = \((\vec{a} \times \vec{b}) \cdot \vec{c}\)
\(\vec{c} \perp(\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{b}})\)
but \(\vec{a} \times \vec{b}\) is perpendicular to \(\vec{a}\) and \(\vec{b}\)
∴ \(\vec{a} \| \vec{b}\)

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(d)

Question 2.
Find the scalar triple product \(\vec{b} \cdot(\vec{c} \times \vec{a})\) where \(\vec{a}\), \(\vec{b}\) and \(\vec{c}\) are respectively.
(i) î + ĵ, î – ĵ, 5î + 2ĵ + 3k̂
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(d) Q.2(1)
= 1 (0 – 3) + 1 (0 – 3) + 0 (5 – 2)
= 3 – 3 = -6

(ii) 5î – ĵ + 4k̂, 2î + 3ĵ + 5k̂, 5î – 2ĵ
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(d) Q.2(2)
= 5 (18 + 10) + 1 (12 – 25) + 4 (- 4 – 15)
= 140 – 13 – 76 = 140 – 89 = 51

Question 3.
Find the volume of the parallelopiped whose sides are given by the vectors.
(i) î + ĵ + k̂, k̂, 3î – ĵ + 2k̂
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(d) Q.3(1)
= 1 (0 + 1) – 1 (0 – 3) + 1 (0 – 0)
= 1 + 3 = 4 cube units.

(ii) (1, 0, 0), (0, 1, 0), (0, 0, 1).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(d) Q.3(2)

Question 4.
Show that the following vector are co-planar
(i) î – 2ĵ + 2k̂, 3î + 4ĵ + 5k̂, -2î + 4ĵ – 4k̂
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(d) Q.4(1)

(ii) î + 2ĵ + 3k̂, -2î – 4ĵ + 5k̂, 3î + 6
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(d) Q.4(2)

Question 5.
Find the value of λ so that the three vectors are co-planar.
(i) î + 2ĵ + 3k̂, 4î + ĵ + λk̂ and λî – 4ĵ + k̂
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(d) Q.5(1)

(ii) (2, -1, 1), (1, 2, -3) and (3, λ, 5)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(d) Q.5(2)
⇒ 2 (10 + 3λ) + 1 (5 + 9) + 1 (λ – 6) = 0
⇒ 20 + 6λ +14 + λ – 6 = 0
⇒ 7λ + 28 = 0 ⇒ λ = -4

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(d)

Question 6.
If \(\vec{a}\), \(\vec{b}\) and \(\vec{c}\) mutually perpendiculars, show that \([\vec{a} .(\vec{b} \times \vec{c})]^2\) = a2b2c2
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(d) Q.6

Question 7.
Show that \([\vec{a}+\vec{b} \vec{b}+\vec{c} \vec{c}+\vec{a}]\) = 2\([\vec{a} \vec{b} \vec{c}]\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(d) Q.7

Question 8.
Prove that \([\vec{a} \times \vec{b} \vec{b} \times \vec{c} \vec{c} \times \vec{a}]\) = \([\vec{a} \vec{b} \vec{c}]^2\)
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(d) Q.8

Question 9.
For \(\vec{a}\) = î + ĵ, \(\vec{b}\) = -î + 2k̂, \(\vec{c}\) = ĵ + k̂ obtain \(\vec{a} \times(\vec{b} \times \vec{c})\) and also verify the formula \(\vec{a} \times(\vec{b} \times \vec{c})\) = \((\vec{a} \cdot \vec{c}) \vec{b}-(\vec{a} \cdot \vec{b}) \vec{c}\).
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(d) Q.9

CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(d)

Question 10.
Prove that \(\vec{a} \times(\vec{b} \times \vec{c})+\vec{b} \times(\vec{c} \times \vec{a})+\vec{c} \times(\vec{a} \times \vec{b})\) and hence prove that \(\vec{a} \times(\vec{b} \times \vec{c}), \vec{b} \times(\vec{c} \times \vec{a}), \vec{c} \times(\vec{a} \times \vec{b})\) are coplanar.
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(d) Q.10

Question 11.
If \(\vec{a}\), \(\vec{b}\) and \(\vec{c}\) unit vectors and \(\hat{a} \times(\hat{b} \times \hat{c})=\frac{1}{2} \hat{b}\) find the angles that â makes with b̂ and ĉ, where b̂, ĉ are not parallel.
Solution:
CHSE Odisha Class 12 Math Solutions Chapter 12 Vectors Ex 12(d) Q.11